Is it possible to transform a 4-column list into a 4-column table in NetLogo 6.2? - netlogo

I have a code that generates an output in list form as below:
I would like the output to look like this:
is it possible to do this in netlogo 6.2?

Yes, but- I think your approach may be overcomplicating what you are after. As an alternative, consider something like this toy model:
extensions [ csv ]
turtles-own [ my_xcor my_ycor ]
globals [ output_list ]
to setup
ca
set output_list [["who" "my_xcor" "my_ycor" "tick"]]
crt 2
reset-ticks
end
to go
ask turtles [
rt random 90 - 45
fd 1
set my_xcor pxcor
set my_ycor pycor
set output_list lput ( list who my_xcor my_ycor ticks ) output_list
]
tick
end
to example-experiment
setup
repeat 5 [ go ]
csv:to-file "example_output.csv" output_list
end
If you run the example-experiment procedure, it will export a file that looks something like:
If you must go this other route, and you can't parse your original csv output in something like R instead, which would potentially be simpler, consider this different setup:
extensions [csv]
globals [ output-list ]
turtles-own [ xcor-list ycor-list tick-list]
to setup
ca
reset-ticks
set output-list [["who" "my_xcor" "my_ycor" "tick"]]
crt 2 [
set xcor-list []
set ycor-list []
set tick-list []
]
repeat 5 [
ask turtles [
rt random 90 - 45
fd 1
set xcor-list lput pxcor xcor-list
set ycor-list lput pycor ycor-list
set tick-list lput ticks tick-list
]
]
end
Now, the idea is to loop over the turtles and collapse each of their tracking lists into a list of lists before exporting:
to export-long
; Iterate over each turtle to extract their listed values
foreach sort turtles [
t ->
; Pull values / lists from each turtle in order
let cur-x-list [xcor-list] of t
let cur-y-list [ycor-list] of t
let cur-tick-list [tick-list] of t
let cur-who-list n-values ( length cur-x-list ) [[who] of t]
( foreach cur-who-list cur-x-list cur-y-list cur-tick-list [
[ a b c d ] ->
let to-append ( list a b c d )
set output-list lput to-append output-list
])
]
; Export the list to csv
csv:to-file "list_example_output.csv" output-list
end
Result:

Related

How to access the first turtle of a code sequence in NetLogo 6.2?

I have the following doubts:
I have several individuals of 9 turtle codes.
The turtle codes are: R1M1 R2M1 R3M1 R1M2 R2M2 R3M2 R1M3 R2M3 R3M3. And I have 10 individuals of each code.
As the code is structured in a loop sequence and the order that the code exits in the result exported in .csv, I would like to ask the first individual of the first code (R1M1) to print the output header. But, I'm only getting it using one-of, and then the header often doesn't come out in the first line of the output. And I don't know how I can access the first turtle from the R1M1 code. Does anyone have any ideas?
What I thought of is calling turtle 0 which has the code R1M1. But, I still don't know how to do this in NetLogo.
OBS.: I tried to use only turtle 0, but in the other codes, too, there is turtle 0 and then the header appears.
Thanks in advance
let n count turtles with [ profiles-code = "R1M1" ]
if n > 0
[
ask one-of turtles with [ profiles-code = "R1M1" ]
[
prepare-header-output;; CALL A PROCEDURE
]
]
An example of how the header is coming out (has 3 individuals from each of the 9 codes)
I would use a flag / semaphore variable to indicate if a header is needed. You'll need to adapt the below if you have your turtles outputting the data, but hopefully this will get you pointed in the right direction- more details in comments:
globals [ need-headers? ]
turtles-own [ class ]
to setup
ca
random-seed 1
set need-headers? true
if file-exists? "test_output.csv" [ file-delete "test_output.csv" ]
crt 10 [
set class item random 5 "ABCDE"
]
reset-ticks
end
to go
if count turtles < 1 [ stop ]
ask turtles [
if random-float 1 < 0.25 [ die ]
]
; Toy output example
file-open "test_output.csv"
foreach range length "ABCDE" [ i ->
; Output headers if needed
if need-headers? [
file-print "turtle-type, count, ticks"
; Change the need-headers? to false so this step will only happen once
set need-headers? false
]
let ltr item i "ABCDE"
let n-type count turtles with [ class = ltr ]
file-print ( word ltr "," n-type "," ticks )
]
file-close
tick
end
Output here looks something like:
but if I don't change need-headers? to false, it looks like:

Netlogo: How to make a turtle move towards an unique patch target?

