I run a command to batch process image files using resmushit:
find /home/user/image/data -type f -print0 | xargs -n 1 -P 10 -0 resmushit -q 85 --preserve-filename
The command runs successfully and tells me the files were optimized and saved however when I check the files in the folder there is no change.
edit: it looks like the problem might be with resmushit. When I run it on pictures within my working directory it works. i.e
resmushit -q 85 --preserve-filename test.jpg
Is there a way to make xargs or a different command to run the command within each folder recursively?
I ended finding for directories and using a bash file so:
find /home/user/image/data -type d -print0 | xargs -n 1 -P 10 -0 bashscript
and the script is:
#!/bin/sh
cd "$*"
resmushit -q 85 --preserve-filename *
Related
I am trying to create a script which looks for x days old files that have a specific string in it, it then removes it and logs the file it has changed.
My way is probably not the best way, but I am new to this so looking for some help. I have got to a stage where the script works but it does not log the file name it has worked on
Working script is
find /home/test -mtime +5 -type f ! -size 0 | xargs grep -E -l '(abc_Pswd_[1-9])' | xargs -n1 sed -i '/abc_Pswd_[1-9].*/d'
I am trying to get the file name from 2nd part of the script I have tried few things
find /home/test -mtime +7 -type f ! -size 0 | xargs grep -E -l '(abc.1x.[1-9] )' > /home/test/tst.log| xargs -n1 sed -i '/abc_Pswd_[1-9].*/d'
This works in terms of logging the result but it exits with the error "sed: no input files"
I am able to get the file name of a last created/modified file in a current directory with this command:
ls -t | head -n1
then the obtained file name I use it with mv command to move it to a directory.
and I'm trying to do it like this:
mv $(ls -t | head -n1) directory/
But it doesn't move the file.
What am I doing wrong?
Maybe like this:
mv "$(ls -t | head -n1)" directory/
So I have a find command as below which finds the libclntsh.so.* files in a directory instantclient.
find instantclient -type f -name "*libclntsh\.so\.[0-9]*\.[0-9]*"
This results in for e.g.,
instantclient/libclntsh.so.11.1
How do I now ln within instantclient directory, ln -s libclntsh.so.11.1 libclntsh.so all with a find command in combination with exec
I should mention here that I DO NOT want to cd into instantclient.
And this is for Alpine Linux.
Use the -execdir option. As per manual:
-execdir command {} ;
Like -exec, but the specified command is run from the subdirectory containing the matched file, which is not normally the directory in which you started find. This a much more secure method for invoking commands, as it avoids race conditions during resolution of the paths to the matched files.
So your command will be:
find instantclient -type f -name "*libclntsh\.so\.[0-9]*\.[0-9]*" -execdir ln -s {} libclntsh.so \;
EDIT:
Another solution
find instantclient -type f -name "*libclntsh\.so\.[0-9]*\.[0-9]*" | xargs -I {} sh -c 'ln -s $(basename {}) instantclient/libclntsh.so'
How can i delete all the file that are ending with *0x0.jpg in CENTOS ? I need to delete multiple files nested into folders and subfolders
I assume you have a shell - try
find /mydirectory -type f -print | grep '0x0.jpg$' | xargs -n1 rm -f
There is probable a more elegant solution but that should work
However I would put an echo in before rm on the first run to ensure that the right files are going to be removed.
Ed Heal's answer works just fine but neither the grep nor xargs calls are necessary. The following should work just as well and be a good bit more efficient for large amounts of files.
find /mydirectory -name '*0x0.jpg' -type f -exec rm -rf () \+
How to Find binary files with or without executable permissions?
I am working on a BASH script that would list in a path:
* Shared Object files,
* scripts, executable files,
* static libraries
It should not display intermediate files like .o (object files).
You can use:
find . -type f -print0 | xargs -0 -n 10 file -i | grep "application/x-executable"
The file program reports file type based on contents, so
file /bin/* | awk -F: '/executable/{print $1}'
reports potentially/actually executable files in /bin.
This worked for me & thought of sharing...
find ./ -type f -name "*" -not -name "*.o" -exec sh -c '
case "$(head -n 1 "$1")" in
?ELF*) exit 0;;
MZ*) exit 0;;
#!*/ocamlrun*)exit0;;
esac
exit 1
' sh {} \; -print