This seems like it would be straightforward to do but I just can not figure it out. I have a query that returns an ARRAY of strings in one of the columns. I want that array to only contain unique strings. Here is my query:
SELECT
f."_id",
ARRAY[public.getdomain(f."linkUrl"), public.getdomain(f."sourceUrl")] AS file_domains,
public.getuniqdomains(s."originUrls", s."testUrls") AS source_domains
FROM
files f
LEFT JOIN
sources s
ON
s."_id" = f."sourceId"
Here's an example of a row from my return table
_id
file_domains
source_domains
2574873
{cityofmontclair.org,cityofmontclair.org}
{cityofmontclair.org}
I need file_domains to only contain unique values, IE a 'set' instead of a 'list'. Like this:
_id
file_domains
source_domains
2574873
{cityofmontclair.org}
{cityofmontclair.org}
Use a CASE expression:
CASE WHEN public.getdomain(f."linkUrl") = public.getdomain(f."sourceUrl")
THEN ARRAY[public.getdomain(f."linkUrl")]
ELSE ARRAY[public.getdomain(f."linkUrl"), public.getdomain(f."sourceUrl")]
END
Related
I have a table with the following field values:
I want to do a select where I can match a value from this keyword column. For example:
SELECT templateid FROM public.templates WHERE keyword='Yes'
I don't want to use LIKE because in the case one of the comma-separated values is Yessy then I will get a return and that's not correct.
It has to be an exact match of one of the comma separated values.
Any clue?
You can convert the string into an array:
SELECT templateid
FROM public.templates
WHERE 'Yes' = any(string_to_array(keyword, ','))
Is it possible to re-map integer values from a Postgres array column in the select? This is what I have:
select unnest(tag_ids) from mention m where id = 288201;
unnest
---------
-143503
-143564
125192
143604
137694
tag_ids is integer[] column
I would like to translate those numbers. Functions like abs(unnest(..)) work but found I cannot use a CASE statement. Tx.
If you want to do anything non-trivial with the elements from an array after unnesting, use the set-returning function like table:
select u.tag_id
from mention m
cross join unnest(m.tag_ids) as u(tag_id)
where m.id = 288201;
Now, u.tag_id is an integer column that you can use like any other column, e.g. in a CASE expression.
I have column options with type jsonb , in format {"names": ["name1", "name2"]} which was created with
UPDATE table1 t1 SET options = (SELECT jsonb_build_object('names', names) FROM table2 t2 WHERE t2.id= t1.id)
and where names have type jsonb array.
SELECT jsonb_typeof(names) FROM table2 give array
Now I want to extract value of names as jsonb array. But query
SELECT jsonb_build_array(options->>'names') FROM table
gave me ["[\"name1\", \"name2\"]"], while I expect ["name1", "name2"]
How can I get value in right format?
The ->> operator will return the value of the field (in your case, a JSON array) as a properly escaped text. What you are looking for is the -> operator instead.
However, note that using the jsonb_build_array on that will return an array containing your original array, which is probably not what you want either; simply using options->'names' should get you what you want.
Actually, you don't need to use jsonb_build_array() function.
Use select options -> 'names' from table; This will fix your issue.
jsonb_build_array() is for generating the array from jsonb object. You are following wrong way. That's why you are getting string like this ["[\"name1\", \"name2\"]"].
Try to execute this sample SQL script:
select j->'names'
from (
select '{"names": ["name1", "name2"]}'::JSONB as j
) as a;
I have a JSON field with a simple numeric array
[46,70,34]
How can I filter query selecting only those rows where present let's say '70' in a JSON field? Something similar to JSON_CONTAINS in MySQL.
I have already tried
SELECT id, name, IN(tags, '70') AS c FROM index WHERE c = 1;
and
SELECT id, name, ALL(var='70' FOR var IN tags) as c FROM index WHERE c=1;
But it doesn't work.
Actully think...
SELECT id, name FROM index WHERE tags = 70;
should just work. JSON arrays, end up working 'like' a MVA.
Otherwise, you would want ANY() (not ALL()), because only one of the values in the JSON array would be 70, not all of them (46 wouldn't match for example!)
SELECT id, name, ANY(var=70 FOR var IN tags) as c FROM index WHERE c=1;
(finally as a numeric value, shouldn't be quoted!)
According to ZF documentation when using fetchAssoc() the first column in the result set must contain unique values, or else rows with duplicate values in the first column will overwrite previous data.
I don't want this, I want my array to be indexed 0,1,2,3... I don't need rows to be unique because I won't modify them and won't save them back to the DB.
According to ZF documentation fetchAll() (when using the default fetch mode, which is in fact FETCH_ASSOC) is equivalent to fetchAssoc(). BUT IT'S NOT.
I've used print_r()function to reveal the truth.
print_r($db->fetchAll('select col1, col2 from table'));
prints
Array
(
[0] => Array
(
[col1] => 1
[col2] => 2
)
)
So:
fetchAll() is what I wanted.
There's a bug in ZF documentation
From http://framework.zend.com/manual/1.11/en/zend.db.adapter.html
The fetchAssoc() method returns data in an array of associative arrays, regardless of what value you have set for the fetch mode, **using the first column as the array index**.
So if you put
$result = $db->fetchAssoc(
'SELECT some_column, other_column FROM table'
);
you'll have as result an array like this
$result['some_column']['other_column']