I understand that Jekyll auto-extracts the date from a post's filename.
How to the same with an image's filename please?
Let's assume the following format of the image filenames:
2020-12-10_A_the_rest_of_the_filename_of_the_image.jpg
2020-12-10_B_the_rest_of_the_filename_of_the_image.jpg
2020-12-10_C_the_rest_of_the_filename_of_the_image.jpg
2021-01-04_A_the_rest_of_the_filename_of_the_image.jpg
2021-01-04_B_the_rest_of_the_filename_of_the_image.jpg
Thus it only includes YYYY-MM-DD and then some further sorting/index information (such as a, b, c, ...), and then the rest of the image's filename.
The main goal is to be able to extract the date as follows:
10 Dec, 2020
10 Dec, 2020
10 Dec, 2020
04 Jan, 2021
04 Jan, 2021
To get the date part out of you file name, you could either use the slice or split filter.
If you do use the split filter, you will want to use the first filter, in order to take the first element of the created array.
To get the date format you want, you can just use the date filter.
With slice:
{{ "2020-12-10_A_the_rest_of_the_filename_of_the_image.jpg" | slice: 0, 10 | date: "%d %b, %Y" }}
With split:
{{ "2020-12-10_A_the_rest_of_the_filename_of_the_image.jpg" | split: "_" | first | date: "%d %b, %Y" }}
Those both results in: 10 Dec, 2020
Additionally, you might want to read the Ruby documentation about the date format available at: https://ruby-doc.org/stdlib-2.4.1/libdoc/time/rdoc/Time.html#method-c-strptime
Related
I would like to be able to convert
"Tue Sep 01 00:00:26 +00:00 2020"
into a date type in Julia using the built in Date function.
I only need the year, month, and date.
This is tricky because you have a time zone here hence you need to use TimeZones.jl
using TimeZones, Dates
df = Dates.DateFormat("e u d H:M:S z y");
d = ZonedDateTime("Tue Sep 01 00:00:26 +00:00 2020", df)
Let se what we got:
julia> d = ZonedDateTime("Tue Sep 01 00:00:26 +00:00 2020", df)
2020-09-01T00:00:26+00:00
julia> Date(d)
2020-09-01
For more try typying ?DateFormat in the console - you will see the docs.
Code Matches Comment
–––––––– ––––––––– ––––––––––––––––––––––––––––––––––––––––––––––––––––––––––
y 1996, 96 Returns year of 1996, 0096
Y 1996, 96 Returns year of 1996, 0096. Equivalent to y
m 1, 01 Matches 1 or 2-digit months
u Jan Matches abbreviated months according to the locale keyword
U January Matches full month names according to the locale keyword
d 1, 01 Matches 1 or 2-digit days
H 00 Matches hours (24-hour clock)
I 00 For outputting hours with 12-hour clock
M 00 Matches minutes
S 00 Matches seconds
s .500 Matches milliseconds
e Mon, Tues Matches abbreviated days of the week
E Monday Matches full name days of the week
p AM Matches AM/PM (case-insensitive)
yyyymmdd 19960101 Matches fixed-width year, month, and day
To parse dates you need the Dates.jl standard library. To parse this particular format though, I think you additionally need the TimeZones.jl package:
using Dates
using TimeZones # gives the `z` for the format below
fmt = dateformat"e u d H:M:S z y" # the format of your string
d = Date("Tue Sep 01 00:00:26 +00:00 2020", fmt)
Then you can simply look at d's values for example with:
julia> d
2020-09-01
julia> year(d)
2020
julia> month(d)
9
julia> day(d)
1
In my google sheet I have a column with dates but its in a text format. here an example what I have:
Oct 01, 2021
Dec 25, 2020
...
...
I want to convert it to a date format
01/10/2021
25/12/2020
....
I need to find the number of days from the dates in this column, by using "date in column" - now(). This does not work with the format "Oct 01, 2021" since its a text, and I am getting an error from Googlesheet.
Thanks in advance
IS
Try this formula in F2:
=ARRAYFORMULA(IFERROR(DATEDIF(
DATE(
RIGHT(E2:E,4),
MATCH(LEFT(E2:E,3),{"Jan";"Feb";"Mar";"Apr";"May";"Jun";"Jul";"Aug";"Sep";"Oct";"Nov";"Dec"},0),
MID(E2:E,5,2)),
NOW(), "D")))
Update
Revised the formula, which goes in F1 and fills the column, to:
={"Days Left";ARRAYFORMULA(
IFERROR(-1 * DATEDIF( DATE( RIGHT(E2:E,4), MATCH(LEFT(E2:E,3),{"Jan";"Feb";"Mar";"Apr";"May";"Jun";"Jul";"Aug";"Sep";"Oct";"Nov";"Dec"},0), MID(E2:E,5,2)), NOW(), "D"),
IFERROR(DATEDIF( NOW(),DATE( RIGHT(E2:E,4), MATCH(LEFT(E2:E,3),{"Jan";"Feb";"Mar";"Apr";"May";"Jun";"Jul";"Aug";"Sep";"Oct";"Nov";"Dec"},0), MID(E2:E,5,2)), "D"))))}
which reverses the date difference values. It also handles date differences for dates either in the future, or in the past.
Use the DATEVALUE() function on a date string, then use DATEDIF() to find the difference between two dates.
