I have the following dataset:
{
"_id" : ObjectId("59668a22734d1d48cf34de08"),
"name" : "Nobody Cares",
"menus" : [
{
"_id" : "menu_123",
"name" : "Weekend Menu",
"description" : "A menu for the weekend",
"groups" : [
{
"name" : "Spirits",
"has_mixers" : true,
"sizes" : [
"Single",
"Double"
],
"categories" : [
{
"name" : "Vodka",
"description" : "Maybe not necessary?",
"drinks" : [
{
"_id" : "drink_123",
"name" : "Absolut",
"description" : "Fancy ass vodka",
"sizes" : [
{
"_id" : "size_123",
"size" : "Single",
"price" : 300
}
]
}
]
}
]
}
],
"mixers" : [
{
"_id" : "mixer_1",
"name" : "Coca Cola",
"price" : 150
},
{
"_id" : "mixer_2",
"name" : "Lemonade",
"price" : 120
}
]
}
]
}
And I'm attempting to retrieve a single drink from that dataset, I'm using the following aggregate query:
db.getCollection('places').aggregate([
{ $match : {"menus.groups.categories.drinks._id" : "drink_123"} },
{ $unwind: "$menus" },
{ $project: { "_id": 1, "menus": { "groups": { "categories": { "drinks": { "name": 1 } } } } } }
])
However, it's returning the full structure of the dataset along with the correct data.
So instead of:
{
"_id": "drink_123",
"name": "Absolut"
}
I get:
{
"_id": ObjectId("59668a22734d1d48cf34de08"),
"menus": {
"groups": {
"categories": {
"drinks": { "name": "Absolut" }
}
}
}
}
For example. Any ideas how to just retrieve the subdocument?
If you need to retain the deeply nested model then this call will produce the desired output:
db.getCollection('places').aggregate([
{ $match : {"menus.groups.categories.drinks._id" : "drink_123"} },
{ $project: {"_id": '$menus.groups.categories.drinks._id', name: '$menus.groups.categories.drinks.name'}},
{ $unwind: "$name" },
{ $unwind: "$name" },
{ $unwind: "$name" },
{ $unwind: "$name" },
{ $unwind: "$_id" },
{ $unwind: "$_id" },
{ $unwind: "$_id" },
{ $unwind: "$_id" }
])
The numerous unwinds are the result of the deep nesting of the drinks subdocuments.
Though, FWIW, this sort of query does perhaps suggest that the model isn't 'read friendly'.
Related
I am new in mongodb ,Please help me out
I have more than 500 students details like this..
{
"_id" : 7,
"name" : "Salena Olmos",
"scores" : [
{
"score" : 90.37826509157176,
"type" : "exam"
},
{
"score" : 42.48780666956811,
"type" : "quiz"
},
{
"score" : 96.52986171633331,
"type" : "homework"
}
]
},
/* 2 */
{
"_id" : 8,
"name" : "Daphne Zheng",
"scores" : [
{
"score" : 22.13583712862635,
"type" : "exam"
},
{
"score" : 14.63969941335069,
"type" : "quiz"
},
{
"score" : 75.94123677556644,
"type" : "homework"
}
]
}
Need to find one student details who got highest marks in "type" exam
Output as follows...
{
"_id" : 7,
"name" : "Salena Olmos",
"scores" : [
{
"score" : 90.37826509157176,
"type" : "exam"
},
{
"score" : 42.48780666956811,
"type" : "quiz"
},
{
"score" : 96.52986171633331,
"type" : "homework"
}
]
}
I need one student details from whole collection. The problem I am facing that need to search in embedded array "score" as well as "type".
