Set Toggle color in SwiftUI - swift

I've implemented a toggle after following Apple's tutorial on user input. Currently, it looks like this:
This is the code that produces this UI:
NavigationView {
List {
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
}
}
Now, I'd like the Toggle's on-color to be blue instead of green.
I tried:
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
.accentColor(.blue)
.foregroundColor(.blue)
.background(Color.blue)
None of these worked and I wasn't able to find any other modifiers, such as tintColor.
How do I change the color of a Toggle?

SwiftUI 3.0
Using tint
A new modifier was introduced that can also change the Toggle color:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.tint(.red)
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.tint(.orange)
SwiftUI 2.0
Using SwitchToggleStyle
You can now set a tint color for the on position only in SwiftUI 2.0:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.red))
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.orange))
SwiftUI 1.0
Using ToggleStyle
I created a new ToggleStyle to change the three colors of the Toggle (on color, off color, and the thumb).
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = Color(UIColor.green)
var offColor = Color(UIColor.systemGray5)
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
Button(action: { configuration.isOn.toggle() } )
{
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
}
}
.font(.title)
.padding(.horizontal)
}
}
Examples of Use
Toggle("", isOn: $toggleState)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .green,
offColor: .red,
thumbColor: Color(UIColor.systemTeal)))
Toggle("", isOn: $toggleState2)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .purple))
From the SwiftUI Book

Just use UIAppearance APIs:
UISwitch.appearance().onTintColor = UIColor.blue
It'll of course by default change the appearance of all the instances of UISwitch, as per UIAppearance documentation.
NOTE: Tested as of Xcode 11 beta 5.

SwiftUI 2.0 (Post WWDC-2020)
Using the new SwiftUI enhancements you can use the .toggleStyle modifier.
// Switch tinting
Toggle(isOn: $order.notifyWhenReady) {
Text("Send notification when ready")
}
.toggleStyle(SwitchToggleStyle(tint: .accentColor))
Note this only works for iOS14/iPadOS14/macOS11 and above.

I haven't found a way to directly change a Toggle color yet but an alternative way to have a blue switch or any other custom views, is to create a custom view of your own. To make a custom blue toggle in its simplest form:
struct BlueToggle : UIViewRepresentable {
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.onTintColor = UIColor.blue
}
}
struct ContentView : View {
var body: some View {
BlueToggle()
}
}
Result:

You can modify the global onTintColor for all UISwitch objects inside init().
#State var enable_dhcp = true
init()
{
UISwitch.appearance().onTintColor = .red
}
var body: some View
{
Toggle("DHCP", isOn: $enable_dhcp)
}

Building off #mohammad-reza-farahani 's solution, here is a fully uncompromising approach to getting the configurability of UISwitch with the implementation protocols if SwiftUI.
First wrap a UISwitch in a UIViewRepresentable and set the colors as you wish:
final class CustomToggleWrapper: UIViewRepresentable {
var isOn: Binding<Bool>
init(isOn: Binding<Bool>) {
self.isOn = isOn
}
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
// On color
uiView.onTintColor = UIColor.blue
// Off color
uiView.tintColor = UIColor.red
uiView.layer.cornerRadius = uiView.frame.height / 2
uiView.backgroundColor = UIColor.red
uiView.isOn = isOn.wrappedValue
// Update bound boolean
uiView.addTarget(self, action: #selector(switchIsChanged(_:)), for: .valueChanged)
}
#objc
func switchIsChanged(_ sender: UISwitch) {
isOn.wrappedValue = sender.isOn
}
}
Second, create a custom toggle style using the wrapped UISwitch:
struct CustomToggleStyle: ToggleStyle {
func makeBody(configuration: Self.Configuration) -> some View {
let toggle = CustomToggleWrapper(isOn: configuration.$isOn)
return HStack {
configuration.label
Spacer()
toggle
}
}
}
Implement a Toggle as you normally would, and apply your CustomToggleStyle:
struct TestView: View {
#State private var isOn: Bool = true
var body: some View {
Toggle(
isOn: $isOn
) {
Text("Test: \(String(isOn))")
}.toggleStyle(CustomToggleStyle()).padding()
}
}

Karol Kulesza and George Valkov have provided a very easy to implement solution. I just wanted to add that you can place the code below inside the app delegate's didFinishLaunching method as well.
UISwitch.appearance().onTintColor = .blue
You can also create more specific appearance configurations with
appearance(whenContainedInInstancesOf:)
See https://www.hackingwithswift.com/example-code/uikit/what-is-the-uiappearance-proxy

