How to Correct Error: Can't Find Mean of List with no numbers - netlogo

I'm trying to get turtles (foragers) to move based on a reporter of mean nest-scent, which should report the mean of nest-scent spread throughout the world, from a high of 200 at the nest to 120 at the opposite corners of the world. However, at the nest, the error below is triggered, and I don't understand why. Isn't a mean nest-scent a list of numbers? How do I correct this error?
Can't find the mean of a list with no numbers: [].
error while forager 7 running MEAN
called by procedure MEAN-NEST-SCENT-IN-CONE
to-report mean-nest-scent-in-cone [cone-distance angle angle-width ] ; ant procedure - reports the mean amount of nest-scent in cone
rt angle
let p patches in-cone cone-distance angle-width
;ask p [ show chemical ]
if p = nobody [report 0]
lt angle
report (mean [nest-scent] of p)
end
`````````````````````````````````

You set up 'p' as a patchset but you are testing whether it is 'nobody'. The primitive for agentsets is any?. Try replacing:
if p = nobody [report 0]
lt angle
report (mean [nest-scent] of p)
with
ifelse any? p
[ lt angle
report mean [nest-scent] of p
]
[ report 0 ]

Related

Netlogo: measure mean distance between start and end patches

I am teaching myself how to create ABMs in Netlogo using the book of Railsback & Grimm 2012. I am having trouble with one book exercise which is on butterflies following "virtual" corridors. Basic idea is that butterflies go uphill for mating using the differences in height as guide. I need to calculate the width of the corridors dividing the number of patches used by the butterflies over the average distance the butterflies fly from the start patch to the end patch. I am
struggling with plotting this corridor width, which I am coding like this:
to-report corridor-width
let patches-visited count patches with [used?]
let mean-distance mean [distance start-patch] of turtles
report patches-visited / mean-distance
I then created a plot in the interface with the command:
plot corridor-width
The error message I get reads:
Division by zero. error while observer running / called by procedure
CORRIDOR-WIDTH called by plot 'Corridor width' pen 'default' update
code called by procedure SETUP called by Button 'setup'
I believe there is something wrong with the way I am coding distance start-patch but I have surfed the web and looked at several codes and I cannot spot my mistake. My whole code looks like this:
globals [ q ] ;; q is the probability that butterfly moves directly to highest patch
turtles-own [ start-patch ]
patches-own [ elevation used? ] ;; patches property of elevation and whether the patch has been used by butterfly or not.
to setup
ca
;; Let's create patches and asign them an elevation and color by using ask patches statement
ask patches
[
;; Elevation decreases linearly with distance from the center of hills. Hills are at (30,30) and
;; (120,120) coordinates. The first hill is 100 units high whereas the second one is 50
let elev1 100 - distancexy 30 30
let elev2 50 - distancexy 120 100
ifelse elev1 > elev2
[ set elevation elev1 ]
[ set elevation elev2 ]
set pcolor scale-color green elevation 0 100
set used? false
]
;; Create 50 butterflies
crt 50
ask turtles [
set size 6
;; set their initial location as their initial patch
setxy random-pxcor random-pycor
set start-patch patch-here
;; have the butterfly draw its path with the pen-down statement
pen-down
]
reset-ticks
;; Initialize the q parameter
set q 0.4
end
;; The master schedule
to go
ask turtles [ move ]
plot corridor-width
tick
if ticks >= 1000
[
let final-corridor-width corridor-width
write "Corridor width: " print final-corridor-width
;export-plot "Corridor width" (word "Corridor-width-output-for-q-" q ".csv")
stop
]
end
;; let's code the butterfly procedure of movement
to move
if elevation >=
[ elevation ] of max-one-of neighbors [ elevation ]
[ stop ]
ifelse random-float 1 < q ;; Decide whether to move to the highest sorrounding
;; patch with p=q
[ uphill elevation ] ;; move deterministically uphill
[ move-to one-of neighbors ] ;; or move randomly
set used? true
end
to-report corridor-width
let patches-visited count patches with [used?]
let mean-distance mean [distance start-patch] of turtles
report patches-visited / mean-distance
end
What happens when the mean-distance is 0?
let mean-distance mean [distance start-patch] of turtles
Essentially, in your setup, you set all the turtle's start-patch to their current patch. So, if you ask all the turtles how far away they are from their start patch, they will all tell you 0 units away.
So, [distance start-patch] of turtles is filled with a list of all 0's.
Thus, a mean of a list of all 0s is 0 causing your divide by 0 error.
Maybe in this situation, you want to report 0 instead...so
ifelse mean-distance = 0
[ report 0]
[report patches-visited / mean-distance]

Q: How to calculate 'hub integration' / how many of your link-neighbors are also my link-neighbors?

In the model I am building I need to make turtles calculate the 'hub integration' of their link-neighbors. By 'hub integration'(HI) I mean the following: HI = number-of-shared-neighbors/n-of-your-neighbors.
