I have a formula that calculates a number based on the response from a google form. Depending on what this number I want to send an email using details from the from as well as a pre typed email in another cell.
In Col1 is a time stamp, in col14 is an employee start date. My formula in Col33 works out how many days they have been employed at the time of submitting the form.
I want to send an email to the person if the number of days is less than 182.
I have an email pre typed out and can place this anywhere. At the moment I have it in all cells in col36. The email address will be in column32.
I have tried a number of different codes and none of them are sending the email no matter what the trigger I have set up is. I have very basic knowledge on apps script so my current code might be completely wrong, but it should show roughly what I'm getting at.
function sendEmail() {
var values = SpreadsheetApp.getActiveSheet().getDataRange().getValues()
for (i in values.length) {
var data = values[i][33];
var emailAddress = values[i][32];
var message = values[i][36];
if (data < 182); {
MailApp.sendEmail(emailAddress, "Flexible Working Request", message);
}
}
}
The current results have just been deleting the data in col33, Col34 & Col36 on the new form response row only.
Sorry if this question has been answered elsewhere, any other answer I found to similar issues I could not get to work.
I got someone who is much better at google apps script at work to give me a hand
It is to do with google forms pushing down formulas to the side
So we had to move the formula calculating the number of days to another sheet and then used this formula which worked
function sendEmailv2() {
var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Form responses
1');
var scrip = Session.getScriptTimeZone();
var date = sheet.getRange(sheet.getLastRow(),14).getValue();
var sub = sheet.getRange(sheet.getLastRow(),1).getValue();
Logger.log(date);
var fortmat = Utilities.formatDate(new Date(date), scrip, "dd/MM/yyyy");
var Subfortmat = Utilities.formatDate(new Date(sub), scrip, "dd/MM/yyyy");
var emailAddress = sheet.getRange(sheet.getLastRow(),32).getValue();
var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet4');
var message = sheet2.getRange(1,1).getValue();
var days = sheet2.getRange(sheet2.getLastRow(),2).getValue();
if (days<182){
MailApp.sendEmail(emailAddress, "Flexible Working Request", message,{noReply:true});
}
}
Thanks!
You don’t need to go over all the columns to get a single cell value, so there is no need for a for loop. You can do it directly with:
var sheet = SpreadsheetApp.getActiveSheet().getSheets[0];
var cell = ["A33"];
var days_value = sheet.getRange(cell).getValue();
Then you can just make an if condition to send the email:
if (days_value < 182){
MailApp.sendEmail(emailAddress, "Flexible Working Request", message);
}
Hope this helps
I am editing an existing script that my team uses for a google form response sheet. The script automatically creates a message body using the headers and response cells for an order every time it is submitted, roughly like this:
Type of Order: Physical
Country: America
Digital Signature:
Favorite Color:
Favorite Food: Pasta
What I've been asked to do, is have the script read through the sheet and not include the header or response for questions that are not answered in any given submission. Like so, for the previous example:
Type of Order: Physical
Country: America
Favorite Food: Pasta
I should start by saying I have close to 0 experience in javascript or Google Apps. I have tried playing around with if clauses using both the len function and a negated isblank function to no avail. These all lead to undefined errors.
As you'll see, the original script was not created by me or the people who have been using it for the last few years.
Original script
function sendFormByEmail(e)
{
Logger.log('value of e is: ' + e);
var email = "xxx#xxx.com";
var s = SpreadsheetApp.getActiveSheet();
var headers = s.getRange(1,1,1,s.getLastColumn()).getValues()[0];
var message = "";
var subject = "Type A Request: ";
// The variable e holds all the form values in an array.
// Loop through the array and append values to the body.
// Insert variables from the spreadsheet into the subject.
// In this case, I wanted the new hire's name and start date in the
// email subject. These are the 3rd and 16th columns in my form.
for(var i in headers)
message += headers[i] + ': '+ e.namedValues[headers[i]].toString() + "\n\n";
subject += e.namedValues[headers[10]].toString() + " - " +
e.namedValues[headers[12]].toString();
MailApp.sendEmail(email, subject, message, {noReply:true});
// Based off of a script originally posted by Amit Agarwal - www.labnol.org
}
You can include a check for blank values inside the for loop.
if (e.namedValues[headers[i]].toString() === "") continue;
I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.
I am doing a card game in Meteor. Each played game is registered in the collection "Games".
A Games' record contain some of the game info as well as some players info and the cards hand of the players (players[i].cards, with values like 4S - 4 of spade, KH - king of heart...). Depending on the cards value, I can display the correct card to the frontend (div.card-KH).
Most of the game data is public but, of course, only the current player's cards must be visible.
