I have a CTE that i want to grab data from, but i want different types of data with the same limit from the same CTE according to different rules.
Example: fruit_cte -> (id::integer, name::text, q1::boolean, q2::boolean)
I could do something like:
SELECT * FROM (SELECT 1 as query_num, * FROM fruit_cte WHERE q1 ORDER BY name LIMIT 100) as ABC
UNION ALL
SELECT * FROM (SELECT 2 as query_num, * FROM fruit_cte WHERE q2 ORDER BY name LIMIT 100) as ABC
UNION ALL
SELECT * FROM (SELECT -1 as query_num, * FROM fruit_cte WHERE NOT q1 AND NOT q2 ORDER BY name LIMIT 100) as ABC
But this is very costly and would be nice to tie this up into 1 select. Is this even possible?
The last select is a nice to have to get data that doesn't meet the requirements but possible to go without.
PG version 11+
You could get it all without the CTE, by using window functions instead.
SELECT type, id, name, q1, q2
FROM (
SELECT
CASE WHEN q1 THEN 1 WHEN q2 THEN 2 ELSE -1 END AS type,
ROW_NUMBER() OVER (
PARTITION BY CASE WHEN q1 THEN 1 WHEN q2 THEN 2 ELSE -1 END
ORDER BY NAME
) AS row_number,
id,
name,
q1,
q2
FROM ...
)
WHERE row_number <= 100
The row_number() will count, sorted by name, and keep a separate tally for every type
Related
How can the results of a "group by" count be normalized by the count's sum?
For example, given:
User Rating (1-5)
----------------------
1 3
1 4
1 2
3 5
4 3
3 2
2 3
The result will be:
User Count Percentage
---------------------------
1 3 .42 (=3/7)
2 1 .14 (=1/7)
3 2 .28 (...)
4 1 .14
So for each user the number of ratings they provided is given as the percentage of the total ratings provided by everyone.
SELECT DISTINCT ON (user) user, count(*) OVER (PARTITION BY user) AS cnt,
count(*) OVER (PARTITION BY user) / count(*) OVER () AS percentage;
The count(*) OVER (PARTITION BY user) is a so-called window function. Window functions let you perform some operation over a "window" created by some "partition" which is here made over the user id. In plain and simple English: the partitioned count(*) is calculated for each distinct user value, so in effect it counts the number of rows for each user value.
Without using a windowing function or variables, you will need to cross join a grouped subquery on a second "maxed" subquery then select again to return a subset you can work with.
SELECT
B.UserID,
B.UserCount,
A.CountAll
FROM
(
SELECT
CountAll=SUM(UserCount)
FROM
(
SELECT
UserCount=COUNT(*)
FROM
MyTable
GROUP BY
UserID
) AS A
)AS C
CROSS JOIN(
SELECT
UserID,
UserCount=COUNT(*)
FROM
MyTable
GROUP BY
UserID
)AS B
Given the following data:
sequence | amount
1 100000
1 20000
2 10000
2 10000
I'd like to write a sql query that gives me the sum of the current sequence, plus the sum of the previous sequence. Like so:
sequence | current | previous
1 120000 0
2 20000 120000
I know the solution likely involves windowing functions but I'm not too sure how to implement it without subqueries.
SQL Fiddle
select
seq,
amount,
lag(amount::int, 1, 0) over(order by seq) as previous
from (
select seq, sum(amount) as amount
from sa
group by seq
) s
order by seq
If your sequence is "sequencial" without holes you can simply do:
SELECT t1.sequence,
SUM(t1.amount),
(SELECT SUM(t2.amount) from mytable t2 WHERE t2.sequence = t1.sequence - 1)
FROM mytable t1
GROUP BY t1.sequence
ORDER BY t1.sequence
Otherwise, instead of t2.sequence = t1.sequence - 1 you could do:
SELECT t1.sequence,
SUM(t1.amount),
(SELECT SUM(t2.amount)
from mytable t2
WHERE t2.sequence = (SELECT MAX(t3.sequence)
FROM mytable t3
WHERE t3.sequence < t1.sequence))
FROM mytable t1
GROUP BY t1.sequence
ORDER BY t1.sequence;
You can see both approaches in this fiddle
I have a table with the following data
Bldg Suit SQFT Date
1 1 1,000 9/24/2012
1 1 1,500 12/31/2011
1 2 800 8/31/2012
1 2 500 10/1/2005
I want to write a query that will sum the max date for each suit record, so the desired result would be 1,800, and must be in one cell/row. This will ultimately be part of subquery, I am just not getting what I expect with the queries I have writtren so far.
