mongodb aggregate function and return the result based on the condition - mongodb

Question

I had two tables vendors and vendorgs.
My condition below,
1.vendors table vendorOrgId === vendorgs table _id
2.status === "active" in vendorgs table
if above condition are satisficed the group the vendors by vendorgs table category.
Is possible to do that
vendors table
const vendors = [{
"name" : "Alfred",
"location" : "FH",
"vendorOrgId" : "1"
},
{
"name" : "Alfred",
"location" : "ADH",
"vendorOrgId" : "2"
},
{
"name" : "Alfred",
"location" : "AFF",
"vendorOrgId" : "41"
}]
vendorgs table
const vendorgs = [
{
"orgName" : "star super market",
"_id" : "1",
"category" : "grocery",
"status" : "active"
},
{
"orgName" : "L.f super market",
"_id" : "41",
"category" : "grocery",
"status" : "active"
},
{
"orgName" : "Fresh mart",
"_id" : "2",
"category" : "Milk",
"status" : "active"
}
]
My Query
db.getCollection('vendors').aggregate([{
"$lookup": {
"from": "vendorgs",
"localField": "vendorOrgId",
"foreignField": "_id",
"as": "data"
},
},
{
"$group": {
"_id": "$data.category",
"category":{"$push":"$data"},
}
},
{
"$match": {
"category.status":true
}
}
])
above query returning empty array
expected result
{
"grocery": [{
"name": "Alfred",
"location": "FH",
"vendorOrgId": "1"
},
{
"name": "Alfred",
"location": "AFF",
"vendorOrgId": "41"
}
],
"milk": [{
"name": "Alfred",
"location": "ADH",
"vendorOrgId": "2"
}]
}
Thanks!!

Answer 1

finally found answer at myself . should write match before group by
db.getCollection('vendors').aggregate([{
"$lookup": {
"from": "vendorgs",
"localField": "vendorOrgId",
"foreignField": "_id",
"as": "data"
},
},
{
"$match": {
"status":"active"
}
},
{
"$group": {
"_id": "$data.category",
"category":{"$push":"$data"},
}
}
])