The problem I have is that it only works partially, but what can I add to make it work?
A2 = [20 4 6 8 5];
A3 = [10 2 3 4 6];
Str=[];
formatSpec = 'P%d (%d,%d)';
for i=1:length(A2)
str = char(sprintf (formatSpec, i, A2(i),A3(i)));
Str=[Str;str];
end
set(handles.text2,'string',Str);
You are not concatenating strings but char-arrays. Thinking it this way, it already answers your question: If you have a two-digit number, the char-array is one element longer than the char-array of a single-digit number... and you cannot concatenate two arrays of different size vertically.
The solution is fairly simple: use actual strings (introduced somewhere around R2016a). Strings are indicated with "" instead of '', which are chars. So replace your charwith string and it works fine. (Even better: provide the formatSpecas ""-string and it sprintf() will return a string right away)
Side note:
BTW, you should always allocate memory if your are looping. That is why the Str has an orange squiggly underline. This is because MATLAB stores arrays in RAM contiguously and has to copy it to a larger section it it outgrows the current one.
So instead of Str=[], write Str = strings(length(A2),1), and index Str(i) = ... in the loop.
Personally, I like num2str more that sprintf but I cannot give a good reason for this, except for that it also works without providing a format.
Related
I have a text file with 1 million decimal digits of "e" number with 80 digits on each line excluding the first and the last line which have 76 and 4 digits and the file has 12501 lines. I want to convert it into a vector in matlab with each digit on each row. I tried num2str function, but the problem is that it gets converted like for example '7.1828e79' (13 characters). What can I do?
P.S.1: The first two lines of the text file (76 and 80 digits) are:
7182818284590452353602874713526624977572470936999595749669676277240766303535 47594571382178525166427427466391932003059921817413596629043572900334295260595630
P.S.2: I used "dlmread" and got a 12501x1 vector, with the first and second row of 7.18281828459045e+75 and 4.75945713821785e+79 and the problem is that when I use num2str for example for the first row value, I get: '7.182818284590453e+75' as a string and not the whole 76 digits. My aim was to do something like this:
e1=dlmread('e.txt');
es1=num2str(e1);
for i=1:12501
for j=1:length(es1(1,:))
a1((i-1)*length(es1(1,:))+j)=es1(i,j);
end
end
e_digits=a1.';
but I get a string like this:
a1='7.182818284590453e+754.759457138217852e+797.381323286279435e+799.244761460668082e+796.133138458300076e+791.416928368190255e+79 5...'
with 262521 characters instead of 1 million digits.
P.S.3: I think the problem might be solved if I can manipulate the text file in a way that I have one digit on each line and simply use dlmread.
Well, this is not hard, there are many ways to do it.
So first you want to load in your file as a Char Array using something simple like (you want a Char Array so that you can easily manipulate it to forget about the lines breaks) :
C = fileread('yourfile.txt'); %loads file as Char Array
D = C(~isspace(C)); %Removes SPACES which are line-breaks
Next, you want to actually append a SPACE between each char (this is because you want to use the num2str transform - and matlab needs to see the space), you can do this using a RESHAPE, a STRTRIM or simply a REGEX:
E = strtrim(regexprep(D, '.{1}', '$0 ')); %Add a SPACE after each Numeric Digit
Now you can transform it using str2num into a Vector:
str2num(E)'; %Converts the Char Array back to Vector
which will give you a single digit each row.
Using your example, I get a vector of 156 x 1, with 1 digit each row as you required.
You can get a digit per row like this
fid = fopen('e.txt','r');
c = textscan(fid,'%s');
c=cat(1,c{:});
c = cellfun(#(x) str2num(reshape(x,[],1)),c,'un',0);
c=cat(1,c{:});
And it is not the only possible way.
Could you please tell what is the final task, how do you plan using the array of e digits?
What is the difference between string and character class in MATLAB?
a = 'AX'; % This is a character.
b = string(a) % This is a string.
