Input data
[
{
"_id" : ObjectId("xxx"),
"ParentNumber" : "12345",
"ChildNumber" : "A123"
},
{
"_id" : ObjectId("yyy"),
"ParentNumber" : "12345",
"ChildNumber" : "B123"
},
{
"_id" : ObjectId("zzz"),
"ParentNumber" : "6789",
"ChildNumber" : "C123"
}
]
Output Needed
[
{
"_id" : ObjectId("aaa"),
"ParentNumber" : "12345",
"Children":[
{ "ChildNumber" : "A123"},
{ "ChildNumber" : "B123"}
]
},
{
"_id" : ObjectId("bbb"),
"ParentNumber" : "6789",
"Children":[
{ "ChildNumber" : "C123"}
]
}
]
I tried the following but can't figure out how to group the parent numbers with children.
db.test.aggregate
(
[
{
$project:
{
"_id" : ObjectId(),
"ParentNumber" : "$ParentNumber",
"Children" : [
{
"ChildNumber" : "$ChildNumber"
}
]
}
}
]
)
I referred to the merge function in mongodb but I can't figure out how to compare one document to another based on a condition and return a result with array.
Thank you
This gives the desired result. Try this:
[{$group: {
_id: "$ParentNumber",
children: {
$push:{'ChildNumber':'$ChildNumber'}
},
}}, {$project: {
"ParentNumber":"$_id",
children:1
}}]
Check this PS: it will not show the objectId of the parent
db.collection.aggregate([
{
$group: {
_id: "$ParentNumber",
Children: {
$push: "$$ROOT"
},
},
},
{
"$project": {
_id: 0,
ParentNumber: "$_id",
Children: {
"ChildNumber": "$Children.ChildNumber"
}
}
}
])
Related
I want to group by and count follow_user.tags.tag_id per record, so no matter how many times the same tag_id show up on the same record, it only counts as 1.
My database structure looks like this:
{
"external_userid" : "EXID1",
"follow_user" : [
{
"userid" : "USERID1",
"tags" : [
{
"tag_id" : "TAG1"
}
]
},
{
"userid" : "USERID2",
"tags" : [
{
"tag_id" : "TAG1"
},
{
"tag_id" : "TAG2"
}
]
}
]
},
{
"external_userid" : "EXID2",
"follow_user" : [
{
"userid" : "USERID1",
"tags" : [
{
"tag_id" : "TAG2"
}
]
}
]
}
Here's my query:
[
{ "$unwind": "$follow_user" }, { "$unwind": "$follow_user.tags" },
{ "$group" : { "_id" : { "follow_user᎐tags᎐tag_id" : "$follow_user.tags.tag_id" }, "COUNT(_id)" : { "$sum" : 1 } } },
{ "$project" : { "total" : "$COUNT(_id)", "tagId" : "$_id.follow_user᎐tags᎐tag_id", "_id" : 0 } }
]
What I expected:
{
"total" : 1,
"tagId" : "TAG1"
},
{
"total" : 2,
"tagId" : "TAG2"
}
What I get:
{
"total" : 2,
"tagId" : "TAG1"
},
{
"total" : 2,
"tagId" : "TAG2"
}
$set - Create a new field follow_user_tags.
1.1. $setUnion - To distinct the value from the Result 1.1.1.
1.1.1. $reduce - Add the value of follow_user.tags.tag_id into array.
$unwind - Deconstruct follow_user_tags array field to multiple documents.
$group - Group by follow_user_tags and perform total count via $sum.
$project - Decorate output document.
db.collection.aggregate([
{
$set: {
follow_user_tags: {
$setUnion: {
"$reduce": {
"input": "$follow_user.tags",
"initialValue": [],
"in": {
"$concatArrays": [
"$$value",
"$$this.tag_id"
]
}
}
}
}
}
},
{
$unwind: "$follow_user_tags"
},
{
$group: {
_id: "$follow_user_tags",
total: {
$sum: 1
}
}
},
{
$project: {
_id: 0,
tagId: "$_id",
total: 1
}
}
])
Sample Mongo Playground
I am new in mongodb ,Please help me out
I have more than 500 students details like this..
{
"_id" : 7,
"name" : "Salena Olmos",
"scores" : [
{
"score" : 90.37826509157176,
"type" : "exam"
},
{
"score" : 42.48780666956811,
"type" : "quiz"
},
{
"score" : 96.52986171633331,
"type" : "homework"
}
]
},
/* 2 */
{
"_id" : 8,
"name" : "Daphne Zheng",
"scores" : [
{
"score" : 22.13583712862635,
"type" : "exam"
},
{
"score" : 14.63969941335069,
"type" : "quiz"
},
{
"score" : 75.94123677556644,
"type" : "homework"
}
]
}
Need to find one student details who got highest marks in "type" exam
Output as follows...
