STM32: analog watchdog does only trigger interrupt HAL_ADC_LevelOutOfWindowCallback once - stm32

Question

Question
Do I need to reset the analog watchdog each time it triggers an
interrupt or is there an error in my code ?
If I need to reset it every time how would I do that ?
Is there a HAL function for it that I can call in the callback?
My Code
Main
HAL_ADC_Start(&hadc2);
ADC and WDG Config
static void MX_ADC2_Init(void){
ADC_AnalogWDGConfTypeDef AnalogWDGConfig = {0};
ADC_ChannelConfTypeDef sConfig = {0};
/** Common config*/
hadc2.Instance = ADC2;
hadc2.Init.ClockPrescaler = ADC_CLOCK_SYNC_PCLK_DIV4;
hadc2.Init.Resolution = ADC_RESOLUTION_8B;
hadc2.Init.ScanConvMode = ADC_SCAN_DISABLE;
hadc2.Init.ContinuousConvMode = ENABLE;
hadc2.Init.DiscontinuousConvMode = DISABLE;
hadc2.Init.ExternalTrigConvEdge = ADC_EXTERNALTRIGCONVEDGE_NONE;
hadc2.Init.ExternalTrigConv = ADC_SOFTWARE_START;
hadc2.Init.DataAlign = ADC_DATAALIGN_RIGHT;
hadc2.Init.NbrOfConversion = 1;
hadc2.Init.DMAContinuousRequests = DISABLE;
hadc2.Init.EOCSelection = ADC_EOC_SINGLE_CONV;
hadc2.Init.LowPowerAutoWait = DISABLE;
hadc2.Init.Overrun = ADC_OVR_DATA_OVERWRITTEN;
if (HAL_ADC_Init(&hadc2) != HAL_OK)
{
Error_Handler();
}
/** Configure Analog WatchDog 1 */
AnalogWDGConfig.WatchdogNumber = ADC_ANALOGWATCHDOG_1;
AnalogWDGConfig.WatchdogMode = ADC_ANALOGWATCHDOG_SINGLE_REG;
AnalogWDGConfig.HighThreshold = 64-1;
AnalogWDGConfig.LowThreshold = 0;
AnalogWDGConfig.Channel = ADC_CHANNEL_1;
AnalogWDGConfig.ITMode = ENABLE;
if (HAL_ADC_AnalogWDGConfig(&hadc2, &AnalogWDGConfig) != HAL_OK)
{
Error_Handler();
}
/** Configure Regular Channel
*/
sConfig.Channel = ADC_CHANNEL_1;
sConfig.Rank = ADC_REGULAR_RANK_1;
sConfig.SingleDiff = ADC_SINGLE_ENDED;
sConfig.SamplingTime = ADC_SAMPLETIME_1CYCLE_5;
sConfig.OffsetNumber = ADC_OFFSET_NONE;
sConfig.Offset = 0;
if (HAL_ADC_ConfigChannel(&hadc2, &sConfig) != HAL_OK)
{
Error_Handler();
}
}
The Callback
void HAL_ADC_LevelOutOfWindowCallback (ADC_HandleTypeDef * hadc){
HAL_GPIO_TogglePin(GPIOB, GPIO_PIN_3);
}

Answer 1

Looking at your code... specifically...
hadc2.Init.EOCSelection = ADC_EOC_SINGLE_CONV
You probably just need to call start again after the interrupt...
HAL_ADC_Start(&hadc2);