Access data in Core Data using relationships and predicate - swift

I am using Core data to store two databases that contain a relationships.
There is a logbook database and a IFRApproaches database.
A logbook entry can have multiple approaches.
An approach can only be linked to one logbook entry.
Attached is screenshots of my data model and relationships.
When the "submit" button is pressed this is the code to save the entry to the logbook, and the approaches as well.. I need the approaches (how ever many) associated with a singular entry. My question is How I can use a predicate to query the database at a later time for all the approaches associated with a various entry.
lazy var newEntry = Logbook(context: LoadData.shared.context)
if errorCount == 0 {
if modifyEntry == false {
if entryHolding.date == nil {
newEntry.date = Date()
} else {
newEntry.date = entryHolding.date
}
newEntry.aircraftID = entryHolding.aircraftID
newEntry.aircraftSelect = LoadData.shared.aircraftArray[aircraftArrayIndexPath!.row]
newEntry.categoryAndClass = newEntry.aircraftSelect?.categoryAndClass
newEntry.typeCode = entryHolding.typeCode
newEntry.from = entryHolding.from
newEntry.to = entryHolding.to
newEntry.route = entryHolding.route
newEntry.totalTime = entryHolding.totalTime
newEntry.pic = entryHolding.PIC
newEntry.sic = entryHolding.SIC
newEntry.solo = entryHolding.solo
newEntry.dual = entryHolding.dual
newEntry.crossCountry = entryHolding.crossCountry
newEntry.night = entryHolding.night
newEntry.simInstrument = entryHolding.simInstrument
newEntry.actualInstrument = entryHolding.actualInstrument
newEntry.hold = Int16(entryHolding.hold)
newEntry.dayLanding = Int16(entryHolding.dayLanding)
newEntry.nightLanding = Int16(entryHolding.nightLanding)
newEntry.bfr = entryHolding.BFR
newEntry.checkride = entryHolding.checkRide
newEntry.ipc = entryHolding.IPC
newEntry.comments = entryHolding.comments
for i in 0..<approach.count {
var newApproach = IFRApproaches(context: LoadData.shared.context)
newApproach.airport = approach[i].airportID
newApproach.typeOfApproach = approach[i].type
newApproach.runway = approach[i].runwayNum
//newApproach.entry = newEntry
newEntry.addToApproaches(newApproach)
LoadData.shared.approachArray.append(newApproach)
}
LoadData.shared.entryArray.append(newEntry)
LoadData.shared.saveData()

Related

How do I populate a LiteDB database if some of my values are null

I am populating a dataGridView from an incomplete excel spreadsheet and generating the LiteDB from the dataGridView. Before the recent update, I wasn't having any issues. Now I am getting the error 'Objects cannot be cast from DBNull to other types'. I can work around this by including dummy values in the original spreadsheet. But ultimately we need to see what information we're missing. How can I accomplish this?
public void CreateDatabase()
{
using (var db = new LiteDatabase(#"C:\Users\BThatcher\Documents\_Personal\Revit\MDL-Sheets\SheetDatabase04.db")) //< ----------------
{
var sheets = db.GetCollection<Sheet>("sheets");
foreach (DataGridViewRow row in dataGridView2.Rows)
{
var sheet = new Sheet
{
SheetSequence = Convert.ToInt32(row.Cells[0].Value),
SheetNumber = row.Cells[1].Value.ToString(),
SheetName = row.Cells[2].Value.ToString(),
AreaNumber = Convert.ToInt32(row.Cells[3].Value),
AreaName = row.Cells[4].Value.ToString(),
SheetDiscipline = row.Cells[5].Value.ToString(),
DisciplineSort = Convert.ToInt32(row.Cells[6].Value),
SheetSort = Convert.ToInt32(row.Cells[7].Value),
ModelName = row.Cells[8].Value.ToString(),
AppearsInSheetlist = row.Cells[9].Value.ToString(),
DesignedBy = row.Cells[10].Value.ToString(),
DrawnBy = row.Cells[11].Value.ToString(),
CheckedBy = row.Cells[12].Value.ToString(),
ApprovedBy = row.Cells[13].Value.ToString(),
SheetTotal = Convert.ToInt32(row.Cells[14].Value),
DesignSoftware = row.Cells[15].Value.ToString(),
HasPdf = row.Cells[16].Value.ToString(),
PdfPath = row.Cells[17].Value.ToString(),
};
sheets.Insert(sheet);
this.Close();
}
}
}
This error are not from LiteDB (there is no DBNull in LiteDB). It's possible this DBNull are getting from row.Cells[n].Value when you try to convert.
LiteDB support nulls and nullable values (like int?).