As the original question was just about changing the toggle on colour and not full Toggle visual customisation, I think something like this would do:
import SwiftUI
struct CustomToggle: UIViewRepresentable {
#Binding var isOn: Bool
func makeCoordinator() -> CustomToggle.Coordinator {
Coordinator(isOn: $isOn)
}
func makeUIView(context: Context) -> UISwitch {
let view = UISwitch()
view.onTintColor = UIColor.red
view.addTarget(context.coordinator, action: #selector(Coordinator.switchIsChanged(_:)), for: .valueChanged)
return view
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
class Coordinator: NSObject {
#Binding private var isOn: Bool
init(isOn: Binding<Bool>) {
_isOn = isOn
}
#objc func switchIsChanged(_ sender: UISwitch) {
_isOn.wrappedValue = sender.isOn
}
}
}
// MARK: - Previews
struct CustomToggle_Previews: PreviewProvider {
static var previews: some View {
ViewWrapper()
}
struct ViewWrapper: View {
#State(initialValue: false) var isOn: Bool
var body: some View {
CustomToggle(isOn: $isOn)
.previewLayout(.fixed(width: 100, height: 100))
}
}
}

The easist way is setting UISwitch.appearance().onTintColor = UIColor.red before using toggle and use SwiftUI Toggle like below.
UISwitch.appearance().onTintColor = UIColor.red
...
let toggle = Toggle(isOn: $vm.dataUsePermission, label: {
Text(I18N.permit_data_usage)
.font(SwiftUI.Font.system(size: 16, weight: .regular))
})
if #available(iOS 14.0, *) {
toggle.toggleStyle(
SwitchToggleStyle(tint: Color(UIColor.m.blue500))
)
} else {
toggle.toggleStyle(SwitchToggleStyle())
}
...
You can alse use same Toggle interface in SwiftUI but different name, and change tint color.
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
If only need Toggle without Label, then
TintableUISwitch(isOn: .constant(true))
Use below code.
import SwiftUI
public struct TintableSwitch<Label>: View where Label: View {
#Binding var isOn: Bool
var label: Label
public init(isOn: Binding<Bool>, #ViewBuilder label: () -> Label) {
self._isOn = isOn
self.label = label()
}
public var body: some View {
HStack {
label
Spacer()
TintableUISwitch(isOn: $isOn, onTintColor: .red) // 📌 CHANGE HERE
}
}
}
public struct TintableUISwitch: UIViewRepresentable {
#Binding var isOn: Bool
private var onTintColor: UIColor
public init(isOn: Binding<Bool>, onTintColor: UIColor = UIColor.m.blue500) {
self._isOn = isOn
self.onTintColor = onTintColor
}
public func makeUIView(context: Context) -> UISwitch {
let uiSwitch = UISwitch()
uiSwitch.addTarget(
context.coordinator,
action: #selector(Coordinator.valueChanged(_:)),
for: .valueChanged
)
uiSwitch.onTintColor = onTintColor
uiSwitch.isOn = isOn
return uiSwitch
}
public func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
public func makeCoordinator() -> Coordinator {
Coordinator(self)
}
public class Coordinator: NSObject {
var tintableSwitch: TintableUISwitch
init(_ tintableSwitch: TintableUISwitch) {
self.tintableSwitch = tintableSwitch
}
#objc
func valueChanged(_ sender: UISwitch) {
tintableSwitch.isOn = sender.isOn
}
}
}
struct TintableSwitch_Previews: PreviewProvider {
static var previews: some View {
VStack {
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
}
}
}
struct TintableUISwitch_Previews: PreviewProvider {
static var previews: some View {
TintableUISwitch(isOn: .constant(true))
}
}

You can change the toggle color in IOS 15.0 using a tint modifier.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.tint(.red)
and below IOS 15.0, You can use toggleStyle modifier to change the toggle color but it will be depreciated in the future.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.toggleStyle(SwitchToggleStyle(tint: .red))

I would change #Mark Moeykens answer a little bit to avoid having the button tap animation. A better solution would be:
#available(iOS 13.0, *)
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = UIColor.proacPrimaryBlue.suColor
var offColor = UIColor.systemGray5.suColor
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
.onTapGesture {
configuration.isOn.toggle()
}
}
.font(.title)
.padding(.horizontal)
}
}

This https://stackoverflow.com/a/56480720/5941807 (for now whit Xcode 11 beta 6) is a solution. To switch between to option a fast way is using the boolean instead of if/else:
showFavoritesOnly ? .red : .blue
for foreground:
Toggle(isOn: $showGreeting) {
Text("Show Favorites only").foregroundColor(showFavoritesOnly ? .blue : .gray)
}
for tint:
uiView.onTintColor = showFavoritesOnly ? UIColor.blue : UIColor.gray
In addition for custom colors: https://stackoverflow.com/a/57744208/5941807

