create a simple DF after reading a parquet file - scala

I am a new developer on Scala and I met some problems to write a simple code on Spark Scala. I have this DF that I get after reading a parquet file :
ID Timestamp
1 0
1 10
1 11
2 20
3 15
And what I want is to create a DF result from the first DF (if the ID = 2 for example, the timestamp should be multiplied by two). So, I created a new class :
case class OutputData(id: bigint, timestamp:bigint)
And here is my code :
val tmp = spark.read.parquet("/user/test.parquet").select("id", "timestamp")
val outputData:OutputData = tmp.map(x:Row => {
var time_result
if (x.getString("id") == 2) {
time_result = x.getInt(2)* 2
}
if (x.getString("id") == 1) {
time_result = x.getInt(2) + 10
}
OutputData2(x.id, time_result)
})
case class OutputData2(id: bigint, timestamp:bigint)
Can you help me please ?

To make the implementation easier, you can cast your df using a case class, the process that Dataset with object notation instead of access to your row each time that you want the value of some element. Apart of that, based on your input and output will take have same format you can use same case class instead of define 2.
Code looks like:
// Sample intput data
val df = Seq(
(1, 0L),
(1, 10L),
(1, 11L),
(2, 20L),
(3, 15L)
).toDF("ID", "Timestamp")
df.show()
// Case class as helper
case class OutputData(ID: Integer, Timestamp: Long)
val newDF = df.as[OutputData].map(record=>{
val newTime = if(record.ID == 2) record.Timestamp*2 else record.Timestamp // identify your id and apply logic based on that
OutputData(record.ID, newTime)// return same format with updated values
})
newDF.show()
The output of above code:
// original
+---+---------+
| ID|Timestamp|
+---+---------+
| 1| 0|
| 1| 10|
| 1| 11|
| 2| 20|
| 3| 15|
+---+---------+
// new one
+---+---------+
| ID|Timestamp|
+---+---------+
| 1| 0|
| 1| 10|
| 1| 11|
| 2| 40|
| 3| 15|
+---+---------+

Related

PySpark UDF: a fir transform example

I am really new to PySpark and am trying to translate some python code into pyspark.
I start with a panda, convert to a document - term matrix and then apply PCA.
The UDF:
class MultiLabelCounter():
def __init__(self, classes=None):
self.classes_ = classes
def fit(self,y):
self.classes_ =
sorted(set(itertools.chain.from_iterable(y)))
self.mapping = dict(zip(self.classes_,
range(len(self.classes_))))
return self
def transform(self,y):
yt = []
for labels in y:
data = [0]*len(self.classes_)
for label in labels:
data[self.mapping[label]] +=1
yt.append(data)
return yt
def fit_transform(self,y):
return self.fit(y).transform(y)
mlb = MultiLabelCounter()
df_grouped =
df_grouped.withColumnRenamed("collect_list(full)","full")
udf_mlb = udf(lambda x: mlb.fit_transform(x),IntegerType())
mlb_fitted = df_grouped.withColumn('full',udf_mlb(col("full")))
I am of course getting NULL results.
I am using spark 2.4.4 version.
EDIT
Adding sample input and output as per request
Input:
|id|val|
|--|---|
|1|[hello,world]|
|2|[goodbye, world]|
|3|[hello,hello]|
Output:
|id|hello|goodbye|world|
|--|-----|-------|-----|
|1|1|0|1|
|2|0|1|1|
|3|2|0|0|
Based upon input data shared, I tried replicating your output and it works. Please see below -
Input Data
df = spark.createDataFrame(data=[(1, ['hello', 'world']), (2, ['goodbye', 'world']), (3, ['hello', 'hello'])], schema=['id', 'vals'])
df.show()
+---+----------------+
| id| vals|
+---+----------------+
| 1| [hello, world]|
| 2|[goodbye, world]|
| 3| [hello, hello]|
+---+----------------+
Now, using explode to create separate rows out of vals list items. Thereafter, using pivot and count will calculate the frequency. Finally, replacing null values with 0 using fillna(0). See below -
from pyspark.sql.functions import *
df1 = df.select(['id', explode(col('vals'))]).groupBy("id").pivot("col").agg(count(col("col")))
df1.fillna(0).orderBy("id").show()
Output
+---+-------+-----+-----+
| id|goodbye|hello|world|
+---+-------+-----+-----+
| 1| 0| 1| 1|
| 2| 1| 0| 1|
| 3| 0| 2| 0|
+---+-------+-----+-----+