concurrent user registration in laravel to mongodb

Controller code
$profileDetailsobj = new \stdClass();$profile = [];
// dd($workshop);
if ($workshop->isPublish == 1 && $course_id) {
// dd("as");
$profile['profileId'] = uniqid().$request->input('first_name').time();
$profile['courseId']=$course_id;
$profile['name'] = $request->input('salutation')." ".$request->input('first_name')." ".$request->input('last_name');
$profileDetailsobj->profileDetails[] = $profile;
$workshop->registeredProfiles = $profileDetailsobj;
$workshop->save();
}
This is my code I want to register multiple user entry to mongodb now its only adding only one entry. How to make as multiple ?

PSI update resource custom field with lookup table (Project Server)

Can someone show me a code to update a enterprise resource custom field with lookup table ? Already ran the internet looking for some sample code but did not succeed.
You can create and update a custom field with a lookup table using the below code . But we can not update or delete builtin custom fields
var projContext = new ProjectContext(projectServerUrl);
CustomFieldCollection CustomField = projContext.CustomFields;
EntityTypes Entitytype = projContext.EntityTypes;
LookupTableCollection lookupTables = projContext.LookupTables;
projContext.Load(CustomField);
projContext.Load(Entitytype);
projContext.Load(lookupTables);
projContext.ExecuteQuery();
CustomFieldCreationInformation NewfieldInfo = new CustomFieldCreationInformation();
NewfieldInfo.Id = new Guid();
NewfieldInfo.Name = "The Name";
NewfieldInfo.Description = "The Description";
NewfieldInfo.IsWorkflowControlled = true;
NewfieldInfo.IsRequired = true;
NewfieldInfo.IsEditableInVisibility = false;
NewfieldInfo.IsMultilineText = false;
LookupTable lookuptable = lookupTables.ToList().Find(x => x.Name == "LookupTableName");
projContext.Load(lookuptable);
projContext.ExecuteQuery();
NewfieldInfo.LookupTable = lookuptable;
NewfieldInfo.EntityType = Entitytype.ProjectEntity;
NewfieldInfo.FieldType = CustomFieldType.TEXT;
projContext.CustomFields.Add(NewfieldInfo);
projContext.CustomFields.Update();
projContext.ExecuteQuery();

