How can I detect press gesture within ButtonStyle in SwiftUI? [duplicate] - swift

I have a Button. I want to set custom background color for highlighted state. How can I do it in SwiftUI?
Button(action: signIn) {
Text("Sign In")
}
.padding(.all)
.background(Color.red)
.cornerRadius(16)
.foregroundColor(.white)
.font(Font.body.bold())

Updated for SwiftUI beta 5
SwiftUI does actually expose an API for this: ButtonStyle.
struct MyButtonStyle: ButtonStyle {
func makeBody(configuration: Self.Configuration) -> some View {
configuration.label
.padding()
.foregroundColor(.white)
.background(configuration.isPressed ? Color.red : Color.blue)
.cornerRadius(8.0)
}
}
// To use it
Button(action: {}) {
Text("Hello World")
}
.buttonStyle(MyButtonStyle())

As far as I can tell, theres no officially supported way to do this as of yet. Here is a little workaround that you can use. This produces the same behavior as in UIKit where tapping a button and dragging your finger off of it will keep the button highlighted.
struct HoverButton<Label: View>: View {
private let action: () -> ()
private let label: () -> Label
init(action: #escaping () -> (), label: #escaping () -> Label) {
self.action = action
self.label = label
}
#State private var pressed: Bool = false
var body: some View {
Button(action: action) {
label()
.foregroundColor(pressed ? .red : .blue)
.gesture(DragGesture(minimumDistance: 0.0)
.onChanged { _ in self.pressed = true }
.onEnded { _ in self.pressed = false })
}
}
}

I was looking for a similar functionality and I did it in the following way.
I created a special View struct returning a Button in the style I need, in this struct I added a State property selected. I have a variable named 'table' which is an Int since my buttons a round buttons with numbers on it
struct TableButton: View {
#State private var selected = false
var table: Int
var body: some View {
Button("\(table)") {
self.selected.toggle()
}
.frame(width: 50, height: 50)
.background(selected ? Color.blue : Color.red)
.foregroundColor(.white)
.clipShape(Circle())
}
}
Then I use in my content View the code
HStack(spacing: 10) {
ForEach((1...6), id: \.self) { table in
TableButton(table: table)
}
}
This creates an horizontal stack with 6 buttons which color blue when selected and red when deselected.
I am not a experienced developer but just tried all possible ways until I found that this is working for me, hopefully it is useful for others as well.

This is for the people who are not satisfied with the above solutions, as they raise other problems such as overlapping gestures(for example, it's quite hard to use this solution in scrollview now). Another crutch is to create a custom button style like this
struct CustomButtonStyle<Content>: ButtonStyle where Content: View {
var change: (Bool) -> Content
func makeBody(configuration: Self.Configuration) -> some View {
return change(configuration.isPressed)
}
}
So, we should just transfer the closure which will return the state of the button and create the button based on this parameter. It will be used like this:
struct CustomButton<Content>: View where Content: View {
var content: Content
init(#ViewBuilder content: () -> Content) {
self.content = content()
}
var body: some View {
Button(action: { }, label: {
EmptyView()
})
.buttonStyle(CustomButtonStyle(change: { bool in
Text("\(bool ? "yo" : "yo2")")
}))
}
}

Okey let me clear everything again. Here is the exact solution
Create the below button modifier.
struct StateableButton<Content>: ButtonStyle where Content: View {
var change: (Bool) -> Content
func makeBody(configuration: Configuration) -> some View {
return change(configuration.isPressed)
}
}
Then use it like below one
Button(action: {
print("Do something")
}, label: {
// Don't create your button view in here
EmptyView()
})
.buttonStyle(StateableButton(change: { state in
// Create your button view in here
return HStack {
Image(systemName: "clock.arrow.circlepath")
Text(item)
Spacer()
Image(systemName: "arrow.up.backward")
}
.padding(.horizontal)
.frame(height: 50)
.background(state ? Color.black : Color.clear)
}))

You need to define a custom style that can be used to provide the two backgrounds for normal and highlighted states:
Button(action: {
print("action")
}, label: {
Text("My Button").padding()
})
.buttonStyle(HighlightableButtonStyle(normal: { Color.red },
highlighted: { Color.green }))
// Custom button style
#available(iOS 15.0, macOS 12.0, tvOS 15.0, watchOS 8.0, *)
struct HighlightableButtonStyle<N, H>: ButtonStyle where N: View, H: View {
private let alignment: Alignment
private let normal: () -> N
private let highlighted: () -> H
init(alignment: Alignment = .center, #ViewBuilder normal: #escaping () -> N, #ViewBuilder highlighted: #escaping () -> H) {
self.alignment = alignment
self.normal = normal
self.highlighted = highlighted
}
func makeBody(configuration: Configuration) -> some View {
return ZStack {
if configuration.isPressed {
configuration.label.background(alignment: alignment, content: normal)
}
else {
configuration.label.background(alignment: alignment, content: highlighted)
}
}
}
}

Related

How can I make a smoothed custom Picker on SwiftUI?

