PowerShell: Expression only with Last item of an Array - powershell

Question

I've been stuck on this for a little while however I've got an array of People and im trying to get the last person and creating a seperate column with that person only.
I've played around with #{NAME = 'NAME' Expression = {}} in Select-Object but I don't really know how to tackle it.
Current:
| Employee |
|---------------|
| John Doe |
| Jane West |
| Jordan Row |
| Paul Willson |
| Andrew Wright |
Desired Result:
| Employee | Employee2 |
|--------------|---------------|
| John Doe | |
| Jane West | |
| Jordan Row | |
| Paul Willson | Andrew Wright |
TIA!

Answer 1

So what I decided to do here is create 2 groups. One group contains all of the values except the last 2, and the other group contains these last 2 values
# create the sample array
$employees = #(
'John Doe'
'Jane West'
'Jordan Row'
'Paul Willson'
'Andrew Wright'
)
$employees |
# Separate objects into 2 groups: those contained in the last 2 values and those not contained in the last 2 values
Group-Object {$_ -in ($employees | Select-Object -Last 2)} |
ForEach-Object {
switch ($_) {
{$_.name -eq 'False'} { # 'False' Name of group where values are not one of the last 2
# Iterate through all the values and assign them to Employee property. Leave Employee2 property blank
$_.group | ForEach-Object {
[PSCustomObject]#{
Employee = $_
Employee2 = ''
}
}
}
{$_.name -eq 'True'} { # 'True' Name of group where values are those of the last 2
# Create an object that assigns the values to Employee and Employee2
[PSCustomObject]#{
Employee = $_.group[0]
Employee2 = $_.group[1]
}
}
}
}
Output
Employee Employee2
-------- ---------
John Doe
Jane West
Jordan Row
Paul Willson Andrew Wright
Edit
Here is another way you can do it
$employees[0..($employees.Count-3)] | ForEach-Object {
[PSCustomObject]#{
Employee = $_
Employee2 = ''
}
}
[PSCustomObject]#{
Employee = $employees[-2]
Employee2 = $employees[-1]
}