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Remove Left and right square brackets using sed/bash
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Remove a pattern using sed which has square brackets and quotes
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How can I use sed to delete line with square brackets?
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Closed 1 year ago.
How can I remove the line "name['todo']['remove'] = 3456" from a text file?
[test.txt]
name['myname']['test'] = 12
name['todo']['remove'] = 3456
name['todo']['remove']['inspection'] = 34
My current approach is not working as expected. The line is still in my file.
sed -i "name\['todo'\]\['remove'\]" test.txt
The error message is "sed: -e expression #1, char 2: extra characters after command"
A simple grep -vF would work fine here that matches using fixed string without requiring escaping of special regex characters:
grep -ivF "name['todo']['remove'] " file
[test.txt]
name['myname']['test'] = 12
name['todo']['remove']['inspection'] = 34
You can use
sed -i "/name\['todo']\['remove'] =/d" test.txt
Note that the pattern is wrapped with / regex delimiters, and the d means the matched line will get removed.
See an online demo:
s="[test.txt]
name['myname']['test'] = 12
name['todo']['remove'] = 3456
name['todo']['remove']['inspection'] = 34"
sed "/name\['todo']\['remove'] =/d" <<< "$s"
yielding
[test.txt]
name['myname']['test'] = 12
name['todo']['remove']['inspection'] = 34
If you want to make sure you only match a whole line with digits after =, you may use "/^name\['todo']\['remove'] = [0-9]*$/d" command with sed.
Related
I am using following command to append string after AMP, but now I want to add after to AMP which is after SET2 or line number 9, can we modify this command to append the string only after SET2 or line number 9? And if I want to add to only to SET1 AMPs or before line number 9 , could someone help me with the command, thanks.
$ sed -i '/AMP/a Target4' test.txt
$ cat test.txt
#SET1
AMP
Target 1
Target 2
AMP
Target 3
Target 4
Target 5
#Set2
AMP
Target 11
Target 12
Note there is no line between above text.
Would you please try the following:
sed -i '
/^#Set2/,${ ;# if the line starts with "#Set2", execute the {block} until the last line $
/AMP/a Target4 ;# append the string after "AMP"
} ;# end of the block
' test.txt
If you want to append the string before the #Set2 line, please try:
sed -i '
1,/^#Set2/ { ;# excecute the {block} while the line number >= 1 until the line matches the pattern /^#Set2/
/AMP/a Target4
}
' test.txt
The expression address1,address2 is a flip-flop operator. Once the
address1 (line number, regular expression, or other condition) meets,
the operator keeps on returning true until the address2 meets.
Then the following command or block is executed from address1 until
address2.
If you want to add to after AMP which is after #Set2 or line number 9,
I think it is better to process up to the 8th line and after the 9th line separately.
For example, the command is below:
sed '
1,8{
/^#Set2/,${
/AMP/a Target4
}
}
9,${
/AMP/a Target4
}' test.txt
I have extracted the following data using 'grep' & 'sed' pipes from a file and now I want to perform a mathematical equation on the last two numbers, delete them and replace them with a single number.
Mathematical operations
Add the numbers together
divide by 2
multiply by 141
ROUNDUP to whole number
File Data
AJ29 IO_0_VRN_10 77.234 78.011
AJ30 IO_L1P_T0_100M 89.886 90.789
AJ31 IO_L1N_T0_100S 101.388 102.406
AK29 IO_L2P_T0_101M 66.163 66.828
AL29 IO_L2N_T0_101S 63.626 64.266
So the line starting AJ29 should appear as:
AJ29 IO_0_VRN_10 10945
I could put it in MS excel / Open Office calc and do this but want to avoid MS and keep it in a single linux script if it is possible. Hope you can help. The script I have so far is below and ideally I'd like to add a few more pipes to achieve this.
grep IOB xc7vx690tffg1930.pkg | sed 's/pin//g' | sed 's/IOB_[A-Za-z0-9]*//g' | sed 's/ /-/g' | sed 's/\t//g' | sed 's/^[-]*//g' | sed 's/-/ /g' | sed 's/ [0-9][0-9] //g' | sed 's/[[:space:]]\+/,/g' | sed 's/,X[0-9A-Z]*,//g' | sed 's/,[0-9]*[A-Z],//g' | sed 's/N\.A\.,/,/g' | sed 's/,$//g' | sed 's/,/ /g'
For calculations, use awk!
