+-------+--------+
| Names | Values |
+-------+--------+
| A | 25 |
+-------+--------+
| B | 12.5 |
+-------+--------+
| C | 37.5 |
+-------+--------+
How can I compare values and return the name of the highest value?
I am using LibreOffice Calc.
The normal VLOOKUP function assumes the values are in the leftmost column, so we can use LOOKUP instead to search in the correct column.
=LOOKUP(MAX(B1:B3);B1:B3;A1:A3)
Documentation: LOOKUP, MAX
Related
I calculate my metrics with SQL and publish the resulting table to Tableau Server. Afterward, use this data source to create charts and dashboards.
For one analysis, I already calculated the measures per day with SQL. When I use the resulting table in Tableau, it aggregates these measures to SUM by default. However, I don't want to have SUM or AVG of the average or SUM of the Percentiles.
What I want is the result when I don't select date dimension and not GROUP BY date in SQL as attached below.
Here is the query:
SELECT
-- date,
COUNT(DISTINCT id) AS count_of_id,
AVG(timediff_in_sec) AS avg_timediff,
PERCENTILE_CONT(0.25) WITHIN GROUP(ORDER BY timediff_in_sec) AS percentile_25,
PERCENTILE_CONT(0.50) WITHIN GROUP(ORDER BY timediff_in_sec) AS percentile_50
FROM
(
--subquery
) AS t1
-- GROUP BY date
Here are the first 10 rows of the resulting table:
+------------+--------------+-------------+---------------+---------------+
| date | avg_timediff | count_of_id | percentile_25 | percentile_50 |
+------------+--------------+-------------+---------------+---------------+
| 10/06/2020 | 61,65186364 | 22 | 8,5765 | 13,3015 |
| 11/06/2020 | 127,2913333 | 3 | 15,6045 | 17,494 |
| 12/06/2020 | 306,0348214 | 28 | 12,2565 | 17,629 |
| 13/06/2020 | 13,2664 | 5 | 11,944 | 13,862 |
| 14/06/2020 | 16,728 | 7 | 14,021 | 17,187 |
| 15/06/2020 | 398,6424595 | 37 | 11,893 | 19,271 |
| 16/06/2020 | 293,6925152 | 33 | 12,527 | 17,134 |
| 17/06/2020 | 155,6554286 | 21 | 13,452 | 16,715 |
| 18/06/2020 | 383,8101429 | 7 | 266,048 | 493,722 |
+------------+--------------+-------------+---------------+---------------+
How can I achieve the desired output above?
Drag them all into the dimensions list, then they will be static dimensions. For your use you could also just drag the Date field to Rows. Aggregating 1 value, which you have for each date, returns the same value whatever the aggregation type.
At the moment I have this chart that I'd like to calculate cost basis from of
| AGG | 0.000004 | 104.40 | 10/5/2018 |
| AGG | 2.675897 | 110.15 | 5/31/2019 |
| AGG | 0.054206 | 110.32 | 6/4/2019 |
| AGG | 0.742459 | 110.39 | 6/6/2019 |
| AGG | 0.365697 | 110.31 | 6/10/2019 |
| AGG | 0.161737 | 110.47 | 6/17/2019 |
|-----+----------+--------+-----------|
| | 4. | 656.04 | |
#+TBLFM: #>$2=vsum(#1..#-1)
#+TBLFM: #>$3=vsum(#1..#-1)
How can I multiply the 2nd column with the 3rd column and sum the result?
Assuming you multiply cols 2 and cols 3 and store the result in col 5, and then the last row of col 5 has the sum (i.e., summing row 1 to row n-1 in col 5):
#+TBLFM: $5 = $2*$3
#+TBLFM: #>$5 = vsum(#1..#-1)
Try vsum(#1$2..#-1$2 * #1$3..#-1$3)
I have the following table that I have loaded in Tableau (It has only one column CreatedOnDate)
+-----------------+
| CreatedOnDate |
+-----------------+
| 1/1/2016 |
| 1/2/2016 |
| 1/3/2016 |
| 1/4/2016 |
| 1/5/2016 |
| 1/6/2016 |
| 1/7/2016 |
| 1/8/2016 |
| 1/9/2016 |
| 1/10/2016 |
| 1/11/2016 |
| 1/12/2016 |
| 1/13/2016 |
| 1/14/2016 |
+-----------------+
I want to be able to find the maximum date in the table, compare it with every date in the table and get the difference in days. For the above table, the maximum date in table is 1/14/2016. Every date is compared to 1/14/2016 to find the difference.
