I want to use sed to replace some strings containing '^' in a text file
The original string (" are part of the string)
"POINT(5.94462 45.569924)^^geo:wktLiteral"
the expected substituted string
"POINT(5.94462 45.569924)"^^geo:wktLiteral
I've tried
sed -i 's/\^\^geo:wktLiteral\"/\"\^\^geo:wktLiteral/' myFile
or
sed -i 's/\x5e\x5egeo:wktLiteral\"/\"\x5e\x5egeo:wktLiteral/' myFile
these two solutions do not work.
Any help is welcome.
If you switch to the WSL Linux terminal, you can use a simpler
sed -i 's/\(\^\^geo:wktLiteral\)"/"\1/' file
Details
\(\^\^geo:wktLiteral\) - Group 1: ^^geo:wktLiteral string
" - a " char
"\1 - replacement: a " char and Group 1 value.
Related
I'm trying to replace strings with sed in ; php_value[date.timezone] = Europe/Riga
i tried something like this:
sed -i 's/; php_value[date.timezone] = Europe/\Riga/; php_value[date.timezone] = America/\Sao_Paulo/g' file
Output:
sed: -e expression #1, char 47: extra characters after command
You can use
sed -i 's/; php_value\[date\.timezone] = Europe\/Riga/; php_value[date.timezone] = America\/Sao_Paulo/g' file
See the online demo.
NOTE:
[ and . are special regex metacharacters and need to be escaped to match literal [ and ., hence, \[ and \. in the regex part
/ is a regex delimiter char here, and should also be escaped. To escape /, use \/. Well, if you use another regex delimiter char, you will have no need escaping /, e.g.
sed -i 's,; php_value\[date\.timezone] = Europe/Riga,; php_value[date.timezone] = America/Sao_Paulo,g' file
See the commas as regex delimiters here.
I want to extract an atomic symbols inside a parentheses using sed.
The data I have is in the form C(X12), and I only want the X symbol
EX: that a test command :
echo "C(Br12)" | sed 's/[0-9][0-9])$//g'
gives me C(Br.
You can use
sed -n 's/.*(\(.*\)[0-9]\{2\})$/\1/p'
See the online demo:
sed -n 's/.*(\(.*\)[0-9]\{2\})$/\1/p' <<< "c(Br12)"
# => Br
Details
-n - suppresses the default line output
.*(\(.*\)[0-9]\{2\})$ - a regex that matches
.* - any text
( - a ( char
\(.*\) - Capturing group 1: any text up to the last....
[0-9]\{2\} - two digits
)$ - a ) at the end of string
\1 - replaces with Group 1 value
p - prints the result of the substitution.
For example:
echo "C(Br12)" | sed 's/C(\(.\).*/\1/'
C( - match exactly literally C(
. match anything
\(.\) - match anythig - one character- and "remember" it in a backreference \1
.* ignore everything behind it
\1 - replace it by the stuff that was remembered. The first character.
Research sed, regex and backreferences for more information.
Try using the following command
echo "C(BR12)" | cut -d "(" -f2 | cut -d ")" -f1 | sed 's/[0-9]*//g'
The cut tool will split and get you the string in middle of the paranthesis.Then pass the string to a sed for replacing the numbers inside the string.
Not a fully sed solution but this will get you the output.
I have file with this text:
mirrors:
docker.io:
endpoint:
- "http://registry:5000"
registry:5000:
endpoint:
- "http://registry:5000"
localhost:
endpoint:
- "http://registry:5000"
I need to replace it with this text in POSIX shell script (not bash):
mirrors:
docker.io:
endpoint:
- "http://docker.io"
registry:5000:
endpoint:
- "http://registry:5000"
localhost:
endpoint:
- "http://localhost"
Replace should be done dynamically in all places without hard-coded names. I mean we should take sub-string from a first line ("docker.io", "registry:5000", "localhost") and replace with it sub-string "registry:5000" in a third line.
I've figure out regex, that splits it on 5 groups: (^ )([^ ]*)(:[^"]*"http:\/\/)([^"]*)(")
Then I've tried to use sed to print group 2 instead of 4, but this didn't work: sed -n 's/\(^ \)\([^ ]*\)\(:[^"]*"http:\/\/\)\([^"]*\)\("\)/\1\2\3\2\5/p'
Please help!
This might work for you (GNU sed):
sed -E '1N;N;/\n.*endpoint:.*\n/s#((\S+):.*"http://)[^"]*#\1\2#;P;D' file
Open up a three line window into the file.
