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How do I get current date/time on the Windows command line in a suitable format for usage in a file/folder name?
(30 answers)
Closed 1 year ago.
i am using batch and i need help formatting this one thing, on saved file the date changes everyday but the "yyyy" is just put down as "yy"
Example: if the year was "2021" the name would be "21"
I havent found anything that could get me the last 2 numbers on the year.
Please help as i need this for work.
Sincerely,
Kythe
You might cut out the part you do not need:
set DT=%date%
set dd=%DT:~0,2%
set mm=%DT:~3,2%
set yy=%DT:~8,2%
echo %dd%
echo %mm%
echo %yy%
echo "day: %dd%, month: %mm%, year: %yy%"
pause
set variable=%date:~start,length% assigns to the variable all the the characters of date indexed between start (counting from 0) and (start + length-1)
EDIT:
On other machine date might be formatted differently, as #Squashman pointed out.
To properly cut out the part you need, try:
echo %date%
Now set dd, mm and yy in the correct way you need them to be set
Related
I required previous month and year value in a variable in Unix . I am not able to find any correct unix command for that.
Meanwhile I have achieved this requirement through sql command, in ext variable and used it.
ext=`sqlplus -s user/pass <<END
set feedback off set pagesize 0
select to_char(add_months(sysdate,-1),'Mon-YYYY') from dual;
exit;
END>>`
But I was looking if I can achieve this by unix command in which I can get same result as Aug-2016.
Most close I have got through unix command is by
ext=date + %b-%Y
which is giving me current month year value as Sep-2016.
But I require previous month value and in same format.Can anyone suggest? Thanks.
Have you tried date -d ?
% date -d '1 month ago' '+%b-%Y'
Aug-2016
I have a script that needs to connect to an ftp server and download a file that is only created on Sunday and Sunday's yyyy-mm-dd-hh-mm-ss is appended to the file name. I need to find the last Sunday's date (based on today's date, I assume) and convert it to yyyy-mm-dd (I don't care about the time) so I can construct the filename in my ftp script. I have searched a lot of threads on this and other sites, but I'm kind of a novice at batch syntax. I cannot make assumptions about the date format on the machine that will run this script, but it will be in the same timezone as the ftp server and it will be running at least Windows 7. I thought about using the PowerShell solution in HOW to find last SUNDAY DATE through batch but I've read there are issues with PS script portability. Any help is greatly appreciated. Let me know if I need to provide more detail. Thanks!
(Get-Date).AddDays(-(get-date).dayofWeek.value__)
A couple years ago I wrote a batch script to find yesterday's date. I made it able to calculate 'yesterday' based on today's date. It takes into account months ending on the 30th or 31st, and even the next few leap years. The way I wrote it expects the date to be in the format 'Wed 02/24/2016' or 'ddd MM/DD/YYYY', so it may not be useful to you.
As I look at it now, it's probably more complicated than it needs to be and could probably use some cleanup, but it worked for my purposes. You might be able to modify it somehow to make it find last Sunday, instead of yesterday.
