Mongodb Query to get only documents in specific days - mongodb

Question

In my mongodb table, I have 2 (relevant for this Q) columns: service, timestamp.
I want to query only rows with service=liveness and that those with timestamp of 12th Novermber 2020.
How can I do it, if timestamp field is of type Number (UNIX epoch number)..?
This is my query currently:
{ service: "liveness" }.
This is how the timestamp column looks like:

Answer 1

To query by two fields you only need this syntax:
db.collection.find({
"field1": yourField1Value,
"field2": yourField2Value
So, if your date is a Number instead of a Date you can try this query:
db.collection.find({
"service": "liveness",
"timestamp": 1600768437934
})
And should works. Example here.
Now, if the problem is parse 12th November 2020 to UNIX timestamp, then the easiest way is convert first the date in your app language.
Edit:
Also, I don't know if I've missunderstood your question but, here is another query.
db.collection.aggregate([
{
"$match": {
"service": "liveness",
}
},
{
"$project": {
"timestamp": {
"$toDate": "$timestamp"
}
}
},
{
"$match": {
"timestamp": {
"$gt": ISODate("1990-01-01"),
"$lt": ISODate("2060-01-01")
}
}
}
])
This query first match all documents with service as liveness, so the next stage is faster. Into $project the timestamp is parsed to Date so you can match again with your date.
Using $gt and $lt you can search by a whole day.
And also, if you can get the days into UNIX timestamp you can do this:
db.collection.find({
"service": "liveness",
"timestamp": {
"$gte": yourDay,
"$lt": nextrDay
}
})
Using $gte and $lt you ensure the query will find all values in the day.