I required a custom solution to a problem in which users can choose a number of different intervals for data comparisons.
Example:
CURRENT_DATE - interval '1 day'
CURRENT_DATE - interval '4 day'
CURRENT_DATE - interval '7 day'
AND so on
So I am looking for a solution in which I can pass the array of integers in intervals like
select CURRENT_DATE - interval '1day' * any(ARRAY[1,4,7])
But it is not possible because
op ANY/ALL (array) requires an operator to yield boolean
demos:db<>fiddle
You can use unnest() to extract the array elements into one record per element and then return the CURRENT_DATE minus each of these elements:
SELECT
CURRENT_DATE - array_element
FROM unnest(ARRAY[1,4,7]) as array_element
Naturally, you can put the unnest() into the SELECT list:
SELECT CURRENT_DATE - unnest(ARRAY[1,4,7])
Edit:
If you need another date range than days you can use intervals for that:
SELECT CURRENT_DATE - unnest(ARRAY[1,4,7]) * interval '1 week'
Related
I want to query data for last 30 days including today from redshift table. below is my query.
my date_column's type is 'timestamp without timezone'
select *
from mytable
WHERE date_column BETWEEN current_date - INTERVAL '30 day' AND current_date
order by date_column desc;
It gives the result for 30 days. But it doesn't include today's result.
I want to query for 30 days result including today's result also.
If it's a timestamp don't use between as it also compares the time part. Use a range query:
where date_column >= current_date - interval '30 day'
and date_column < current_date + interval '1 day'
Note that the upper bound is using < together with "tomorrow"
With Postgres this could be simplified to
where date_column >= current_date - 30
and date_column < current_date + 1
but Redshift isn't Postgres and I don't know if that would work there.
I'm trying to compare values of current month's data to previous months using PostgreSQL. So if today is 4/23/2018, I want the data for 3/23/2018.
I've tried current_date - interval '1 month' but it is problematic for months with 31 days.
My table is structured as simply as
date, value
Check this example query:
WITH dates AS (SELECT date::date FROM generate_series('2018-01-01'::date, '2018-12-31'::date, INTERVAL '1 day') AS date)
SELECT
start_dates.date AS start_date,
end_dates.date AS end_date
FROM
dates AS start_dates
RIGHT JOIN dates AS end_dates
ON ( start_dates.date + interval '1 month' = end_dates.date AND
end_dates.date - interval '1 month' = start_dates.date);
It will output all end_dates and corresponding start_dates. The corresponding dates are defined by interval '1 month' and checked in both ways:
start_dates.date + interval '1 month' = end_dates.date AND
end_dates.date - interval '1 month' = start_dates.date
The output looks like this:
....
2018-02-26 2018-03-26
2018-02-27 2018-03-27
2018-02-28 2018-03-28
2018-03-29
2018-03-30
2018-03-31
2018-03-01 2018-04-01
2018-03-02 2018-04-02
2018-03-03 2018-04-03
2018-03-04 2018-04-04
....
Note, that there are 'gaps' for days without corresponding dates.
Back to your table, join the table with itself (giving aliases) and use given join condition, so the query would look like this:
SELECT
start_dates.value - end_dates.value AS change,
start_dates.date AS start_date,
end_dates.date AS end_date
FROM
_your_table_name_ AS start_dates
RIGHT JOIN _your_table_name_ AS end_dates
ON ( start_dates.date + interval '1 month' = end_dates.date AND
end_dates.date - interval '1 month' = start_dates.date);
Given the following table structure:
create table t (
d date,
v int
);
After populating with some dates and values, there is a way to find the value of the previous month using simple calculations and the LAG function, without resorting to joins. I am not sure how it compares from a performance perspective, so please run your own tests before selecting which solution to use.
select
*,
lag(v, day_of_month) over (order by d) as v_end_of_last_month,
lag(v, last_day_of_previous_month + day_of_month - cast(extract(day from d - interval '1 month') as int)) over (order by d) as v_same_day_last_month
from (
select
*,
lag(day_of_month, day_of_month) over (order by d) as last_day_of_previous_month
from (
select
*,
cast(extract(day from d) as int) as day_of_month
from
t
) t_dom
) t_dom_ldopm;
You may note that between the 29th and 31st of March, the comparison will be made against the 28th of February, since the same day does not exist in February for those particular dates. The same logic applies to other months with different number of days.
I'm trying to make a SELECT query which will compare current time with time at database. For example in database there is a record '2018-02-07 12:00:00' and I wanna compare it to current time. If current time is '2018-02-07 11:00:00', record '2018-02-07 12:00:00' should be visible in results. It should compare two dates and shows only those who are 1h before or after current time.'
Tried something like this:
SELECT * FROM events WHERE age(current_date, event_date) < '1 hour';
or
SELECT * FROM events WHERE event_date > (now() - INTERVAL '1 hour');
those that are 1h before or after current time
Wouldn't the logic look like this?
SELECT e.*
FROM events e
WHERE e.event_date > now() - INTERVAL '1 hour' AND
e.event_date < now() + INTERVAL '1 hour'
I have the table users.
Columns:
user_id - integer
user_date - integer(unix timestamp)
Some of rows have user_date and some have NULL.
I need to find all user_id's which user_date includes period between '2012-10-21' and '2012-10-24'
SELECT *
FROM users
WHERE user_date BETWEEN
EXTRACT(EPOCH FROM date '2012-10-21') AND
EXTRACT(EPOCH FROM date '2012-10-24' + interval '1 day');
If you don't want the end date to be included, remove the bit adding a day to that.
select *
from users
where
timestamp 'epoch' + user_date * interval '1 second' between '2012-10-21' and '2012-10-24'
and
user_date is not null
How to get last 3 months records from the table.
SELECT *
from table
where month > CURRENT_DATE-120
and month < CURRENT_DATE
order by month;
I have used the above query is it correct? shall I use this for get last 3 month record from the table.
You can use built-in INTERVAL instruction
Check how this works:
SELECT CURRENT_DATE - INTERVAL '3 months'
and you can rewrite your SQL to:
SELECT * from table where date > CURRENT_DATE - INTERVAL '3 months'
(not checked but this should give you an idea how to use INTERVAL instruction)
Try that:
SELECT *
FROM table
WHERE month BETWEEN EXTRACT(MONTH FROM NOW() - INTERVAL '3 months')
AND EXTRACT(MONTH FROM NOW())
ORDER BY month
;
This filters the last 3 calendar months
SELECT * from table where date >= to_char(CURRENT_DATE - INTERVAL '3 months', 'YYYY-MM-01')::date
select date::date
from generate_series((current_date - INTERVAL '1 Month')::date, (current_date - INTERVAL '1 DAY')::date,'1
day'::interval) date
WHERE date >= date_trunc('month', current_date - interval '3' month)
and date < date_trunc('month', current_date)
This will give last three months date list, excluding current months date. Example if current month is November. This list will give use all dates of August, Septemeber and October.