Sed replace strings starts with special characters - sed

I'm trying to replace strings with sed in ; php_value[date.timezone] = Europe/Riga
i tried something like this:
sed -i 's/; php_value[date.timezone] = Europe/\Riga/; php_value[date.timezone] = America/\Sao_Paulo/g' file
Output:
sed: -e expression #1, char 47: extra characters after command


You can use
sed -i 's/; php_value\[date\.timezone] = Europe\/Riga/; php_value[date.timezone] = America\/Sao_Paulo/g' file
See the online demo.
NOTE:
[ and . are special regex metacharacters and need to be escaped to match literal [ and ., hence, \[ and \. in the regex part
/ is a regex delimiter char here, and should also be escaped. To escape /, use \/. Well, if you use another regex delimiter char, you will have no need escaping /, e.g.
sed -i 's,; php_value\[date\.timezone] = Europe/Riga,; php_value[date.timezone] = America/Sao_Paulo,g' file
See the commas as regex delimiters here.

Related

how to use '^' char in a replace expression

I want to use sed to replace some strings containing '^' in a text file
The original string (" are part of the string)
"POINT(5.94462 45.569924)^^geo:wktLiteral"
the expected substituted string
"POINT(5.94462 45.569924)"^^geo:wktLiteral
I've tried
sed -i 's/\^\^geo:wktLiteral\"/\"\^\^geo:wktLiteral/' myFile
or
sed -i 's/\x5e\x5egeo:wktLiteral\"/\"\x5e\x5egeo:wktLiteral/' myFile
these two solutions do not work.
Any help is welcome.

If you switch to the WSL Linux terminal, you can use a simpler
sed -i 's/\(\^\^geo:wktLiteral\)"/"\1/' file
Details
\(\^\^geo:wktLiteral\) - Group 1: ^^geo:wktLiteral string
" - a " char
"\1 - replacement: a " char and Group 1 value.

Need assistance with escapes in my groovy command

I need to replace a version string in a file. My search pattern is regex
and my replacement is a variable.
String search = "\\d+.\\d+.\\d+-.\\d+"
String replace = "1.0.0-${BUILD_ID}"
MyFile = "foo"
sh ("""
sed -i -r "s/($search/$replace/g)" $MyFile
""")
The result I am getting
+ sed -i -r s/(\d+.\d+.\d+-.\d+/1.0.0-25/g) foo
sed: bad option in substitution expression

I found the issue with my code. If I remove parenthesis (), the string replacement works as a charm.

Replace every " within string

I have lines in a text file which looks like this example:
"2009217",2015,3,"N","N","2","UPPER DARBY FIREFIGHTERS "PAC"","","","","7235 WEST CHESTER PIKE","","UPPER DARBY","PA","19082","","6106220269",4245.0100,650.0000,.0000
I want to replace every double quote in multiple partial strings similar to this "UPPER DARBY FIREFIGHTERS "PAC""across the whole file.
So the result should be as below for each instance of the recurring double quotes:
"2009217",2015,3,"N","N","2","UPPER DARBY FIREFIGHTERS PAC","","","","7235 WEST CHESTER PIKE","","UPPER DARBY","PA","19082","","6106220269",4245.0100,650.0000,.0000
I came to this sed line:
cat file.txt | sed "s/\([^,]*,[^,]*,[^,]*,[^,]*,[^,]*,[^,]*,\)\([^,]*\),\(.*\)/\1\2\3/"
But now I don't know how to replace the double quote within \2.
Is that possible with sed?

I would personally use awk for that because it is more readable:
#!/usr/bin/env awk
BEGIN {
# Use ',' as the input and output field delimiter
FS=OFS=","
}
{
# Iterate through all fields. (NF is the number of fields.)
for(i=1;i<=NF;i++) {
# If the field starts and ends with a '"'
if($i ~ /^".*"$/) {
# Replace all '""
gsub(/"/,"",$i)
# Wrap in '"' again
$i = "\"" $i "\""
}
}
}
print

