I have this powershell script. The idea is to generate a report but the I need to split the string on "certificate.common_name" and put on separate column.
here's my script, and this works okay, however, I cannot assume the client code will always start in position 7.
$WriteStr = $order.certificate.common_name, $order.date_created, $order.certificate.days_remaining, $order.certificate.common_name.Substring(7,2), $Tag -join, ","
so basically, I want to get "1z" on this string(certificate.common_name) "*.test.1z.sample.com"
Related
I am trying to write a Powershell code to identify a string with a specific character from a filename from multiple files.
An example of a filename
20190902091031_202401192_50760_54206_6401.pdf
$Variable = $Filename.Substring(15,9)
Results:
202401192 (this is what I am after)
However in some instances the filename will be like below
20190902091031_20240119_50760_54206_6401.pdf
$Variable = $Filename.Substring(15,9)
Results:
20240119_ (this is NOT what I am after)
I am trying to find a code to identify the 9th character,
IF the 9th character = "_"
THEN Set
$Variable = $Filename.Substring(15,8)
Results:
20240119
All credit to TheMadTechnician who beat me to the punch with this answer.
To expand on the technique a bit, use the split method or operator to split a string every time a certain character shows up. Your data is separated by the underscore character, so is a perfect example of using this technique. By using either of the following:
$FileName.Split('_')
$FileName -split '_'
You can turn your long string into an array of shorter strings, each containing one of the parts of your original string. Since you want the 2nd one, you use the array descriptor [1] (0 is 1st) and you're done.
Good luck
I have a file with multiple blocks of test. FOR EACH block of test, I want to be able to extract what is in the square bracket, the line containing the FIRST instance of the word "area", and what is on the right of the square bracket. Everything will be a string. Essentially what I want to do is store each string into a variable in a hash so i can print it into a 3 column csv file.
Here's a sample of what the file looks like:
Student-[K-6] Exceptional in Math
/home/area/kinder/mathadvance.txt, 12
Students in grade K-12 shown to be exceptional in math.
Placed into special after school program.
See /home/area/overall/performance.txt, 200
Student-[Junior] Weak Performance
Students with overall weak performance.
Summer program services offered as shown in
"/home/area/services/summer.txt", 212
Student-[K-6] Physical Excerise Time Slots
/home/area/pe/schedule.txt, 303
Assigned time slots for PE based on student's grade level. Make reference to
/home/area/overall/classtimes.txt, 90
I want to to have a final csv file that looks like:
Grade,Topic,Path
K-6, Exceptional in Math, /home/area/kinder/mathadvance.txt, 12
K-6, Physical Exercise Time Slots, /home/area/pe/schedule.txt, 303
Junior, Weak Performance, "/home/area/services/summer.txt", 212
Since it's a csv file, I know it will also separate at the line number when exporting into excel but I'm fine with that.
I started off by putting the grade type into an array because I want to be able to add more strings to it for different grade levels.
My program looks like this so far:
#!/usr/bin/perl
use strict;
use warnings;
my #grades = ("K-6", "Junior", "Community-College", "PreK");
I was thinking that I will need to do some sort of system sed command to grab what is in the brackets and store it into a variable. Then I will grab everything to the right of the bracket on the line and store it into a variable. And then I will grep for a line containing "area" to get the path and I will store it as a string into a variable, put these in a hash, and then print into csv. I'm not sure if I'm thinking about this the right way. Also, I have NO IDEA how to do this for each BLOCK of text in the file. I need it by block because each block has its own corresponding grades, topics, and paths.
perl -000 -ne '($grade, $topic) = /\[(.*)\] (.*)/;
($path) = m{(.*/area/.*)};
print "$grade, $topic, $path\n"' -- file.txt
-000 turns on paragraph mode, -n won't read line by line, but paragraph by paragraph
/\[(.*)\] (.*)/ matches the square brackets and whatever follows them up to a newline. The inside of the square brackets and the following text are captured using the parentheses.
m{(.*/area/.*)} captures the line containing "area". It uses the m{} syntax instead of // so we don't have to backslash the slashes (avoiding so called "leaning toothpick syndrome")
If I run the below code, $SRN can be written as output or added to another variable, but trying to include either another variable or regular text causes it to be overwritten from the beginning of the line. I'm assuming it's something to do with how I'm assigning $autocode and $SRN initially but can't tell what it's trying to do.