Related

How can I detect press gesture within ButtonStyle in SwiftUI? [duplicate]

I have a Button. I want to set custom background color for highlighted state. How can I do it in SwiftUI?
Button(action: signIn) {
Text("Sign In")
}
.padding(.all)
.background(Color.red)
.cornerRadius(16)
.foregroundColor(.white)
.font(Font.body.bold())
Updated for SwiftUI beta 5
SwiftUI does actually expose an API for this: ButtonStyle.
struct MyButtonStyle: ButtonStyle {
func makeBody(configuration: Self.Configuration) -> some View {
configuration.label
.padding()
.foregroundColor(.white)
.background(configuration.isPressed ? Color.red : Color.blue)
.cornerRadius(8.0)
}
}
// To use it
Button(action: {}) {
Text("Hello World")
}
.buttonStyle(MyButtonStyle())
As far as I can tell, theres no officially supported way to do this as of yet. Here is a little workaround that you can use. This produces the same behavior as in UIKit where tapping a button and dragging your finger off of it will keep the button highlighted.
struct HoverButton<Label: View>: View {
private let action: () -> ()
private let label: () -> Label
init(action: #escaping () -> (), label: #escaping () -> Label) {
self.action = action
self.label = label
}
#State private var pressed: Bool = false
var body: some View {
Button(action: action) {
label()
.foregroundColor(pressed ? .red : .blue)
.gesture(DragGesture(minimumDistance: 0.0)
.onChanged { _ in self.pressed = true }
.onEnded { _ in self.pressed = false })
}
}
}
I was looking for a similar functionality and I did it in the following way.
I created a special View struct returning a Button in the style I need, in this struct I added a State property selected. I have a variable named 'table' which is an Int since my buttons a round buttons with numbers on it
struct TableButton: View {
#State private var selected = false
var table: Int
var body: some View {
Button("\(table)") {
self.selected.toggle()
}
.frame(width: 50, height: 50)
.background(selected ? Color.blue : Color.red)
.foregroundColor(.white)
.clipShape(Circle())
}
}
Then I use in my content View the code
HStack(spacing: 10) {
ForEach((1...6), id: \.self) { table in
TableButton(table: table)
}
}
This creates an horizontal stack with 6 buttons which color blue when selected and red when deselected.
I am not a experienced developer but just tried all possible ways until I found that this is working for me, hopefully it is useful for others as well.
This is for the people who are not satisfied with the above solutions, as they raise other problems such as overlapping gestures(for example, it's quite hard to use this solution in scrollview now). Another crutch is to create a custom button style like this
struct CustomButtonStyle<Content>: ButtonStyle where Content: View {
var change: (Bool) -> Content
func makeBody(configuration: Self.Configuration) -> some View {
return change(configuration.isPressed)
}
}
So, we should just transfer the closure which will return the state of the button and create the button based on this parameter. It will be used like this:
struct CustomButton<Content>: View where Content: View {
var content: Content
init(#ViewBuilder content: () -> Content) {
self.content = content()
}
var body: some View {
Button(action: { }, label: {
EmptyView()
})
.buttonStyle(CustomButtonStyle(change: { bool in
Text("\(bool ? "yo" : "yo2")")
}))
}
}
Okey let me clear everything again. Here is the exact solution
Create the below button modifier.
struct StateableButton<Content>: ButtonStyle where Content: View {
var change: (Bool) -> Content
func makeBody(configuration: Configuration) -> some View {
return change(configuration.isPressed)
}
}
Then use it like below one
Button(action: {
print("Do something")
}, label: {
// Don't create your button view in here
EmptyView()
})
.buttonStyle(StateableButton(change: { state in
// Create your button view in here
return HStack {
Image(systemName: "clock.arrow.circlepath")
Text(item)
Spacer()
Image(systemName: "arrow.up.backward")
}
.padding(.horizontal)
.frame(height: 50)
.background(state ? Color.black : Color.clear)
}))
You need to define a custom style that can be used to provide the two backgrounds for normal and highlighted states:
Button(action: {
print("action")
}, label: {
Text("My Button").padding()
})
.buttonStyle(HighlightableButtonStyle(normal: { Color.red },
highlighted: { Color.green }))
// Custom button style
#available(iOS 15.0, macOS 12.0, tvOS 15.0, watchOS 8.0, *)
struct HighlightableButtonStyle<N, H>: ButtonStyle where N: View, H: View {
private let alignment: Alignment
private let normal: () -> N
private let highlighted: () -> H
init(alignment: Alignment = .center, #ViewBuilder normal: #escaping () -> N, #ViewBuilder highlighted: #escaping () -> H) {
self.alignment = alignment
self.normal = normal
self.highlighted = highlighted
}
func makeBody(configuration: Configuration) -> some View {
return ZStack {
if configuration.isPressed {
configuration.label.background(alignment: alignment, content: normal)
}
else {
configuration.label.background(alignment: alignment, content: highlighted)
}
}
}
}

`ColorPicker` with active label?