Someone please help me
Try this
db.collection.aggregate([
{
$group: {
_id: "$_id",
scores: {
$first: "$scores"
},
data: {
$push: "$$ROOT"
}
}
},
{
$unwind: "$data"
},
{
$match: {
"data.scores.type": "exam"
}
},
{
$sort: {
"data.scores.score": -1
}
},
{
$project: {
_id: 1,
name: "$data.name",
scores: "$scores"
}
},
{
$limit: 1
}
])
Sample Playground
While this doesn't answer the question, it is related. This one filters out all the subdocuments which match the conditions "greater or equal 90" and type "exam"
db.collection.aggregate([
{
$match: {
"scores.score": {
$gte: 90
},
"scores.type": "exam"
}
},
{
$project: {
name: true,
list: {
$filter: {
input: "$scores",
as: "list",
cond: {
$and: [
{
$gt: [
"$$list.score",
90
]
},
{
$eq: [
"$$list.type",
"exam"
]
}
]
}
}
}
}
}
])
which returns
[
{
"_id": 7,
"list": [
{
"score": 90.37826509157176,
"type": "exam"
}
],
"name": "Salena Olmos"
}
]
https://mongoplayground.net/p/hYnVzZbuNFI
If you want the entire document, then add doc: "$$ROOT", to the projection.
my mongodb document set look like this
{
"_id" : ObjectId("59093a8e1104a53169"),
"createdAt" : ISODate("2017-05-03T02:03:58.249+0000"),
"phone" : "0000000000",
"email" : "abc#gmail.com",
"dob" : "12/26/1976",
"password" : "*******",
"stripeID" : "***",
"picture" : "htt://g",
"name" : {
"first" : "P",
"last" : "e"
},
"addresses" : [
{
"description" : "237 S ABCD, USA",
"_id" : ObjectId("59093bsaaudua"),
"loc" : [
-008.2478742,
124.0517012
]
},
{
"apartment" : "",
"description" : "787 S Defghsvd USA",
"_id" : ObjectId("5a26b77dfhgswj"),
"loc" : [
-18.01,
34.039058
]
},
{
"description" : "13210 hdsg sdjhf 90284, USA",
"_id" : ObjectId("5d2482basasas17be1"),
"loc" : [
-18.01,
-18.01
]
}
]
}
what i need to do is compare loc[0] with loc[1] if addresses exists in the document and know how many of them has this x === y. i don't know how to approach this. any help would be great. thanks in advance.
i.e. what i want is in all the documents if any user has equal loc array element's, then i want to find those documents. my query should return like:
{
"description" : "13210 hdsg sdjhf 90284, USA",
"_id" : ObjectId("5d2482basasas17be1"),
"loc" : [
-18.01,
-18.01
]
}
this should do the trick:
db.collection.aggregate([
{
$unwind: '$addresses'
},
{
$match: {
$expr: {
$eq: [
{ $arrayElemAt: ["$addresses.loc", 0] },
{ $arrayElemAt: ["$addresses.loc", 1] }
]
}
}
},
{
$replaceRoot: {
newRoot: "$addresses"
}
}
])
https://mongoplayground.net/p/YRnbPm-qfe6
if you also want the count, you can do this:
db.collection.aggregate([
{
$unwind: '$addresses'
},
{
$match: {
$expr: {
$eq: [
{ $arrayElemAt: ["$addresses.loc", 0] },
{ $arrayElemAt: ["$addresses.loc", 1] }
]
}
}
},
{
$replaceRoot: {
newRoot: "$addresses"
}
},
{
$group: {
_id: null,
count: {
$sum: 1
},
addresses: {
$push: '$$ROOT'
}
}
},
{
$project: {
_id: 0
}
}
])
https://mongoplayground.net/p/Kqi4J7f-4go
I'm new to MongoDB.
