I'm trying to get all order ids that used a specific promo code (ABC123). However, I want to see all subsequent orders, rather than just all the ids. For example, if we have the following table:
Account_id
order_id
promo_code
1
123
NULL (no promo code used)
2
124
ABC123
3
125
HelloWorld!
2
125
NULL
1
126
ABC123
2
127
HelloWorld!
3
128
ABC123
Ideally, what I want to get is this (ordered by account_id):
Account_id
order_id
promo_code
1
126
ABC123
2
124
ABC123
2
125
NULL
2
127
HelloWorld!
3
128
ABC123
As you can see promo_code = ABC123 is like a placeholder in which all once that ID is found, I want all preceding order_ids.
So far to filer all the account_ids that used this promo_code is:
SELECT account_ids, order_id, promo_code
FROM orders
WHERE account_id IN (SELECT account_id FROM order WHERE promo_code = 'ABC123');
This allows me to get the account_ids that have an order where the desired promo_code was used.
Thanks in advance!
Extract all account_id-s that used 'ABC123' and the smallest corresponding order_number-s (the t CTE) then join these with the table and filter/order the result set.
with t as
(
select distinct on (account_id) account_id, order_id
from the_table where promo_code = 'ABC123'
order by account_id, order_id
)
select the_table.*
from the_table
inner join t on the_table.account_id = t.account_id
where the_table.order_id >= t.order_id -- the subsequent orders
order by the_table.account_id, the_table.order_id;
SQL Fiddle
Related
I have a table containing data that has a column named id that looks like below:
id
value 1
value 2
value 3
1
244
550
1000
1
251
551
700
1
540
60
1200
...
...
...
...
2
19
744
2000
2
10
903
100
2
44
231
600
2
120
910
1100
...
...
...
...
I want to take 50 sample rows per id that exists but if less than 50 exist for the group to simply take the entire set of data points.
For example I would like a maximum 50 data points randomly selected from id = 1, id = 2 etc...
I cannot find any previous questions similar to this but have tried taking a stab at at least logically working through the solution where I could iterate and union all queries by id and limit to 50:
SELECT * FROM (SELECT * FROM schema.table AS tbl WHERE tbl.id = X LIMIT 50) UNION ALL;
But it's obvious that you cannot use this type of solution because UNION ALL requires aggregating outputs from one id to the next and I do not have a list of id values to use in place of X in tbl.id = X.
Is there a way to accomplish this by gathering that list of unique id values and union all results or is there a more optimal way this could be done?
If you want to select a random sample for each id, then you need to randomize the rows somehow. Here is a way to do it:
select * from (
select *, row_number() over (partition by id order by random()) as u
from schema.table
) as a
where u <= 50;
Example (limiting to 3, and some row number for each id so you can see the selection randomness):
setup
DROP TABLE IF EXISTS foo;
CREATE TABLE foo
(
id int,
value1 int,
idrow int
);
INSERT INTO foo
select 1 as id, (1000*random())::int as value1, generate_series(1, 100) as idrow
union all
select 2 as id, (1000*random())::int as value1, generate_series(1, 100) as idrow
union all
select 3 as id, (1000*random())::int as value1, generate_series(1, 100) as idrow;
Selection
select * from (
select *, row_number() over (partition by id order by random()) as u
from foo
) as a
where u <= 3;
Output:
id
value1
idrow
u
1
542
6
1
1
24
86
2
1
155
74
3
2
505
95
1
2
100
46
2
2
422
33
3
3
966
88
1
3
747
89
2
3
664
19
3
In case you are looking to get 50 (or less) from each group of IDs then you can use windowing -
From question - "I want to take 50 sample rows per id that exists but if less than 50 exist for the group to simply take the entire set of data points."
Query -
with data as (
select row_number() over (partition by id order by random()) rn,
* from table_name)
select * from data where rn<=50 order by id;
Fiddle.