How to remove Spark values that are out of sequence

I need to remove some values from dataframe that is not in right place.
I have the following dataframe, for example:
+-----+-----+
|count|PHASE|
+-----+-----+
| 1| 3|
| 2| 3|
| 3| 6|
| 4| 6|
| 5| 8|
| 6| 4|
| 7| 4|
| 8| 4|
+-----+-----+
I need to remove 6 and 8 from dataframe because of some rules:
phase === 3 and lastPhase.isNull
phase === 4 and lastPhase.isin(2, 3)
phase === 6 and lastPhase.isin(4, 5)
phase === 8 and lastPhase.isin(6, 7)
This is a huge dataframe and those misplaced values can happen many times.
Could you help with that, please?
Expected output:
+-----+-----+------+
|count|PHASE|CHANGE|
+-----+-----+------+
| 1| 3| 3|
| 2| 3| 3|
| 3| 6| 3|
| 4| 6| 3|
| 5| 8| 3|
| 6| 4| 4|
| 7| 4| 4|
| 8| 4| 4|
+-----+-----+------+
val rows = Seq(
Row(1, 3),
Row(2, 3),
Row(3, 6),
Row(4, 6),
Row(5, 8),
Row(6, 4),
Row(7, 4),
Row(8, 4)
)
val schema = StructType(
Seq(StructField("count", IntegerType), StructField("PHASE", IntegerType))
)
val df = spark.createDataFrame(
spark.sparkContext.parallelize(rows),
schema
)
Thanks in advance!
If I correctly understood your question, you want to populate column CHANGE as follow:
For a dataframe sorted by count column, for each row, if the value of the PHASE column matches a defined set of rules, set this value in CHANGE column. If value doesn't match the rules, set latest valid PHASE value in CHANGE column
To do so, You can use an user-defined aggregate function to setup CHANGE column over a window ordered by COUNT column
First, you define an Aggregator object where its buffer will be the last valid phase, and you implement your set of rules in its reduce function:
import org.apache.spark.sql.expressions.Aggregator
import org.apache.spark.sql.{Encoder, Encoders}
object LatestValidPhase extends Aggregator[Integer, Integer, Integer] {
def zero: Integer = null
def reduce(lastPhase: Integer, phase: Integer): Integer = {
if (lastPhase == null && phase == 3) {
phase
} else if (Set(2, 3).contains(lastPhase) && phase == 4) {
phase
} else if (Set(4, 5).contains(lastPhase) && phase == 6) {
phase
} else if (Set(6, 7).contains(lastPhase) && phase == 8) {
phase
} else {
lastPhase
}
}
def merge(b1: Integer, b2: Integer): Integer = {
throw new NotImplementedError("should not use as general aggregation")
}
def finish(reduction: Integer): Integer = reduction
def bufferEncoder: Encoder[Integer] = Encoders.INT
def outputEncoder: Encoder[Integer] = Encoders.INT
}
Then you transform it into an aggregate user-defined function that you apply over your window ordered by COUNT column:
import org.apache.spark.sql.expressions.Window
import org.apache.spark.sql.functions.{col, udaf}
val latest_valid_phase = udaf(LatestValidPhase)
val window = Window.orderBy("count")
df.withColumn("CHANGE", latest_valid_phase(col("PHASE")).over(window))

Sum columns of a Spark dataframe and create another dataframe

I have a dataframe like below -
I am trying to create another dataframe from this which has 2 columns - the column name and the sum of values in each column like this -
So far, I've tried this (in Spark 2.2.0) but throws a stack trace -
val get_count: (String => Long) = (c: String) => {
df.groupBy("id")
.agg(sum(c) as "s")
.select("s")
.collect()(0)
.getLong(0)
}
val sqlfunc = udf(get_count)
summary = summary.withColumn("sum_of_column", sqlfunc(col("c")))
Are there any other alternatives of accomplishing this task?
I think that the most efficient way is to do an aggregation and then build a new dataframe. That way you avoid a costly explode.
First, let's create the dataframe. BTW, it's always nice to provide the code to do it when you ask a question. This way we can reproduce your problem in seconds.
val df = Seq((1, 1, 0, 0, 1), (1, 1, 5, 0, 0),
(0, 1, 0, 6, 0), (0, 1, 0, 4, 3))
.toDF("output_label", "ID", "C1", "C2", "C3")
Then we build the list of columns that we are interested in, the aggregations, and compute the result.
val cols = (1 to 3).map(i => s"C$i")
val aggs = cols.map(name => sum(col(name)).as(name))
val agg_df = df.agg(aggs.head, aggs.tail :_*) // See the note below
agg_df.show
+---+---+---+
| C1| C2| C3|
+---+---+---+
| 5| 10| 4|
+---+---+---+
We almost have what we need, we just need to collect the data and build a new dataframe:
val agg_row = agg_df.first
cols.map(name => name -> agg_row.getAs[Long](name))
.toDF("column", "sum")
.show
+------+---+
|column|sum|
+------+---+
| C1| 5|
| C2| 10|
| C3| 4|
+------+---+
EDIT:
NB: df.agg(aggs.head, aggs.tail :_*) may seem strange. The idea is simply to compute all the aggregations computed in aggs. One would expect something more simple like df.agg(aggs : _*). Yet the signature of the agg method is as follows:
def agg(expr: org.apache.spark.sql.Column,exprs: org.apache.spark.sql.Column*)
maybe to ensure that at least one column is used, and this is why you need to split aggs in aggs.head and aggs.tail.
What i do is to define a method to create a struct from the desired values:
def kv (columnsToTranspose: Array[String]) = explode(array(columnsToTranspose.map {
c => struct(lit(c).alias("k"), col(c).alias("v"))
}: _*))
This functions receives a list of columns to transpose (your 3 last columns in your case) and transform them in a struct with the column name as key and the column value as value
And then use that method to create an struct and process it as you want
df.withColumn("kv", kv(df.columns.tail.tail))
.select( $"kv.k".as("column"), $"kv.v".alias("values"))
.groupBy("column")
.agg(sum("values").as("sum"))
First apply the previous defined function to have the desired columns as the said struct, and then deconstruct the struct to have a column key and a column value in each row.
Then you can aggregate by the column name and sum the values
INPUT
+------------+---+---+---+---+
|output_label| id| c1| c2| c3|
+------------+---+---+---+---+
| 1| 1| 0| 0| 1|
| 1| 1| 5| 0| 0|
| 0| 1| 0| 6| 0|
| 0| 1| 0| 4| 3|
+------------+---+---+---+---+
OUTPUT
+------+---+
|column|sum|
+------+---+
| c1| 5|
| c3| 4|
| c2| 10|
+------+---+

