In pgAdmin 4, the column value is seen as a square bracket [...] instead of an empty value.
The column data type is character(4) and name is carr_desig_icao_cd. Database is postgreSql.
How to avoid the square brackets? I tried pgAdmin 4 preferences but no luck.
Thanks for your help.
Output from psql is as below:
Could it be something to do with converting to_char?
Here are results of my testing.
This query produced no brackets and dots:
select at1.score
This query produced brackets and dots
select to_char(at1.score, '999')
I noticed when this was downloaded and opened in Excel, there were no brackets but three spaces at the start of the column.
This query removed the brackets and dots in PgAdmin and removed the spaces after downloading to Excel:
select replace(to_char(at1.score, '999'), ' ', '')
Just noting also that this was a sub query as part of a bigger query that looked a bit like this:
select
cm.course_id
, us.user_id
, gm.title
, (select replace(to_char(at1.score * 20, '999'), ' ', '') || '% ' || to_char(at1.attempt_date, 'yyyy-mm-dd') from attempt at1 where at1.pk1 = gg.highest_attempt_pk1)
from
etc (joins of course_main cm, users us, gradebook_main gm, gradebook_grade gg, attempt at)
This screenshot shows before and after
Related
a have a column as below
mystring
AC1853551,AC1854125,AC1855220,AC188115,AC1884120,AC1884390,AC1885102
I need to transformm it to get this output
mystring
('AC1853551','AC1854125','AC1855220','AC188115','AC1884120','AC1884390','AC1885102')
Here is my query that i tried
select CONCAT('( , CONCAT (mystring, ')')) from mytablename
I'm getting an error when it comes to insert a single quote '
Then i thought about replacing the comma with a ','
How to get desired output
i'm using postgres 10
A literal quote is coded as a doubled quote:
select '(''' || replace(mycolumn, ',', ''',''') || ''')'
from mytable
See live demo.
I know that I can do a text search in Postgres with TextSearch and get some result with
select ts_headline('german',content, tq, 'MaxFragments=4, MinWords=5, MaxWords=12,
ShortWord=3, StartSel = <strong>, StopSel = </strong>') as highlight, ...
FROM to_tsquery('german', 'test') tq ...
Is there a similar way to apply to content the same limitations? i.e. to get directly up to 12 words from the column content.
You could use regular expressions:
SELECT (regexp_match(
regexp_replace(content, '[^\w\s]+', ' ', 'g'),
'^\s*((?:\w+\s+){9}\w+)'
))[1] FROM ...
That will first replace everything that is not a space or alphanumerical character with a space and then return the first 10 words.
I find in my sql database string whit weird whitespace which cannot be replace like REPLACE(string, ' ', '') RTRIM and cant it even find with string = '% %'. This space is even transfered to new table when using SELECT string INTO
If i select this string in managment studio and copy that is seems is normal space and when everything is works but cant do nothing directly from database. What else can i do? Its some kind of error or can i try some special character for this?
First, you must identify the character.
You can do that by using a tally table (or a cte) and the Unicode function:
The following script will return a table with two columns: one contains a char and the other it's unicode value:
DECLARE #Str nvarchar(100) = N'This is a string containing 1 number and some words.';
with Tally(n) as
(
SELECT TOP(LEN(#str)) ROW_NUMBER() OVER(ORDER BY ##SPID)
FROM sys.objects a
--CROSS JOIN sys.objects b -- (unremark if there are not enough rows in the tally cte)
)
SELECT SUBSTRING(#str, n, 1) As TheChar,
UNICODE(SUBSTRING(#str, n, 1)) As TheCode
FROM Tally
WHERE n <= LEN(#str)
You can also add a condition to the where clause to only include "special" chars:
AND SUBSTRING(#str, n, 1) NOT LIKE '[a-zA-Z0-9]'
Then you can replace it using it's unicode value using nchar (I've used 32 in this example since it's unicode "regular" space:
SELECT REPLACE(#str, NCHAR(32), '|')
Result:
This|is|a|string|containing|1|number|and|some|words.
How to return last n words using Postgres.
I have tried using LEFT method.
SELECT DISTINCT LEFT(name, -4) FROM my_table;
but it return last 4 characters ,i want to return last 3 words.
demo:db<>fiddle
You can do this using a the SUBSTRING() function and regular expressions:
SELECT
SUBSTRING(name FROM '((\S+\s+){0,3}\S+$)')
FROM my_table
This has been explained here: How can I match the last two words in a sentence in PostgreSQL?
\S+ is a string of non-whitespace characters
\s+ is a string of whitespace characters (e.g. one space)
(\S+\s+){0,3} Zero to three words separated by a space
\S+$ one word at the end of the text.
-> creates 4 words (or less if there are no more).
One way is to use regexp_split_to_array() to split the string into the words it contains and then put a string back together using the last 3 words in that array.
SELECT coalesce(w.words[array_length(w.words, 1) - 2] || ' ', '')
|| coalesce(w.words[array_length(w.words, 1) - 1] || ' ', '')
|| coalesce(w.words[array_length(w.words, 1)], '')
FROM mytable t
CROSS JOIN LATERAL (SELECT regexp_split_to_array(t."name", ' ') words) w;
db<>fiddle
RIGHT() should do
SELECT RIGHT('MYCOLUMN', 4); -- returns LUMN
UPD
You can convert to array and then back to string
SELECT array_to_string(sentence[(array_length(sentence,1)-3):(array_length(sentence,1))],' ','*')
FROM
(
SELECT regexp_split_to_array('this is the one of the way to get the last four words of the string', E'\\s+') AS sentence
) foo;
DEMO HERE
With this query
SELECT trim(title) FROM (
SELECT
unnest( xpath('//p[#class="secTitle1"]', xmlText )::varchar[] ) AS title
FROM t1
) as t2
and XML input text with lines and spaces,
<root>
...
<p class="x">
text text
text text
</p><p> ...</p>
...
</root>
The trim() have no effect (!). It is a PostgreSQL bug? How to apply fn:normalize-space() with the XPath? I need something like "WHERE title is not null"? (Oracle is simpler...) How to do this simple query with PostreSQL?
Workaround
I need a well-configured build-in function, not a workaround... But I need to work and to show results, so I am using regular expression...
SELECT id, TRIM(regexp_replace(tit, E'[\\n\\r\\t ]+', ' ', 'g')) AS tit
FROM (
SELECT
id, -- xpath returns array of 1, 2, or more strings
unnest( xpath('//p[#class="secTitle1"]', texto )::VARCHAR[] ) AS tit
FROM t
) AS tmp
So, a "only simple space trim" is not friendly, not util (!).
EDIT after #mu comment
I try
SELECT id, TRIM(tit, E'\\n\\r\\t') AS tit
and
SELECT id, TRIM(tit, '\n\r\t') AS tit
both NOT WORKs.
QUESTION REMAINS:
there are no TRIM-option or postgresql configuration to say to TRIM work as it is required?
can I use normalize-space() at xpath? How?
I am using PostgreSQL 9.1, need to upgrade?
It works in 9.2, and it works on 8.4 too.
postgres=# select trim(unnest(string_to_array(e'\t\tHello\n\t\tHello\n\t\tHello', e'\n')), e'\t');
btrim
-------
Hello
Hello
Hello
(3 rows)
your regexp replace any char \n or \r or \t, but trim working with string "\n\r\t". It has different meaning than you expect.