Consider the following code:
struct ContentView: View {
#State var color: Color = .blue
var body: some View {
ColorPicker(selection: $color) {
Label("Pallete", systemImage: "paintpalette")
}
}
}
It brings up a color picker modal view if you tap on color circle. I would like the same to happen also for taps on the label.
These is way to use the fancy system color picker any way we like, but as of iOS 15 it will require bringing with UIKit.
Create a new view struct like this:
import SwiftUI
struct ColorPickerPanel: UIViewControllerRepresentable {
#Binding var color: Color
func makeCoordinator() -> Coordinator {
Coordinator(self)
}
func makeUIViewController(context: Context) -> UIColorPickerViewController {
let picker = UIColorPickerViewController()
picker.delegate = context.coordinator
return picker
}
func updateUIViewController(_ picker: UIColorPickerViewController, context: Context) {
picker.selectedColor = UIColor(color)
}
class Coordinator: NSObject, UIColorPickerViewControllerDelegate {
var parent: ColorPickerPanel
init(_ pageViewController: ColorPickerPanel) {
self.parent = pageViewController
}
func colorPickerViewControllerDidSelectColor(_ viewController: UIColorPickerViewController) {
parent.color = Color(uiColor: viewController.selectedColor)
}
}
}
Then use it like this:
struct ContentView: View {
#State var color: Color = .accentColor
#State var isColorPickerPresented = false
var body: some View {
VStack {
Button {
isColorPickerPresented = true
} label: {
ColorPicker(selection: $color) {
Label("Pallete", systemImage: "paintpalette")
.allowsHitTesting(true)
.accessibilityAddTraits(.isButton)
}
}
}
.sheet(isPresented: $isColorPickerPresented) {
ZStack (alignment: .topTrailing) {
ColorPickerPanel(color: $color)
Button {
isColorPickerPresented = false
} label: {
Image(systemName: "xmark.circle.fill")
.foregroundStyle(.tint, .secondary)
.font(.title)
}
.offset(x: -10, y: 10)
}
}
}
}
You may provide another to dismiss picker, of course.

UISwitch.appearance().onTintColor not working since iOS 14 [duplicate]