In the find query I'm using the following structure:
db.report.find({'accountList.transactionList.description': /.*aear.*/i})
However, accountList contains multiple values, and so does transaction list, the exact query would be:
db.report.find({'accountList[0].transactionList[4].description': /.*aear.*/i})
The problem is that accountList has multiple accounts, and only one of them has the value 'aear' in the description. When I'm executing the query it returns me both accounts, and I'd like to keep only the account where aear is in its description. Also, this MUST be iterable over many files, since it file has different transactionLists, therefore in some documents aear will not appear at all, and in others it might appear multiple types, always in different positions. I believe something must be done in projection, but setting it like this doesn't work:
.projection({"accountList.id":1,"accountList.transactionList.description":1})
Here's the output:
"accountList" : [
{
"id" : "1",
"type" : "xD",
"currency" : "EUR",
"transactionList" : [
{
"onDate" : ISODate("2019-08-25T21:00:00.000-03:00"),
"description" : "aear"
},
{
"onDate" : ISODate("2019-08-25T21:00:00.000-03:00"),
"description" : "bb"
},
{
"onDate" : ISODate("2019-08-25T21:00:00.000-03:00"),
"description" : "cc"
}
]
},
{
"id" : "2",
"type" : "xD",
"currency" : "USD",
"transactionList" : [
{
"onDate" : ISODate("2019-08-15T21:00:00.000-03:00"),
"description" : "aa",
},
{
"onDate" : ISODate("2019-08-14T21:00:00.000-03:00"),
"description" : "ee"
}
]
}
]
And I'd like something like this, where I''m only getting the path to where the condition is met:
"accountList" : [
{
"id" : "1",
"type" : "xD",
"currency" : "EUR",
"transactionList" : [
{
"onDate" : ISODate("2019-08-25T21:00:00.000-03:00"),
"description" : "aear"
},
To accomplish that you need to use aggregate. I believe this code will work in your case:
db.report.aggregate([
{ "$match": { "accountList.transactionList.description": { $regex: "aear", $options: "i"} } },
{ "$unwind": "$accountList" },
{ "$unwind": "$accountList.transactionList" },
{ "$match": { "accountList.transactionList.description": { $regex: "aear", $options: "i"} } },
{ "$group": {
"_id": {
"_id": "$_id",
"accountListId": "$accountList.id",
"accountListType": "$accountList.type",
"accountListCurrency": "$accountList.currency",
},
"transactionList": { "$push": "$accountList.transactionList" }
}},
{ "$group": {
"_id": "$_id._id",
"accountList": {
"$push": {
"id": "$_id.accountListId",
"type": "$_id.accountListType",
"currency": "$_id.accountListCurrency",
"transactionList": "$transactionList"
}
}
}}
])
Updating my answer as this question got updated with new required o/p :
Answer for New Question :
If you've only one transaction matching to given criteria /.*aear.*/i, let's say description is unique across accountList array of report document(exact for provided sample):
db.report.aggregate([{
$match: {
'accountList.transactionList.description': /.*aear.*/i
}
},{ $unwind: '$accountList' },{ $unwind: '$accountList.transactionList' },{$match :{ 'accountList.transactionList.description': /.*aear.*/i}}, { $project: { 'accountList': 1, _id: 0 } }])
But, if you've multiple descriptions (across multiple objects in accountsList array of a report document) matches to given criteria in accountList :
db.report.aggregate([{
$match: {
'accountList.transactionList.description': /.*aear.*/i
}
