Trying to convert the number numeric value in this string to a percent. Is there any easy way to do this in powershell?
"Percentage of records ","0.02"
So, the output would look like :
Percentage of records , 2%
Thanks in advance for any suggestions you can provide.
Yes, you can convert the string to a float data type (single, double, decimal), and then convert it back using a format string, like so:
"Percentage of records ", ([double]'0.02').ToString('P0')
And if you want it to output in a single line, you could use:
"Percentage of records: $(([double]'0.02').ToString('P0'))"
Explanation:
Convert your string to a float datatype: [double]'0.02'
Convert that float back into a string: .ToString()
But we want to format it as a percentage, so we supply P0 as a parameter.
i. P - means to format the value as a percentage, this performs the N * 100 operation for you and then adds on the percent sign
ii. 0 - controls the number of decimal places to show. In your case, you want to show zero decimal places.
Note: The percentage format string will round your value to the nearest decimal that you specify.
Example:
0.021.ToString('P0')
# returns 2%
0.025.ToString('P0')
# returns 3%
As #mklement0 pointed out in the comments. I hadn't considered that your sample may be a single string, like:
'"Percentage of records ","0.02"'
I assumed it was two strings, which you separated with a comma.
In the event it is a single string, then you need to extract the number to use it. Once you have isolated the number, then you can use my advice above:
$yourString = '"Percentage of records ","0.02"'
# probably the more "proper" way
$pctValue = ($yourString -split ',' -replace '"')[1]
# or
# a hacky way I just thought of that happens to work in this scenario
$pctValue = (iex $yourString)[1]
Explanation of first example:
-split ',' - Take the string, and break it out into multiple strings, separating them by comma
-replace '"','' - Replace all instances of " with blank. The second parameter is optional since you are removing. Could be written as -replace '"'
(...)[1] - This is saying to take the SECOND string that it returned (starts at zero). In this case it would be your 0.02 value.
Explanation of second example (this is a bit of a hack, but thought it would be fun to include anyway):
iex - alias for Invoke-Expression - it's telling powershell to run whatever is inside of the string verbatim. So it's the equivalent of typing "Percentage of records ","0.02" into powershell and hitting enter. Which in PowerShell terms, that is the equivalent of passing it a list of strings.
Use -f (format operator) in powerhsell for build your string :
"Percentage of records, {0:0%} " -f 0.02
or in percentage :
"Percentage of records, {0:P0} " -f 0.02
Related
I am creating a script converting a csv file in an another format.
To do so, i need my numbers to have a fixed format to respect column size : 00000000000000000,00 (20 characters, 2 digits after comma)
I have tried to format the number with -f and the method $value.toString("#################.##") without success
Here is an example Input :
4000000
45817,43
400000
570425,02
15864155,69
1068635,69
128586256,9
8901900,04
29393,88
126858346,88
1190011,46
2358411,95
139594,82
13929,74
11516,85
55742,78
96722,57
21408,86
717,01
54930,49
391,13
2118,64
Any hints are welcome :)
Thank you !
tl;dr:
Use 0 instead of # in the format string:
PS> $value = 128586256.9; $value.ToString('00000000000000000000.00')
00000000000128586256.90
Note:
Alternatively, you could construct the format string as an expression:
$value.ToString('0' * 20 + '.00')
The resulting string reflects the current culture with respect to the decimal mark; e.g., with fr-FR (French) in effect, , rather than . would be used; you can pass a specific [cultureinfo] object as the second argument to control what culture is used for formatting; see the docs.
As in your question, I'm assuming that $value already contains a number, which implies that you've already converted the CSV column values - which are invariably strings - to numbers.
To convert a string culture-sensitively to a number, use [double]::Parse('1,2'), for instance (this method too has an overload that allows specifying what culture to use).
Caveat: By contrast, a PowerShell cast (e.g. [double] '1.2') is by design always culture-invariant and only recognizes . as the decimal mark, irrespective of the culture currently in effect.
zerocukor287 has provided the crucial pointer:
To unconditionally represent a digit in a formatted string and default to 0 in the absence of an available digit, use 0, the zero placeholder in a .NET custom numeric format string
By contrast, #, the digit placeholder, represents only digits actually present in the input number.
To illustrate the difference:
PS> (9.1).ToString('.##')
9.1 # only 1 decimal place available, nothing is output for the missing 2nd
PS> (9.1).ToString('.00')
9.10 # only 1 decimal place available, 0 is output for the missing 2nd
Since your input uses commas as decimal point, you can split on the comma and format the whole number and the decimal part separately.
