I have a set of data stored in neo4j in milliseconds.
I'm trying to get the data then change it to date format and compare it to today's date in where clause to get Media posts for today only.
I have tried with these
MATCH (media:Media)
RETURN date(datetime({millisecond:media.dateCreated}))
and it returns
Neo.ClientError.Statement.ArgumentError: year must be specified
next, I've tried
MATCH (media:Media)
RETURN apoc.date.field(media.dateCreated)
and it returns
Neo.ClientError.Statement.SyntaxError: Unknown function
'apoc.date.field' (line 2, column 28 (offset: 45)) "MATCH
(media:Media) RETURN apoc.date.field(media.dateCreated)" ^
I have tried multiple ways that more or less return the same kind of error
I expect the data to be shown in date format instead of milliseconds.
You can use epochMillis to create the date from milliseconds.
MATCH (media:Media)
RETURN date(datetime({epochMillis:media.dateCreated}))
This returns the date in the format as shown in the following screenshot:
This query:
RETURN datetime({epochMillis: 1475292465000});
returns the datetime that corresponds to the epoch timestamp 1475292465000:
╒════════════════════════════════════════╕
│"datetime({epochMillis: 1475292465000})"│
╞════════════════════════════════════════╡
│"2016-10-01T03:27:45Z" │
└────────────────────────────────────────┘
If you actually want a date, you can use this query:
RETURN date(datetime({epochMillis: 1475292465000}));
Related
I have a syntax, but it doesn't work.
Here is my query:
SELECT *
FROM aqua.reading
WHERE
CAST(reading.pres_date AS VARCHAR)
BETWEEN LIKE '2022-10-18%' AND LIKE '2022-10-18%'
it says:
ERROR: type "like" does not exist
LINE 1: ... WHERE CAST(reading.pres_date AS VARCHAR) BETWEEN LIKE '2022...
^
SQL state: 42704
Character: 77
I am trying to get all the data with timestamp and timezone and implement a date range
Don't compare dates (or timestamps) as strings. Compare them to proper date (or timestamp) values. Given the fact that you use the same "date" but with a wildcard at the end, I am assuming(!) that pres_date is in fact a timestamp column and you want to find all rows with a given date regardless of the time value of the timestamp.
The best approach is to use a range query with >= ("greater than or equal) on the lower value and < (strictly lower than) on the next day:
SELECT *
FROM aqua.reading
WHERE reading.pres_date >= DATE '2022-10-18'
AND reading.pres_date < DATE '2022-10-19'
Alternatively you can cast the timestamp to a date and use the = operator if you really want to pick just one day:
SELECT *
FROM aqua.reading
WHERE cast(reading.pres_date as DATE) = DATE '2022-10-18'
However that will not make use of a potential index on pres_date so is likely to be slower than the range query from the first solution
I have a data stored in Firestore, the data add to Firestore every second, so in 24 hours I have 1440 documents (24 * 60), I want to fetch only round hour from the Firestore for show it on a Graph, how can I get only round hour from Firestore?
First of all, you will have to store the firestore documents with a timestamp property and then query the documents with the timestamp value which gives a rounded hour using DateTime and DateFormat APIs of flutter.
Once you've got a timestamp back from Firestore, something like :
Timestamp(seconds=1560523991, nanoseconds=286000000)
You can get only rounded hour from the timestamp value using 2 ways :
You need to parse it into an object of type DateTime:
DateTime myDateTime = (snapshot.data.documents[index].data['timestamp']).toDate(); // prints 2020-05-09 15:27:04.074
This will return your Firestore timestamp in the dart's DateTime format. In order to convert your DateTime object you can use DateFormat class from the intl package. You can use your obtained DateTime object to get the format of your choice like this:
Possible Solution 1 :
DateFormat.Hm().format(myDateTime); //prints 15.27
So the query should look for documents with:
DateFormat.m().format(myDateTime) to be “00” as
DateFormat.m() returns minutes and if minutes == 00 then the timestamp is rounded to the nearest hour.