I would like to replicate this picker in swiftUI. In particular, I have a button on the bottom left of the screen and when I click it I would like to show different icons (similar to the image below, but vertically). As soon as I click on one of the choices the button should shrink back to the initial form (circle) with the chosen icon.
When closed:
When open:
I am new to this language and to app in general, I tried with a Pop Up menu, but it is not the desired result, for now I have an horizontal segmented Picker.
You can't do this with the built-in Picker, because it doesn't offer a style like that and PickerStyle doesn't let you create custom styles (as of the 2022 releases).
You can create your own implementation out of other SwiftUI views instead. Here's what my brief attempt looks like:
Here's the code:
enum SoundOption {
case none
case alertsOnly
case all
}
struct SoundOptionPicker: View {
#Binding var option: SoundOption
#State private var isExpanded = false
var body: some View {
HStack(spacing: 0) {
button(for: .none, label: "volume.slash")
.foregroundColor(.red)
button(for: .alertsOnly, label: "speaker.badge.exclamationmark")
.foregroundColor(.white)
button(for: .all, label: "volume.2")
.foregroundColor(.white)
}
.buttonStyle(.plain)
.background {
Capsule(style: .continuous).foregroundColor(.black)
}
}
#ViewBuilder
private func button(for option: SoundOption, label: String) -> some View {
Button {
withAnimation(.easeOut) {
if isExpanded {
self.option = option
isExpanded = false
} else {
isExpanded = true
}
}
} label: {
Image(systemName: label)
.fontWeight(.bold)
.padding(10)
}
.frame(width: shouldShow(option) ? buttonSize : 0, height: buttonSize)
.opacity(shouldShow(option) ? 1 : 0)
.clipped()
}
private var buttonSize: CGFloat { 44 }
private func shouldShow(_ option: SoundOption) -> Bool {
return isExpanded || option == self.option
}
}
struct ContentView: View {
#State var option = SoundOption.none
var body: some View {
ZStack {
Color(hue: 0.6, saturation: 1, brightness: 0.2)
SoundOptionPicker(option: $option)
.shadow(color: .gray, radius: 3)
.frame(width: 200, alignment: .trailing)
}
}
}

Broken SwiftUI Transitions

I have a pretty simple view modifier for presenting toasts
struct ToastItemModifier<Item: Equatable, M: View>: ViewModifier {
typealias Style = ToastStyle
// MARK: - Environment
#Environment(\.colorScheme)
var colorScheme
// MARK: - Properties
private let style: Style
private let item: Item?
private let message: (Item) -> M
#Binding
private var isPresented: Bool
init(item: Item?, isPresented: Binding<Bool>, #ViewBuilder message: #escaping (Item) -> M, style: Style) {
self.style = style
self.item = item
self.message = message
_isPresented = isPresented
}
/// Indicates if content is presented.
private var contentIsPresented: Bool {
item != nil && isPresented
}
private var animation: Animation {
.easeInOut(duration: 1)
}
// MARK: - ViewModifier
func body(content: Content) -> some View {
ZStack {
content
ZStack {
if let item = item, contentIsPresented {
overlay(item: item)
.transition(.asymmetric(insertion: .scale(scale: 0.5), removal: .opacity).animation(animation))
}
}
}
.onReceive(Timer.publish(every: 3, on: .main, in: .default).autoconnect().first()) { _ in
isPresented = false
}
}
private func overlay(item: Item) -> some View {
HStack {
Image(uiImage: style.image)
.padding(.leading, 20)
message(item)
.font(Font.custom("DMSans-Bold", size: 18))
.foregroundColor(.white)
.padding(.trailing)
}
.frame(height: 66)
.background(style.background(for: colorScheme))
.cornerRadius(20)
.edgesIgnoringSafeArea(.all)
.shadow(color: Color.black.opacity(0.15), radius: 12, x: 0, y: 8)
}
}
Using an asymmetric transition, I can achieve a scale upon insertion and an opacity fade upon removal. However, changing those transitions to ones like .slide or .move, completely breaks the transition.
Are certain transitions broken in SwiftUI? I've had great success with opacity and scale but the other ones don't seem to work.
See my comment to question (above) and I'd move animation to container, like
ZStack {
if let item = item, contentIsPresented {
overlay(item: item)
.transition(.asymmetric(insertion: .scale(scale: 0.5), removal: .opacity))
}
}
.animation(animation, value: isPresented) // << here !!

