Can't get result when running the query from Spring Data Jpa - postgresql

Question

When running the following query in pgAdmin, everything is good but when I run the query from java code i get an error.
I tried to cast the variables but no result, I get an error of cast syntax
The query interface:
public interface SeanceRepository extends JpaRepository<Seance, Integer>{
#Query(value = "select * from seance, patient where extract(month from date) = ?1 "
+ "and extract(year from date) = ?2 and patient.id = seance.patient_id",
nativeQuery = true)
public List<Object> getSeanceByMonthYear(String month, String year);
}
The error :
org.postgresql.util.PSQLException: ERREUR: l'opérateur n'existe pas : double precision = character varying
Indice : Aucun opérateur ne correspond au nom donné et aux types d'arguments.
Vous devez ajouter des conversions explicites de type.
Position : 62
at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2440) ~[postgresql-42.2.5.jar:42.2.5]
at org.postgresql.core.v3.QueryExecutorImpl.processResults(QueryExecutorImpl.java:2183) ~[postgresql-42.2.5.jar:42.2.5]
at org.postgresql.core.v3.QueryExecutorImpl.execute(QueryExecutorImpl.java:308) ~[postgresql-42.2.5.jar:42.2.5]
Patient.java
#Entity
#Table(name = "Patient")
#JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
public class Patient {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int id;
private String firstName;
private String lastName;
private String cin;
private Date birthDate;
private String phoneNumber;
private Boolean active;
//getters and setters
}
seance.java
#Entity
#Table(name = "Seance")
#JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
public class Seance {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int id;
private Date date;
#OneToOne
private Patient patient;
#OneToOne
private TypeConsultation typeConsultation;
private String motif;
//getters and setters

Answer 1

It is because the function extract a double and you compare it to a string

Answer 2

As you can see in https://w3resource.com/PostgreSQL/extract-function.php
The extract function() is used to retrieves subfields such as year or
hour from date/time values. The source must be a value expression of
type timestamp, time, or interval. The field is an identifier or
string that selects what field to be extracted from the source value.
Syntax:
extract(field from timestamp) or extract(field from interval)
Return Type: double precision.
PostgreSQL Version: 9.3
extract returns a value in double presision and you try to compare it to a varchar. It can not be done by postgresSQL automatically, you have to do it explicitly:
#Query(value = "select * from seance, patient where extract(month from date)::varchar(255) = ?1 "
+ "and extract(year from date)::varchar(255) = ?2 and patient.id = seance.patient_id",
nativeQuery = true)