I've implemented a toggle after following Apple's tutorial on user input. Currently, it looks like this:
This is the code that produces this UI:
NavigationView {
List {
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
}
}
Now, I'd like the Toggle's on-color to be blue instead of green.
I tried:
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
.accentColor(.blue)
.foregroundColor(.blue)
.background(Color.blue)
None of these worked and I wasn't able to find any other modifiers, such as tintColor.
How do I change the color of a Toggle?
SwiftUI 3.0
Using tint
A new modifier was introduced that can also change the Toggle color:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.tint(.red)
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.tint(.orange)
SwiftUI 2.0
Using SwitchToggleStyle
You can now set a tint color for the on position only in SwiftUI 2.0:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.red))
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.orange))
SwiftUI 1.0
Using ToggleStyle
I created a new ToggleStyle to change the three colors of the Toggle (on color, off color, and the thumb).
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = Color(UIColor.green)
var offColor = Color(UIColor.systemGray5)
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
Button(action: { configuration.isOn.toggle() } )
{
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
}
}
.font(.title)
.padding(.horizontal)
}
}
Examples of Use
Toggle("", isOn: $toggleState)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .green,
offColor: .red,
thumbColor: Color(UIColor.systemTeal)))
Toggle("", isOn: $toggleState2)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .purple))
From the SwiftUI Book
Just use UIAppearance APIs:
UISwitch.appearance().onTintColor = UIColor.blue
It'll of course by default change the appearance of all the instances of UISwitch, as per UIAppearance documentation.
NOTE: Tested as of Xcode 11 beta 5.
SwiftUI 2.0 (Post WWDC-2020)
Using the new SwiftUI enhancements you can use the .toggleStyle modifier.
// Switch tinting
Toggle(isOn: $order.notifyWhenReady) {
Text("Send notification when ready")
}
.toggleStyle(SwitchToggleStyle(tint: .accentColor))
Note this only works for iOS14/iPadOS14/macOS11 and above.
I haven't found a way to directly change a Toggle color yet but an alternative way to have a blue switch or any other custom views, is to create a custom view of your own. To make a custom blue toggle in its simplest form:
struct BlueToggle : UIViewRepresentable {
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.onTintColor = UIColor.blue
}
}
struct ContentView : View {
var body: some View {
BlueToggle()
}
}
Result:
You can modify the global onTintColor for all UISwitch objects inside init().
#State var enable_dhcp = true
init()
{
UISwitch.appearance().onTintColor = .red
}
var body: some View
{
Toggle("DHCP", isOn: $enable_dhcp)
}
Building off #mohammad-reza-farahani 's solution, here is a fully uncompromising approach to getting the configurability of UISwitch with the implementation protocols if SwiftUI.
First wrap a UISwitch in a UIViewRepresentable and set the colors as you wish:
final class CustomToggleWrapper: UIViewRepresentable {
var isOn: Binding<Bool>
init(isOn: Binding<Bool>) {
self.isOn = isOn
}
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
// On color
uiView.onTintColor = UIColor.blue
// Off color
uiView.tintColor = UIColor.red
uiView.layer.cornerRadius = uiView.frame.height / 2
uiView.backgroundColor = UIColor.red
uiView.isOn = isOn.wrappedValue
// Update bound boolean
uiView.addTarget(self, action: #selector(switchIsChanged(_:)), for: .valueChanged)
}
#objc
func switchIsChanged(_ sender: UISwitch) {
isOn.wrappedValue = sender.isOn
}
}
Second, create a custom toggle style using the wrapped UISwitch:
struct CustomToggleStyle: ToggleStyle {
func makeBody(configuration: Self.Configuration) -> some View {
let toggle = CustomToggleWrapper(isOn: configuration.$isOn)
return HStack {
configuration.label
Spacer()
toggle
}
}
}
Implement a Toggle as you normally would, and apply your CustomToggleStyle:
struct TestView: View {
#State private var isOn: Bool = true
var body: some View {
Toggle(
isOn: $isOn
) {
Text("Test: \(String(isOn))")
}.toggleStyle(CustomToggleStyle()).padding()
}
}
Karol Kulesza and George Valkov have provided a very easy to implement solution. I just wanted to add that you can place the code below inside the app delegate's didFinishLaunching method as well.
UISwitch.appearance().onTintColor = .blue
You can also create more specific appearance configurations with
appearance(whenContainedInInstancesOf:)
