I am trying to import JSON file where a value contains data like this
"\"Koslov Git †girish\" Ges"
The return should be like "Koslov Git †girish Ges"
The extra \" are the troubles
I tried REGEXP_REPLACE(values, '\\''+', '''', 'g') with no luck. How can I get rid of this. Note the first and last double quotes should not be replaced
with data(json_object) as (
values ('"\"Koslov Git †girish\" Ges"'::jsonb)
)
select regexp_replace(json_object::text, '\\"', '', 'g')
from data;
Db<>fiddle.
Related
In pgAdmin 4, the column value is seen as a square bracket [...] instead of an empty value.
The column data type is character(4) and name is carr_desig_icao_cd. Database is postgreSql.
How to avoid the square brackets? I tried pgAdmin 4 preferences but no luck.
Thanks for your help.
Output from psql is as below:
Could it be something to do with converting to_char?
Here are results of my testing.
This query produced no brackets and dots:
select at1.score
This query produced brackets and dots
select to_char(at1.score, '999')
I noticed when this was downloaded and opened in Excel, there were no brackets but three spaces at the start of the column.
This query removed the brackets and dots in PgAdmin and removed the spaces after downloading to Excel:
select replace(to_char(at1.score, '999'), ' ', '')
Just noting also that this was a sub query as part of a bigger query that looked a bit like this:
select
cm.course_id
, us.user_id
, gm.title
, (select replace(to_char(at1.score * 20, '999'), ' ', '') || '% ' || to_char(at1.attempt_date, 'yyyy-mm-dd') from attempt at1 where at1.pk1 = gg.highest_attempt_pk1)
from
etc (joins of course_main cm, users us, gradebook_main gm, gradebook_grade gg, attempt at)
This screenshot shows before and after
a have a column as below
mystring
AC1853551,AC1854125,AC1855220,AC188115,AC1884120,AC1884390,AC1885102
I need to transformm it to get this output
mystring
('AC1853551','AC1854125','AC1855220','AC188115','AC1884120','AC1884390','AC1885102')
Here is my query that i tried
select CONCAT('( , CONCAT (mystring, ')')) from mytablename
I'm getting an error when it comes to insert a single quote '
Then i thought about replacing the comma with a ','
How to get desired output
i'm using postgres 10
A literal quote is coded as a doubled quote:
select '(''' || replace(mycolumn, ',', ''',''') || ''')'
from mytable
See live demo.
I'm writting a file from a DB-Procedure.
I need to export a string value and I have to add double quotes in front and back of the string.
exp: "TEST".
I use the following code but the result is always like """TEST""" and I don't know why.
EXECUTE 'COPY (
SELECT concat(''"'', x.text1, ''"'')
FROM my_table x
) to ''' || dump_path || ''' WITH (FORMAT csv, DELIMITER '','', ENCODING ''WIN1252'')';
I need to build a SQL statement to be submitted on a linked server. The statement makes use of #parameters and case statements which contain quotation marks.
I found this Microsoft article 'How to pass a variable', which seemed ideal, however I am not able to get everything going. It seems that the linked server is not enabled for the final and neatest suggestion of calling Sp_executesql, so I have been trying the first two examples.
To start with, here is a cut down example of my SQL statement on its own:
SELECT *,
CASE WHEN FLDA = 'ABC' THEN 'DEF' ELSE 'ABC' END AS COL1
FROM MYTABLE
WHERE FLDB = #PARM
1, I can get the query to work when excluding the CASE statement:
DECLARE #TSQL NVARCHAR(4000), #PARM NVARCHAR(10)
SET #PARM = 'ABC'
SET #TSQL = 'SELECT * FROM OPENQUERY(MYLINKEDSERVER, ''
SELECT *
FROM MYTABLE
WHERE FLDA = '''''+#PARM+''''''')'
EXEC (#TSQL)
However I don't understand why I require 5 quotes before #PARM and then 7(!) after it? When coding SQL statements in a string in previous languages just 2 quotations together acted as a single. So why 5 and 7?
2, I can't get the SQL to work at all when attempting to add the CASE statement. I have tried all combinations of 2,3,4 quotations but to no avail: Do I again need a certain amount of opening quotes and then a different amount of closing quotes?
DECLARE #TSQL NVARCHAR(4000), #PARM NVARCHAR(10)
SET #PARM = 'ABC'
SET #TSQL = 'SELECT * FROM OPENQUERY(MYLINKEDSERVER, ''
SELECT *,
CASE WHEN FLDA = ''ABC'' THEN ''DEF'' ELSE ''ABC'' END AS COL1
FROM MYTABLE
WHERE FLDA = '''''+#PARM+''''''')'
EXEC (#TSQL)
Any help greatly appreciated!
Cheers
Mark
my first question was why do I need 5 and 7 quotes, so there was no error message there, but I get the point that I could have listed some of the errors seen when I was getting the incorrect number of quotes.
However the tip to use Print was very useful, so thank you all for that!
So it transpires that I do indeed require a pair of
quotes where a single quote is required. However, as I am creating a SQL string within a string, I need to double that again. So I first need to end my string with a single quote and then add 4 quotes to create the double quote required to proceed the variable - hence 5. And likewise, I need 4 quotes to get a pair of quotes following the variable, another pair of quotes for the quote to end the statement and then a final one to wrap around the end bracket of the OPENQUERY command....I hope that sort of reads correct!
So:
WHERE FLDA = '''''+#PARM+''''''')'
Printed as:
WHERE FLDA = ''ABC''')
And for my CASE statement, I required 4 set of quotes, to equate to 2. So:
CASE WHEN FLDA = ''''ABC'''' THEN ''''DEF'''' ELSE ''''ABC'''' END AS COL1
Printed as:
CASE WHEN FLDA = ''ABC'' THEN ''DEF'' ELSE ''ABC'' END AS COL1
How to remove backslash in redshift?
For example:
1\234
I want only:
1 234
I have tried regexp_replace function but it didn't work.
REPLACE(string1, old_chars, new_chars)
select replace('1\\2345','\\',' ')
http://docs.aws.amazon.com/redshift/latest/dg/r_REPLACE.html