The documentation suggests:
There are two ways to represent text in MATLAB®. You can store text in character arrays. A typical use is to store short pieces of text as character vectors. And starting in Release 2016b, you can also store multiple pieces of text in string arrays. String arrays provide a set of functions for working with text as data.
This is how the two representations differ:
Element access. To represent char vectors of different length, one had to use cell arrays, e.g. ch = {'a', 'ab', 'abc'}. With strings, they can be created in actual arrays: str = [string('a'), string('ab'), string('abc')].
However, to index characters in a string array directly, the curly bracket notation has to be used:
str{3}(2) % == 'b'
Memory use. Chars use exactly two bytes per character. strings have overhead:
a = 'abc'
b = string('abc')
whos a b
returns
Name Size Bytes Class Attributes
a 1x3 6 char
b 1x1 132 string
The best place to start for understanding the difference is the documentation. The key difference, as stated there:
A character array is a sequence of characters, just as a numeric array is a sequence of numbers. A typical use is to store short pieces of text as character vectors, such as c = 'Hello World';.
A string array is a container for pieces of text. String arrays provide a set of functions for working with text as data. To convert text to string arrays, use the string function.
Here are a few more key points about their differences:
They are different classes (i.e. types): char versus string. As such they will have different sets of methods defined for each. Think about what sort of operations you want to do on your text, then choose the one that best supports those.
Since a string is a container class, be mindful of how its size differs from an equivalent character array representation. Using your example:
>> a = 'AX'; % This is a character.
>> b = string(a) % This is a string.
>> whos
Name Size Bytes Class Attributes
a 1x2 4 char
b 1x1 134 string
Notice that the string container lists its size as 1x1 (and takes up more bytes in memory) while the character array is, as its name implies, a 1x2 array of characters.
They can't always be used interchangeably, and you may need to convert between the two for certain operations. For example, string objects can't be used as dynamic field names for structure indexing:
>> s = struct('a', 1);
>> name = string('a');
>> s.(name)
Argument to dynamic structure reference must evaluate to a valid field name.
>> s.(char(name))
ans =
1
Strings do have a bit of overhead, but still increase by 2 bytes per character. After every 8 characters it increases the size of the variable. The red line is y=2x+127.
figure is created using:
v=[];N=100;
for ct = 1:N
s=char(randi([0 255],[1,ct]));
s=string(s);
a=whos('s');v(ct)=a.bytes;
end
figure(1);clf
plot(v)
xlabel('# characters')
ylabel('# bytes')
p=polyfit(1:N,v,1);
hold on
plot([0,N],[127,2*N+127],'r')
hold off
One important practical thing to note is, that strings and chars behave differently when interacting with square brackets. This can be especially confusing when coming from python. consider following example:
>>['asdf' '123']
ans =
'asdf123'
>> ["asdf" "123"]
ans =
1×2 string array
"asdf" "123"
I want to use fscanf for reading a text file containing 4 rows with an unknown number of columns. The newline is represented by two consecutive spaces.
It was suggested that I pass : as the sizeA parameter but it doesn't work.
How can I read in my data?
update: The file format is
String1 String2 String3
10 20 30
a b c
1 2 3
I have to fill 4 arrays, one for each row.
See if this will work for your application.
fid1=fopen('test.txt');
i=1;
check=0;
while check~=1
str=fscanf(fid1,'%s',1);
if strcmp(str,'')~=1;
string(i)={str};
end
i=i+1;
check=strcmp(str,'');
end
fclose(fid1);
X=reshape(string,[],4);
ar1=X(:,1)
ar2=X(:,2)
ar3=X(:,3)
ar4=X(:,4)
Once you have 'ar1','ar2','ar3','ar4' you can parse them however you want.
I have found a solution, i don't know if it is the only one but it works fine:
A=fscanf(fid,'%[^\n] *\n')
B=sscanf(A,'%c ')
Z=fscanf(fid,'%[^\n] *\n')
C=sscanf(Z,'%d')
....
You could use
rawText = getl(fid);
lines = regexp(thisLine,' ','split);
tokens = {};
for ix = 1:numel(lines)
tokens{end+1} = regexp(lines{ix},' ','split'};
end
This will give you a cell array of strings having the row and column shape or your original data.