Expected Output
+-----------------+------------+
| CreatedOnDate | Difference |
+-----------------+------------+
| 1/1/2016 | 13 |
| 1/2/2016 | 12 |
| 1/3/2016 | 11 |
| 1/4/2016 | 10 |
| 1/5/2016 | 9 |
| 1/6/2016 | 8 |
| 1/7/2016 | 7 |
| 1/8/2016 | 6 |
| 1/9/2016 | 5 |
| 1/10/2016 | 4 |
| 1/11/2016 | 3 |
| 1/12/2016 | 2 |
| 1/13/2016 | 1 |
| 1/14/2016 | 0 |
+-----------------+------------+
My goal is to create this Difference calculated field. I am struggling to find a way to do this using DATEDIFF.
And help would be appreciated!!
woodhead92, this approach would work, but means you have to use table calculations. Much more flexible approach (available since v8) is Level of Details expressions:
First, define a MAX date for the whole dataset with this calculated field called MaxDate LOD:
{FIXED : MAX(CreatedOnDate) }
This will always calculate the maximum date on table (will overwrite filters as well, if you need to reflect them, make sure you add them to context.
Then you can use pretty much the same calculated field, but no need for ATTR or Table Calculations:
DATEDIFF('day', [CreatedOnDate], [MaxDate LOD])
Hope this helps!
I have a table that looks like
+-------+-----------+
| value | timestamp |
+-------+-----------+
and I'm trying to build a query that gives a result like
+-------+-----------+------------+------------------------+
| value | timestamp | MAX(value) | timestamp of max value |
+-------+-----------+------------+------------------------+
so that the result looks like
+---+----------+---+----------+
| 1 | 1.2.1001 | 3 | 1.1.1000 |
| 2 | 5.5.1021 | 3 | 1.1.1000 |
| 3 | 1.1.1000 | 3 | 1.1.1000 |
+---+----------+---+----------+
but I got stuck on joining the column with the corresponding timestamps.
Any hints or suggestions?
Thanks in advance!
For further information (if that helps):
In the real project the max-values are grouped by month and day (with group by clause, which works btw), but somehow I got stuck on joining the timestamps for max-values.
EDIT
Cross joins are a good idea, but I want to have them grouped by month e.g.:
+---+----------+---+----------+
| 1 | 1.1.1101 | 6 | 1.1.1300 |
| 2 | 2.6.1021 | 5 | 5.6.1000 |
| 3 | 1.1.1200 | 6 | 1.1.1300 |
| 4 | 1.1.1040 | 6 | 1.1.1300 |
| 5 | 5.6.1000 | 5 | 5.6.1000 |
| 6 | 1.1.1300 | 6 | 1.1.1300 |
+---+----------+---+----------+
EDIT 2
I've added a fiddle for some sample data and and example of the current query.
http://sqlfiddle.com/#!1/efa42/1
How to add the corresponding timestamp to the maximum?
Try a cross join with two sub queries, the first one selects all records, the second one gets one row that represents the time_stamp of the max value, <3;"1000-01-01"> for example.
SELECT col_value,col_timestamp,max_col_value, col_timestamp_of_max_value FROM table1
cross join
(
select max(col_value) max_col_value ,col_timestamp col_timestamp_of_max_value from table1
group by col_timestamp
order by max_col_value desc
limit 1
) A --One row that represents the time_stamp of the max value, ie: <3;"1000-01-01">
Use the window cause you use with pg
Select *, max( value ) over (), max( timestamp ) over() from table
That gives you the max values from all values in every row
http://www.postgresql.org/docs/9.1/static/tutorial-window.html
I have a spreadsheet with column A which holds a timestamp and updates daily. Column B holds a value. Like the following:
+--------------------+---------+
| 11/24/2012 1:14:21 | $487.20 |
| 11/25/2012 1:14:03 | $487.20 |
| 11/26/2012 1:14:14 | $487.20 |
| 11/27/2012 1:14:05 | $487.20 |
| 11/28/2012 1:13:56 | $487.20 |
| 11/29/2012 1:13:57 | $487.20 |
| 11/30/2012 1:13:53 | $487.20 |
| 12/1/2012 1:13:54 | $492.60 |
+--------------------+---------+
What I am trying to do is get the average of the last 7, 14, 30 days.
I been playing with GoogleClock() function in order to filter the dates in column A but I can't seem to find the way to subtract TODAY - 7 days. I suspect FILTER will also help, but I am a little bit lost.
There are a few ways to go about this; one way is to return an array of values with a QUERY function (this assumes a header row in row 1, and you want the last 7 dates):
=QUERY(A2:B;"select B order by A desc limit 7";0)
and you can wrap this in whatever aggregation function you like:
=AVERAGE(QUERY(A2:B;"select B order by A desc limit 7";0))