}, { $unwind: '$accountList' }, { $unwind: '$accountList.transactionList' }, { $match: { 'accountList.transactionList.description': /.*aear.*/i } },
{ $group: { _id: '$_id', accountList: { $push: '$accountList' }, data: { $first: '$$ROOT' } } }
, { $addFields: { 'data.accountList': '$accountList' } }, { $replaceRoot: { 'newRoot': '$data' } }, { $project: { 'accountList': 1, _id: 0 } }
])
Output :
/* 1 */
{
"accountList" : [
{
"id" : "1100",
"type" : "xD",
"currency" : "EUR",
"transactionList" : {
"onDate" : ISODate("2019-08-26T00:00:00.000Z"),
"description" : "aear"
}
},
{
"id" : "1200",
"type" : "xD",
"currency" : "USD",
"transactionList" : {
"onDate" : ISODate("2019-08-16T00:00:00.000Z"),
"description" : "aear"
}
}
]
}
/* 2 */
{
"accountList" : [
{
"id" : "1",
"type" : "xD",
"currency" : "EUR",
"transactionList" : {
"onDate" : ISODate("2019-08-26T00:00:00.000Z"),
"description" : "aear"
}
}
]
}
If in case you've multiple matching descriptions in transaction array & also in other objects of accounts array (this will work for all above scenarios as well but it might not be needed as per requirement, it can be bulky, Check document#3 in Output for clarification) :
db.report.aggregate([
{ "$match": { "accountList.transactionList.description": /.*aear.*/i } },
{ "$unwind": "$accountList" },
{ "$unwind": "$accountList.transactionList" },
{ "$match": { "accountList.transactionList.description": /.*aear.*/i } },
{
"$group": {
"_id": {
"docId": "$_id",
"accountsListObjId": "$accountList.id"
},
"transactionList": { "$push": "$accountList.transactionList" },
"accountList": { "$first": '$accountList' }
}
}
, { $addFields: { 'accountList.transactionList': '$transactionList' } },
{
"$group": {
"_id": "$_id.docId",
"accountList": { $push: '$accountList' }
}
}, { $project: { 'accountList': 1, _id: 0 } }
])
Output :
/* 1 */
{
"accountList" : [
{
"id" : "1100",
"type" : "xD",
"currency" : "EUR",
"transactionList" : [
{
"onDate" : ISODate("2019-08-26T00:00:00.000Z"),
"description" : "aear"
}
]
},
{
"id" : "1200",
"type" : "xD",
"currency" : "USD",
"transactionList" : [
{
"onDate" : ISODate("2019-08-16T00:00:00.000Z"),
"description" : "aear"
}
]
}
]
}
/* 2 */
{
"accountList" : [
{
"id" : "1",
"type" : "xD",
"currency" : "EUR",
"transactionList" : [
{
"onDate" : ISODate("2019-08-26T00:00:00.000Z"),
"description" : "aear"
}
]
}
]
}
/* 3 */
{
"accountList" : [
{
"id" : "00",
"type" : "xD",
"currency" : "EUR",
"transactionList" : [
{
"onDate" : ISODate("2019-08-26T00:00:00.000Z"),
"description" : "aear"
},
{
"onDate" : ISODate("2019-08-26T00:00:00.000Z"),
"description" : "aear"
}
]
},
{
"id" : "100",
"type" : "xD",
"currency" : "USD",
"transactionList" : [
{
"onDate" : ISODate("2019-08-16T00:00:00.000Z"),
"description" : "aear"
}
]
}
]
}
If you're looking for exact text, you can do this as well(cause regex is not allowed in cond) :
db.report.aggregate([
{
$match: {
'accountList.transactionList.description': 'aear'
}
}, { $unwind: '$accountList' }, {
$addFields: {
'accountList.transactionList': {
$filter: {
input: '$accountList.transactionList',
as: 'eachTransaction',
cond: { $eq: ["$$eachTransaction.description", 'aear'] }
}
}
}
}, { $match: { 'accountList.transactionList': { $ne: [] } } }, { $group: { _id: '$_id', accountList: { $push: '$accountList' }, data: { $first: '$$ROOT' } } }
, { $addFields: { 'data.accountList': '$accountList' } }, { $replaceRoot: { 'newRoot': '$data' } }, { $project: { 'accountList': 1, _id: 0 } }])
Output : Same as above.