Thanks in advance.
You can use the following (See SQL Fiddle with Demo):
select sum(t1.sqft) Total
from yourtable t1
inner join
(
select max(dt) mxdt, suit, bldg
from yourtable
group by suit, bldg
) t2
on t1.dt = t2.mxdt
and t1.bldg = t2.bldg
and t1.suit = t2.suit
; With Data As
(
Select Bldg, Suit, SQFT, Row_Number() Over (Partition By Bldg, Suit Order By Date DESC) As RowID
From YourTableNameHere
)
Select Bldg, Sum(SQFT) As TotalSQFT
From Data
Where RowId = 1
Group By Bldg
I am wondering if there is some easy way, a function, or other method to return data from a query with the following results.
I have a SQL Express DB 2008 R2, a table that contains numerical data in a given column, say col T.
I am given a value X in code and would like to return up to three records. The record where col T equals my value X, and the record before and after, and nothing else. The sort is done on col T. The record before may be beginning of file and therefore not exist, likewise, if X equals the last record then the record after would be non existent, end of file/table.
The value of X may not exist in the table.
This I think is similar to get a range of results in numerical order.
Any help or direction in solving this would be greatly appreciated.
Thanks again,
It might not be the most optimal solution, but:
SELECT T
FROM theTable
WHERE T = X
UNION ALL
SELECT *
FROM
(
SELECT TOP 1 T
FROM theTable
WHERE T > X
ORDER BY T
) blah
UNION ALL
SELECT *
FROM
(
SELECT TOP 1 T
FROM theTable
WHERE T < X
ORDER BY T DESC
) blah2
DECLARE #x int = 100
;WITH t as
(
select ROW_NUMBER() OVER (ORDER BY T ASC) AS row_nm,*
from YourTable
)
, t1 as
(
select *
from t
WHERE T = #x
)
select *
from t
CROSS APPLY t1
WHERE t.row_nm BETWEEN t1.row_nm -1 and t1.row_nm + 1
Wonder if someone could give me a quick hand. I have 2 select queries (as shown below) and I want to compare the results of both and only return the result that has the most recent date.
So say I have the following 2 results from the queries:-
--------- ---------- ----------------------- --------------- ------ --
COMPANY A EMPLOYEE A 2007-10-16 17:10:21.000 E-mail 6D29D6D5 SYSTEM 1
COMPANY A EMPLOYEE A 2007-10-15 17:10:21.000 E-mail 6D29D6D5 SYSTEM 1
I only want to return the result with the latest date (so the first one). I thought about putting the results into a temporary table and then querying that but just wondering if there's a simpler, more efficient way?
SELECT * FROM (
SELECT fc.accountidname, fc.owneridname, fap.actualend, fap.activitytypecodename, fap.createdby, fap.createdbyname,
ROW_NUMBER() OVER (PARTITION BY fc.accountidname ORDER BY fap.actualend DESC) AS RN
FROM FilteredContact fc
INNER JOIN FilteredActivityPointer fap ON fc.parentcustomerid = fap.regardingobjectid
WHERE fc.statecodename = 'Active'
AND fap.ownerid = '0F995BDC'
AND fap.createdon < getdate()
) tmp WHERE RN = 1
SELECT * FROM (
SELECT fa.name, fa.owneridname, fa.new_technicalaccountmanageridname, fa.new_customerid, fa.new_riskstatusname,
fa.new_numberofopencases, fa.new_numberofurgentopencases, fap.actualend, fap.activitytypecodename, fap.createdby, fap.createdbyname,
ROW_NUMBER() OVER (PARTITION BY fa.name ORDER BY fap.actualend DESC) AS RN
FROM FilteredAccount fa
INNER JOIN FilteredActivityPointer fap ON fa.accountid = fap.regardingobjectid
WHERE fa.statecodename = 'Active'
AND fap.ownerid = '0F995BDC'
AND fap.createdon < getdate()
) tmp2 WHERE RN = 1
if the tables have the same structure (column count and column types to match), then you could just union the results of the two queries, then order by the date desc and then select the top 1.
select top 1 * from
(
-- your first query
union all
-- your second query.
) T
order by YourDateColumn1 desc
You should GROUP BY and use MAX(createdon)