{
"_id" : 7,
"name" : "Salena Olmos",
"scores" : [
{
"score" : 90.37826509157176,
"type" : "exam"
},
{
"score" : 42.48780666956811,
"type" : "quiz"
},
{
"score" : 96.52986171633331,
"type" : "homework"
}
]
}
I need one student details from whole collection. The problem I am facing that need to search in embedded array "score" as well as "type".
Someone please help me
Try this
db.collection.aggregate([
{
$group: {
_id: "$_id",
scores: {
$first: "$scores"
},
data: {
$push: "$$ROOT"
}
}
},
{
$unwind: "$data"
},
{
$match: {
"data.scores.type": "exam"
}
},
{
$sort: {
"data.scores.score": -1
}
},
{
$project: {
_id: 1,
name: "$data.name",
scores: "$scores"
}
},
{
$limit: 1
}
])
Sample Playground
While this doesn't answer the question, it is related. This one filters out all the subdocuments which match the conditions "greater or equal 90" and type "exam"
db.collection.aggregate([
{
$match: {
"scores.score": {
$gte: 90
},
"scores.type": "exam"
}
},
{
$project: {
name: true,
list: {
$filter: {
input: "$scores",
as: "list",
cond: {
$and: [
{
$gt: [
"$$list.score",
90
]
},
{
$eq: [
"$$list.type",
"exam"
]
}
]
}
}
}
}
}
])
which returns
[
{
"_id": 7,
"list": [
{
"score": 90.37826509157176,
"type": "exam"
}
],
"name": "Salena Olmos"
}
]
https://mongoplayground.net/p/hYnVzZbuNFI
If you want the entire document, then add doc: "$$ROOT", to the projection.
my mongodb document set look like this
{
"_id" : ObjectId("59093a8e1104a53169"),
"createdAt" : ISODate("2017-05-03T02:03:58.249+0000"),
"phone" : "0000000000",
"email" : "abc#gmail.com",
"dob" : "12/26/1976",
"password" : "*******",
"stripeID" : "***",
"picture" : "htt://g",
"name" : {
"first" : "P",
"last" : "e"
},
"addresses" : [
{
"description" : "237 S ABCD, USA",
"_id" : ObjectId("59093bsaaudua"),
"loc" : [
-008.2478742,
124.0517012
]
},
{
"apartment" : "",
"description" : "787 S Defghsvd USA",
"_id" : ObjectId("5a26b77dfhgswj"),
"loc" : [
-18.01,
34.039058
]
},
{
"description" : "13210 hdsg sdjhf 90284, USA",
"_id" : ObjectId("5d2482basasas17be1"),
"loc" : [
-18.01,
-18.01
]
}
]
}
what i need to do is compare loc[0] with loc[1] if addresses exists in the document and know how many of them has this x === y. i don't know how to approach this. any help would be great. thanks in advance.
i.e. what i want is in all the documents if any user has equal loc array element's, then i want to find those documents. my query should return like:
{
"description" : "13210 hdsg sdjhf 90284, USA",
"_id" : ObjectId("5d2482basasas17be1"),
"loc" : [
-18.01,
-18.01
]
}
this should do the trick:
db.collection.aggregate([
{
$unwind: '$addresses'
},
{
$match: {
$expr: {
$eq: [
{ $arrayElemAt: ["$addresses.loc", 0] },
{ $arrayElemAt: ["$addresses.loc", 1] }
]
}
}
},
{
$replaceRoot: {
newRoot: "$addresses"
}
}
])
https://mongoplayground.net/p/YRnbPm-qfe6
if you also want the count, you can do this:
db.collection.aggregate([
{
$unwind: '$addresses'
},
{
$match: {
$expr: {
$eq: [
{ $arrayElemAt: ["$addresses.loc", 0] },
{ $arrayElemAt: ["$addresses.loc", 1] }
]
}
}
},
{
$replaceRoot: {
newRoot: "$addresses"
}
},
{
$group: {
_id: null,
count: {
$sum: 1
},
addresses: {
$push: '$$ROOT'
}
}
},
{
$project: {
_id: 0
}
}
])
https://mongoplayground.net/p/Kqi4J7f-4go
UserDetails
{
"_id" : "5c23536f807caa1bec00e79b",
"UID" : "1",
"name" : "A",
},
{
"_id" : "5c23536f807caa1bec00e78b",
"UID" : "2",
"name" : "B",
},
{
"_id" : "5c23536f807caa1bec00e90",
"UID" : "3",
"name" : "C"
}
UserProducts
{
"_id" : "5c23536f807caa1bec00e79c",
"UPID" : "100",
"UID" : "1",
"status" : "A"
},
{
"_id" : "5c23536f807caa1bec00e79c",
"UPID" : "200",
"UID" : "2",
"status" : "A"
},
{
"_id" : "5c23536f807caa1bec00e52c",
"UPID" : "300",
"UID" : "3",
"status" : "A"
}
Groups
{
"_id" : "5bb20d7556db6915846da55f",
"members" : {
"regularStudent" : [
"200" // UPID
],
}
},
{
"_id" : "5bb20d7556db69158468878",
"members" : {
"regularStudent" : {
"0" : "100" // UPID
}
}
}
Step 1
I have to take UID from UserDetails check with UserProducts then take UPID from UserProducts
Step 2
we have to check this UPID mapped to Groups collection or not ?.
members.regularStudent we are mapped UPID
Step 3
Suppose UPID not mapped means i want to print the UPID from from UserProducts
I have tried but couldn't complete this, kindly help me out on this.