See https://www.hackingwithswift.com/example-code/uikit/what-is-the-uiappearance-proxy
As the original question was just about changing the toggle on colour and not full Toggle visual customisation, I think something like this would do:
import SwiftUI
struct CustomToggle: UIViewRepresentable {
#Binding var isOn: Bool
func makeCoordinator() -> CustomToggle.Coordinator {
Coordinator(isOn: $isOn)
}
func makeUIView(context: Context) -> UISwitch {
let view = UISwitch()
view.onTintColor = UIColor.red
view.addTarget(context.coordinator, action: #selector(Coordinator.switchIsChanged(_:)), for: .valueChanged)
return view
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
class Coordinator: NSObject {
#Binding private var isOn: Bool
init(isOn: Binding<Bool>) {
_isOn = isOn
}
#objc func switchIsChanged(_ sender: UISwitch) {
_isOn.wrappedValue = sender.isOn
}
}
}
// MARK: - Previews
struct CustomToggle_Previews: PreviewProvider {
static var previews: some View {
ViewWrapper()
}
struct ViewWrapper: View {
#State(initialValue: false) var isOn: Bool
var body: some View {
CustomToggle(isOn: $isOn)
.previewLayout(.fixed(width: 100, height: 100))
}
}
}
The easist way is setting UISwitch.appearance().onTintColor = UIColor.red before using toggle and use SwiftUI Toggle like below.
UISwitch.appearance().onTintColor = UIColor.red
...
let toggle = Toggle(isOn: $vm.dataUsePermission, label: {
Text(I18N.permit_data_usage)
.font(SwiftUI.Font.system(size: 16, weight: .regular))
})
if #available(iOS 14.0, *) {
toggle.toggleStyle(
SwitchToggleStyle(tint: Color(UIColor.m.blue500))
)
} else {
toggle.toggleStyle(SwitchToggleStyle())
}
...
You can alse use same Toggle interface in SwiftUI but different name, and change tint color.
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
If only need Toggle without Label, then
TintableUISwitch(isOn: .constant(true))
Use below code.
import SwiftUI
public struct TintableSwitch<Label>: View where Label: View {
#Binding var isOn: Bool
var label: Label
public init(isOn: Binding<Bool>, #ViewBuilder label: () -> Label) {
self._isOn = isOn
self.label = label()
}
public var body: some View {
HStack {
label
Spacer()
TintableUISwitch(isOn: $isOn, onTintColor: .red) // 📌 CHANGE HERE
}
}
}
public struct TintableUISwitch: UIViewRepresentable {
#Binding var isOn: Bool
private var onTintColor: UIColor
public init(isOn: Binding<Bool>, onTintColor: UIColor = UIColor.m.blue500) {
self._isOn = isOn
self.onTintColor = onTintColor
}
public func makeUIView(context: Context) -> UISwitch {
let uiSwitch = UISwitch()
uiSwitch.addTarget(
context.coordinator,
action: #selector(Coordinator.valueChanged(_:)),
for: .valueChanged
)
uiSwitch.onTintColor = onTintColor
uiSwitch.isOn = isOn
return uiSwitch
}
public func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
public func makeCoordinator() -> Coordinator {
Coordinator(self)
}
public class Coordinator: NSObject {
var tintableSwitch: TintableUISwitch
init(_ tintableSwitch: TintableUISwitch) {
self.tintableSwitch = tintableSwitch
}
#objc
func valueChanged(_ sender: UISwitch) {
tintableSwitch.isOn = sender.isOn
}
}
}
struct TintableSwitch_Previews: PreviewProvider {
static var previews: some View {
VStack {
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
}
}
}
struct TintableUISwitch_Previews: PreviewProvider {
static var previews: some View {
TintableUISwitch(isOn: .constant(true))
}
}
You can change the toggle color in IOS 15.0 using a tint modifier.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.tint(.red)
and below IOS 15.0, You can use toggleStyle modifier to change the toggle color but it will be depreciated in the future.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.toggleStyle(SwitchToggleStyle(tint: .red))
I would change #Mark Moeykens answer a little bit to avoid having the button tap animation. A better solution would be:
#available(iOS 13.0, *)
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = UIColor.proacPrimaryBlue.suColor
var offColor = UIColor.systemGray5.suColor
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
.onTapGesture {
configuration.isOn.toggle()
}
}
.font(.title)
.padding(.horizontal)
}
}
This https://stackoverflow.com/a/56480720/5941807 (for now whit Xcode 11 beta 6) is a solution. To switch between to option a fast way is using the boolean instead of if/else:
showFavoritesOnly ? .red : .blue
for foreground:
Toggle(isOn: $showGreeting) {
Text("Show Favorites only").foregroundColor(showFavoritesOnly ? .blue : .gray)
}
for tint:
uiView.onTintColor = showFavoritesOnly ? UIColor.blue : UIColor.gray
In addition for custom colors: https://stackoverflow.com/a/57744208/5941807