UISwitch.appearance().onTintColor not working since iOS 14 [duplicate]

I've implemented a toggle after following Apple's tutorial on user input. Currently, it looks like this:
This is the code that produces this UI:
NavigationView {
List {
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
}
}
Now, I'd like the Toggle's on-color to be blue instead of green.
I tried:
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
.accentColor(.blue)
.foregroundColor(.blue)
.background(Color.blue)
None of these worked and I wasn't able to find any other modifiers, such as tintColor.
How do I change the color of a Toggle?
SwiftUI 3.0
Using tint
A new modifier was introduced that can also change the Toggle color:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.tint(.red)
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.tint(.orange)
SwiftUI 2.0
Using SwitchToggleStyle
You can now set a tint color for the on position only in SwiftUI 2.0:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.red))
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.orange))
SwiftUI 1.0
Using ToggleStyle
I created a new ToggleStyle to change the three colors of the Toggle (on color, off color, and the thumb).
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = Color(UIColor.green)
var offColor = Color(UIColor.systemGray5)
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
Button(action: { configuration.isOn.toggle() } )
{
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
}
}
.font(.title)
.padding(.horizontal)
}
}
Examples of Use
Toggle("", isOn: $toggleState)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .green,
offColor: .red,
thumbColor: Color(UIColor.systemTeal)))
Toggle("", isOn: $toggleState2)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .purple))
From the SwiftUI Book
Just use UIAppearance APIs:
UISwitch.appearance().onTintColor = UIColor.blue
It'll of course by default change the appearance of all the instances of UISwitch, as per UIAppearance documentation.
NOTE: Tested as of Xcode 11 beta 5.
SwiftUI 2.0 (Post WWDC-2020)
Using the new SwiftUI enhancements you can use the .toggleStyle modifier.
// Switch tinting
Toggle(isOn: $order.notifyWhenReady) {
Text("Send notification when ready")
}
.toggleStyle(SwitchToggleStyle(tint: .accentColor))
Note this only works for iOS14/iPadOS14/macOS11 and above.
I haven't found a way to directly change a Toggle color yet but an alternative way to have a blue switch or any other custom views, is to create a custom view of your own. To make a custom blue toggle in its simplest form:
struct BlueToggle : UIViewRepresentable {
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.onTintColor = UIColor.blue
}
}
struct ContentView : View {
var body: some View {
BlueToggle()
}
}
Result:
You can modify the global onTintColor for all UISwitch objects inside init().
#State var enable_dhcp = true
init()
{
UISwitch.appearance().onTintColor = .red
}
var body: some View
{
Toggle("DHCP", isOn: $enable_dhcp)
}
Building off #mohammad-reza-farahani 's solution, here is a fully uncompromising approach to getting the configurability of UISwitch with the implementation protocols if SwiftUI.
First wrap a UISwitch in a UIViewRepresentable and set the colors as you wish:
final class CustomToggleWrapper: UIViewRepresentable {
var isOn: Binding<Bool>
init(isOn: Binding<Bool>) {
self.isOn = isOn
}
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
// On color
uiView.onTintColor = UIColor.blue
// Off color
uiView.tintColor = UIColor.red
uiView.layer.cornerRadius = uiView.frame.height / 2
uiView.backgroundColor = UIColor.red
uiView.isOn = isOn.wrappedValue
// Update bound boolean
uiView.addTarget(self, action: #selector(switchIsChanged(_:)), for: .valueChanged)
}
#objc
func switchIsChanged(_ sender: UISwitch) {
isOn.wrappedValue = sender.isOn
}
}
Second, create a custom toggle style using the wrapped UISwitch:
struct CustomToggleStyle: ToggleStyle {
func makeBody(configuration: Self.Configuration) -> some View {
let toggle = CustomToggleWrapper(isOn: configuration.$isOn)
return HStack {
configuration.label
Spacer()
toggle
}
}
}
Implement a Toggle as you normally would, and apply your CustomToggleStyle:
struct TestView: View {
#State private var isOn: Bool = true
var body: some View {
Toggle(
isOn: $isOn
) {
Text("Test: \(String(isOn))")
}.toggleStyle(CustomToggleStyle()).padding()
}
}
Karol Kulesza and George Valkov have provided a very easy to implement solution. I just wanted to add that you can place the code below inside the app delegate's didFinishLaunching method as well.
UISwitch.appearance().onTintColor = .blue
You can also create more specific appearance configurations with
