I have 4 coordinates assigned to variables, so I would just like to colour in the rectangle that is created from these variables. I tried the fill function, but I cant gather much information from the example.
When I try to use:
fill(bottom left point, top right point,'g')
the figure it makes only shows a line between those points, and doesn't colour in the entire area.
I'm using MATLAB R2019b, if that helps.
Also, if its possible to fill the rectangle with a pattern instead, please let me know aswell.
Thanks in advance
Related
I tried to customise leaflet heatmap.js to render rectangles to generate a heatmap. I was doing good so far. But, there are spacing in between rectangles that I can't get rid of. As in the picture.
heatmap
Solutions that I tried: turn off antialiasing, add offset. While adding offset remove the space, it creates an area with "blended color" which I don't want to have. I wonder if there is a solution to remove the gap or remove the blending color in heatmap.js.
Thanks and regards.
Turn out it is precision problem of the leaflet latlong to screen coordinate function. I have fixed it by recalculate the coordinate.
For Example, I have the below image used for demo purpose only
Fill close portion with pattern
if user tap on any part of T-Shirt, than T-Shirt should be filled with selected pattern image.
I have used to find an array of the point contains close area it takes time as well to find close region points and try to draw color at that points, but it takes too much time to draw because there are many points for the close region.
I have used code from below link
https://github.com/Chintan-Dave/UIImageScanlineFloodfill
This algorithm is actually for flood fill, but I have added one more method to collect all points to one NSSet.
A help is too much appreciated.
Thanks in advance.
I have an image (represented as green) overlaying a box (represented as blue), and the image is going to be transform: scale()ing in size. When this happens I need all edges of the image to complete their transformation at the same time.
To do this I need to calculate the transform-origin based on where the image is located overtop of the bounding box, using JavaScript. Assume I know all the coordinates that getBoundingClientRect() provides, for both elements.
In the six examples below I’ve placed a red dot where the transform-origin percentages should intersect.
I just can’t figure out the math to get there. The closest I've come to finding an answer is with this question, but it's a little vague and I'm not sure I fully understand the answer itself. I would greatly appreciate help with this, and will happily provide more details if I'm missing something.
After fiddling around, I figured out the formula is:
(
(box.left - image.left) /
(image.width - box.width)
) * 100
I am having trouble to change the bar color, I want it to be white in the middle, and red at the edge. Looking at matlab's description
if I do:
bar(y,'FaceColor','w','EdgeColor','r','LineWidth',1)
It should give me the above. However, when I actually run it, it only give me white graph.
Update: my y is:
y=zeros(1,5000); y(3000)=1; y(4000)=1;
Using the above, I got....
With so many bars, Matlab probably has trouble differentiating edge ('EdgeColor') and fill ('FaceColor') of each. After all, each complete bar is less than a screen pixel.
I suggest you use white edge and colored fill. That works for me. It's as if 'FaceColor' had precedence over 'EdgeColor'.
bar(y,'FaceColor','r','EdgeColor','w','LineWidth',1)
Or better yet: replace each bar by a line, that is, use stem:
stem(y,'r','marker','none')
I would like to expand a line to a wider polygon. Add 10 meter on both sides of the line for example.
Here is an example of what I would like
Take this line
And expand it to a wider polygon, like this
I did this manually, is there a way to do this automaticly?
Changing the KML or using a program?
Thanks
Vincent
Depending on how accurate you need this – this is not trivial.
One possible algorithm could be:
for each segment do
expand segment to rectangle with width 2r
targetShape.join(rectangle)
next
for each point do
expand point to circle with radius r
targetShape.join(circle)
next
targetShape.outerHull(precision)
Each single line in this routine is tricky and depends on your expectations.
You could leave out the circles and instead make the rectangles longer, but this wil not work on sharp turns.
All of this involves ugly calculations to figure orthogonal lines etc.
You could try it in an graphic tool, gimp or inkskape :-)