Possible Solution 2 :
Convert timestamp into timestring using :
Let TimeString = snapshot.data.documents[index].data['timestamp']).toDate().toString() // prints ‘2019-12-28 18:48:48.364’
Let time = TimeString.split(“ “)[1] // prints 18:48:48.364
To check if the minutes is “00” :
if time.substring(3,5) == “00”, then it's a rounded hour. //here it is 48
You will have to put these timestamp conversion logics and then query as I mentioned for the rounded hour timestamp. There are no readymade available functions/methods to get the firestore documents with rounded hours.
Firestore supports "IN" Queries.
Store as Timestamp, and try with following
const roundhour1 = new Date('2021-10-01T01:00:00.000z');
const roundhour2 = new Date('2021-10-01T02:00:00.000z');
And then write the query like below:
database.collection("collectionName").where("fieldName", "in", ["roundhour1", "roundhour2"]);
You can have up to 10 values (roundhourX) to check "IN" of, so need to fire 3 queries to get all 24 hours data.
When trying to add days to a date in another column the value returns as a number, not a date.
I have tried to set the column format as the date for both columns B and C. I also tried using the DATEVALUE() function, but I don't think I used it properly.
=ARRAYFORMULA(IF(ROW(B:B)=1,"Second Notification",IF(LEN(B:B), B:B+1,)))
I want the value in column C to return as a date.
use this with TEXT formula:
={"Second Notification";
ARRAYFORMULA(IF(LEN(B2:B), TEXT(B2:B+1, "MM/dd/yyyy hh:mm:ss"), ))}
I am trying to convert a long utc value into "yyyy-MM-dd HH:mm:ss" formatted pattern. I am expecting my data to be converted on 24 hours range scale and in GMT. My code passes all the test cases, I push the data into database using the jar that is newly built with this code -
dbRecord("order_dt_utc") = if (orderTs.isDefined) Some(new DateTime(orderTs.get, DateTimeZone.UTC).toString("yyyy-MM-dd HH:mm:ss")) else None
and now, when I query my database, I find that the data is still converting on 12 hours range. The query -
SELECT order_id, order_dt, order_dt_utc, order_ts_utc, from_unixtime(order_ts_utc/1000) FROM order_items where order_dt >= '2018-08-01' AND order_dt <= '2018-08-02' ORDER BY order_dt_utc LIMIT 1000;
And you can see the the values are not matching in the columns from_unixtime(order_ts_utc/1000) and order_dt_utc -
I am not able to figure the reason for this behaviour.
To convert Time Zone use the function first:
CONVERT_TZ (dateobj, oldtz, newtz)
After that use the date_format function:
date_format(from_unixtime(order_ts_utc), '%Y-%m-%d %H:%i:%s');
to format your time to 00-23 format.
I'm trying to convert value for DIM_DT_ID to MMddYY. I'm successful in doinf that. However, query fails because ultimately I'm comparing a character value to date here. Is there a way by which I can get value for DIM_DT_ID in MMddyy format and its data type still remains DATE ?
Here DIM_DT_ID
SELECT DIM_DT_ID
DIM_DT_ID >= FORMATDATE('MMddyy',ADDDAY(TO_date('yyyy-MM-dd','2016-12-21'), -25)); from abc;
Regards,
Ajay
In Denodo, to convert a string to a date field, use "to_date()" (which returns a date).
Then, don't convert back to a string, leave that field as a date (so don't use "Formatdate()", which returns a string).
So:
SELECT *
FROM MyTable
WHERE now() >= to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate)
In my example, "now()" is a date, and so is the output of the to_date function... so you can do a comparison.
If you try to convert the date back to a string using formatdate, it won't work:
#This doesn't work:
SELECT *
FROM MyTable
WHERE now() >= formatdate('MMddyy',to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate))
It doesn't work because we are comparing a date ("now()") to a string.