Your description of trying to get the UNION ALL without specifying all the branches ahead of time is aiming for a LATERAL join. And that is one way to solve the problem. But unless you have a table of all distinct ids, you would have to compute one on the fly. For example (using the same fiddle as Pankaj used):
with uniq as (select distinct id from test)
select foo.* from uniq cross join lateral
(select * from test where test.id=uniq.id order by random() limit 3) foo
This could be either slower or faster than the Window Function method, depending on your system and your data and your indexes. In my hands, it was quite a bit faster even with the need to dynamically compute the list of distinct ids.
This is my table_gamers:
game_id
user1
user2
timestamp
1
890
123
2022-01-01
2
123
768
2022-02-09
I need to find for each user:
The first user they played.
Their first game ID.
Their MIN timestamp (timestamp from their first game).
This is what I need:
User
User They Played
Game ID
timestamp
890
123
1
2022-01-01
123
890
1
2022-01-01
768
123
2
2022-02-09
This is my query:
SELECT user1 FROM table_gamers WHERE MIN(timestamp)
UNION ALL
SELECT user1 FROM table_gamers WHERE MIN(timestamp)
How do I query each User's First Opponent? I am confused.
doing step by step by some with_clauses:
first get all matches user1-user2, user2-user1
second give some ids by ordering by timestamp
third get what you want:
with base_data as (
select game_id,user1,user2,timestamp from table_gamers
union all
select game_id,user2,user1,timestamp from table_gamers
),
base_id as (
select
row_number() over (order by base_data.timestamp) as id,
row_number() over (PARTITION by base_data.user1 order by base_data.timestamp) as id_2,
*
from base_data
)
select * from base_id
where id_2 = 1 order by timestamp
retults in
id id_2 game_id user1 user2 timestamp
2 1 1 123 890 2022-01-01T00:00:00.000Z
1 1 1 890 123 2022-01-01T00:00:00.000Z
4 1 2 768 123 2022-02-09T00:00:00.000Z
i hope that gives you the right idea
https://www.db-fiddle.com/f/9PrxioFeVaTmtVcYdteovj/0
Before, I had to solve something similar:
Here was my pivot and flatten for another solution:
I want to do the same thing on the example below but it is slightly different because there are no ranks.
In my previous example, the table looked like this:
LocationID Code Rank
1 123 1
1 124 2
1 138 3
2 999 1
2 888 2
2 938 3
And I was able to use this function to properly get my rows in a single column.
-- Check if tables exist, delete if they do so that you can start fresh.
IF OBJECT_ID('tempdb.dbo.#tbl_Location_Taxonomy_Pivot_Table', 'U') IS NOT NULL
DROP TABLE #tbl_Location_Taxonomy_Pivot_Table;
IF OBJECT_ID('tbl_Location_Taxonomy_NPPES_Flattened', 'U') IS NOT NULL
DROP TABLE tbl_Location_Taxonomy_NPPES_Flattened;
-- Pivot the original table so that you have
SELECT *
INTO #tbl_Location_Taxonomy_Pivot_Table
FROM [MOAD].[dbo].[tbl_Location_Taxonomy_NPPES] tax
PIVOT (MAX(tax.tbl_lkp_Taxonomy_Seq)
FOR tax.Taxonomy_Rank in ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13],[14],[15])) AS pvt
-- ORDER BY Location_ID
-- Flatten the tables.
SELECT Location_ID
,max(piv.[1]) as Tax_Seq_1
,max(piv.[2]) as Tax_Seq_2
,max(piv.[3]) as Tax_Seq_3
,max(piv.[4]) as Tax_Seq_4
,max(piv.[5]) as Tax_Seq_5
,max(piv.[6]) as Tax_Seq_6
,max(piv.[7]) as Tax_Seq_7
,max(piv.[8]) as Tax_Seq_8
,max(piv.[9]) as Tax_Seq_9
,max(piv.[10]) as Tax_Seq_10
,max(piv.[11]) as Tax_Seq_11
,max(piv.[12]) as Tax_Seq_12
,max(piv.[13]) as Tax_Seq_13
,max(piv.[14]) as Tax_Seq_14
,max(piv.[15]) as Tax_Seq_15
-- JOIN HERE
INTO tbl_Location_Taxonomy_NPPES_Flattened
FROM #tbl_Location_Taxonomy_Pivot_Table piv
GROUP BY Location_ID
So, then here is the data I would like to work with in this example.