Change background color of TextEditor in SwiftUI

TextEditor seems to have a default white background. So the following is not working and it displayed as white instead of defined red:
var body: some View {
TextEditor(text: .constant("Placeholder"))
.background(Color.red)
}
Is it possible to change the color to a custom one?
iOS 16
You should hide the default background to see your desired one:
TextEditor(text: .constant("Placeholder"))
.scrollContentBackground(.hidden) // <- Hide it
.background(.red) // To see this
iOS 15 and below
TextEditor is backed by UITextView. So you need to get rid of the UITextView's backgroundColor first and then you can set any View to the background.
struct ContentView: View {
init() {
UITextView.appearance().backgroundColor = .clear
}
var body: some View {
List {
TextEditor(text: .constant("Placeholder"))
.background(.red)
}
}
}
Demo
You can find my simple trick for growing TextEditor here in this answer
Pure SwiftUI solution on iOS and macOS
colorMultiply is your friend.
struct ContentView: View {
#State private var editingText: String = ""
var body: some View {
TextEditor(text: $editingText)
.frame(width: 400, height: 100, alignment: .center)
.cornerRadius(3.0)
.colorMultiply(.gray)
}
}
Update iOS 16 / SwiftUI 4.0
You need to use .scrollContentBackground(.hidden) instead of UITextView.appearance().backgroundColor = .clear
https://twitter.com/StuFFmc/status/1556561422431174656
Warning: This is an iOS 16 only so you'll probably need some if #available and potentially two different TextEditor component.
extension View {
/// Layers the given views behind this ``TextEditor``.
func textEditorBackground<V>(#ViewBuilder _ content: () -> V) -> some View where V : View {
self
.onAppear {
UITextView.appearance().backgroundColor = .clear
}
.background(content())
}
}
Custom Background color with SwiftUI on macOS
On macOS, unfortunately, you have to fallback to AppKit and wrap NSTextView.
You need to declare a view that conforms to NSViewRepresentable
This should give you pretty much the same behaviour as SwiftUI's TextEditor-View and since the wrapped NSTextView does not draw its background, you can use the .background-ViewModifier to change the background
struct CustomizableTextEditor: View {
#Binding var text: String
var body: some View {
GeometryReader { geometry in
NSScrollableTextViewRepresentable(text: $text, size: geometry.size)
}
}
}
struct NSScrollableTextViewRepresentable: NSViewRepresentable {
typealias Representable = Self
// Hook this binding up with the parent View
#Binding var text: String
var size: CGSize
// Get the UndoManager
#Environment(\.undoManager) var undoManger
// create an NSTextView
func makeNSView(context: Context) -> NSScrollView {
// create NSTextView inside NSScrollView
let scrollView = NSTextView.scrollableTextView()
let nsTextView = scrollView.documentView as! NSTextView
// use SwiftUI Coordinator as the delegate
nsTextView.delegate = context.coordinator
// set drawsBackground to false (=> clear Background)
// use .background-modifier later with SwiftUI-View
nsTextView.drawsBackground = false
// allow undo/redo
nsTextView.allowsUndo = true
return scrollView
}
func updateNSView(_ scrollView: NSScrollView, context: Context) {
// get wrapped nsTextView
guard let nsTextView = scrollView.documentView as? NSTextView else {
return
}
// fill entire given size
nsTextView.minSize = size
// set NSTextView string from SwiftUI-Binding
nsTextView.string = text
}
// Create Coordinator for this View
func makeCoordinator() -> Coordinator {
Coordinator(self)
}
// Declare nested Coordinator class which conforms to NSTextViewDelegate
class Coordinator: NSObject, NSTextViewDelegate {
var parent: Representable // store reference to parent
init(_ textEditor: Representable) {
self.parent = textEditor
}
// delegate method to retrieve changed text
func textDidChange(_ notification: Notification) {
// check that Notification.name is of expected notification
// cast Notification.object as NSTextView
guard notification.name == NSText.didChangeNotification,
let nsTextView = notification.object as? NSTextView else {
return
}
// set SwiftUI-Binding
parent.text = nsTextView.string
}
// Pass SwiftUI UndoManager to NSTextView
func undoManager(for view: NSTextView) -> UndoManager? {
parent.undoManger
}
// feel free to implement more delegate methods...
}
}
Usage
ContenView: View {
#State private var text: String
var body: some View {
VStack {
Text("Enter your text here:")
CustomizableTextEditor(text: $text)
.background(Color.red)
}
.frame(minWidth: 600, minHeight: 400)
}
}
Edit:
Pass reference to SwiftUI UndoManager so that default undo/redo actions are available.
Wrap NSTextView in NSScrollView so that it is scrollable. Set minSize property of NSTextView to enclosing SwiftUIView-Size so that it fills the entire allowed space.
Caveat: Only first line of this custom TextEditor is clickable to enable text editing.
This works for me on macOS
extension NSTextView {
open override var frame: CGRect {
didSet {
backgroundColor = .clear
drawsBackground = true
}
}
}
struct ContentView: View {
#State var text = ""
var body: some View {
TextEditor(text: $text)
.background(Color.red)
}
Reference this answer
To achieve this visual design here is the code I used.
iOS 16
TextField(
"free_form",
text: $comment,
prompt: Text("Type your feedback..."),
axis: .vertical
)
.lineSpacing(10.0)
.lineLimit(10...)
.padding(16)
.background(Color.themeSeashell)
.cornerRadius(16)
iOS 15
ZStack(alignment: .topLeading) {
RoundedRectangle(cornerRadius: 16)
.foregroundColor(.gray)
TextEditor(text: $comment)
.padding()
.focused($isFocused)
if !isFocused {
Text("Type your feedback...")
.padding()
}
}
.frame(height: 132)
.onAppear() {
UITextView.appearance().backgroundColor = .clear
}
You can use Mojtaba's answer (the approved answer). It works in most cases. However, if you run into this error:
"Return from initializer without initializing all stored properties"
when trying to use the init{ ... } method, try adding UITextView.appearance().backgroundColor = .clear to .onAppear{ ... } instead.
Example:
var body: some View {
VStack(alignment: .leading) {
...
}
.onAppear {
UITextView.appearance().backgroundColor = .clear
}
}
Using the Introspect library, you can use .introspectTextView for changing the background color.
TextEditor(text: .constant("Placeholder"))
.cornerRadius(8)
.frame(height: 100)
.introspectTextView { textView in
textView.backgroundColor = UIColor(Color.red)
}
Result
import SwiftUI
struct AddCommentView: View {
init() {
UITextView.appearance().backgroundColor = .clear
}
var body: some View {
VStack {
if #available(iOS 16.0, *) {
TextEditor(text: $viewModel.commentText)
.scrollContentBackground(.hidden)
} else {
TextEditor(text: $viewModel.commentText)
}
}
.background(Color.blue)
.frame(height: UIScreen.main.bounds.width / 2)
.overlay(
RoundedRectangle(cornerRadius: 5)
.stroke(Color.red, lineWidth: 1)
)
}
}
It appears the UITextView.appearance().backgroundColor = .clear trick in IOS 16,
only works for the first time you open the view and the effect disappear when the second time it loads.
So we need to provide both ways in the app. Answer from StuFF mc works.
var body: some View {
if #available(iOS 16.0, *) {
mainView.scrollContentBackground(.hidden)
} else {
mainView.onAppear {
UITextView.appearance().backgroundColor = .clear
}
}
}
// rename body to mainView
var mainView: some View {
TextEditor(text: $notes).background(Color.red)
}