Something like this:
$csv = #'
Item;Price
Item1;4000000
Item2;45817,43
Item3;400000
Item4;570425,02
Item5;15864155,69
Item6;1068635,69
Item7;128586256,9
Item8;8901900,04
Item9;29393,88
Item10;126858346,88
Item11;1190011,46
Item12;2358411,95
Item13;139594,82
Item14;13929,74
Item15;11516,85
Item16;55742,78
Item17;96722,57
Item18;21408,86
Item19;717,01
Item20;54930,49
Item21;391,13
Item22;2118,64
'# | ConvertFrom-Csv -Delimiter ';'
foreach ($item in $csv) {
$num,$dec = $item.Price -split ','
$item.Price = '{0:D20},{1:D2}' -f [int64]$num, [int]$dec
}
# show on screen
$csv
# output to (new) csv file
$csv | Export-Csv -Path 'D:\Test\formatted.csv' -Delimiter ';'
Output in screen:
Item Price
---- -----
Item1 00000000000004000000,00
Item2 00000000000000045817,43
Item3 00000000000000400000,00
Item4 00000000000000570425,02
Item5 00000000000015864155,69
Item6 00000000000001068635,69
Item7 00000000000128586256,09
Item8 00000000000008901900,04
Item9 00000000000000029393,88
Item10 00000000000126858346,88
Item11 00000000000001190011,46
Item12 00000000000002358411,95
Item13 00000000000000139594,82
Item14 00000000000000013929,74
Item15 00000000000000011516,85
Item16 00000000000000055742,78
Item17 00000000000000096722,57
Item18 00000000000000021408,86
Item19 00000000000000000717,01
Item20 00000000000000054930,49
Item21 00000000000000000391,13
Item22 00000000000000002118,64
I do things like this all the time, usually for generating computernames. That custom numeric format string reference will come in handy. If you want a literal period, you have to backslash it.
1..5 | % tostring 00000000000000000000.00
00000000000000000001.00
00000000000000000002.00
00000000000000000003.00
00000000000000000004.00
00000000000000000005.00
Adding commas to long numbers:
psdrive c | % free | % tostring '0,0' # or '#,#'
18,272,501,760
"Per mille" character ‰ :
.00354 | % tostring '#0.##‰'
3.54‰
I have the following Powershell variable
$var = "AB-0045"
I would like to increase the number in the string to become "AB-0046".
I can do:
$newNumber = [int]$var.Substring($var.length -4,4) + 1
Which will give me the desired number 46, but then I have to append that 46 as a string to a new string "AB-00".
Is there a better way to do that?
Now that you have the integer, you'll have to convert back to string formatted in the way you'd like and concatenate.
I'd recommend adding to "AB-" rather than "AB-00" in case your number goes over 100.
To pad leading zeros, you can use the -f operator.
e.g. "{0:d4}" -f 45
You'll still need to get the integer first (45 in the example) from your original string.
I tested with regex class Replace() method and string class Split() method with string formatter. Split() seems faster provided your string is always in the same format. The Replace() method does not care what happens before the last 4 numbers:
# Replace Method
[regex]::Replace($var,'\d{4}$',{([int]$args[0].Value+1).ToString('0000')})
# Split method
$a,[int]$b = $var.split('-'); "{0}-{1:0000}" -f $a,++$b
How can I count the scale of a given decimal in Powershell?
$a = 0.0001
$b = 0.000001
Casting $a to a string and returning $a.Length gives a result of 6...I need 4.
I thought there'd be a decimal or math function but I haven't found it and messing with a string seems inelegant.
There's probably a better mathematic way but I'd find the decimal places like this:
$a = 0.0001
$decimalPlaces = ("$a" -split '\.')[-1].TrimEnd('0').Length
Basically, split the string on the . character and get the length of the last string in the array. Wrapping $a in double-quotes implicitly calls .ToString() with an invariant culture (you could expand this as $a.ToString([CultureInfo]::InvariantCulture)), making this method to determine the number of decimal places culture-invariant.
.TrimEnd('0') is used in case $a were sourced from a string, not a proper number type, it's possible that trailing zeroes could be included that should not count as decimal places. However, if you want the scale and not just the used decimal places, leave .TrimEnd('0') off like so:
$decimalPlaces = ("$a" -split '\.')[-1].Length
mclayton helpfully linked to this answer to a related C# question in a comment, and the solution there can indeed be adapted to PowerShell, if working with or conversion to type [decimal] is acceptable:
# Define $a as a [decimal] literal (suffix 'd')
# This internally records the scale (number of decimal places) as specified.
$a = 0.0001d
# [decimal]::GetBits() allows extraction of the scale from the
# the internal representation:
[decimal]::GetBits($a)[-1] -shr 16 -band 0xFF # -> 4, the number of decimal places
The System.Decimal.GetBits method returns an array of internal bit fields whose last element contains the scale in bits 16 - 23 (8 bits, even though the max. scale allowed is 28), which is what the above extracts.