I have turtles (patients), and they can only use only one bed each (white patch). Since patients are randomly generated in a waiting room (green patches), sometimes two or more of them get at the same distance and therefore they find the same patch as its target. I tried to add an attribute to the patch with the purpose of assigning that particular bed to a specific patient. The idea is something like this (please indulge on the ugly code, I'm learning :P):
globals [
waitxmax
waitxmin
waitymax
waitymin
box
]
breed [ patients patient ]
patients-own [ target ]
patches-own [ assigned ]
to setup-wait-room
set waitxmax -15
set waitxmin 15
set waitymax 11
set waitymin 15
ask patches with [
pxcor >= waitxmax and
pxcor <= waitxmin and
pycor >= waitymax and
pycor <= waitymin
] [ set pcolor green ]
end
to setup-beds
let cmy 7
let cmx 15
let dst 3
let nbox 7
ask patch cmx cmy [ set pcolor white ]
let i 1
while [ i < nbox ] [
ask patch (cmx - dst) cmy [ set pcolor white ]
set i i + 1
set cmx cmx - dst
]
ask patches with [ pcolor = white ] [ set assigned false ]
set box patches with [ pcolor = white ]
end
to setup-patients
create-patients start-patients [
set shape "person"
set target nobody
move-to one-of patches with [ pcolor = green ] ]
end
to setup [
clear-all
setup-wait-room
setup-beds
reset-ticks
]
to go
ask patients [ go-to-bed ]
tick
end
to go-to-bed
let _p box with [ self != [ patch-here ] of myself ]
if target = nobody [
set target min-one-of _p [ distance myself ]
ask target [ set assigned myself ]
]
;;; FIXME
if ([ assigned ] of target) != self [ show "not true" ]
if target != nobody [
face target
fd 1
]
end
When I print the two sides of the comparison below FIXME, from the command center I actually get the expected result. For example: both patient 0 and patient 1 have the same target (patch -3 7), but that patch is assigned to (patient 0). I would have expected that comparison to force patient 1 to get a new target since the bed doesn't have his name (I haven't written that code yet), but it always evaluates to true. This is more notorious as more patients I add over available beds (if no beds available, they should wait as soon as one gets free).
When inspecting trough the interface I also see that the patch -3 7 says (patient 0), so I don't know what's happening. Command center example:
observer> show [ assigned ] of patch -3 7
observer: (patient 0)
observer> if ([ assigned ] of patch -3 7) = [self] of patient 0 [ show "true" ]
observer: "true"
observer> if ([ assigned ] of patch -3 7) = [self] of patient 1 [ show "true" ]
;;;; SETUP AND GO
(patient 0): (patch -3 7)
(patient 0): (patient 0)
(patient 0): "true"
(patient 2): (patch 12 7)
(patient 2): (patient 2)
(patient 2): "true"
(patient 1): (patch -3 7)
(patient 1): (patient 1)
(patient 1): "true"
Maybe I'm just overthinking this and there are is a simpler way to assign a bed to a patient and vice versa?
There seems to be a chunk or two missing from your code above (I can't copy-paste and run it), so please have a look at the option below.
This version works by having a single place to store the 'claimed' beds- in the turtle variable. Since the turtle variables can be queried as a list using of, a bed-less turtle can check if there are any beds that are not already present in that list and, if so, claim one.
turtles-own [ owned-bed ]
to setup
ca
ask n-of 5 patches [
set pcolor green
]
crt 10 [
set owned-bed nobody
claim-unclaimed-bed
if owned-bed != nobody [
print word "I own the bed " owned-bed
]
]
reset-ticks
end
to claim-unclaimed-bed
; If I have no bed
if owned-bed = nobody [
; Pull the current owned beds for comparison
let all-owned-beds [owned-bed] of turtles
; Pull those beds that are green AND are not found in 'all-owned-beds'
let available-beds patches with [
pcolor = green and not member? self all-owned-beds
]
; If there are any beds available, claim one
ifelse any? available-beds [
set owned-bed one-of available-beds
] [
; If there are none available, print so
print "There are no available beds."
]
]
end
Edit: Forgot the actual question title- to actually move to their owned-bed (if they have one) in the example above, they simply face it and move how you like- for example:
to go
ask turtles with [ owned-bed != nobody ] [
ifelse distance owned-bed > 1 [
face owned-bed
fd 1
] [
move-to owned-bed
]
]
tick
end
Edit: added complexity
Ok, for an added element of severity, you will likely want to avoid using multiple with [ ... = x statements, and instead to use a primitive called min-one-of which returns the agent with the minimum value of some reporter. Then, you want to tell NetLogo to keep asking the next most severe and the next most severe, etc. One way to do this is with a while loop, which basically says "While this condition is met, continue evaluating the following code." Be careful with while loops- if you forget to write your code such that eventually the condition is no longer true, the while loop will just continue running until you will eventually Tools > Halt your model (or, as has happened to me with a large model, NetLogo crashes).
I've reworked the code (much of what was above is unchanged) to include such a while loop. Note as well that, since the model needs to check which beds are available multiple times, I've made that code into a to-report chunk to condense / simplify.
turtles-own [ owned-bed severity ]
to setup
ca
ask n-of 5 patches [
set pcolor green
]
crt 10 [
set owned-bed nobody
set severity random-float 10
]
let current-available-beds report-available-beds
while [any? current-available-beds] [
; From the turtles with no bed, ask the one with the lowest severity number to
; claim an unclaimed bed. Then, reset the current-available-beds
ask min-one-of ( turtles with [owned-bed = nobody] ) [ severity ] [
claim-unclaimed-bed
if owned-bed != nobody [
show ( word "I have a severity of " severity " so I am claiming the bed " owned-bed )
]
]
set current-available-beds report-available-beds
]
reset-ticks
end
to-report report-available-beds
let all-owned-beds [owned-bed] of turtles
report patches with [
pcolor = green and not member? self all-owned-beds
]
end
to claim-unclaimed-bed
; If I have no bed
if owned-bed = nobody [
let available-beds report-available-beds
; If there are any beds available, claim one
ifelse any? available-beds [
set owned-bed one-of available-beds
] [
; If there are none available, print so
print "There are no available beds."
]
]
end