Expected Output:
["300"]
Note: Expected Output is ["300"] , because UserProducts having UPID 100 & 200 but Groups collection mapped only 100& 200.
My Code
var queryResult = db.UserDetails.aggregate(
{
$lookup: {
from: "UserProducts",
localField: "UID",
foreignField: "UID",
as: "userProduct"
}
},
{ $unwind: "$userProduct" },
{ "$match": { "userProduct.status": "A" } },
{
"$project": { "_id" : 0, "userProduct.UPID" : 1 }
},
{
$group: {
_id: null,
userProductUPIDs: { $addToSet: "$userProduct.UPID" }
}
});
let userProductUPIDs = queryResult.toArray()[0].userProductUPIDs;
db.Groups.aggregate([
{
$unwind: "$members.regularStudent"
},
{
$group: {
_id: null,
UPIDs: { $addToSet: "$members.regularStudent" }
}
},
{
$project: {
members: {
$setDifference: [ userProductUPIDs , "$UPIDs" ]
},
_id : 0
}
}
])
My Output
{
"members" : [
"300",
"100"
]
}
You need to fix that second aggregation and get all UPIDs as an array. To achieve that you can use $cond and based on $type either return an array or use $objectToArray to run the conversion, try:
db.Groups.aggregate([
{
$project: {
students: {
$cond: [
{ $eq: [ { $type: "$members.regularStudent" }, "array" ] },
"$members.regularStudent",
{ $map: { input: { "$objectToArray": "$members.regularStudent" }, as: "x", in: "$$x.v" } }
]
}
}
},
{
$unwind: "$students"
},
{
$group: {
_id: null,
UPIDs: { $addToSet: "$students" }
}
},
{
$project: {
members: {
$setDifference: [ userProductUPIDs , "$UPIDs" ]
},
_id : 0
}
}
])
I have the following dataset:
{
"_id" : ObjectId("59668a22734d1d48cf34de08"),
"name" : "Nobody Cares",
"menus" : [
{
"_id" : "menu_123",
"name" : "Weekend Menu",
"description" : "A menu for the weekend",
"groups" : [
{
"name" : "Spirits",
"has_mixers" : true,
"sizes" : [
"Single",
"Double"
],
"categories" : [
{
"name" : "Vodka",
"description" : "Maybe not necessary?",
"drinks" : [
{
"_id" : "drink_123",
"name" : "Absolut",
"description" : "Fancy ass vodka",
"sizes" : [
{
"_id" : "size_123",
"size" : "Single",
"price" : 300
}
]
}
]
}
]
}
],
"mixers" : [
{
"_id" : "mixer_1",
"name" : "Coca Cola",
"price" : 150
},
{
"_id" : "mixer_2",
"name" : "Lemonade",
"price" : 120
}
]
}
]
}
And I'm attempting to retrieve a single drink from that dataset, I'm using the following aggregate query:
db.getCollection('places').aggregate([
{ $match : {"menus.groups.categories.drinks._id" : "drink_123"} },
{ $unwind: "$menus" },
{ $project: { "_id": 1, "menus": { "groups": { "categories": { "drinks": { "name": 1 } } } } } }
])
However, it's returning the full structure of the dataset along with the correct data.
So instead of:
{
"_id": "drink_123",
"name": "Absolut"
}
I get:
{
"_id": ObjectId("59668a22734d1d48cf34de08"),
"menus": {
"groups": {
"categories": {
"drinks": { "name": "Absolut" }
}
}
}
}
For example. Any ideas how to just retrieve the subdocument?
If you need to retain the deeply nested model then this call will produce the desired output:
db.getCollection('places').aggregate([
{ $match : {"menus.groups.categories.drinks._id" : "drink_123"} },
{ $project: {"_id": '$menus.groups.categories.drinks._id', name: '$menus.groups.categories.drinks.name'}},
{ $unwind: "$name" },
{ $unwind: "$name" },
{ $unwind: "$name" },
{ $unwind: "$name" },
{ $unwind: "$_id" },
{ $unwind: "$_id" },
{ $unwind: "$_id" },
{ $unwind: "$_id" }
])
The numerous unwinds are the result of the deep nesting of the drinks subdocuments.
Though, FWIW, this sort of query does perhaps suggest that the model isn't 'read friendly'.