Function currying in scala - scala

Question

I’m learning scala and read this concept called ‘currying’. I know it is used to divide the parameters in a function and pass them one by one. So from what I understood I tried creating a simple basic currying function below:
def add_num(a:Int,b:Int)(c:Int):Int={a+b+c}
add_num(10,20)
add_num(10)
But it gives me an error when I call the function with values 10 and 20. What i understood is it will remember the values and then I can pass the third value as 10 separately. I’m unable to understand this concept. Can someone help me in understanding this concept in most basic terms.
Error is missing argument list for method add_num. Unsupplied methods are only converted to functions when a function type is executed.

Answer 1

A curried function is applied to multiple argument lists, instead of just
one. An example of a non-curried function, which adds two Int parameters, x and y:
scala> def plainOldSum(x: Int, y: Int) = x + y
plainOldSum: (x: Int, y: Int)Int
scala> plainOldSum(1, 2)
res4: Int = 3
A similar function that’s curried:
scala> def curriedSum(x: Int)(y: Int) = x + y
curriedSum: (x: Int)(y: Int)Int
scala> curriedSum(1)(2)
res5: Int = 3
What's happening here is that when you invoke curriedSum, you actually
get two traditional function invocations back-to-back. The first function
invocation takes a single Int parameter named x, and returns a function
value for the second function. This second function takes the Int parameter
y.
Here's a function named first that does in spirit what the first traditional
function invocation of curriedSum would do:
scala> def first(x: Int) = (y: Int) => x + y
first: (x: Int)Int => Int
Applying the first function to 1—in other words, invoking the first function
and passing in 1—yields the second function:
scala> val second = first(1)
second: Int => Int = <function1>
Applying the second function to 2 yields the result:
scala> second(2)
res6: Int = 3
These first and second functions are just an illustration of the currying
process. They are not directly connected to the curriedSum function. Nevertheless,
there is a way to get an actual reference to curriedSum's "second"
function. You can use the placeholder notation to use curriedSum in a partially
applied function expression, like this:
scala> val onePlus = curriedSum(1)_
onePlus: Int => Int = <function1>
The underscore in curriedSum(1)_ is a placeholder for the second parameter
list.2 The result is a reference to a function which, when invoked, adds one
to its sole Int argument and returns the result:
scala> onePlus(2)
res7: Int = 3
And here's how you'd get a function that adds two to its sole Int argument:
scala> val twoPlus = curriedSum(2)_
twoPlus: Int => Int = <function1>
scala> twoPlus(2)
res8: Int = 4