# Load the property set to allow us to get to the email body.
$item.load($psPropertySet) # Load the data.
$bod = ($item.Body.Text -creplace '(?m)^\s*\r?\n','') -split "\n" # Get the body text, remove blank lines, split on line breaks to create an array (otherwise it is a single string).
$autocode = $bod[4].split('-')[2] # Get line 4 (should be Title), split on dash, look for 3rd element, this should contain our automation code.
$SRN = $bod[1] -replace 'ID: ','' # Get line 2 (should be ID), find and replace the preceding text.
# Skip processing if autocode does not match our list of handled ones.
if ($autocode -cin $autocodes)
{
write-host "$SRN $autocode"
write-host "$autocode $SRN"
write-host "$SRN test"
$var = "$SRN $autocode"
$var
}
The code results in this, you can see if $SRN isn't at the start of the line it is fine. Unsure where the extra spaces come from either:
KRNE8385
KRNE SR1788385
test8385
KRNE8385
I would expect to see this:
SR1788385 KRNE
KRNE SR1788385
SR1788385 test
SR1788385 KRNE
LotPings pointed me down the right path, both variables still had either "0D" or "\r" in them. My regex replace was only getting rid of them on blank lines, and I split the array on "\n" only. Changing line 3 in the original code to the below appears to have resolved the issue. First time seeing Format-Hex, but it appears to be excellent for troubleshooting such issues.
$bod = ($item.Body.Text -creplace '(?m)^\s*\r?\n','') -split "\r\n"
How do I take a substring where I don't know the length of the thing I want, but I know that the end of it is a CR/LF?
I'm communicating with a server trying to extract some information. The start point of the substring is well defined, but the end point can be variable. In other scripting languages, I'd expect there to be a find() command, but I haven't found one in PowerShell yet. Most articles and SE questions refer to Get-Content, substring, and Select-String, with the intent to replace a CRLF rather than just find it.
The device I am communicating with has a telnet-like command structure. It starts out with it's model as a prompt. You can give it commands and it responds. I'm trying to grab the hostname from it. This is what a prompt, command, and response look like in a terminal:
TSS-752>hostname
Host Name: ThisIsMyHostname
TSS-752>
I want to extract the hostname. I came across IndexOf(), which seems to work like the find command I am looking for. ":" is a good start point, and then I want to truncate it to the next CRLF.
NOTE: I have made my code work to my satisfaction, but in the interest of not receiving anymore downvotes (3 at the time of this writing) or getting banned again, I will not post the solution, nor delete the question. Those are taboo here. Taking into account the requests for more info from the comments has only earned me downvotes, so I think I'm just stuck in the SO-Catch-22.
You could probably have found the first 20 examples in c# outlining this exact same approach, but here goes with PowerShell examples
If you want to find the index at which CR/LF occurs, use String.IndexOf():
PS C:\> " `r`n".IndexOf("`r`n")
2
Use it to calculate the length parameter argument for String.Substring():
$String = " This phrase starts at index 4 ends at some point`r`nand then there's more"
# Define the start index
$Offset = 4
# Find the index of the end marker
$CRLFIndex = $string.IndexOf("`r`n")
# Check that the end marker was actually found
if($CRLFIndex -eq -1){
throw "CRLF not found in string"
}
# Calculate length based on end marker index - start index
$Length = $CRLFIndex - $Offset
# Generate substring
$Substring = $String.Substring($Offset,$Length)
I am generating CSV, and I want to store numbers without exponential format.
Please give me some suggestion.
I tried:
I used , perfectly,
I tried single quote before the large number, so I got as expected out in CSV, but number fore it showed single quote, if I click that number then number displaying perfectly.
I tried with delimeter, that is ' quote before one trailing slash.
So far no luck.
You might try using something like the Math::BigInt module:
use Math::BigInt;
my $num = new Math::BigInt(2);
$num=$num**128;
print "$num\n";
which will output:
340282366920938463463374607431768211456