To read an arbitrary line of text then break it up according the the formating information you have available. My example uses a single space character.
This uses regular expressions to define the separator. Regular expressions powerful but too complex to describe here. See the MATLAB help for regexp and regular expressions.
I have a string and I need two characters to be returned.
I tried with strsplit but the delimiter must be a string and I don't have any delimiters in my string. Instead, I always want to get the second number in my string. The number is always 2 digits.
Example: 001a02.jpg I use the fileparts function to delete the extension of the image (jpg), so I get this string: 001a02
The expected return value is 02
Another example: 001A43a . Return values: 43
Another one: 002A12. Return values: 12
All the filenames are in a matrix 1002x1. Maybe I can use textscan but in the second example, it gives "43a" as a result.
(Just so this question doesn't remain unanswered, here's a possible approach: )
One way to go about this uses splitting with regular expressions (MATLAB's strsplit which you mentioned):
str = '001a02.jpg';
C = strsplit(str,'[a-zA-Z.]','DelimiterType','RegularExpression');
Results in:
C =
'001' '02' ''
In older versions of MATLAB, before strsplit was introduced, similar functionality was achieved using regexp(...,'split').
If you want to learn more about regular expressions (abbreviated as "regex" or "regexp"), there are many online resources (JGI..)
In your case, if you only need to take the 5th and 6th characters from the string you could use:
D = str(5:6);
... and if you want to convert those into numbers you could use:
E = str2double(str(5:6));
If your number is always at a certain position in the string, you can simply index this position.
In the examples you gave, the number is always the 5th and 6th characters in the string.
filename = '002A12';
num = str2num(filename(5:6));
Otherwise, if the formating is more complex, you may want to use a regular expression. There is a similar question matlab - extracting numbers from (odd) string. Modifying the code found there you can do the following
all_num = regexp(filename, '\d+', 'match'); %Find all numbers in the filename
num = str2num(all_num{2}) %Convert second number from str
I'm fairly new to Matlab, although not to programming. I'm trying to hash a string, and get back a single value that acts as a unique id for that string. I'm using this DataHash function from FileExchange which returns the hash as an integer vector. So far the best solution I've found for converting this to a single numeric value goes:
hash_opts.Format = 'uint8';
hash_vector = DataHash(string, hash_opts);
hash_string = num2str(hash_vector);
% Use a simple regex to remove all whitespace from the string,
% takes it from '1 2 3 4' to '1234'
hash_string = regexprep(hash_string, '[\s]', '');
hashcode = str2double(hash_string);
A reproducible example that doesn't depend on DataHash:
hash_vector = [1, 23, 4, 567];
hash_string = num2str(hash_vector);
% Use a simple regex to remove all whitespace from the string,
% takes it from '1 2 3 4' to '1234'
hash_string = regexprep(hash_string, '[\s]', '');
hashcode = str2double(hash_string); % Output: 1234567
Are there more efficient ways of achieving this, without resorting to a regex?
Yes, Matlab's regex implementation isn't particularly fast. I suggest that you use strrep:
hashcode = str2double(strrep(hash_string,' ',''));
Alternatively, you can use a string creation method that doesn't insert spaces in the first place:
hash_vector = [1, 23, 4, 567];
hash_string = str2double(sprintf('%d',hash_vector))
Just make sure that your hash number is less than 2^53 or the conversion to double might not be exact.
I'v seen there's already an answer - though it loses precission as it omits leading 0s - I'm not really sure if it will cause you troubles but I wouldn't want to rely on it.
As you output as uint8 why don't you use hex values instead - this will give you the exactly same number. Converting back is also easy using dec2hex.
hash_vector = [1, 23, 4, 253]
hash_str=sprintf('%02x',hash_vector); % to assure every 8 bit use 2 hex digits!
hash_dig=hex2dec(hash_str)
btw. - your sampe hash contains 567 - an impossible number in uint8.
Having looked at DataHash the question would also be why not use base64 or hex in the first place.