I want to use order by clause in my last sql query and I have more than 3 union queries. I do not want to order the top 2 union query but I want to use order by clause in my last sql statement.
Currently, getting error
ORDER BY items must appear in the select list if the statement contains a UNION, INTERSECT or EXCEPT operator.
select 'Total Number of pat' Name, convert(varchar(20), count(id)) Number from table2 where id = 5
union
select 'Total Number of Doc' Name, convert(varchar(20), count(id)) Number from table3
union
select x.usertype, count(distinct userid) cnt
from [dbo].table1 t
cross apply (values (
case when t.userid like '%[0-9][0-9[0-9]' then 'transition' else 'non transition' end,
t.userid
)) x(usertype, userid)
where t.date >= dateadd(day,-7, getdate())
group by x.usertype
order by usertype desc
order by is sorting the result of the unions all together however you can introduce a orderIndex column for imlementing the right ordering.
Here the sample:
I've tried to build sample data in the following code.
create table table1(
userid varchar(100),
usertype varchar(100),
date date
)
insert into table1(userid, date) values ('Einsmayr', '2020-10-27')
insert into table1(userid, date) values ('Eins123', '2020-10-27')
insert into table1(userid, date) values ('Einschmid', '2020-10-27')
insert into table1(userid, date) values ('Einshuber', '2020-10-27')
insert into table1(userid, date) values ('Einsreitmayr', '2020-10-27')
create table table2 (
Name varchar(100),
id int
)
insert into table2(Name, id) values('Zweirich', 5)
insert into table2(Name, id) values('Zweifel', 6)
create table table3 (
Name varchar(100),
id int
)
insert into table3(Name, id) values('Dreisinger', 17)
insert into table3(Name, id) values('Dreibert', 18)
This allows the following queries:
select usertype, Number
from (
select 'Total Number of pat' usertype, convert(varchar(20), count(id)) Number, 1 orderIndex from table2 where id = 5
union
select 'Total Number of Doc' Name, convert(varchar(20), count(id)) Number, 2 orderIndex from table3
union
select usertype, count(distinct userid) Number, 3 orderIndex
from (
select userid, case when userid like '%[0-9][0-9[0-9]' then 'transition' else 'non transition' end usertype
from table1
where date >= dateadd(day,-7, getdate())
) x
group by x.usertype
) y
order by y.orderIndex, y.usertype
Find the solution here: https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=ac396c48f5dbcb4a53ad40fac70e9236
Related
I want to get the min(id) from a table based on the date inserted, as not always the min(id) will be the same as the id of the min(date_inserted). I can do it with subquery but I need to do it without the subquery as it is part of a bigger SQL.
This is what I got so far:
create table tbl(
id int ,
userid int,
dt timestamp)
SELECT id
FROM (
-- if I could do min(id order by dt) that would solve the issue
select id, row_number() over(partition by userid order by dt) row_number
from table
where userid = :userid
) withs
WHERE row_number=1
BEGIN;
CREATE temp TABLE teacher (
name text,
salary numeric
);
INSERT INTO teacher
VALUES ('b1', 90000);
INSERT INTO teacher
VALUES ('f1', 87000);
INSERT INTO teacher
VALUES ('a', 65000),
('b', 90000),
('c', 40000),
('d', 95000),
('e', 60000),
('f', 87000);
COMMIT;
query
with recursive cte as(
(select name, salary, 1 as rn
from teacher order by salary desc limit 1)
union all
select l.* from cte c cross join lateral(
select name, salary, rn + 1 from teacher t
where t.salary < c.salary
order by salary desc
limit 1
) l
)
table cte order by salary desc;
If all salary are distinct,then above mentioned query can imitate as rank/row_number.
I am wondering how to use recursive query to replicate/imitate dense_rank.
related post: https://dba.stackexchange.com/questions/286627/get-top-two-rows-per-group-efficiently
I have a table Orders, it has the following columns:
OrderID, ClientID, BankNumber, Adres, Name;
I want to write a query that gives me this result: distinct clientid name and adres on one row with all the belonging orders and corespondating bankaccount numbers on one row: This is my example.
ClientID Adres Name order1 Banknumber Order2 Banknumber order3 Banknumber
First you cannot query something and come up with a results set with infinite number of columns, but you could combine orders and show them in 1 column.
if you are on SQL Azure or SQL2017 you can also use STRING_AGG like this:
select customer.Id, customer.Name, orderSummary.orderData
(select STRING_AGG(orderID+'-'+banknumber+', ') as orderData from orders where customerId = customer.Id) orderSummary
from Customers as customer
You can look at this post for more answers
How to concatenate text from multiple rows into a single text string in SQL server?
And Subquery from Microsoft:
https://technet.microsoft.com/en-us/library/ms189575(v=sql.105).aspx
here is a working sample.
Hope it works for you.