appearance(whenContainedInInstancesOf:)
See https://www.hackingwithswift.com/example-code/uikit/what-is-the-uiappearance-proxy
As the original question was just about changing the toggle on colour and not full Toggle visual customisation, I think something like this would do:
import SwiftUI
struct CustomToggle: UIViewRepresentable {
#Binding var isOn: Bool
func makeCoordinator() -> CustomToggle.Coordinator {
Coordinator(isOn: $isOn)
}
func makeUIView(context: Context) -> UISwitch {
let view = UISwitch()
view.onTintColor = UIColor.red
view.addTarget(context.coordinator, action: #selector(Coordinator.switchIsChanged(_:)), for: .valueChanged)
return view
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
class Coordinator: NSObject {
#Binding private var isOn: Bool
init(isOn: Binding<Bool>) {
_isOn = isOn
}
#objc func switchIsChanged(_ sender: UISwitch) {
_isOn.wrappedValue = sender.isOn
}
}
}
// MARK: - Previews
struct CustomToggle_Previews: PreviewProvider {
static var previews: some View {
ViewWrapper()
}
struct ViewWrapper: View {
#State(initialValue: false) var isOn: Bool
var body: some View {
CustomToggle(isOn: $isOn)
.previewLayout(.fixed(width: 100, height: 100))
}
}
}
The easist way is setting UISwitch.appearance().onTintColor = UIColor.red before using toggle and use SwiftUI Toggle like below.
UISwitch.appearance().onTintColor = UIColor.red
...
let toggle = Toggle(isOn: $vm.dataUsePermission, label: {
Text(I18N.permit_data_usage)
.font(SwiftUI.Font.system(size: 16, weight: .regular))
})
if #available(iOS 14.0, *) {
toggle.toggleStyle(
SwitchToggleStyle(tint: Color(UIColor.m.blue500))
)
} else {
toggle.toggleStyle(SwitchToggleStyle())
}
...
You can alse use same Toggle interface in SwiftUI but different name, and change tint color.
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
If only need Toggle without Label, then
TintableUISwitch(isOn: .constant(true))
Use below code.
import SwiftUI
public struct TintableSwitch<Label>: View where Label: View {
#Binding var isOn: Bool
var label: Label
public init(isOn: Binding<Bool>, #ViewBuilder label: () -> Label) {
self._isOn = isOn
self.label = label()
}
public var body: some View {
HStack {
label
Spacer()
TintableUISwitch(isOn: $isOn, onTintColor: .red) // 📌 CHANGE HERE
}
}
}
public struct TintableUISwitch: UIViewRepresentable {
#Binding var isOn: Bool
private var onTintColor: UIColor
public init(isOn: Binding<Bool>, onTintColor: UIColor = UIColor.m.blue500) {
self._isOn = isOn
self.onTintColor = onTintColor
}
public func makeUIView(context: Context) -> UISwitch {
let uiSwitch = UISwitch()
uiSwitch.addTarget(
context.coordinator,
action: #selector(Coordinator.valueChanged(_:)),
for: .valueChanged
)
uiSwitch.onTintColor = onTintColor
uiSwitch.isOn = isOn
return uiSwitch
}
public func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
public func makeCoordinator() -> Coordinator {
Coordinator(self)
}
public class Coordinator: NSObject {
var tintableSwitch: TintableUISwitch
init(_ tintableSwitch: TintableUISwitch) {
self.tintableSwitch = tintableSwitch
}
#objc
func valueChanged(_ sender: UISwitch) {
tintableSwitch.isOn = sender.isOn
}
}
}
struct TintableSwitch_Previews: PreviewProvider {
static var previews: some View {
VStack {
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
}
}
}
struct TintableUISwitch_Previews: PreviewProvider {
static var previews: some View {
TintableUISwitch(isOn: .constant(true))
}
}
You can change the toggle color in IOS 15.0 using a tint modifier.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.tint(.red)
and below IOS 15.0, You can use toggleStyle modifier to change the toggle color but it will be depreciated in the future.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.toggleStyle(SwitchToggleStyle(tint: .red))
I would change #Mark Moeykens answer a little bit to avoid having the button tap animation. A better solution would be:
#available(iOS 13.0, *)
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = UIColor.proacPrimaryBlue.suColor
var offColor = UIColor.systemGray5.suColor
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
.onTapGesture {
configuration.isOn.toggle()
}
}
.font(.title)
.padding(.horizontal)
}
}
This https://stackoverflow.com/a/56480720/5941807 (for now whit Xcode 11 beta 6) is a solution. To switch between to option a fast way is using the boolean instead of if/else:
showFavoritesOnly ? .red : .blue
for foreground:
Toggle(isOn: $showGreeting) {
Text("Show Favorites only").foregroundColor(showFavoritesOnly ? .blue : .gray)
}
for tint:
uiView.onTintColor = showFavoritesOnly ? UIColor.blue : UIColor.gray
In addition for custom colors: https://stackoverflow.com/a/57744208/5941807