SwiftUI - Hiding a ScrollView's indicators makes it stop scrolling

I'm trying to hide the indicators of a ScrollView but when I try doing so, the ScrollView just doesn't scroll anymore. I'm using macOS if that matters.
ScrollView(showsIndicators: false) {
// Everything is in here
}
On request of #SoOverIt
Demo:
Nothing special, just launched some other test example. Xcode 11.2 / macOS 10.15
var body : some View {
VStack {
ScrollView([.vertical], showsIndicators: false) {
Group {
Text("AAA")
Text("BBB")
Text("CCC")
Text("DDD")
Text("EEE")
}
Group {
Text("AAA")
Text("BBB")
Text("CCC")
Text("DDD")
Text("EEE")
}
Group {
Text("AAA")
Text("BBB")
Text("CCC")
Text("DDD")
Text("EEE")
}
Group {
Text("AAA")
Text("BBB")
Text("CCC")
Text("DDD")
Text("EEE")
}
}
.frame(height: 100)
.border(Color.blue)
}
.border(Color.red)
}
I fixed the issue.
extension View {
func hideIndicators() -> some View {
return PanelScrollView{ self }
}
}
struct PanelScrollView<Content> : View where Content : View {
let content: () -> Content
var body: some View {
PanelScrollViewControllerRepresentable(content: self.content())
}
}
struct PanelScrollViewControllerRepresentable<Content>: NSViewControllerRepresentable where Content: View{
func makeNSViewController(context: Context) -> PanelScrollViewHostingController<Content> {
return PanelScrollViewHostingController(rootView: self.content)
}
func updateNSViewController(_ nsViewController: PanelScrollViewHostingController<Content>, context: Context) {
}
typealias NSViewControllerType = PanelScrollViewHostingController<Content>
let content: Content
}
class PanelScrollViewHostingController<Content>: NSHostingController<Content> where Content : View {
var scrollView: NSScrollView?
override func viewDidAppear() {
self.scrollView = findNSScrollView(view: self.view)
self.scrollView?.scrollerStyle = .overlay
self.scrollView?.hasVerticalScroller = false
self.scrollView?.hasHorizontalScroller = false
super.viewDidAppear()
}
func findNSScrollView(view: NSView?) -> NSScrollView? {
if view?.isKind(of: NSScrollView.self) ?? false {
return (view as? NSScrollView)
}
for v in view?.subviews ?? [] {
if let vc = findNSScrollView(view: v) {
return vc
}
}
return nil
}
}
Preview:
struct MyScrollView_Previews: PreviewProvider {
static var previews: some View {
ScrollView{
VStack{
Text("hello")
Text("hello")
Text("hello")
Text("hello")
Text("hello")
}
}.hideIndicators()
}
}
So... I think that's the only way for now.
You basically just put a View over your ScrollView indicator with the same backgroundColor as your background View
Note: This obviously only works if your background is static with no content at the trailing edge.
Idea
struct ContentView: View {
#Environment(\.colorScheme) var colorScheme: ColorScheme
let yourBackgroundColorLight: Color = .white
let yourBackgroundColorDark: Color = .black
var yourBackgroundColor: Color { colorScheme == .light ? yourBackgroundColorLight : yourBackgroundColorDark }
var body: some View {
ScrollView {
VStack {
ForEach(0..<1000) { i in
Text(String(i)).frame(width: 280).foregroundColor(.green)
}
}
}
.background(yourBackgroundColor) //<-- Same
.overlay(
HStack {
Spacer()
Rectangle()
.frame(width: 10)
.foregroundColor(yourBackgroundColor) //<-- Same
}
)
}
}
Compact version
You could improve this like that, I suppose you have your color dynamically set up inside assets.
Usage:
ScrollView {
...
}
.hideIndicators(with: <#Your Color#>)
Implementation:
extension View {
func hideIndicators(with color: Color) -> some View {
return modifier(HideIndicators(color: color))
}
}
struct HideIndicators: ViewModifier {
let color: Color
func body(content: Content) -> some View {
content
.overlay(
HStack {
Spacer()
Rectangle()
.frame(width: 10)
.foregroundColor(color)
}
)
}
}