=DATEDIF(DATEVALUE("Oct 01, 2020"), DATEVALUE("Dec 25, 2020"), "D")
UPDATE: To find the date between today and a date string in another cell use this example:
=DATEDIF(DATEVALUE(A2), NOW(), "D")
If cell A2 contains string Oct 01, 2020, it will return 70 for today 2020-12-10
I have three columns with date formatted differently in SAS:
12 june 2017 00:15 - full date
2016 - only year
12 - only month
I Need to change the format of date and subtract after the dates to get results in the number of months.
for instance, "12 June 2017 00:15" - December 2016 = 7
how to do it?
As you have probably already found, there isn't a ready-made SAS date informat that will correctly handle your full date field, so you'll need to write a bit of custom logic to convert it before doing your calculation. date9. is the closest matching format I could find:
data example;
fulldate = '12 june 2017 00:15';
year = 2016;
month = 12;
/* Convert string to date9 format and input */
fulldate_num = input(
cats(
scan(fulldate,1),
substr(scan(fulldate,2,' '),1,3),
scan(fulldate,3)
), date9.
);
/* Calculate difference in months */
monthdiff = intck('month', mdy(month,1,year), fulldate_num);
run;
Convert the "full date" field to a SAS date value.
Convert the combo of year and month to a SAS date value, too.
Use the INTCK function to find the difference in months.
For example:
data dates ;
input dt $18. yy mm ;
mm_diff = intck ("mon", input (cats (yy, mm), yymmn6.), input (dt, anydtdte12.)) ;
put mm_diff= ;
cards ;
12 june 2017 00:15 2016 12
11 june 2018 00:15 2017 3
;
run ;
The log will print:
mm_diff=6
mm_diff=15
As a side note, the statement "there isn't a ready-made SAS date informat that will correctly handle your full date field" made elsewhere in this thread is incorrect. As the program snippet above shows, the ANYDTDTEw. informat handles it with aplomb. It's just incumbent upon the programmer to supply a sufficient informat width W. Above, it is selected as W=12. If you're reluctant to guess and/or count, just use ANYDTDTE32.
Regards,
Paul Dorfman
Assuming that you have three numeric variables and the first one contains valid SAS datetime values you should first convert both to valid SAS date values. You can then use the INTCK() function to count months.
nmonths = intck('month',datepart(VAR1),mdy(VAR3,1,VAR2));
Hello I'm having two problems with converting a concatenated date value into an actual date.
I've tired looking here to convert the concatenated value with to_char(DATE ...) but I keep getting odd dates. I think it is because my month does not have a zero padding in front of it.
This is my base query:
SELECT
expiry_month,
expiry_year,
to_date(CONCAT(expiry_year, expiry_month), 'YYYY/MM'),
FROM thisTable
Here is an example of the data output:
expiry_month expiry_year concatvalues
9 2018 20189-01-01
1 2019 20191-01-01
5 2016 20165-01-01
3 2019 20193-01-01
10 2017 201710-01-01
2 2020 20202-01-01
I think I need to LPAD() my month value to get the correct date parsed. E.g. 01 not 1, and 05 not 5.
However when I try to LPAD the month values it does not work. I've tried:
lpad(to_char(expiry_month),2,'0'),
I get this error 'HINT: No function matches the given name and argument types. You might need to add explicit type casts.'
Which I don't understand because lpad is a function. Any suggestion on how to use LPAD()?
Thank you for the advice.
EDIT 1
I've tried to update the to_date() function with this code:
to_date(CONCAT(payment_cards.expiry_year || ' - ' || payment_cards.expiry_month || ' - 01'), 'YYYY-MM-01') and now it is throwing a different error:
ERROR: invalid value "- " for "MM" DETAIL: Value must be an integer.
I'm still thinking I need to pad the month date?
There's a '/' missing:
SELECT
expiry_month,
expiry_year,
to_date(CONCAT(expiry_year, '/', expiry_month), 'YYYY/MM') AS the_start_of_year_month
FROM thisTable ;
will produce:
expiry_month | expiry_year | the_start_of_year_month
-----------: | ----------: | :----------------------
9 | 2018 | 2018-09-01
1 | 2019 | 2019-01-01
5 | 2016 | 2016-05-01
3 | 2019 | 2019-03-01
10 | 2017 | 2017-10-01
2 | 2020 | 2020-02-01
The date format is specifying '/' and it wasn't there, so, the whole text was taken as the year, and the month and day were taken as 1/1. CONCAT('2018','9') was just returning '20189' (which is a valid year).
dbfiddle here
Use:
make_date(year int, month int, day int)
like:
make_date(expiry_year, expiry_month, 1)
Postgresql documentation
I have a data source that returns a date as a string in the form of 'MON YYYY' (APR 2014, MAY 2014, etc.).
I tried making a calculated field off of this information with the following formula:
DATEPARSE('MMM YYYY', [Field1])
This is a sample set of the data I'm getting (I added the pipe as a divider):
Field1 || Calculated Field
APR 2014 || 12/22/2013
APR 2015 || 12/28/2014
APR 2016 || 12/27/2015
AUG 2014 || 12/22/2013
AUG 2015 || 12/28/2014
AUG 2016 || 12/27/2015
I've also tried to add a day field, but that results in the same incorrect data as above:
DATE(DATEPARSE('dd MMM YYYY','01 ' +[Field1]))
Is there something I'm perhaps misunderstanding about the dateparse function?
It turns out that YYYY means something totally different than yyyy. The capitalized MMMwas necessary for the MON type description. This worked for me:
DATE(DATEPARSE('MMM yyyy',[Field1]))
If you date the date off you'll get the hour, minute, second fields as well.
Dateparse converted it from a string [Field1] into a Date type using the aforementioned format of three digit month, a space, and a four digit year (e.g. AUG 2014 -> 8/2/2014).