How to detect a 'Click' gesture in SwiftUI tvOS

Using:
SwiftUI
Swift 5
tvOS
Xcode Version 11.2.1
I just want to detect a click gesture on the URLImage below
JFYI I am very new to Xcode, Swift and SwiftUI (less than 3 weeks).
URLImage(URL(string: channel.thumbnail)!,
delay: 0.25,
processors: [ Resize(size: CGSize(width:isFocused ? 300.0 : 225.0, height:isFocused ? 300.0 : 225.0), scale: UIScreen.main.scale) ],
content: {
$0.image
.resizable()
.aspectRatio(contentMode: .fill)
.clipped()
})
.frame(width: isFocused ? 300.0 : 250.0, height:isFocused ? 300.0 : 250.0)
.clipShape(Circle())
.overlay(
Circle().stroke( isFocused ? Color.white : Color.black, lineWidth: 8))
.shadow(radius:5)
.focusable(true, onFocusChange:{ (isFocused) in
withAnimation(.easeInOut(duration:0.3)){
self.isFocused = isFocused
}
if(isFocused){
self.manager.bannerChannel = self.channel
print(self.manager.bannerChannel)
self.manager.loadchannelEPG(id: self.channel.id)
}
})
.padding(20)
}
The only workaround I have found is wrapping it in a NavigationLink
or a Button but then focusable on the button doesn't run.
I found out that focusable runs on a Button/NavigationLink if I add corner radius to it but then the default click action doesn't run
Also, TapGesture is not available in tvOS
Since Gestures are available maybe there is a way using gestures that I cannot figure out.
OR
If there is a way to tap into focusable on a button (although this is the less favoured alternative since this changes the look I want to achieve).
Edit: onTapGesture() is now available starting in tvOS 16
tvOS 16
struct ContentView: View {
#FocusState var focused1
#FocusState var focused2
var body: some View {
HStack {
Text("Clickable 1")
.foregroundColor(self.focused1 ? Color.red : Color.black)
.focusable(true)
.focused($focused1)
.onTapGesture {
print("clicked 1")
}
Text("Clickable 2")
.foregroundColor(self.focused2 ? Color.red : Color.black)
.focusable(true)
.focused($focused2)
.onTapGesture {
print("clicked 2")
}
}
}
}
Previous Answer for tvOS 15 and earlier
It is possible, but not for the faint of heart. I came up with a somewhat generic solution that may help you. I hope in the next swiftUI update Apple adds a better way to attach click events for tvOS and this code can be relegated to the trash bin where it belongs.
The high level explanation of how to do this is to make a UIView that captures the focus and click events, then make a UIViewRepresentable so swiftUI can use the view. Then the view is added to the layout in a ZStack so it's hidden, but you can receive focus and respond to click events as if the user was really interacting with your real swiftUI component.
First I need to make a UIView that captures the events.
class ClickableHackView: UIView {
weak var delegate: ClickableHackDelegate?
override init(frame: CGRect) {
super.init(frame: frame)
}
override func pressesEnded(_ presses: Set<UIPress>, with event: UIPressesEvent?) {
if event?.allPresses.map({ $0.type }).contains(.select) ?? false {
delegate?.clicked()
} else {
superview?.pressesEnded(presses, with: event)
}
}
override func didUpdateFocus(in context: UIFocusUpdateContext, with coordinator: UIFocusAnimationCoordinator) {
delegate?.focus(focused: isFocused)
}
required init?(coder: NSCoder) {
fatalError("init(coder:) has not been implemented")
}
override var canBecomeFocused: Bool {
return true
}
}
The clickable delegate:
protocol ClickableHackDelegate: class {
func focus(focused: Bool)
func clicked()
}
Then make a swiftui extension for my view
struct ClickableHack: UIViewRepresentable {
#Binding var focused: Bool
let onClick: () -> Void
func makeUIView(context: UIViewRepresentableContext<ClickableHack>) -> UIView {
let clickableView = ClickableHackView()
clickableView.delegate = context.coordinator
return clickableView
}
func updateUIView(_ uiView: UIView, context: UIViewRepresentableContext<ClickableHack>) {
}
func makeCoordinator() -> Coordinator {
return Coordinator(self)
}
class Coordinator: NSObject, ClickableHackDelegate {
private let control: ClickableHack
init(_ control: ClickableHack) {
self.control = control
super.init()
}
func focus(focused: Bool) {
control.focused = focused
}
func clicked() {
control.onClick()
}
}
}
Then I make a friendlier swiftui wrapper so I can pass in any kind of component I want to be focusable and clickable
struct Clickable<Content>: View where Content : View {
let focused: Binding<Bool>
let content: () -> Content
let onClick: () -> Void
#inlinable public init(focused: Binding<Bool>, onClick: #escaping () -> Void, #ViewBuilder content: #escaping () -> Content) {
self.content = content
self.focused = focused
self.onClick = onClick
}
var body: some View {
ZStack {
ClickableHack(focused: focused, onClick: onClick)
content()
}
}
}
Example usage:
struct ClickableTest: View {
#State var focused1: Bool = false
#State var focused2: Bool = false
var body: some View {
HStack {
Clickable(focused: self.$focused1, onClick: {
print("clicked 1")
}) {
Text("Clickable 1")
.foregroundColor(self.focused1 ? Color.red : Color.black)
}
Clickable(focused: self.$focused2, onClick: {
print("clicked 2")
}) {
Text("Clickable 2")
.foregroundColor(self.focused2 ? Color.red : Color.black)
}
}
}
}
If you'd like to avoid UIKit, you can achieve the desired solution with Long Press Gesture by setting a really small duration of pressing.
1. Only Press:
If you only need to handle the pressing action and don't need long pressing at all.
ContentView()
.onLongPressGesture(minimumDuration: 0.01, pressing: { _ in }) {
print("pressed")
}
2. Press and Long press:
If you need to handle both pressing and Long pressing.
var longPress: some Gesture {
LongPressGesture(minimumDuration: 0.5)
.onEnded { _ in
print("longpress")
}
}
ContentView()
.highPriorityGesture(longPress)
.onLongPressGesture(minimumDuration: 0.01, pressing: { _ in }) {
print("press")
}