You need to build the Order1, order2, order3...and BankNumber1,BankNumber2...dynamically. I have hard coded in my example
drop table #t1
create table #t1(OrderID Int, ClientID int, BankNumber varchar(50), [Address] varchar(50), Name varchar(50))
insert into #t1
select 1,11,'111','xyz1','xyz'
union all
select 2,22,'112','xyz2','xyzz'
union all
select 3,33,'113','xyz3','xyzzz'
union all
select 100,11,'111','xyz1','xyz'
union all
select 200,22,'112','xyz2','xyzz'
union all
select 300,33,'113','xyz3','xyzzz'
;with cte as
(
select OrderID,ClientID,BankNumber,Address,Name,ROW_NUMBER()over (partition by clientid order by orderid asc) RN
from #t1
)
select ClientID
,max([Order 1]) Order1
,max([Order 2]) Order2
,max([BankNumber 1]) BankNumber1
,max([BankNumber 2]) BankNumber2
from
(
select ClientID,Address,Name,OrderID,BankNumber,'Order '+cast(rn as varchar(10)) OrderSeq
,'BankNumber '+cast(rn as varchar(10)) BankNumberSeq
from cte
) as ST
pivot(max(OrderID) for OrderSeq in ([Order 1],[Order 2])) as pt1
pivot(max(BankNumber) for BankNumberSeq in ([BankNumber 1],[BankNumber 2])) as pt2
group by ClientID
I need to write a T-SQL group by query for a table with multiple dates and seq columns:
DROP TABLE #temp
CREATE TABLE #temp(
id char(1),
dt DateTime,
seq int)
Insert into #temp values('A','2015-03-31 10:00:00',1)
Insert into #temp values('A','2015-08-31 10:00:00',2)
Insert into #temp values('A','2015-03-31 10:00:00',5)
Insert into #temp values('B','2015-09-01 10:00:00',1)
Insert into #temp values('B','2015-09-01 10:00:00',2)
I want the results to contains only the items A,B with their latest date and the corresponding seq number, like:
id MaxDate CorrespondentSeq
A 2015-08-31 10:00:00.000 2
B 2015-09-01 10:00:00.000 2
I am trying with (the obviously wrong!):
select id, max(dt) as MaxDate, max(seq) as CorrespondentSeq
from #temp
group by id
which returns:
id MaxDate CorrespondentSeq
A 2015-08-31 10:00:00.000 5 <-- 5 is wrong
B 2015-09-01 10:00:00.000 2
How can I achieve that?
EDIT
The dt datetime column has duplicated values (exactly same date!)
I am using SQL Server 2005
You can use a ranking subselect to get only the highest ranked entries for an id:
select id, dt, seq
from (
select id, dt, seq, rank() over (partition by id order by dt desc, seq desc) as r
from #temp
) ranked
where r=1;
SELECT ID, DT, SEQ
FROM (
SELECT ID, DT, SEQ, Row_Number()
OVER (PARTITION BY id ORDER BY dt DESC, seq DESC) AS row_number
FROM temp
) cte
WHERE row_number = 1;
Demo : http://www.sqlfiddle.com/#!3/3e3d5/5
With trial and errors maybe I have found a solution, but I'm not completely sure this is correct:
select A.id, B.dt, max(B.seq)
from (select id, max(dt) as maxDt
from #temp
group by id) as A
inner join #temp as B on A.id = B.id AND A.maxDt = B.dt
group by A.id, B.dt
Select id, dt, seq
From #temp t
where dt = (Select Max(dt) from #temp
Where id = t.Id)
If there are duplicate rows, then you also need to specify what the query processor should use to determine which of the duplicates to return. Say you want the lowest value of seq,
Then you could write:
Select id, dt, seq
From #temp t
where dt = (Select Max(dt) from #temp
Where id = t.Id)
and seq = (Select Min(Seq) from #temp
where id = t.Id
and dt = t.dt)
I am trying to find duplicate rows in my DB, like this:
SELECT email, COUNT(emailid) AS NumOccurrences
FROM users
GROUP BY emailid HAVING ( COUNT(emailid) > 1 )
This returns the emailid and the number of matches found. Now what I want do is compare the ID column to another table I have and set a column there with the count.
The other table has a column named duplicates, which should contain the amount of duplicates from the select. So let's say we have 3 rows with the same emailid. The duplicates column has a "3" in all 3 rows. What I want is a "2" in the first 2 and nothing or 0 in the last of the 3 matching ID rows.
Is this possible?
Update:
I managed to have a temporary table now, which looks like this:
mailid | rowcount | AmountOfDups
643921 | 1 | 3
643921 | 2 | 3
643921 | 3 | 3
Now, how could I decide that only the first 2 should be updated (by mailid) in the other table? The other table has mailid as well.
SELECT ...
ROW_NUMBER() OVER (PARTITION BY email ORDER BY emailid DESC) AS RN
FROM ...
...is a great starting point for such a problem. Never underestimate the power of ROW_NUMBER()!
Using Sql Server 2005+ you could try something like (full example)
DECLARE #Table TABLE(
ID INT IDENTITY(1,1),
Email VARCHAR(20)
)
INSERT INTO #Table (Email) SELECT 'a'
INSERT INTO #Table (Email) SELECT 'b'
INSERT INTO #Table (Email) SELECT 'c'
INSERT INTO #Table (Email) SELECT 'a'
INSERT INTO #Table (Email) SELECT 'b'
INSERT INTO #Table (Email) SELECT 'a'
; WITH Duplicates AS (
SELECT Email,
COUNT(ID) TotalDuplicates
FROM #Table
GROUP BY Email
HAVING COUNT(ID) > 1
)
, Counts AS (
SELECT t.ID,
ROW_NUMBER() OVER(PARTITION BY t.Email ORDER BY t.ID) EmailID,
d.TotalDuplicates
FROM #Table t INNER JOIN
Duplicates d ON t.Email = d.Email
)
SELECT ID,
CASE
WHEN EmailID = TotalDuplicates
THEN 0
ELSE TotalDuplicates - 1
END Dups
FROM Counts