Note: A PowerShell number literal that is a fractional number without the d suffix - e.g., 0.0001 becomes a [double] instance, i.e. a double-precision binary floating-point number.
PowerShell automatically converts [double] to [decimal] values on demand, but do note that there can be rounding errors due to the differing internal representations, and that [double] can store larger numbers than [decimal] can (although not accurately).
A [decimal] literal - one with suffix d (note that C# uses suffix m) - is parsed with a scale exactly as specified, so that applying the above to 0.000d and 0.010d yields 3 in both cases; that is, the trailing zeros are meaningful.
This does not apply if you (implicitly) convert from [double] instances such as 0.000 and 0.010, for which the above yields 0 and 2, respectively.
A string-based solution:
To offer a more concise (also culture-invariant) alternative to Bender The Greatest's helpful answer:
$a = 0.0001
("$a" -replace '.+\.').Length # -> 4, the number of decimal places
Caveat: This solution relies on the default string representation of a [double] number, which need not match the original input format; for instance, .0100, when stringified later, becomes '0.01'; however, as discussed above, you can preserve trailing zeros if you start with a [decimal] literal: .0100d stringifies to '0.0100' (input number of decimals preserved).
"$a", uses an expandable string (PowerShell's string interpolation) to create a culture-invariant string representation of the number so as to ensure that the string representation uses . as the decimal mark.
In effect, PowerShell calls $a.ToString([cultureinfo]::InvariantCulture) behind the scenes.[1].
By contrast, .ToString() (argument-less) applies the rules of the current culture, and in some cultures it is , - not . - that is used as the decimal mark.
Caveat: If you use just $a as the LHS of -replace, $a is implicitly stringified, in which case you - curiously - get culture-sensitive behavior, as with .ToString() - see this GitHub issue.
-replace '.+\.' effectively removes all characters up to and including the decimal point from the input string, and .Length counts the characters in the resulting string - the number of decimal places.
[1] Note that casts from strings in PowerShell too use the invariant culture (effectively, ::Parse($value, [cultureinfo]::InvariantCulture) is called) so that in order to parse a a culture-local string representation you'll need to use the ::Parse() method explicitly; e.g., [double]::Parse('1,2'), not [double] '1,2'.
We need to convert a plain number to a currency value. However, nothing we find seems to work.
We tried the basic code below, but that returns a value of $123,456.00 when it should be $1,234.56.
$rawNumber = 123456
$newNumber = 0
$newNumber = "{0:c}" -f $rawNumber
We tried different iterations of "{0:c}" (c2, c1,etc), but it always returns a number, but just adding zeroes on to the end.
We tried converting the number to a string and inserting the decimal, commas and dollar sign, but we're dealing with numbers that can be as short as two or as long as ten, so it becomes something of a beast to try and plan for every possible combination.
Are we missing something obvious to easily convert numbers to a currency value?
Thank you for any help you can provide.
If you have a subdivision of the primary unit of a currency, you need to divide the input value to get the number of primary units, in this case:
$dollars = $rawNumber / 100
$formattedString = '{0:C}' -f $dollars
Beware that the resulting formatted string will depend on the current locale. You can pass a [cultureinfo] object to the ToString() method of the target object instead if you want a specific locale enforced. Here shown with en-US, de-DE and da-DK:
PS C:\> 'en-US','de-DE','da-DK' |ForEach-Object { $dollars.ToString('C',[cultureinfo]$_) }
$1,234.56
1.234,56 €
1.234,56 kr.
You can format the input using {0:C2} the 2 in C2 is the amount of decimal places.
Example:
$rawNumber = 123456
$newNumber = 0
$newNumber = "{0:C2}" -f $rawNumber
I need to add decimal to an integer.
Eg:
Amount = 12345
The output should be
Amount = 123.45
Could someone help me how to achieve this using power shell
Always use a comma if you're looking to format a long string, adding a decimal point implies the number has a decimal component.
(12345).ToString("N0")
12,345
the N0 is a default formatting string which here gives the comma separated string.
if you're looking to fix badly stored decimal numbers or something where your question is actually what you're looking for, dividing by 100 will work for your needs.
12345 / 100
123.45
if you need a more code based solution which handles trailing zeroes or something you could use this:
$num = 12345
$numstr = "$num"
$splitat = $numstr.Length - 2
$before = $numstr.Substring(0,$SplitAt)
$after = $numstr.Substring($SplitAt)
"$($before).$($after)"
or this
"12345" -replace '(\d*)(\d{2})','$1.$2'