This might work for you (GNU sed):
sed -r ':a;s/^((([^",]*,)*("[^",]*",([^",]*,)*)*)"[^",]*)"([^,])/\1\6/;ta' file
This removes extra double quotes from strings surrounded by double quotes and delimited by ,'s.
It does this by eliminating properly constructed double quotes strings and non-quoted strings (in this example numbers) and then removes double quotes that are not followed by ,
[^",]*, # non double quoted strings
"[^",]*", # properly quoted strings
(([^",]*,)*("[^",]*",([^",]*,)*)*) # eliminate all properly constructed strings
"[^",]*"([^,]) # improper double quotes
^
|

replace a line that contains a string with special characters

i want to replace lines which contains a string that has some special characters.
i used \ and \ for escape special characters but nothing changes in file.
i use sed like this:
> sed -i '/pnconfig\[\'dbhost\'\] = \'localhost\'/c\This line is removed.' tco.php
i just want to find lines that contains :
$pnconfig['dbhost'] = 'localhost';
and replace that line with:
$pnconfig['dbhost'] = '1.1.1.1';

Wrap the sed in double quotes as
sed -i "s/\(pnconfig\['dbhost'\] = \)'localhost'/\1'1.1.1.1'/" filename
Test
$ echo "\$pnconfig['dbhost'] = 'localhost';" | sed "s/\(pnconfig\['dbhost'\] = \)'localhost'/\1'1.1.1.1'/"
$pnconfig['dbhost'] = '1.1.1.1';

Use as below:
sed -i.bak '/pnconfig\[\'dbhost\'\] = \'localhost\'/pnconfig\[\'dbhost\'\] = \'1.1.1.1\'/' tco.php
Rather than modifying the file for the first time, create back up and then search for your pattern and then replace it with the other as above in your file tco.php

You don't have to worry about backslashing single quotes by using double quotes for sed.
sed -i.bak "/pnconfig\['dbhost'\] = 'localhost'/s/localhost/1.1.1.1/g" File

Try this one.
sed "/$pnconfig\['dbhost']/s/localhost/1.1.1.1/"

sed substitute with quotes and wildcard

I need to replace if ($_SESSION['POST']['*']==1){ with if (isset($_SESSION['POST']['*']) && $_SESSION['POST']['*']==1){
(I'm using * as a wild card)
I've tried sed -i "s/if ($_SESSION['POST']['.*']/if (isset($_SESSION['POST']['.*']) && $_SESSION['POST']['.*']/g" *.php and a few other variations without success.

Here goes...
sed "s/\(if (\)\(\$_SESSION\['POST']\['\([^']*\)']\)==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
Using double quotes means that the $ symbols must be escaped, otherwise they will be interpreted as shell variables. The square brackets need to be escaped, otherwise they will be interpreted as the beginning of a range. It's OK to leave the closing square brackets as they are.
In order to capture the key, I have used a character class [^']*. This means zero or more characters that are not a single quote.
In the replacement, the captured groups (the parts between parentheses in the match) are referred to using \1, \2, etc.
Testing it out:
$ cat file
if ($_SESSION['POST']['foo']==1){
// do something
}
if ($_SESSION['POST']['bar']==1){
// do something else
}
$ sed "s/\(if (\)\(\$_SESSION\['POST']\['\([^']*\)']\)==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
if (isset($_SESSION['POST']['foo']) && $_SESSION['POST']['foo']==1){
// do something
}
if (isset($_SESSION['POST']['bar']) && $_SESSION['POST']['bar']==1){
// do something else
}
By the way it makes the command a few characters shorter if you use extended regexp mode (-r or -E). In extended mode, the parentheses enclosing capture groups don't have to be escaped but literal ones do, so your command would then be:
sed -r "s/(if \()(\$_SESSION\['POST']\['([^']*)'])==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file

This sed should work:
s="if (\$_SESSION['POST']['name']==1){"
sed -r 's/(if +)\((([^=]+)[^\)]+)/\1(isset(\3) \&\& \2/' <<< "$s"
if (isset($_SESSION['POST']['name']) && $_SESSION['POST']['name']==1){
PS: Use sed -E instead of sed -r on OSX.

Here's another.
This is what we need to produce:
Pattern: if (\$_SESSION\['POST'\]\['\([^']*\)'\]
Replacement: if (isset($_SESSION['POST']['\1']) \&\& $_SESSION['POST']['\1']
When quoted in shell level:
Pattern: "if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]"
Replacement: "if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']"
Putting it together:
sed -i "s|if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]|if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']|g" file
Test:
# sed "s|if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]|if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']|g" <<'EOF'
> if ($_SESSION['POST']['ABC']==1){
> EOF
if (isset($_SESSION['POST']['ABC']) && $_SESSION['POST']['ABC']==1){