One option could be to exclude the cards of the other players at publish time but I still need the number of cards to display the decks (only the remaining cards, hidden) of the other players.
Is there a way to replace the card value of each cards (except user's ones) in players[i].cards to, say, BACK (div.card-BACK) at publish time? Else, what would be the good design pattern to do this in Meteor?
Interesting question which I think there should be an official guideline to.
They have a bit in the docs about publishing:
http://docs.meteor.com/#/full/meteor_publish (secretinfo field only published to admins)
You could do the same but you would have to check the userId and have a player1secretinfo, player2secretinfo etc. (or perhaps a secretinfo array/object but then you would have to only publish one particular index/property)
You could also do a transform in the publications:
https://www.eventedmind.com/items/meteor-transforming-collection-documents
Please post it, if you find a good solution :)
Here is the only solution I found (I don't really like it but it works) :
Basically, you have to store a temporary document, with the same id but modified data, to another Collection, publish that document from that Collection and finally, from client side, subscribe to that publication.
Of course, never make hidden part of the original document available through another publication.
Meteor.publish('gameWithHiddenCards', function (gameId) {
var self = this;
//Transform function
var transform = function(item) {
for (var i=0; i<item.players.length; i++){
if ((item.players[i].id != self.userId))
for (var j = 0; j < item.players[i].cards.length; j++)
item.players[i].cards[j] = 'back';
return item;
};
/* 1. Observe changes in game ;
2. Apply transform function on game data ;
3. Store it to another Collection. */
var observer = Games.find({_id: gameId}).observe({
added: function (document) {
self.added('secure_games', document._id, transform(document));
},
changed: function (newDocument, oldDocument) {
self.changed('secure_games', newDocument._id, transform(newDocument));
},
removed: function (oldDocument) {
self.removed('secure_games', oldDocument._id);
}
});
self.onStop(function () {
observer.stop();
});
// Return altered game
return SecureGames.find({_id: gameId});
});
I would like to create a Google Sheets with event triggers. I'm using Google Apps Script.
I succeeded, thanks to Stack Overflow, to create a Google Sheets with an automatic mail notification when a cell is modified by a user.
Now I would like to know if this is possible when cell is modified by a function (not user's modification), such as :
if (today() >= B3 ; "late" ; "not late")
The function checks date, and give result "late" or "not late".
When deadlines are reached, the function would return "late" and a mail would be sent to warn me. The body mail would have the value of the cell in the B, D and E column and in the same row of the cell modified (I know how to do this using e.source, getRange and getRow)
So far, i've tried this, but it's not working
function sendNotification(e) {
if("F" == e.range.getA1Notation().charAt(0)) {
if(e.value == "Late") {
//Define Notification Details
var recipients = "user#example.com";
var subject = "Deadlines" ;
var body = "deadline reached";
//Send the Email
MailApp.sendEmail(recipients, subject, body);
}
}
}
How can I set up mail notifications when cells in F column have the "late" value (with "late" being the result of a function) ?
You can use a simple script that runs on a timer trigger and checks for any modification in a specific column in your sheet.
I use script like that for a lot of tasks, including calendar and sheets monitoring.
Below is a test code that works on column F, you have to run it once manually to create the scriptProperties value that I use to detect changes.
Then create a time trigger to run it every hour or any other timer value you find useful.
The only issue would be if you have a very long sheet, you could reach the length limit of the properties... (right now I don't remember the max length, will have to check ;-)
Code :
function checkColumnF() {
var sh = SpreadsheetApp.getActiveSheet();
var values = sh.getRange('F1:F').getValues().join('-');
if(PropertiesService.getScriptProperties().getKeys().length==0){ // first time you run the script
PropertiesService.getScriptProperties().setProperty('oldValues', values);
return;
}
var oldValues = PropertiesService.getScriptProperties().getProperty('oldValues').split('-');
var valuesArray = values.split('-');
while (valuesArray.length>oldValues.length){
oldValues.push('x'); // if you append some rows since last exec
}
Logger.log('oldValues = '+oldValues)
Logger.log('current values = '+valuesArray)
for(var n=0;n<valuesArray.length;n++){
if(oldValues[n] != valuesArray[n]){ // check for any difference
sendMail(n+1,valuesArray[n]);
}
}
PropertiesService.getScriptProperties().setProperty('oldValues', values);
}
function sendMail(row,val){
Logger.log('value changed on row '+row+' value = '+val+' , mail sent');
// uncomment below when you are sure everything runs fine to avoid sending dozens of emails while you test !
//MailApp.sendEmail(Session.getActiveUser().getEmail(),'value changed in your sheet','Row '+row+' is now '+val);
}