Set Toggle color in SwiftUI

I've implemented a toggle after following Apple's tutorial on user input. Currently, it looks like this:
This is the code that produces this UI:
NavigationView {
List {
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
}
}
Now, I'd like the Toggle's on-color to be blue instead of green.
I tried:
Toggle(isOn: $showFavoritesOnly) {
Text("Show Favorites only")
}
.accentColor(.blue)
.foregroundColor(.blue)
.background(Color.blue)
None of these worked and I wasn't able to find any other modifiers, such as tintColor.
How do I change the color of a Toggle?
SwiftUI 3.0
Using tint
A new modifier was introduced that can also change the Toggle color:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.tint(.red)
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.tint(.orange)
SwiftUI 2.0
Using SwitchToggleStyle
You can now set a tint color for the on position only in SwiftUI 2.0:
Toggle(isOn: $isToggleOn) {
Text("Red")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.red))
Toggle(isOn: $isToggleOn) {
Text("Orange")
Image(systemName: "paintpalette")
}
.toggleStyle(SwitchToggleStyle(tint: Color.orange))
SwiftUI 1.0
Using ToggleStyle
I created a new ToggleStyle to change the three colors of the Toggle (on color, off color, and the thumb).
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = Color(UIColor.green)
var offColor = Color(UIColor.systemGray5)
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
Button(action: { configuration.isOn.toggle() } )
{
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
}
}
.font(.title)
.padding(.horizontal)
}
}
Examples of Use
Toggle("", isOn: $toggleState)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .green,
offColor: .red,
thumbColor: Color(UIColor.systemTeal)))
Toggle("", isOn: $toggleState2)
.toggleStyle(
ColoredToggleStyle(label: "My Colored Toggle",
onColor: .purple))
From the SwiftUI Book
Just use UIAppearance APIs:
UISwitch.appearance().onTintColor = UIColor.blue
It'll of course by default change the appearance of all the instances of UISwitch, as per UIAppearance documentation.
NOTE: Tested as of Xcode 11 beta 5.
SwiftUI 2.0 (Post WWDC-2020)
Using the new SwiftUI enhancements you can use the .toggleStyle modifier.
// Switch tinting
Toggle(isOn: $order.notifyWhenReady) {
Text("Send notification when ready")
}
.toggleStyle(SwitchToggleStyle(tint: .accentColor))
Note this only works for iOS14/iPadOS14/macOS11 and above.
I haven't found a way to directly change a Toggle color yet but an alternative way to have a blue switch or any other custom views, is to create a custom view of your own. To make a custom blue toggle in its simplest form:
struct BlueToggle : UIViewRepresentable {
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.onTintColor = UIColor.blue
}
}
struct ContentView : View {
var body: some View {
BlueToggle()
}
}
Result:
You can modify the global onTintColor for all UISwitch objects inside init().
#State var enable_dhcp = true
init()
{
UISwitch.appearance().onTintColor = .red
}
var body: some View
{
Toggle("DHCP", isOn: $enable_dhcp)
}
Building off #mohammad-reza-farahani 's solution, here is a fully uncompromising approach to getting the configurability of UISwitch with the implementation protocols if SwiftUI.
First wrap a UISwitch in a UIViewRepresentable and set the colors as you wish:
