Some of the documents in the collection contains Birthday field like given below -
------- birthday : "Friday, February 7, 2014 at 8:03:22 PM" ------
I want to convert to Date 'DD/MM/YYYY' Format.
using python can someone solve this
You want to use python's strptime, all you need to do is specify the structure of your string like so:
from datetime import datetime
new_date = datetime.strptime("Friday, February 7, 2014 at 8:03:22 PM", '%A, %B %d, %Y at %I:%M:%S %p').strftime('%d/%m/%Y')
Related
In my google sheet I have a column with dates but its in a text format. here an example what I have:
Oct 01, 2021
Dec 25, 2020
...
...
I want to convert it to a date format
01/10/2021
25/12/2020
....
I need to find the number of days from the dates in this column, by using "date in column" - now(). This does not work with the format "Oct 01, 2021" since its a text, and I am getting an error from Googlesheet.
Thanks in advance
IS
Try this formula in F2:
=ARRAYFORMULA(IFERROR(DATEDIF(
DATE(
RIGHT(E2:E,4),
MATCH(LEFT(E2:E,3),{"Jan";"Feb";"Mar";"Apr";"May";"Jun";"Jul";"Aug";"Sep";"Oct";"Nov";"Dec"},0),
MID(E2:E,5,2)),
NOW(), "D")))
Update
Revised the formula, which goes in F1 and fills the column, to:
={"Days Left";ARRAYFORMULA(
IFERROR(-1 * DATEDIF( DATE( RIGHT(E2:E,4), MATCH(LEFT(E2:E,3),{"Jan";"Feb";"Mar";"Apr";"May";"Jun";"Jul";"Aug";"Sep";"Oct";"Nov";"Dec"},0), MID(E2:E,5,2)), NOW(), "D"),
IFERROR(DATEDIF( NOW(),DATE( RIGHT(E2:E,4), MATCH(LEFT(E2:E,3),{"Jan";"Feb";"Mar";"Apr";"May";"Jun";"Jul";"Aug";"Sep";"Oct";"Nov";"Dec"},0), MID(E2:E,5,2)), "D"))))}
which reverses the date difference values. It also handles date differences for dates either in the future, or in the past.
Use the DATEVALUE() function on a date string, then use DATEDIF() to find the difference between two dates.
=DATEDIF(DATEVALUE("Oct 01, 2020"), DATEVALUE("Dec 25, 2020"), "D")
UPDATE: To find the date between today and a date string in another cell use this example:
=DATEDIF(DATEVALUE(A2), NOW(), "D")
If cell A2 contains string Oct 01, 2020, it will return 70 for today 2020-12-10
I've a Date Time string as 27th October 2020 07:30 PM.
And I want it in format yyyy-mm-dd 07:30 PM.
Is there a way to convert in flutter?
If you import the intl package from pub.dev you can format the date any way you like.
https://pub.dev/packages/intl
You can see here in the docs where all the available premade datetime formatting constructors are. https://pub.dev/documentation/intl/latest/intl/DateFormat-class.html
ICU Name Skeleton
-------- --------
DAY d
ABBR_WEEKDAY E
WEEKDAY EEEE
ABBR_STANDALONE_MONTH LLL
STANDALONE_MONTH LLLL
NUM_MONTH M
NUM_MONTH_DAY Md
NUM_MONTH_WEEKDAY_DAY MEd
ABBR_MONTH MMM
ABBR_MONTH_DAY MMMd
ABBR_MONTH_WEEKDAY_DAY MMMEd
MONTH MMMM
MONTH_DAY MMMMd
MONTH_WEEKDAY_DAY MMMMEEEEd
ABBR_QUARTER QQQ
QUARTER QQQQ
YEAR y
YEAR_NUM_MONTH yM
YEAR_NUM_MONTH_DAY yMd
YEAR_NUM_MONTH_WEEKDAY_DAY yMEd
YEAR_ABBR_MONTH yMMM
YEAR_ABBR_MONTH_DAY yMMMd
YEAR_ABBR_MONTH_WEEKDAY_DAY yMMMEd
YEAR_MONTH yMMMM
YEAR_MONTH_DAY yMMMMd
YEAR_MONTH_WEEKDAY_DAY yMMMMEEEEd
YEAR_ABBR_QUARTER yQQQ
YEAR_QUARTER yQQQQ
HOUR24 H
HOUR24_MINUTE Hm
HOUR24_MINUTE_SECOND Hms
HOUR j
HOUR_MINUTE jm
HOUR_MINUTE_SECOND jms
HOUR_MINUTE_GENERIC_TZ jmv
HOUR_MINUTE_TZ jmz
HOUR_GENERIC_TZ jv
HOUR_TZ jz
MINUTE m
MINUTE_SECOND ms
SECOND s
You can also make your own formatting however you like. For example, I have my formatting like so:
DateFormat.yMMMd().format(transactions[index].date),
Do you have a DateTime type or a String type ?
DateTime date = DateTime.now();
print(date.toString())
Cause I get what you want with that code.
console :
2020-10-23 15:36:11.846645
This is my date column which is on my dateframe:
data <- data.frame(year_month = c("2015-01-01", "2015-02-01", "2015-03-01", "2015-04-01", "2015-05-01", "2015-06-01"))
class(data$year_month)
[1] "factor"
I tried:
data$year_month1<-as.Date(as.factor(data$year_month), format="%b %Y")
I want:
" Jan 2015", "Feb 2015", "Mar 2015", "Apr 2015", "May 2015", "Jun 2105"
What happens:
My column on data$year_month1 comes Empty.
I tried quite a few solutions that I found here but the format does not change at all or it comes empty.
Help, please>
format(as.Date(data$year_month), format="%b %Y")
#first convert to Date, without as.factor (why did you do that?)
#then convert it to character as you want it, with format()
I'm trying to save a date to MongoDB from FullCalendar in my Grails application.
I'm trying to parse the string 2015-12-27T00:00:00.000Z into the below format:
def startDate = new Date().parse("YYYY-MM-dd'T'HH:mm:ss.SSSXXX",it.start)
def endDate = new Date().parse("YYYY-MM-dd'T'HH:mm:ss.SSSXXX",it.end)
But, weirdly when I print the formatted date, I get Sun Dec 28 05:30:00 IST 2014. I don't know what or how that particular date is picked.
You should use lowercase y for year. Uppercase Y is for "Week year".
new Date().parse("yyyy-MM-dd'T'HH:mm:ss.SSSXXX", "2015-12-27T00:00:00.000Z")
===> Sat Dec 26 19:00:00 EST 2015
import java.text.SimpleDateFormat;
println new SimpleDateFormat("yyyy-MM-dd HH:mm:ssX").parse("2018-07-30 09:57:15 +0800")
Convert Long date format to specific short date format.
I want to get the Date from Datepicker(Jcalander) , format to dd-mm-yyyy format and assign to String variable. I tried using codes shown below. But didnt get the date format i want.
SimpleDateFormat simpleFormat = (SimpleDateFormat) jCalendarCombo1.getDateFormat();
Date date = jCalendarCombo1.getDate();
System.out.println(date); // Prints Thu Mar 28 00:00:00 IST 2013
String s = simpleFormat.format(date);
System.out.println(s); // prints Thursday, March 28, 2013
System.out.println("Date SHORT format: " + DateFormat.getDateInstance(DateFormat.SHORT).format(date)); // prints 3/28/13
If you want a fixed, non locale dependent format, you can just create it yourself;
SimpleDateFormat shortformat = new SimpleDateFormat("dd-MM-yyyy");
String s = shortformat.format(date);
System.out.println(s); // Prints 29-03-2013