LocationID Foreign Key
2 2
2 670
2 2902
2 5389
3 3
3 722
3 2905
3 5561
So I have some data that is formatted like this:
I have used pivot on data like this before--But the difference was it had a rank also. Is there a way to get my foreign keys to show up in this format using a pivot?
locationID FK1 FK2 FK3 FK4
2 2 670 2902 5389
3 3 722 2905 5561
Another way I'm looking to solve this is like this:
Another way I could look at doing this is I have the values in:
this form as well:
LocationID Address_Seq
2 670, 5389, 2902, 2,
3 722, 5561, 2905, 3
etc
is there anyway I can get this to be the same?
ID Col1 Col2 Col3 Col4
2 670 5389, 2902, 2
This, adding a rank column and reversing the orders, should gives you what you require:
SELECT locationid, [4] col1, [3] col2, [2] col3, [1] col4
FROM
(
SELECT locationid, foreignkey,rank from #Pivot_Table ----- temp table with a rank column
) x
PIVOT (MAX(x.foreignkey)
FOR x.rank in ([4],[3],[2],[1]) ) pvt
i have a table and i want to know where duplicate records are present for same columns. These are my columns and i want to get record where group_id or week are different for same code and fweek and newcode
Id newcode fweek code group_id week
1 343001 2016-01 343 100 8
2 343002 2016-01 343 100 8
3 343001 2016-01 343 101 08
Required record is
Id newcode fweek code group_id week
3 343001 2016-01 343 101 08
To find the duplicate values i have joined the table with itself.
and we need to group the results with code,fweek and newcode to get more than one duplicate rows if they exist. i have used max() to get last inserted row.
you don't need to use is distinct from (it is same for inequality + NULL). if you don't want to compare NULL ones, use <> operator.
You find more information about here info
select r.*
from your_table r
where r.id in (select max(r.id)
from your_table r
join your_table r2 on r2.code = r.code and r2.fweek = r.fweek and r2.newcode = r.newcode
where
r2.group_id is distinct from r.group_id or
r2.week is distinct from r.week
group by r.code,
r.fweek,
r.newcode
having count(*) > 1)
Given the following table
group | weight | category_id | category_name_plus
1 10 100 Ab
1 20 101 Bcd
1 30 100 Efghij
2 10 101 Bcd
2 20 101 Cdef
2 30 100 Defgh
2 40 100 Ab
3 10 102 Fghijkl
3 20 101 Ab
The "weight" is unique for each group and is also an indicator for the order of records inside the group.
What I want is to retrieve one record per group filtered by category_id, but only the record having the highest "weight" inside its "group".
Example for filtering by category_id = 100:
group | weight | category_id | category_name_plus
1 30 100 Efghij
2 40 100 Ab
Example for filtering by category_id = 101:
group | weight | category_id | category_name_plus
1 20 101 Bcd
2 20 101 Cdef
3 20 101 Ab
How can I select just these rows?
I tried fiddling with UNIQUE, MAX(category_id) etc. but I'm still unable to get the correct results. The main problem for me is to get the category_name_plus value here.
I am working with PostgreSQL 9.4(beta 3), because I also need various other niceties like "WITH ORDINALITY" etc.
The rank window function should do the trick:
SELECT "group", weight, category_id, category_name_plus
FROM (SELECT "group", weight, category_id, category_name_plus,
RANK() OVER (PARTITION BY "group"
ORDER BY weight DESC) AS rk
FROM my_table) t
WHERE rk = 1 AND category_id = 101
Note:
"group" is a reserved word in SQL, so it has to be surrounded by quotes in order to be used as a column name. It would probably be better, though, to replace it with a non-reserved word, such as "group_id".
Try something like:
SELECT DISTINCT ON (category_id) *
from your_table
order by category_id, weight desc