I have a table with the following field values:
I want to do a select where I can match a value from this keyword column. For example:
SELECT templateid FROM public.templates WHERE keyword='Yes'
I don't want to use LIKE because in the case one of the comma-separated values is Yessy then I will get a return and that's not correct.
It has to be an exact match of one of the comma separated values.
Any clue?
You can convert the string into an array:
SELECT templateid
FROM public.templates
WHERE 'Yes' = any(string_to_array(keyword, ','))
Related
This seems like it would be straightforward to do but I just can not figure it out. I have a query that returns an ARRAY of strings in one of the columns. I want that array to only contain unique strings. Here is my query:
SELECT
f."_id",
ARRAY[public.getdomain(f."linkUrl"), public.getdomain(f."sourceUrl")] AS file_domains,
public.getuniqdomains(s."originUrls", s."testUrls") AS source_domains
FROM
files f
LEFT JOIN
sources s
ON
s."_id" = f."sourceId"
Here's an example of a row from my return table
_id
file_domains
source_domains
2574873
{cityofmontclair.org,cityofmontclair.org}
{cityofmontclair.org}
I need file_domains to only contain unique values, IE a 'set' instead of a 'list'. Like this:
_id
file_domains
source_domains
2574873
{cityofmontclair.org}
{cityofmontclair.org}
Use a CASE expression:
CASE WHEN public.getdomain(f."linkUrl") = public.getdomain(f."sourceUrl")
THEN ARRAY[public.getdomain(f."linkUrl")]
ELSE ARRAY[public.getdomain(f."linkUrl"), public.getdomain(f."sourceUrl")]
END
I have column options with type jsonb , in format {"names": ["name1", "name2"]} which was created with
UPDATE table1 t1 SET options = (SELECT jsonb_build_object('names', names) FROM table2 t2 WHERE t2.id= t1.id)
and where names have type jsonb array.
SELECT jsonb_typeof(names) FROM table2 give array
Now I want to extract value of names as jsonb array. But query
SELECT jsonb_build_array(options->>'names') FROM table
gave me ["[\"name1\", \"name2\"]"], while I expect ["name1", "name2"]
How can I get value in right format?
The ->> operator will return the value of the field (in your case, a JSON array) as a properly escaped text. What you are looking for is the -> operator instead.
However, note that using the jsonb_build_array on that will return an array containing your original array, which is probably not what you want either; simply using options->'names' should get you what you want.
Actually, you don't need to use jsonb_build_array() function.
Use select options -> 'names' from table; This will fix your issue.
jsonb_build_array() is for generating the array from jsonb object. You are following wrong way. That's why you are getting string like this ["[\"name1\", \"name2\"]"].
Try to execute this sample SQL script:
select j->'names'
from (
select '{"names": ["name1", "name2"]}'::JSONB as j
) as a;
I have two tables. I want to update the emodnet_code column values of the table named 2018_01 based on the column emodnet_type of another table named shiptype_emodnet and using the matching of values of two other columns: column aisshiptype from 2018_01 table and column aisshiptype from shyptype_emodnet table. Query returned successfully but 0 rows affected:
UPDATE "2018_01"
SET emodnet_code = shiptype_emodnet.emodnet_type
FROM "shiptype_emodnet"
WHERE '2018_01.aisshiptype' = 'shiptype_emodnet.aisshiptype';
You are comparing string constants in your WHERE clause, not columns. So your where clause:
WHERE '2018_01.aisshiptype' = 'shiptype_emodnet.aisshiptype';
is always false, because the string literal '2018_01.aisshiptype' is never the same as the string literal 'shiptype_emodnet.aisshiptype'. So your where condition is essentially the same as:
where false
Identifiers need to be quoted with double quotes ("). Single quotes (') are only for string literals.
UPDATE "2018_01"
SET emodnet_code = shiptype_emodnet.emodnet_type
FROM "shiptype_emodnet"
WHERE "2018_01".aisshiptype = shiptype_emodnet.aisshiptype;
And you only need the double quotes for columns or tables that use names that are illegal in SQL or were created using double quotes and mixed case.
Can you try:
UPDATE "2018_01" t
SET t.emodnet_code = (SELECT shiptype_emodnet.emodnet_type
FROM shiptype_emodnet
WHERE t.aisshiptype = shiptype_emodnet.aisshiptype
Limit 1);
You should add limit 1 for update each row
I'm using PostgreSQL 9.3.
I have a varchar column in a table that can be null and I want to update it depending of its value is null or not.
I didn't manage to do a function that takes a String as argument and updates the value like this:
If the column is null, the function concatenates the current string value, a comma and the string given as argument, else it just adds the string at the end of the current string value (without comma).
So how can I make a different Update depending of the column value to update?
You can use a case statement to conditionally update a column:
update the_table
set the_colum = case
when the column is null then 'foobar'
else the_column||', '||'foobar'
end
An another approach
UPDATE foo
SET bar = COALESCE(NULLIF(concat_ws(', ', NULLIF(bar, ''), NULLIF('a_string', '')), ''), 'a_string')
I have a string value in a varchar column. It is a string that has two parts. Splitting it before it hits the database is not an option.
The column's values look like this:
one_column:
'part1 part2'
'part1 part2'
So what I want is a a result set that looks like:
col1,col2:
part1,part2
part1,part2
How can I do this in a SELECT statement? I found a pgsql function to split the string into an array but I do not know how to get it into two columns.
select split_part(one_column, ' ', 1) AS part1,
split_part(one_column, ' ', 2) AS part2 ...