final class CustomToggleWrapper: UIViewRepresentable {
var isOn: Binding<Bool>
init(isOn: Binding<Bool>) {
self.isOn = isOn
}
func makeUIView(context: Context) -> UISwitch {
UISwitch()
}
func updateUIView(_ uiView: UISwitch, context: Context) {
// On color
uiView.onTintColor = UIColor.blue
// Off color
uiView.tintColor = UIColor.red
uiView.layer.cornerRadius = uiView.frame.height / 2
uiView.backgroundColor = UIColor.red
uiView.isOn = isOn.wrappedValue
// Update bound boolean
uiView.addTarget(self, action: #selector(switchIsChanged(_:)), for: .valueChanged)
}
#objc
func switchIsChanged(_ sender: UISwitch) {
isOn.wrappedValue = sender.isOn
}
}
Second, create a custom toggle style using the wrapped UISwitch:
struct CustomToggleStyle: ToggleStyle {
func makeBody(configuration: Self.Configuration) -> some View {
let toggle = CustomToggleWrapper(isOn: configuration.$isOn)
return HStack {
configuration.label
Spacer()
toggle
}
}
}
Implement a Toggle as you normally would, and apply your CustomToggleStyle:
struct TestView: View {
#State private var isOn: Bool = true
var body: some View {
Toggle(
isOn: $isOn
) {
Text("Test: \(String(isOn))")
}.toggleStyle(CustomToggleStyle()).padding()
}
}
Karol Kulesza and George Valkov have provided a very easy to implement solution. I just wanted to add that you can place the code below inside the app delegate's didFinishLaunching method as well.
UISwitch.appearance().onTintColor = .blue
You can also create more specific appearance configurations with
appearance(whenContainedInInstancesOf:)
See https://www.hackingwithswift.com/example-code/uikit/what-is-the-uiappearance-proxy
As the original question was just about changing the toggle on colour and not full Toggle visual customisation, I think something like this would do:
import SwiftUI
struct CustomToggle: UIViewRepresentable {
#Binding var isOn: Bool
func makeCoordinator() -> CustomToggle.Coordinator {
Coordinator(isOn: $isOn)
}
func makeUIView(context: Context) -> UISwitch {
let view = UISwitch()
view.onTintColor = UIColor.red
view.addTarget(context.coordinator, action: #selector(Coordinator.switchIsChanged(_:)), for: .valueChanged)
return view
}
func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
class Coordinator: NSObject {
#Binding private var isOn: Bool
init(isOn: Binding<Bool>) {
_isOn = isOn
}
#objc func switchIsChanged(_ sender: UISwitch) {
_isOn.wrappedValue = sender.isOn
}
}
}
// MARK: - Previews
struct CustomToggle_Previews: PreviewProvider {
static var previews: some View {
ViewWrapper()
}
struct ViewWrapper: View {
#State(initialValue: false) var isOn: Bool
var body: some View {
CustomToggle(isOn: $isOn)
.previewLayout(.fixed(width: 100, height: 100))
}
}
}
The easist way is setting UISwitch.appearance().onTintColor = UIColor.red before using toggle and use SwiftUI Toggle like below.
UISwitch.appearance().onTintColor = UIColor.red
...
let toggle = Toggle(isOn: $vm.dataUsePermission, label: {
Text(I18N.permit_data_usage)
.font(SwiftUI.Font.system(size: 16, weight: .regular))
})
if #available(iOS 14.0, *) {
toggle.toggleStyle(
SwitchToggleStyle(tint: Color(UIColor.m.blue500))
)
} else {
toggle.toggleStyle(SwitchToggleStyle())
}
...
You can alse use same Toggle interface in SwiftUI but different name, and change tint color.
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