Scala & Spark: Add value to every cell of every row

I have a two DataFrames:
scala> df1.show()
+----+----+----+---+----+
|col1|col2|col3| |colN|
+----+----+----+ +----+
| 2|null| 3|...| 4|
| 4| 3| 3| | 1|
| 5| 2| 8| | 1|
+----+----+----+---+----+
scala> df2.show() // has one row only (avg())
+----+----+----+---+----+
|col1|col2|col3| |colN|
+----+----+----+ +----+
| 3.6|null| 4.6|...| 2|
+----+----+----+---+----+
and a constant val c : Double = 0.1.
Desired output is a df3: Dataframe that is given by
,
with n=numberOfRow and m=numberOfColumn.
I already looked through the list of sql.functions and failed implementing it myself with some nested map operations (fearing performance issues). One idea I had was:
val cBc = spark.sparkContext.broadcast(c)
val df2Bc = spark.sparkContext.broadcast(averageObservation)
df1.rdd.map(row => {
for (colIdx <- 0 until row.length) {
val correspondingDf2value = df2Bc.value.head().getDouble(colIdx)
row.getDouble(colIdx) * (1 - cBc.value) + correspondingDf2value * cBc.value
}
})
Thank you in advance!
(cross)join combined with select is more than enough and will be much more efficient than mapping. Required imports:
import org.apache.spark.sql.functions.{broadcast, col, lit}
and expression:
val exprs = df1.columns.map { x => (df1(x) * (1 - c) + df2(x) * c).alias(x) }
join and select:
df1.crossJoin(broadcast(df2)).select(exprs: _*)

Spark: Add column to dataframe conditionally

I am trying to take my input data:
A B C
--------------
4 blah 2
2 3
56 foo 3
And add a column to the end based on whether B is empty or not:
A B C D
--------------------
4 blah 2 1
2 3 0
56 foo 3 1
I can do this easily by registering the input dataframe as a temp table, then typing up a SQL query.
But I'd really like to know how to do this with just Scala methods and not having to type out a SQL query within Scala.
I've tried .withColumn, but I can't get that to do what I want.
Try withColumn with the function when as follows:
val sqlContext = new SQLContext(sc)
import sqlContext.implicits._ // for `toDF` and $""
import org.apache.spark.sql.functions._ // for `when`
val df = sc.parallelize(Seq((4, "blah", 2), (2, "", 3), (56, "foo", 3), (100, null, 5)))
.toDF("A", "B", "C")
val newDf = df.withColumn("D", when($"B".isNull or $"B" === "", 0).otherwise(1))
newDf.show() shows
+---+----+---+---+
| A| B| C| D|
+---+----+---+---+
| 4|blah| 2| 1|
| 2| | 3| 0|
| 56| foo| 3| 1|
|100|null| 5| 0|
+---+----+---+---+
I added the (100, null, 5) row for testing the isNull case.
I tried this code with Spark 1.6.0 but as commented in the code of when, it works on the versions after 1.4.0.
My bad, I had missed one part of the question.
Best, cleanest way is to use a UDF.
Explanation within the code.
// create some example data...BY DataFrame
// note, third record has an empty string
case class Stuff(a:String,b:Int)
val d= sc.parallelize(Seq( ("a",1),("b",2),
("",3) ,("d",4)).map { x => Stuff(x._1,x._2) }).toDF
// now the good stuff.
import org.apache.spark.sql.functions.udf
// function that returns 0 is string empty
val func = udf( (s:String) => if(s.isEmpty) 0 else 1 )
// create new dataframe with added column named "notempty"
val r = d.select( $"a", $"b", func($"a").as("notempty") )
scala> r.show
+---+---+--------+
| a| b|notempty|
+---+---+--------+
| a| 1| 1111|
| b| 2| 1111|
| | 3| 0|
| d| 4| 1111|
+---+---+--------+
How about something like this?
val newDF = df.filter($"B" === "").take(1) match {
case Array() => df
case _ => df.withColumn("D", $"B" === "")
}
Using take(1) should have a minimal hit