Answer for Old Question :
Ok you've two options here, Please try these :
If you've only one object in accountList which does matches with the given filter then you can simply do this:
db.report.find({'accountList.transactionList.description': /.*aear.*/i}, {'accountList.$': 1})
Output :
/* 1 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df0c7"),
"accountList" : [
{
"id" : "4474",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
/* 2 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df0d7"),
"accountList" : [
{
"id" : "4400",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
/* 3 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df077"),
"accountList" : [
{
"id" : "0000",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
/* 4 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df1c7"),
"accountList" : [
{
"id" : "0101",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
Downside of above .find () query is it would get only first matching object in accountList, If you've multiple matching objects for given filter in accountList then you need to use aggregation (this aggregation query can be used for earlier scenario as well, Please check output for diff) :
db.report.aggregate([
{
$match: {
"accountList.transactionList.description": /.*aear.*/i
}
},
{ $unwind: "$accountList" },
{
$match: {
"accountList.transactionList.description": /.*aear.*/i
}
}, { $group: { _id: '$_id', accountList: { $push: '$accountList' }, doc: { $first: '$$ROOT' } } }, { $addFields: { 'doc.accountList': '$accountList' } },
{ $replaceRoot: { 'newRoot': '$doc' } }
])
Output :
// This first object is best example where you need aggregation
/* 1 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df1c7"),
"accountList" : [
{
"id" : "0101",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
},
{
"id" : "1111",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
/* 2 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df0d7"),
"accountList" : [
{
"id" : "4400",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
/* 3 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df077"),
"accountList" : [
{
"id" : "0000",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
/* 4 */
{
"_id" : ObjectId("5d6435145a0d22d3c86df0c7"),
"accountList" : [
{
"id" : "4474",
"transactionList" : [
{
"description" : "aear"
},
{
"description" : "koe"
}
]
}
]
}
Try this query:
db.report.find({'accountList[0].transactionList[4].description': { $regex: /.*aear.*/i} })
OR - Which will return only the first matching document:
db.report.find({'accountList[0].transactionList[4].description': /.*aear.*/i}).limit(1)
UserDetails
{
"_id" : "5c23536f807caa1bec00e79b",
"UID" : "1",
"name" : "A",
},
{
"_id" : "5c23536f807caa1bec00e78b",
"UID" : "2",
"name" : "B",
},
{
"_id" : "5c23536f807caa1bec00e90",
"UID" : "3",
"name" : "C"
}
UserProducts
{
"_id" : "5c23536f807caa1bec00e79c",
"UPID" : "100",
"UID" : "1",
"status" : "A"
},
{
"_id" : "5c23536f807caa1bec00e79c",
"UPID" : "200",
"UID" : "2",
"status" : "A"
},
{
"_id" : "5c23536f807caa1bec00e52c",
"UPID" : "300",
"UID" : "3",
"status" : "A"
}
Groups
{
"_id" : "5bb20d7556db6915846da55f",
"members" : {
"regularStudent" : [
"200" // UPID
],
}
},
{
"_id" : "5bb20d7556db69158468878",
"members" : {
"regularStudent" : {
"0" : "100" // UPID
}
}
}
Step 1
I have to take UID from UserDetails check with UserProducts then take UPID from UserProducts
Step 2
we have to check this UPID mapped to Groups collection or not ?.
members.regularStudent we are mapped UPID
Step 3
Suppose UPID not mapped means i want to print the UPID from from UserProducts
I have tried but couldn't complete this, kindly help me out on this.
Expected Output:
["300"]
Note: Expected Output is ["300"] , because UserProducts having UPID 100 & 200 but Groups collection mapped only 100& 200.