$ awk '{$(NF-1)=sprintf("%.0f", ($(NF-1) + $NF)/2 * 141); NF--}1' file
AJ29 IO_0_VRN_10 10945
AJ30 IO_L1P_T0_100M 12738
AJ31 IO_L1N_T0_100S 14367
AK29 IO_L2P_T0_101M 9376
AL29 IO_L2N_T0_101S 9016
This replaces the penultimate field with the result of (penultimate*last)/2 * 141). To make it round, we use %.0f format as indicated in Awk printf number in width and round it up.
Also, it looks to me that you are piping way too many things: I counted one call to grep and 13 (!) to sed. You can probably use sed -e 'first block' -e 'second block' ... instead.
Explanation
In awk, NF refers to the number of fields on the current line. Since $n refers to the field number n, with $(NF-1) we refer to the penultimate field.
{...}1 do stuff and then print the resulting line. 1 evaluates as True and anything True triggers awk to perform its default action, which is to print the current line.
$(NF-1) + $NF)/2 * 141 perform the calculation: `(penultimate + last) / 2 * 141
{$(NF-1)=sprintf( ... ) assign the result of the previous calculation to the penultimate field. Using sprintf with %.0f we make sure the rounding is performed, as described above.
{...; NF--} once the calculation is done, we have its result in the penultimate field. To remove the last column, we just say "hey, decrease the number of fields" so that the last one gets "removed".
I need to free a string from unwanted characters. In this example I want to filter all +'s and all -'s from b and write the result to c. So if b is +fdd-dfdf+, c should be +-+.
read b
c=$(echo $b | sed 's/[^(\+|\-)]//g')
But when i run the script, the console says:
sed: -e expression #1, char 15: Invalid range end
The reason is the \- in my regular expression. How can I solve this problem and say, that I want to filter all -'s?
are you looking for this?
kent$ echo 'a + b + c - d - e'|sed 's/[^-+]//g'
++--
Hi I want to replace a string coming between to symbols by using sed
example: -amystring -bxyz
what to replace mystring with ****
value after -a can be anything like -amystring 123 -bxyz, -amystring 123<newline_char>, -a'mystring 123' -bxyz, -a'mystring 123'<newline_char>
I tried following regex but it does not work in all the cases
sed -re "s#(-w)([^\s\-]+)#\1**** #g"
can anybody help me to solve this issue ?
MyString="YourStringWithoutRegExSpecialCharNotEscaped"
sed "s/-a${MyString} -b/-a**** -b/g"
if you can escape your string for any regex key char like * + . \ / with something like
echo "${MyString}" | sed 's/\[*.\\/+?]/\\&/g' | read -r MyString
before us it in sed.
otherwise, you need to better define the edge pattern
I have some java code declaring a 2d array that I want to flip.
Content is like:
zData[0][0] = 198;
zData[0][1] = 198;
zData[0][2] = 198;
...
And I want to flip indices to have
zData[0][0] = 198;
zData[1][0] = 198;
zData[2][0] = 198;
So I tried doing it with sed:
sed -r 's#zData[([0-9]*)][([0-9]*)]#zData[\2][\1]#g' DataSample1.java
But unfortunately sed says:
sed: -e expression #1, char 43: Unmatched ) or \)
Might the string "zData" hold kind of flag or option?
I tried not using the -r option but I have the same kind of message for:
sed 's#zData[\(\[\0\-\9\]\*\)][\(\[\0\-\9\]\*\)]#zData[\2][\1]#g' DataSample1.java
Thanks for your help
Simples:
$ sed -r 's/(zData)(\[[^]]+])(\[[^]]+])/\1\3\2/' file
zData[0][0] = 198;
zData[1][0] = 198;
zData[2][0] = 198;
Regexplanation:
# Match
(zData) # Capture the variable name we want to transpose
( # Start capture group for first index
\[ # Opening bracket escaped to mean literal [
[^]]+ # One or more none ] characters i.e the digits
] # The closing literal ] doesn't need escaping here.
) # Close the capture
(\[[^]]+]) # Same regexp as before for the second index
# Replace
\1\3\2 # Switch the indexes but rearranging the 2nd and 3rd capture groups
Note: Switch \[[^]]+] to if it is clearer \[[0-9]+] for you, so instead of saying match an opening square bracket followed by one or more none-closing brackets followed by a closing bracket you are saying match an opening square bracket followed by one or more digit followed by a closing bracket.
Try that one:
sed 's#\([a-zA-Z0-9_-]\+\)\(\[[^]]*\]\)\(\[[^]*]\]\)\(.*$\)#\1\3\2\4#'
It adds four captures for the variable name, the first index, the second index and the rest and then switches order.
Edit: #Sudo_O's solution with extended regular expressions is much more readable. Thx for that! Nevertheless, on some systems sed -r may not be available, since it is not part of basic POSIX.