HI is a value that the 'turtle x' assigns to every other turtle that shares a link with her (we will call every linked turtles as 'turtle y'). The value of HI is thus the fraction of the number of nodes that are linked to both turtles x and y, with the number of nodes linked to turtle y.
I am using as references the Netlogo dictionary and the book 'An Introduction to Agent-Based Modeling' from Wilensky and Rand. Still, without the help of this community it would be really hard for me, if not impossible, to learn more advanced procedures.
EDIT 3 ---
I am greatly thankful for all the help received. I finally have a running procedure.
For the record, my final code of the 'hub integration procedure' is the following:
to find-hi
ask turtles [
foreach sort link-neighbors [
ask ? [
if count [my-links] of self > 1 and count [my-links] of myself > 1 [
let hi ( calc-HI self myself )
run-procedure ] ] ] ]
end
to-report calc-HI [ XX YY ]
let sizeX count [my-links] of XX
let sizeY count [my-links] of YY
let sizeXY count (turtle-set [link-neighbors] of XX [link-neighbors] of YY)
report (sizeX + sizeY - sizeXY) / sizeY
end
I think you want to count the number of neighbours, not list them all out.
One approach to count the number in common is to count the neighbours of X, count the neighbours of Y and count the agents who are either neighbours of X or Y. A turtle who is a neighbour of both X and Y will still only appear once in the agentset constructed, so the size of the intersection is the sum of the individual counts then subtract the size of the union.
This code expects you to nominate two turtles and reports the HI of turtle YY from the perspective of turtle XX (note that there is no checking that the two turtles have a link between them). I am not sure I have understood the calculation that you want, but you can amend as required.
to-report calc-HI [ XX YY ]
let sizeX count [my-links] of XX
let sizeY count [my-links] of YY
let sizeXY count (turtle-set [link-neighbors] of XX [link-neighbors] of YY)
report (sizeX + sizeY - sizeXY) / sizeY
end
You're using print in your reporter, try using report instead.
E.G.:
to-report who-of-neighbors
report [who] of link-neighbors
end
More info on to-report right here.

NetLogo: How to pull coordinates from neighboring patches based on patch-variable

I have limited programming experience (mechanical engineering student, so a bit of matlab and labview experience) and am very new to NetLogo, so I apologize in advance if this question is pretty basic or my code is of poor quality.
I need to have my turtles move to 1 of 2 possible neighboring patches based on a given probability function. The two patches that I need to input to the probability function are the two neighboring patches with the lowest nest-scent value. I have been able to pull the two lowest nest-scent values, but I cannot figure out how to actually figure out which patches those are, and how to put those coordinates into an ifelse statement to move the turtle to one of them based on the aformentioned probability function. I have the following code that is obviously not working:
to move
set farthest-patch sort-by < [nest-scent] of neighbors
let a1x pxcor of item 0 farthest-patch
let a1y pycor of item 0 farthest-patch
let a2x pxcor of item 1 farthest-patch
let a2y pycor of item 1 farthest-patch
let a1 item 0 farthest-patch
let a2 item 1 farthest-patch
let x (((a1 + a2) / 100 ) - 1)
let probability-move 0.5 * (1 + ((exp(x) - exp( - x)) / (exp(x) + exp( - x))))
ifelse random-float 1 < probability-move
[set to-move 1]
[set to-move 0]
let a1-probability (a1 / (a1 + a2))
ifelse random-float 1 < a1-probability
[set destination [a1x a1y]]
[set destination [a2x a2y]]
ifelse count turtles-here >= 20
[set full 1]
[set full 0]
if [a1x a21] = full
[set destination [a2x a2y]]
if [a2x a2y] = full
[set destination [a1x a1y]]
if [a2x a2y] and [a1x a1y] = full
[set to-move 0]
ifelse to-move = 1
[move-to destination]
[stop]
end
Basically what I have (tried) to do here is sort a farthest-patches list by increasing nest-scent, and I have pulled the two lowest nest-scent values in order to input those values into my probability functions (both for whether or not to move, and if they are to move which of the two patches to select). I am not sure how to properly pull the patch coordinates of the patches that the a1 and a2 values were taken from.
Thanks for any help,
Brad
okay, you are making life way more complicated than it needs to be. You can select the two patches (or turtles) with the smallest values of a variable with min-n-of. Look it up in the dictionary to get the details.
Having found the two candidates, the best option is to use the rnd extension for choosing the destination because it has a primitive for random selection by weight. Finally, since you are using a function of your variable as the weight (rather than the variable value itself), you need a way to construct that weight. The best option is to separate it out - you could also have a second variable with the weight value, but that just proliferates variables.