set yearCounter=0
set yyyy=%date:~10,4%
set mm=%date:~4,2%
set dd=%date:~7,2%
::use these to override the actual date values for testing
::set yyyy=xxxx
::set mm=xx
::set dd=xx
if %dd%==01 goto LDoM ::Last Day of Month
set DS=%yyyy%%mm%%dd%
set /A yesterday=%DS%-1
goto endyesterday
:LDoM
set /A lastyyyy=%yyyy%-%yearCounter%
if %yesterday:~4,2%==01 set lastmm=12& set lastdd=31& goto LDoY ::Last Day of Year
if %yesterday:~4,2%==02 set lastmm=01& set lastdd=31
if %yesterday:~4,2%==03 set lastmm=02& goto february
if %yesterday:~4,2%==04 set lastmm=03& set lastdd=31
if %yesterday:~4,2%==05 set lastmm=04& set lastdd=30
if %yesterday:~4,2%==06 set lastmm=05& set lastdd=31
if %yesterday:~4,2%==07 set lastmm=06& set lastdd=30
if %yesterday:~4,2%==08 set lastmm=07& set lastdd=31
if %yesterday:~4,2%==09 set lastmm=08& set lastdd=31
if %yesterday:~4,2%==10 set lastmm=09& set lastdd=30
if %yesterday:~4,2%==11 set lastmm=10& set lastdd=31
if %yesterday:~4,2%==12 set lastmm=11& set lastdd=30
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:february
set leapyear=n
set lastdd=28
if %yesterday:~0,4%==2016 set leapyear=y
if %yesterday:~0,4%==2020 set leapyear=y
if %yesterday:~0,4%==2024 set leapyear=y
if %yesterday:~0,4%==2028 set leapyear=y
if %leapyear%==y set lastdd=29
set yesterday=%lastyyyy%%lastmm%%lastdd%
goto endYesterday
:LDoY
set /A yearCounter=%yearCounter%+1
set /A lastyyyy=%yyyy%-%yearCounter%
set yesterday=%lastyyyy%%lastmm%%lastdd%
:endYesterday
#echo off
echo %yyyy% %lastyyyy%
echo %mm% %lastmm%
echo %dd% %lastdd%
echo.
echo today = %yyyy%%mm%%dd%
echo yesterday = %yesterday%
Working with date and time using pure batch can be done, but it is not very convenient.
The GetTimestamp.bat utility makes date/time computations and formatting simple within a batch context. It is pure script (hybrid JScript/batch) that runs natively on any Windows machine from XP onward. The previous link points to the most recent version. The utility was first introduced with a number of examples at http://www.dostips.com/forum/viewtopic.php?t=4847.
Full documentation is available from the command line via getTimestamp /?, or getTimestamp /?? for paged output.
With GetTimestamp, the solution can be as simple as:
#echo off
:: Get the current day of the week, with 0=Sunday, 6=Saturday
:: to be used as an offset from today to get the most recent Sunday
call getTimeStamp -f {w} -r offset
:: Use the offset to get the most recent Sunday in YYYY-MM-DD format
call getTimeStamp -od -%offset% -f {iso-dt} -r lastSunday
:: Show the result
echo lastSunday=%lastSunday%
Try the following from a batch file:
for /f "usebackq" %%d in (`powershell -noprofile -command "'{0:yyyy-MM-dd}' -f [DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek)"`) do set "lastSunday=%%d"
echo %lastSunday%
:: -> e.g., "2016-02-21", when run on 2016-02-25
To try this directly on the command prompt, replace %%d with %d.
The PowerShell expression at the heart of the command,
[DateTime]::Now.AddDays(-1 * [DateTime]::Now.DayOfWeek),
which calculates the date of the most recent Sunday, was gratefully borrowed from the answer that you link to in your question.
'{0:yyyy-MM-dd}' -f ... applies the desired yyyy-mm-dd formatting to the date.
powershell -noprofile command ... invokes the PowerShell expression and outputs its result to stdout.
for /f "usebackq" %%d in (`...`) do set lastSunday=%%d captures the output from the PowerShell command and assigns it to batch variable lastSunday.
While invoking PowerShell for just one command from a batch file will be slow, being able to calculate the desired date so conveniently probably outweighs performance concerns.
I am generating the date in a format of YYYYMMDD so that i can append it in the filename that the batch program generates.
But in my local system echo %date% returns
echo %date%
Tue 09/08/2015
The date information is returned so i can modify it the way i want
In server, the same does not return date values
echo %date%
/Tu
I dont have date values to modify it to my required format YYYYMMDD
How do I go about this? Is there any Windows date and time setting that i should be looking at?
The date format depends on the regional settings of your machine. You can check them in control panel (run intl.cpl), they seem to be broken.
I know there are similar questions but I have not been able to make any work. I need to check a particular file date and time against the current date and time.
