This question already has answers here:
Assured 6 digit random number
(8 answers)
Closed 1 year ago.
I am new to Gatling and Scala Environment.
How to generate a Random Numeric String having 6 digits, in Gatling?
For example, I need to feed "123456" for an attribute in Gatling.
Thanks for the help.
You could start with what you've got and make the following change...
...filter(_.isDigit).take(6).mkString
...but I'd be more inclined toward the following.
(Random.nextInt(900000)+100000).toString
Note: For the 1st proposed solution, leading zeros are possible, "010203" for example. That's not the case for the 2nd. Not sure which is preferred.
Scala 2.13.x option:
util.Random.between(100000, 1000000)
//minimum (inclusive)--^ ^--maximum (exclusive)
Related
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How to replace a string pattern with increasing integers using regex
(2 answers)
Closed 1 year ago.
When you create multiple cursors in VSCode, how can you type a number at each cursor such that each number is 1 greater than the previous number, starting at 0?
You can use the extension Regex Text Generator
For match expression use: .*
For generator expression use: {{=i}}
This question already has an answer here:
Learning Regular Expressions [closed]
(1 answer)
Closed 4 years ago.
i need some help to write correct regex validation. I want password with no spaces, min. 6 symbols, doesn't matter numbers or letters or symbols. Alphabet a-zA-Z and а-яА-Я(RU). How i can do that?
"^(?=.*[A-Za-z])(?=.*\\d)[A-Za-z\\d]{6,}$"
You can take a look at this link
This question already has answers here:
Remove nth character from string
(4 answers)
Closed 4 years ago.
I'm trying to remove the third character from a string. however, there does not seem to be a clean way to do this. I couldn't find an extension that does this and using a library is a bit overkill
I probably could take the first start range up to this character, then the last range and concatenating these together feels quite wrong and there must be a better way IMO
Any help is appreciated!, Thanks!
You can do that the below way:
var str = "I am Bla Bla"
if str.count > 2 {
str.remove(at: String.Index(encodedOffset: 2))
print(str)
}
Hope this helps.
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How does one go from a Unicode character to its description?
(2 answers)
Closed 6 years ago.
I'm asking again because this question got put on hold:
is there a file/data representation of the unicode 9.0 standard?
there is a website http://unicode.org/ that lists the standard
and there is a page here - http://www.unicode.org/charts/ that has pdfs of all the scripts. For example, 1E900 to 1E95F is reserved for Adlam.
I'm hoping there is some sort of unicode.metadata file that can be read in and parsed so that the following queries can be made:
what is the code range for Osmanya?
how many characters are there for Brahmi?
Unicode is a large standard. The JDK (if it is the Java platform you’re interested in) does not provide APIs that cover ‘all of Unicode’.
I believe the most popular library out there is ICU.
If however the queries you mentioned are all that you’re interested in, then perhaps the java.lang.Character API is all you need.
java.lang.Character.UnicodeBlock.OSMANYA (though I see no method to obtain the codepoint range)
java.lang.Character.UnicodeBlock.BRAHMI
You can for example query whether a codepoint is within the range for Osmanya, by testing the value of (Character$UnicodeBlock/of 1234) for equivalence with Character$UnicodeBlock/OSMANYA.
This question already has answers here:
NSArray from NSCharacterSet
(9 answers)
Closed 7 years ago.
When I'm trying
print(NSCharacterSet.URLQueryAllowedCharacterSet())
it prints
<__NSCFCharacterSet: 0x1759b900>
How do I make it more informative?
You can get a representation of the character set using bitmapRepresentation which could be queried. Or you could do basically the same thing with a loop over all characters and using characterIsMember:. The output is potentially big...
There isn't really a simple option or a generic concise output to what you're asking for. It isn't a common requirement.