I want to access data using Odata, but there is $expand. I know that when using $ in flutter, it will call new value
access data using odata in flutter
https://192.168.x.x/odata/UserLokasiOdata?$expand=HSEOL_TR_Relate_USERLOK_LOKASI&$filter=USERID eq 'jubang'
But in flutter can not show the respond anything
In a raw string, "$" and "" mean nothing special, they are just characters like any other. In an interpreted string, "$" starts an interpolation and "" starts an escape.
Since you want the interpolation for "$dollars", you can't use "$" literally, so you need to escape it:
int dollars = 100;
print("I have \$$dollars."); //I have $100.
If you don't want to use an escape, you can combine the string from raw and interpreted parts:
int dollars = 100;
print(r"I have $" "$dollars."); //I have $100.
Two adjacent string literals are combined into one string, even if they are different types of string.
or
When you are using literals instead of variables you can also use raw strings:
print(r"I have $100."); //I have $100.
Related
I'm new to writing apex triggers. I've looked through a lot of the apex developer documentation, and I can't seem to find the combination of functions that I should use to automatically trim characters from a text field.
My org has two text fields on the Case object, which automatically store the email addresses that are included in an email-to-case. The text fields have a 255 character limit each. We are seeing errors pop up because the number of email addresses that these fields contain often exceeds 255 characters.
I need to write a trigger that can trim these text fields to the last ".com" before it hits the 255 character limit.
Perhaps I'm going about this all wrong. Any advice?
You can use replace() function in Apex.
String s1 = 'abcdbca';
String target = 'bc';
String replacement = 'xy';
String s2 = s1.replace(target, replacement);
If you need to use regular expression to find the pattern, then you can use replaceAll()
String s1 = 'a b c 5 xyz';
String regExp = '[a-zA-Z]';
String replacement = '1';
String s2 = s1.replaceAll(regExp, replacement);
For more information please refer Apex Reference Guide
The following code I think that covers what you are searching:
String initialUrl = 'https://stackoverflow.com/questions/69136581/what-function-do-i-use-in-a-salesforce-apex-trigger-to-trim-a-text-field';
Integer comPosition = initialUrl.indexOf('.com');
System.debug(initialUrl.left(comPosition + 4));
//https://stackoverflow.com
The main problems that I see are that other extensions are not covered (like ".net" urls) and that urls that have a ".com" appearing previous to the last one (something like "https://www.comunications.com"). But I think that this covers most of the use cases.
Why not increasing the length of that specific field? Trimming the text might cause data loss or unusable. Just go to object manager find that object and that specific field. Edit field and increase the length.
I have a list of Text views that include a year saved as an int. I'm displaying it in an interpolated string:
Text("\($0.property) \($0.year) \($0.etc)")
The problem, it adds a comma to the int, for example it displays 1,944 instead of the year 1944. I'm sure this is a simple fix but i've been unable to figure out how to remove the comma. Thanks!
There is explicit Text(verbatim:) constructor to render string without localization formatting, so a solution for your case is
Text(verbatim: "\($0.property) \($0.year) \($0.etc)")
Use Text(String(yourIntValue)) if you use interpolation you need to cast it as a string directly. If you allow the int to handle it, it shows with a ,.
So to recap.
let yourIntValue = 1234
Text(String(yourIntValue)) // will return `1234`.
Text("\(yourIntValue)") // will return `1,234`.
I use the built-in format parameter. It's useful for formatting well beyond just this one specific usage (no commas).
Text("Disk Cache \(URLCache.shared.currentDiskUsage,
format: .number.grouping(.never))"))
If I have a number that is over 1,000, so that it has a comma in it, how can I either strip out the commas, or convert this number into a Double, so that I can run mathematical operations on it?
Right now, I have the following code:
let oldBFTally: Double = Double(plBFTally.text!)!
let newBFTally: Double = round(1000 * (rawValue + oldBFTally) / 1000)
This code works great, as long as the number is under 1000. But, being that I am formatting the number as text, so that it has commas (ie: 1,234.56), whenever I try to run that first line, it errors out, saying: "fatal error: unexpectedly found nil while unwrapping an Optional value".
Any ideas what I can do to navigate around this issue?