Entity Framework 6 and Async() Performance

i have a question about Entity Framework 6 and ToListAsync()/ToList().
if i have a little amount of data (around 1000 rows) i have noticed that ToListAsync() is faster than ToList().
But if i have a huge amount of data (around 600.000 rows) ToList() is faster than ToListAsync().
Here you can fine the code, someone can explain me why?.
//SharedAnagra contains around 1000 rows
static List<SharedAnagra> GetSharedAnagraList()
{
using (Intranet2k3Entities intranet2K3Entities = new Intranet2k3Entities())
{
List<SharedAnagra> listaSharedAnagras = (from a in intranet2K3Entities.sharedAnagra
select new SharedAnagra
{
AnagraActive = a.AnagraActive,
AnagraId = a.AnagraID,
AnagraName = a.AnagraName,
OfficeId = a.OfficeID
}).ToList();
return listaSharedAnagras;
}
}
static async Task<List<SharedAnagra>> GetSharedAnagraListAsync()
{
using (Intranet2k3Entities intranet2K3Entities = new Intranet2k3Entities())
{
List<SharedAnagra> listaSharedAnagras = await (from a in intranet2K3Entities.sharedAnagra
select new SharedAnagra
{
AnagraActive = a.AnagraActive,
AnagraId = a.AnagraID,
AnagraName = a.AnagraName,
OfficeId = a.OfficeID
}).ToListAsync();
return listaSharedAnagras;
}
}
//sharedAnagraNDGClienti contains 950000 rows
static List<SharedAnagraNdgClienti> ListaSharedNdgClienti()
{
using (Intranet2k3Entities intranet2K3Entities = new Intranet2k3Entities())
{
List<SharedAnagraNdgClienti> lista = (from a in intranet2K3Entities.sharedAnagraNDGClienti
select new SharedAnagraNdgClienti
{
Cm = a.CM,
CodFisc = a.CodFisc,
Cognome = a.Cognome,
Descrizione = a.Descrizione,
FilialePrevalente = a.Filiale_Prevalente,
Ndg = a.NDG,
Nome = a.Nome,
Telefono = a.Telefono,
Tipologia = a.Tipologia,
Trae = a.TRAE,
Tsae = a.TSAE
}).AsNoTracking().ToList();
return lista;
}
}
static async Task<List<SharedAnagraNdgClienti>> GetIssueTypeByIdAsync()
{
List<SharedAnagraNdgClienti> listaSharedAnagraNdgClienti;
using (Intranet2k3Entities intranet2K3Entities = new Intranet2k3Entities())
{
listaSharedAnagraNdgClienti = await (from a in intranet2K3Entities.sharedAnagraNDGClienti
select new SharedAnagraNdgClienti
{
Cm = a.CM,
CodFisc = a.CodFisc,
Cognome = a.Cognome,
Descrizione = a.Descrizione,
FilialePrevalente = a.Filiale_Prevalente,
Ndg = a.NDG,
Nome = a.Nome,
Telefono = a.Telefono,
Tipologia = a.Tipologia,
Trae = a.TRAE,
Tsae = a.TSAE
}).AsNoTracking().ToListAsync();
}
return listaSharedAnagraNdgClienti;
}
I think this is not a problem of your query.This is an issue of EF 6+ framework itself.I personally didn't do any R&D about Asyn vc Sync.But I have found out some useful posts about that.Hope that will help to you.
When to really use async ?
In most applications using async will have no noticeable benefits and
even could be detrimental. Use tests, profiling and common sense to
measure the impact of async in your particular scenario before
committing to it.
Here is that article : Async Query & Save (EF6 onwards)
And here is the Great research done by one of the Stackoveflow user.You can read that too.Great one.
Entity Framework async operation takes ten times as long to complete