Here is a complete working model. Please copy the whole thing into a new instance of NetLogo and try and understand how it works, rather than just copy the relevant bits into your code because min-n-of, using agentsets and passing variables to procedures are important aspects of NetLogo that you need to know about. I have also set up colouring etc so you can see the choices it makes.
extensions [rnd]
patches-own [ nest-scent ]
to setup
clear-all
create-turtles 1 [ set color red ]
ask patches
[ set nest-scent random 100
set plabel nest-scent
]
reset-ticks
end
to go
ask one-of turtles [ move ]
tick
end
to move
set pcolor blue
let targets min-n-of 2 neighbors [ nest-scent ]
let destination rnd:weighted-one-of targets [ calc-weight nest-scent ]
move-to destination
end
to-report calc-weight [ XX ]
let weight 0.5 * (1 + ((exp(XX) - exp( - XX)) / (exp(XX) + exp( - XX))))
report weight
end

Find the presence of other turtles in a given direction upto a distance

I wish to find out whether in a given turtle's heading there is another agent present upto a given distance.
Here the Distance is "D".
Note:
Any agent present before D in the given direction should be also considered.
Even the direction doesn't coincide with the other's agent centre but just touches it ,even then that agent should be considered.
Problem:
No turtle-ahead procedure available. Combination of patch-ahead and turtles-on not applicable due to patch-size>> turtle-size.
Possible approach:
1.Represent the turtle's heading by the equation of a line.
to-report calculate-line[x y angle]
let m tan angle
let A m
let B -1
let C (- m * x + y)
report (list A B C)
end
to-report heading-to-angle [ h ]
report (90 - h) mod 360
end
let line-equ calculate-line (xcor) (ycor) (heading-to-angle heading)
2.Calculate the perpendicular distance from other turtles here, Check if there are within a range that the size of other turtles.
to-report value[A X1 Y1];;A is list of coefficents of line, x1 and y1 are coordinates of red turtle
if-else(abs((item 0 A * X1 + item 1 A * Y1 + item 2 A) / (sqrt((item 0 A ^ 2) + (item 1 A ^ 2) ))) < [size] of wall )
[ report "true"][report "false"]
end
3.To check if the red turtle is within D. One could obtain a line perpendicular to black one and compute the red turtle distance from it to check if it is less than or equal to D. But then that adds more complication.(Though one can simplify rotate the turtle by 90 left or right and get the line equation.)
This is what I meant by my comment. Run this code (as its own model). What it does is turn all the turtles on a few 'ahead' patches a different colour. I know this is not what you are trying to do, but the agentset candidates is a relatively small number of turtles. These are the only ones that you have to check whether they are on the correct path. So instead of turning them a different colour you could check the direction that they are from your initial turtle.
to setup
clear-all
set-patch-size 25
resize-world -10 10 -10 10
create-turtles 1000
[ setxy random-xcor random-ycor
set color yellow
set size 0.4
]
ask one-of turtles
[ set color red
set size 1
check-from-me 5
]
end
to check-from-me [howfar]
let counter 0
let candidates turtles-here
while [counter < howfar]
[ set counter counter + 1
set candidates (turtle-set candidates turtles-on patch-ahead counter)
]
ask candidates [set color red]
end
to-report check-wall
let return false
hatch 1[
set color black
set size ([size] of one-of walls) / 2
show (2.5 * ([size] of myself))
while [distance myself < (2.5 * ([size] of myself))]
[
fd ([size] of one-of walls) / 64
if any? walls in-radius size
[
set return true
]
show distance myself
]
]
report return
end
The above works. But still is approx. I am looking for better solution with probably less maths as one elucidated in the question.

What is the most efficient way to ask other turtle who can see the caller turtle in NetLogo?

I was wondering if anyone has a good idea to filter turtles who have the caller turtle in their vision and in their cone of vision with the least computational cost?
Now I am using something like this:
Member? Caller-Agent agents in-cone 5 100
or just who are agents who can see me?
I was wondering if anyone knows how can I check if heading of other agents in some radius X is toward the caller agent ?
So , this is the way I did it:
I used abs( towards myself - heading) < 50
I thought it might include cone with angle of 100 since it uses absolute value.
This is just a test program to see if it works:
ask turtles[set label "" set color green]
ask turtle 7 [
set color red
set label "Caller"
ask other (turtles with [distance myself <= 3 and abs( towards myself - heading) < 50 ])
[
set color yellow
]
ask other turtles [
set label (Member? turtle 7 Other turtles in-cone 3 100)
]
]
and this one cone 80 and abs( towards myself - heading) < 40 :
There is a problem with this approach:
if an agent is as same location of the caller then I will get the error that there is no heading defined to same point or something like that!
Error is : No heading is defined from a point (7,7) to that same point. error while turtle 28 running TOWARDS
Update:
[(distance myself <= 3 and distance myself > 0 and abs( subtract-headings towards myself heading ) < 60) or distance myself = 0 ]