My Code
var queryResult = db.UserDetails.aggregate(
{
$lookup: {
from: "UserProducts",
localField: "UID",
foreignField: "UID",
as: "userProduct"
}
},
{ $unwind: "$userProduct" },
{ "$match": { "userProduct.status": "A" } },
{
"$project": { "_id" : 0, "userProduct.UPID" : 1 }
},
{
$group: {
_id: null,
userProductUPIDs: { $addToSet: "$userProduct.UPID" }
}
});
let userProductUPIDs = queryResult.toArray()[0].userProductUPIDs;
db.Groups.aggregate([
{
$unwind: "$members.regularStudent"
},
{
$group: {
_id: null,
UPIDs: { $addToSet: "$members.regularStudent" }
}
},
{
$project: {
members: {
$setDifference: [ userProductUPIDs , "$UPIDs" ]
},
_id : 0
}
}
])
My Output
{
"members" : [
"300",
"100"
]
}
You need to fix that second aggregation and get all UPIDs as an array. To achieve that you can use $cond and based on $type either return an array or use $objectToArray to run the conversion, try:
db.Groups.aggregate([
{
$project: {
students: {
$cond: [
{ $eq: [ { $type: "$members.regularStudent" }, "array" ] },
"$members.regularStudent",
{ $map: { input: { "$objectToArray": "$members.regularStudent" }, as: "x", in: "$$x.v" } }
]
}
}
},
{
$unwind: "$students"
},
{
$group: {
_id: null,
UPIDs: { $addToSet: "$students" }
}
},
{
$project: {
members: {
$setDifference: [ userProductUPIDs , "$UPIDs" ]
},
_id : 0
}
}
])
I have the following collection:
{
"_id" : ObjectId("56f036e032ea1f27634e2f1f"),
"mockups" : [
{
"versions" : [
{
"title" : "About us 1",
"timestamp" : "2016-01-10T12:31:23.104Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17922")
},
{
"title" : "About us 3",
"timestamp" : "2016-03-11T15:34:11.108Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17923")
},
{
"title" : "About us 2",
"timestamp" : "2016-02-21T16:15:23.101Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17924")
}
],
"_id" : ObjectId("56ec65a9041c87dd6bd17921")
},
{
"versions" : [
{
"title" : "Contact us 1",
"timestamp" : "2016-04-10T11:34:33.103Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17924")
},
{
"title" : "Contact us 3",
"timestamp" : "2016-06-21T16:13:26.101Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17926")
},
{
"title" : "Contact us 2",
"timestamp" : "2016-05-11T13:34:13.106Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17925")
}
],
"_id" : ObjectId("56ec65a9041c87dd6bd17929")
}
]
}
I want to return all mockups with the latest version that would result in something similar to the following:
{
"_id" : ObjectId("56f036e032ea1f27634e2f1f"),
"mockups" : [
{
"versions" : [
{
"title" : "About us 3",
"timestamp" : "2016-03-11T15:34:11.108Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17923")
}
],
"_id" : ObjectId("56ec65a9041c87dd6bd17921")
},
{
"versions" : [
{
"title" : "Contact us 3",
"timestamp" : "2016-06-21T16:13:26.101Z",
"_id" : ObjectId("56ec65a9041c87dd6bd17926")
}
],
"_id" : ObjectId("56ec65a9041c87dd6bd17929")
}
]
}
I have been playing with aggregate, sort, and limit, but I am extremely new to mongodb. I am currently left with having to just return everything and using something like lodash to get the version I need.
Is there a way to query this properly so that I am getting the results I need from the mongo as opposed to using something like lodash after I get the results back?
For a solution using aggregation, would suggest running the following pipeline to get the desired output:
db.collection.aggregate([
{ "$unwind": "$mockups" },
{ "$unwind": "$mockups.versions" },
{ "$sort": { "mockups.versions.timestamp": -1 } },
{
"$group": {
"_id": "$mockups._id",
"title": { "$first": "$mockups.versions.title" },
"timestamp": { "$first": "$mockups.versions.timestamp" },
"id" : { "$first": "$mockups.versions._id" },
"main_id": { "$first": "$_id" }
}
},
{
"$group": {
"_id": "$_id",
"versions": {
"$push": {
"title": "$title",
"timestamp": "$timestamp",
"_id": "$id"
}
},
"main_id": { "$first": "$main_id" }
}
},
{
"$group": {
"_id": "$main_id",
"mockups": {
"$push": {
"versions": "$versions",
"_id": "$_id"
}
}
}
}
])
I didn't actually understood what is the range for "latest" version ,however I think you can use some thing like this:
example:
db.collection.find({
versions.timestamp: {
$gte: ISODate("2010-04-29T00:00:00.000Z"),
$lt: ISODate("2010-05-01T00:00:00.000Z")
}
})
if you want to use the aggregate you can put this condition in the $match .