Add Hyperlink to Cell in Excel 2007 Using Open XML SDK 2.0

I can't seem to find any documentation or code samples on how to add a hyperlink to a cell in Excel 2007 using the Open XML SDK 2.0. I am using the following code, but is there a step I am missing?
WorksheetPart workSheetPart = ExcelUtilities.GetWorkSheetPart(mWorkBookPart, "Program");
workSheetPart.AddHyperlinkRelationship(new Uri("http://www.google.com", UriKind.Absolute), true);
workSheetPart.Worksheet.Save();
mWorkBookPart.Workbook.Save();
Then when I try and open the Excel document it says the file is corrupted because the Relationship Id for the hyperlink cannot be found. How do you setup or create that Relationship Id?
Another possibility, (which I used), is to use the HYPERLINK formula for Excel. I needed to create individual hyperlinks in each cell, yet the cells had to display different text, (I had to display tracking numbers in the cells yet have a hyperlink for each tracking number to the carrier's site and had to handle multiple carriers).
Once I instantiated an individual cell, the formula was applied in this manner to each cell (there are undoubtedly numerous way):
// ...
Cell cell1 = new Cell(){ CellReference = "A1", StyleIndex = (UInt32Value)1U, DataType = CellValues.InlineString };
CellValue cellValue1 = new CellValue();
CellFormula cellFormula1 = new CellFormula() { Space = SpaceProcessingModeValues.Preserve };
cellFormula1.Text = #"HYPERLINK(""http://www.theclash.com"", ""Radio Clash"")";
cellValue1.Text = "Radio Clash";
cell1.Append(cellFormula1);
cell1.Append(cellValue1);
// append cell, etc.
In this way, I was able to create individual hyperlinks and text for each cell. By the way, the links will appear with the default font color unless you reference a style with blue font.
Hope this helps.
I was able to add a hyperlink to a cell using System.IO.Packaging code:
private void HyperlinkCreate(PackagePart part, XmlNamespaceManager nsm, XmlNode _cellElement, string CellAddress)
{
Uri _hyperlink = new Uri("http://www.yahoo.com");
XmlNode linkParent = _cellElement.OwnerDocument.SelectSingleNode("//d:hyperlinks", nsm);
if (linkParent == null)
{
// create the hyperlinks node
linkParent = _cellElement.OwnerDocument.CreateElement("hyperlinks", #"http://schemas.openxmlformats.org/spreadsheetml/2006/main");
XmlNode prevNode = _cellElement.OwnerDocument.SelectSingleNode("//d:conditionalFormatting", nsm);
if (prevNode == null)
{
prevNode = _cellElement.OwnerDocument.SelectSingleNode("//d:mergeCells", nsm);
if (prevNode == null)
{
prevNode = _cellElement.OwnerDocument.SelectSingleNode("//d:sheetData", nsm);
}
}
_cellElement.OwnerDocument.DocumentElement.InsertAfter(linkParent, prevNode);
}
string searchString = string.Format("./d:hyperlink[#ref = '{0}']", CellAddress);
XmlElement linkNode = (XmlElement)linkParent.SelectSingleNode(searchString, nsm);
XmlAttribute attr;
if (linkNode == null)
{
linkNode = _cellElement.OwnerDocument.CreateElement("hyperlink", #"http://schemas.openxmlformats.org/spreadsheetml/2006/main");
// now add cell address attribute
linkNode.SetAttribute("ref", CellAddress);
linkParent.AppendChild(linkNode);
}
attr = (XmlAttribute)linkNode.Attributes.GetNamedItem("id", #"http://schemas.openxmlformats.org/officeDocument/2006/relationships");
if (attr == null)
{
attr = _cellElement.OwnerDocument.CreateAttribute("r", "id", #"http://schemas.openxmlformats.org/officeDocument/2006/relationships");
linkNode.Attributes.Append(attr);
}
PackageRelationship relationship = null;
string relID = attr.Value;
if (relID == "")
relationship = part.CreateRelationship(_hyperlink, TargetMode.External, #"http://schemas.openxmlformats.org/officeDocument/2006/relationships/hyperlink");
else
{
relationship = part.GetRelationship(relID);
if (relationship.TargetUri != _hyperlink)
relationship = part.CreateRelationship(_hyperlink, TargetMode.External, #"http://schemas.openxmlformats.org/officeDocument/2006/relationships/hyperlink");
}
attr.Value = relationship.Id;
}
I then translated this code using the Open XML SDK 2.0 and it doesn't work. It seems the AddHyperlinkRelationship method doesn't actually add the relationship to the .rels file. I'm not sure why, but it sure seems like a bug to me.
private void HyperlinkCreate(PackagePart part, XmlNamespaceManager nsm, XmlNode _cellElement, string CellAddress)
{