If the second line contains endpoint:, replace the last piece of text following http:// with the first piece of text before :
Print/Delete the first line of the window and then replenish the three line window by appending the next line.
Repeat until the end of the file.
Awk would be a better candidate for this, passing in the string to change to as a variable str and the section to change (" docker.io" or " localhost" or " registry:5000") and so:
awk -v findstr=" docker.io" -v str="http://docker.io" '
$0 ~ findstr { dockfound=1 # We have found the section passed in findstr and so we set the dockfound marker
}
/endpoint/ && dockfound==1 { # We encounter endpoint after the dockfound marker is set and so we set the found marker
found=1;
print;
next
}
found==1 && dockfound==1 { # We know from the found and the dockfound markers being set that we need to process this line
match($0,/^[[:space:]]+-[[:space:]]"/); # Match the start of the line to the beginning quote
$0=substr($0,RSTART,RLENGTH)str"\""; # Print the matched section followed by the replacement string (str) and the closing quote
found=0; # Reset the markers
dockfound=0
}1' file
One liner:
awk -v findstr=" docker.io" -v str="http://docker.io" '$0 ~ findstr { dockfound=1 } /endpoint/ && dockfound==1 { found=1;print;next } found==1 && dockfound==1 { match($0,/^[[:space:]]+-[[:space:]]"/);$0=substr($0,RSTART,RLENGTH)str"\"";found=0;dockfound=0 }1' file
I need to replace a version string in a file. My search pattern is regex
and my replacement is a variable.
String search = "\\d+.\\d+.\\d+-.\\d+"
String replace = "1.0.0-${BUILD_ID}"
MyFile = "foo"
sh ("""
sed -i -r "s/($search/$replace/g)" $MyFile
""")
The result I am getting
+ sed -i -r s/(\d+.\d+.\d+-.\d+/1.0.0-25/g) foo
sed: bad option in substitution expression
I found the issue with my code. If I remove parenthesis (), the string replacement works as a charm.
I need to replace if ($_SESSION['POST']['*']==1){ with if (isset($_SESSION['POST']['*']) && $_SESSION['POST']['*']==1){
(I'm using * as a wild card)
I've tried sed -i "s/if ($_SESSION['POST']['.*']/if (isset($_SESSION['POST']['.*']) && $_SESSION['POST']['.*']/g" *.php and a few other variations without success.
Here goes...
sed "s/\(if (\)\(\$_SESSION\['POST']\['\([^']*\)']\)==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
Using double quotes means that the $ symbols must be escaped, otherwise they will be interpreted as shell variables. The square brackets need to be escaped, otherwise they will be interpreted as the beginning of a range. It's OK to leave the closing square brackets as they are.
In order to capture the key, I have used a character class [^']*. This means zero or more characters that are not a single quote.
In the replacement, the captured groups (the parts between parentheses in the match) are referred to using \1, \2, etc.
Testing it out:
$ cat file
if ($_SESSION['POST']['foo']==1){
// do something
}
if ($_SESSION['POST']['bar']==1){
// do something else
}
$ sed "s/\(if (\)\(\$_SESSION\['POST']\['\([^']*\)']\)==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
if (isset($_SESSION['POST']['foo']) && $_SESSION['POST']['foo']==1){
// do something
}
if (isset($_SESSION['POST']['bar']) && $_SESSION['POST']['bar']==1){
// do something else
}
By the way it makes the command a few characters shorter if you use extended regexp mode (-r or -E). In extended mode, the parentheses enclosing capture groups don't have to be escaped but literal ones do, so your command would then be:
sed -r "s/(if \()(\$_SESSION\['POST']\['([^']*)'])==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
This sed should work:
s="if (\$_SESSION['POST']['name']==1){"
sed -r 's/(if +)\((([^=]+)[^\)]+)/\1(isset(\3) \&\& \2/' <<< "$s"
if (isset($_SESSION['POST']['name']) && $_SESSION['POST']['name']==1){
PS: Use sed -E instead of sed -r on OSX.
Here's another.
This is what we need to produce:
Pattern: if (\$_SESSION\['POST'\]\['\([^']*\)'\]
Replacement: if (isset($_SESSION['POST']['\1']) \&\& $_SESSION['POST']['\1']
When quoted in shell level:
Pattern: "if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]"
Replacement: "if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']"
Putting it together:
sed -i "s|if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]|if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']|g" file
Test:
# sed "s|if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]|if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']|g" <<'EOF'
> if ($_SESSION['POST']['ABC']==1){
> EOF
if (isset($_SESSION['POST']['ABC']) && $_SESSION['POST']['ABC']==1){