So far I have
Set cdate=%date%
Set filename="c:\myfile"
If Not Exist %filename% GOTO CREATEFILE
For %%f In(%filename%) DoSet filedatetime=%%~tf
If %filedatetime:~0,-9%" == "%cdate% GOTO SHOFILE
My problem is that the cdate returned has the day of the week included in the date but the file date does not. Example cdate= Thur 1/01/2015. How can I get the cdate not to have the day of the week?
Thanks
For %%f In (%filename%) Do Set "filedatetime=%%~tf"
If "%filedatetime:~0,-9%"=="%cdate:~4%" GOTO SHOFILE
Note the required space after in and do
The set "var=value" syntax ensures that any trailing spaces on the batch line are not included in the value assigned to var.
if /i "%var%"=="value" performs a comparison on variables/values containing separators (eg spaces) The '/i' make the comparison case-insensitive if required.
Your cdate can be set like this:
SET cdate=%date:~4%
This has the following output:
echo %cdate%
01/01/2015
Each night I need to do work on a folder 36 days old from the current date. I have a system that writes files to a daily structure like below. I need to keep 35days worth on the local disk and so each night I need to archive off the 36th day. Here is the kicker... There are approx 2 million files per day, so I cannot efficiently scan the whole 2009 folder and only move files older than 35 days. What I need to do is though a batch script determine the path of the folder that is 36days old and then apply my archive logic. I have scripts to determine but having trouble doing the determination to 36 days old. In a pinch I can use perl if there is not a batch way to do this. --Shawn
Folder structure is like this:
2009\07\01
2009\07\02
2009\07\03
.
.
.
2009\08\01
2009\08\02
2009\08\03
#EDIT: Helen's great answer has me 99% of the way there. My only problem is that the month and day out of the vbs is not padded with a zero which i have to deal with in the folder structure. Does anyone have an easy way to pad in a leading 0 if the day or month is less than 10?
Here is what I am doing so far:
for /F "tokens=1-3 delims=/" %%x in ('cscript //nologo get36thday.vbs') do (
SET YYYY=%%z
SET MM=%%x
SET DD=%%y)
except %MM% ends up being 7 instead of 07
The batch option is pretty wicked you will need to calculate which month it is then based of of that run a while loop counting down the days. I would high recommend perl as it would be a few lines of code
using the DateTime module from CPAN
http://search.cpan.org/dist/DateTime/lib/DateTime.pm
my $dt = DateTime->now->subtract(days => 36);
The batch way to determine the date would be too compilcated; it's much easier to use a script for that. Sorry, no Perl sample but a VBScript one:
WScript.Echo DateAdd("d", Date, -36)
You can call this script from a batch file and read the calculated date like this:
for /f %%d in ('cscript //nologo datediff.vbs') do set dt=%%d
If you came here with google like me:
To fix the leading zero's in the .vbs I add a zero in front and strip the right 2 characters.
"0" & "7" -> "07" and "0" & "14" -> "14"
OldDateCode.vbs:
OldDate = DateAdd("d", Date, -36)
DateCode = Year(OldDate) & Right("0" & Month(OldDate), 2) & Right("0" & Day(OldDate), 2)
WScript.Echo DateCode
I also wanted to keep the 1st folder of the month so I compare the last 2 digits (day) with "01"
VBS code to check for 1st day:
If Right(DateCode, 2)="01" then
WScript.Echo "The 1st:" & vbCrLf & DateCode
Else
WScript.Echo "Not the 1st:" & vbCrLf & DateCode
End If
CheckDate.bat:
#Echo Off
Set Folder=D:
for /f %%d in ('cscript //nologo OldDateCode.vbs') do set OldDateCode=%%d
If "%OldDateCode:~6,7%"=="01" (
Echo "Old Backup: %OldDateCode% 1st of the month: keeping..."
) ELSE (
Echo "Old Backup: %OldDateCode% not the 1st of the month: removing..."
RD /S /Q "%Folder%\%OldDateCode%"
)
pause
Make a folder in D:\ with the datecode of 36 days ago. Play around with the -36 and the datecodes.