WorksheetPart workSheetPart = ExcelUtilities.GetWorkSheetPart(mWorkBookPart, "Program");
Uri hyperlinkUri = new Uri("http://www.yahoo.com", UriKind.Absolute);
Hyperlinks hyperlinks = workSheetPart.Worksheet.Descendants<Hyperlinks>().FirstOrDefault();
// Check to see if the <x:hyperlinks> element exists; if not figure out
// where to insert it depending on which elements are present in the Worksheet
if (hyperlinks == null)
{
// Create the hyperlinks node
hyperlinks = new Hyperlinks();
OpenXmlCompositeElement prevElement = workSheetPart.Worksheet.Descendants<ConditionalFormatting>().FirstOrDefault();
if (prevElement == null)
{
prevElement = workSheetPart.Worksheet.Descendants<MergeCells>().FirstOrDefault();
if (prevElement == null)
{
// No FirstOrDefault needed since a Worksheet requires SheetData or the excel doc will be corrupt
prevElement = workSheetPart.Worksheet.Descendants<SheetData>().First();
}
}
workSheetPart.Worksheet.InsertAfter(hyperlinks, prevElement);
}
Hyperlink hyperlink = hyperlinks.Descendants<Hyperlink>().Where(r => r.Reference.Equals(CellAddress)).FirstOrDefault();
if (hyperlink == null)
{
hyperlink = new Hyperlink() { Reference = CellAddress, Id = string.Empty };
}
HyperlinkRelationship hyperlinkRelationship = null;
string relId = hyperlink.Id;
if (relId.Equals(string.Empty))
{
hyperlinkRelationship = workSheetPart.AddHyperlinkRelationship(hyperlinkUri, true);
}
else
{
hyperlinkRelationship = workSheetPart.GetReferenceRelationship(relId) as HyperlinkRelationship;
if (!hyperlinkRelationship.Uri.Equals(hyperlinkUri))
{
hyperlinkRelationship = workSheetPart.AddHyperlinkRelationship(hyperlinkUri, true);
}
}
hyperlink.Id = hyperlinkRelationship.Id;
hyperlinks.AppendChild<Hyperlink>(hyperlink);
workSheetPart.Worksheet.Save();
}
You should be adding it to an object that accepts hyperlinks, such as a cell, instead of the worksheet. Something like this should work for you:
using DocumentFormat.OpenXml.Spreadsheet;
using DocumentFormat.OpenXml;
namespace GeneratedCode
{
public class GeneratedClass
{
// Creates an Worksheet instance and adds its children.
public Worksheet GenerateWorksheet()
{
Worksheet worksheet1 = new Worksheet(){ MCAttributes = new MarkupCompatibilityAttributes(){ Ignorable = "x14ac" } };
worksheet1.AddNamespaceDeclaration("r", "http://schemas.openxmlformats.org/officeDocument/2006/relationships");
worksheet1.AddNamespaceDeclaration("mc", "http://schemas.openxmlformats.org/markup-compatibility/2006");
worksheet1.AddNamespaceDeclaration("x14ac", "http://schemas.microsoft.com/office/spreadsheetml/2009/9/ac");
SheetDimension sheetDimension1 = new SheetDimension(){ Reference = "A1" };
SheetViews sheetViews1 = new SheetViews();
SheetView sheetView1 = new SheetView(){ TabSelected = true, WorkbookViewId = (UInt32Value)0U };
sheetViews1.Append(sheetView1);
SheetFormatProperties sheetFormatProperties1 = new SheetFormatProperties(){ DefaultRowHeight = 14.4D, DyDescent = 0.3D };
SheetData sheetData1 = new SheetData();
Row row1 = new Row(){ RowIndex = (UInt32Value)1U, Spans = new ListValue<StringValue>() { InnerText = "1:1" }, DyDescent = 0.3D };
Cell cell1 = new Cell(){ CellReference = "A1", StyleIndex = (UInt32Value)1U, DataType = CellValues.SharedString };
CellValue cellValue1 = new CellValue();
cellValue1.Text = "0";
cell1.Append(cellValue1);
row1.Append(cell1);
sheetData1.Append(row1);
Hyperlinks hyperlinks1 = new Hyperlinks();
Hyperlink hyperlink1 = new Hyperlink(){ Reference = "A1", Id = "rId1" };
hyperlinks1.Append(hyperlink1);
PageMargins pageMargins1 = new PageMargins(){ Left = 0.7D, Right = 0.7D, Top = 0.75D, Bottom = 0.75D, Header = 0.3D, Footer = 0.3D };
worksheet1.Append(sheetDimension1);
worksheet1.Append(sheetViews1);
worksheet1.Append(sheetFormatProperties1);
worksheet1.Append(sheetData1);
worksheet1.Append(hyperlinks1);
worksheet1.Append(pageMargins1);
return worksheet1;
}
}
}
Easiest way is to use the HyperLink formular, but the links aren't blue by default, this is why the styleIndex is set.
private Cell BuildHyperlinkCell(string url) =>
new Cell
{
DataType = new EnumValue<CellValues>(CellValues.String),
CellFormula = new CellFormula($"HyperLink(\"{url}\")"),
StyleIndex = 4u
};
Adding the styling to the workbook:
http://www.dispatchertimer.com/tutorial/how-to-create-an-excel-file-in-net-using-openxml-part-3-add-stylesheet-to-the-spreadsheet/