Find Minimum Timestamp From 2 Users POSTGRES - postgresql

Question

This is my table_gamers:
game_id
user1
user2
timestamp
1
890
123
2022-01-01
2
123
768
2022-02-09
I need to find for each user:
The first user they played.
Their first game ID.
Their MIN timestamp (timestamp from their first game).
This is what I need:
User
User They Played
Game ID
timestamp
890
123
1
2022-01-01
123
890
1
2022-01-01
768
123
2
2022-02-09
This is my query:
SELECT user1 FROM table_gamers WHERE MIN(timestamp)
UNION ALL
SELECT user1 FROM table_gamers WHERE MIN(timestamp)
How do I query each User's First Opponent? I am confused.

Answer 1

doing step by step by some with_clauses:
first get all matches user1-user2, user2-user1
second give some ids by ordering by timestamp
third get what you want:
with base_data as (
select game_id,user1,user2,timestamp from table_gamers
union all
select game_id,user2,user1,timestamp from table_gamers
),
base_id as (
select
row_number() over (order by base_data.timestamp) as id,
row_number() over (PARTITION by base_data.user1 order by base_data.timestamp) as id_2,
*
from base_data
)
select * from base_id
where id_2 = 1 order by timestamp
retults in
id id_2 game_id user1 user2 timestamp
2 1 1 123 890 2022-01-01T00:00:00.000Z
1 1 1 890 123 2022-01-01T00:00:00.000Z
4 1 2 768 123 2022-02-09T00:00:00.000Z
i hope that gives you the right idea
https://www.db-fiddle.com/f/9PrxioFeVaTmtVcYdteovj/0