But, being that I am formatting the number as text, so that it has commas (ie: 1,234.56)
You're trying to tackle the problem in the wrong way. If you're generating this string in the first place, then if you want to perform mathematical operations on the number, you shouldn't be displaying it as a string in the UI, then trying to go backwards from the UI back to a number. That's misusing your presentation layer as your data model.
Instead of trying to go back and forth between the UI, use the original value you generated the string from.
#Jim is correct; your text field should simply contain a textual representation of your internal variable, so you shouldn't need to convert back to a double, but for reference, you can use a NumberFormatter
import Foundation
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
if let number = formattter.number(from:"10,000") {
print(number.doubleValue)
}
When I was reading spark source code here, I saw code like $(a_variable).
What does it mean?
I copy the code here:
final val blockSize: IntParam = new IntParam(this, "blockSize",
"Block size for stacking input data in matrices. Data is stacked within partitions." +
" If block size is more than remaining data in a partition then " +
"it is adjusted to the size of this data. Recommended size is between 10 and 1000",
ParamValidators.gt(0))
/** #group getParam */
final def getBlockSize: Int = $(blockSize)
That isn't special Scala syntax, it's a method name. In Scala $ is a legal identifier. The method is inherited from the org.apache.spark.ml.param.Param trait.
See the source.
I believe that the dollar sign is usually used for string interpolation. What that means is that if I want to use a val(ue)/var(iable) inside a string (denoted with an s before the first double quotation), I can access such vals/vars using the $ sign. Otherwise, we won't be able to use vals/vars inside a string since it would not know how to escape the string characters.
Example:
val favoriteFruit = "strawberry"
val strawberryCount = 12
println(s"My favorite fruit is ${favoriteFruit}. I've had ${strawberryCount} pieces today!") // string interpolation
In your case, however it seems that $ is a shortcut to getOrDefault the var/val (as sourced by #Michael Zajac and #kingledion...gets the value/variable. If it does not exist, gets the default value/variable). Using getOrDefault may be a more robust solution in cases in which you expect the parameter to not always have a corresponding value, for which you can set a default value.
I've research this topic extensibly and I'm asking as a last resort before assuming that there is no wildcard for what I want to do.
I need to pull up all the text input elements from the document and add it to an array. However, I only want to add the input elements that have an id.
I know you can use the \S* wildcard when using an id selector such as $(#\S*), however I can't use this because I need to filter the results by text type only as well, so I searching by attribute.
I currently have this:
values_inputs = $("input[type='text'][id^='a']");
This works how I want it to but it brings back only the text input elements that start with an 'a'. I want to get all the text input elements with an 'id' of anything.
I can't use:
values_inputs = $("input[type='text'][id^='']"); //or
values_inputs = $("input[type='text'][id^='*']"); //or
values_inputs = $("input[type='text'][id^='\\S*']"); //or
values_inputs = $("input[type='text'][id^=\\S*]");
//I either get no values returned or a syntax error for these
I guess I'm just looking for the equivalent of * in SQL for JQuery attribute selectors.
Is there no such thing, or am I just approaching this problem the wrong way?
Actually, it's quite simple:
var values_inputs = $("input[type=text][id]");
Your logic is a bit ambiguous. I believe you don't want elements with any id, but rather elements where id does not equal an empty string. Use this.
values_inputs = $("input[type='text']")
.filter(function() {
return this.id != '';
});
Try changing your selector to:
$("input[type='text'][id]")
I figured out another way to use wild cards very simply. This helped me a lot so I thought I'd share it.
You can use attribute wildcards in the selectors in the following way to emulate the use of '*'. Let's say you have dynamically generated form in which elements are created with the same naming convention except for dynamically changing digits representing the index:
id='part_x_name' //where x represents a digit
If you want to retrieve only the text input ones that have certain parts of the id name and element type you can do the following:
var inputs = $("input[type='text'][id^='part_'][id$='_name']");
and voila, it will retrieve all the text input elements that have "part_" in the beginning of the id string and "_name" at the end of the string. If you have something like
id='part_x_name_y' // again x and y representing digits
you could do:
var inputs = $("input[type='text'][id^='part_'][id*='_name_']"); //the *= operator means that it will retrieve this part of the string from anywhere where it appears in the string.
Depending on what the names of other id's are it may start to get a little trickier if other element id's have similar naming conventions in your document. You may have to get a little more creative in specifying your wildcards. In most common cases this will be enough to get what you need.