If only need Toggle without Label, then
TintableUISwitch(isOn: .constant(true))
Use below code.
import SwiftUI
public struct TintableSwitch<Label>: View where Label: View {
#Binding var isOn: Bool
var label: Label
public init(isOn: Binding<Bool>, #ViewBuilder label: () -> Label) {
self._isOn = isOn
self.label = label()
}
public var body: some View {
HStack {
label
Spacer()
TintableUISwitch(isOn: $isOn, onTintColor: .red) // 📌 CHANGE HERE
}
}
}
public struct TintableUISwitch: UIViewRepresentable {
#Binding var isOn: Bool
private var onTintColor: UIColor
public init(isOn: Binding<Bool>, onTintColor: UIColor = UIColor.m.blue500) {
self._isOn = isOn
self.onTintColor = onTintColor
}
public func makeUIView(context: Context) -> UISwitch {
let uiSwitch = UISwitch()
uiSwitch.addTarget(
context.coordinator,
action: #selector(Coordinator.valueChanged(_:)),
for: .valueChanged
)
uiSwitch.onTintColor = onTintColor
uiSwitch.isOn = isOn
return uiSwitch
}
public func updateUIView(_ uiView: UISwitch, context: Context) {
uiView.isOn = isOn
}
public func makeCoordinator() -> Coordinator {
Coordinator(self)
}
public class Coordinator: NSObject {
var tintableSwitch: TintableUISwitch
init(_ tintableSwitch: TintableUISwitch) {
self.tintableSwitch = tintableSwitch
}
#objc
func valueChanged(_ sender: UISwitch) {
tintableSwitch.isOn = sender.isOn
}
}
}
struct TintableSwitch_Previews: PreviewProvider {
static var previews: some View {
VStack {
TintableSwitch(isOn: .constant(true), label: {
Text("Switch")
})
Toggle(isOn: .constant(true), label: {
Text("Switch")
})
}
}
}
struct TintableUISwitch_Previews: PreviewProvider {
static var previews: some View {
TintableUISwitch(isOn: .constant(true))
}
}
You can change the toggle color in IOS 15.0 using a tint modifier.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.tint(.red)
and below IOS 15.0, You can use toggleStyle modifier to change the toggle color but it will be depreciated in the future.
Toggle(isOn: $isToggleOn) {
Text("Toggle")
}.toggleStyle(SwitchToggleStyle(tint: .red))
I would change #Mark Moeykens answer a little bit to avoid having the button tap animation. A better solution would be:
#available(iOS 13.0, *)
struct ColoredToggleStyle: ToggleStyle {
var label = ""
var onColor = UIColor.proacPrimaryBlue.suColor
var offColor = UIColor.systemGray5.suColor
var thumbColor = Color.white
func makeBody(configuration: Self.Configuration) -> some View {
HStack {
Text(label)
Spacer()
RoundedRectangle(cornerRadius: 16, style: .circular)
.fill(configuration.isOn ? onColor : offColor)
.frame(width: 50, height: 29)
.overlay(
Circle()
.fill(thumbColor)
.shadow(radius: 1, x: 0, y: 1)
.padding(1.5)
.offset(x: configuration.isOn ? 10 : -10))
.animation(Animation.easeInOut(duration: 0.1))
.onTapGesture {
configuration.isOn.toggle()
}
}
.font(.title)
.padding(.horizontal)
}
}
This https://stackoverflow.com/a/56480720/5941807 (for now whit Xcode 11 beta 6) is a solution. To switch between to option a fast way is using the boolean instead of if/else:
showFavoritesOnly ? .red : .blue
for foreground:
Toggle(isOn: $showGreeting) {
Text("Show Favorites only").foregroundColor(showFavoritesOnly ? .blue : .gray)
}
for tint:
uiView.onTintColor = showFavoritesOnly ? UIColor.blue : UIColor.gray
In addition for custom colors: https://stackoverflow.com/a/57744208/5941807