How to create a table to know which turtles visited each patch in the world?

I would like to remove a doubt and have some help.
I have a closed world of 600X600 patches. Each patch spawns a turtle (using the sprout command). Each turtle makes a series of moves and returns a value for its home patch. I would like to have the following result: know which turtle was in each patch in the world and export this result in table form in .csv
I created a list for this. But, NetLogo is running for a while and then it closes and doesn't finish the model. And so I think if I create a table it should work. The question is: will creating a table solve the problem of the model not running? And if so, how can I create a table by generating an output from that table in .csv? But, I haven't found a NetLogo command that I can create a table to adjust my code to.
Any tip is very welcome. I thank the attention
globals [ edge-size output-turtle-visits ]
patches-own [ turtle-visits ]
to setup
ca
random-seed 1
set edge-size 599
set-patch-size 1.2
resize-world 0 edge-size 0 edge-size
let pcolors []
set pcolors [ 85 95 ]
ask patches [ sprout 1 ]
ask patches [
set turtle-visits n-values count turtles [0]
set pcolor item (random 2) pcolors
]
reset-ticks
end
to go
ask turtles [
rt random 360
fd 1
]
ask patches [
foreach [who] of turtles-here [ id ->
let current-num-visits item id turtle-visits
set turtle-visits replace-item id turtle-visits (current-num-visits + 1)
]
]
end
to output
file-open ( output-turtle-visits )
file-print ( word "id_turtle;my_xcor;my_ycor;turtle_visits" )
foreach sort patches
[
t ->
ask t
[
file-print ( word self " ; " xcor " ; " ycor " ; " turtle-visits )
]
]
file-print "" ;; blank line
file-close
end

How to separate values from a list using commas in netlogo?

Situation: I have a code that exports turtle coordinates according to the code below:
to path
file-open (word fileName ".csv")
file-print (word self xcor " " ycor)
file-close
end
The result is something like:
(turtle 1)[1 1 1 1 1 2] [4 4 4 2 1 5]
Question: How can I export this same list, but with its items separated by commas?
From [1 2 1 1 1] to [1,2,1,1,1], for example.
Thanks in advance
If you are trying to process this in R or something after the fact, I'd recommend potentially reporting in long format (ie, each line indicates a turtle, a tick [or similar], and the coordinates)- I find it simpler to process.
To answer your actual question- one way would be to manually collapse each list of coordinates into a string separated by commas. For example, see the toy model below.
Simple setup:
extensions [csv]
globals [ test ]
turtles-own [ xcor-list ycor-list ]
to setup
ca
crt 10 [
set xcor-list []
set ycor-list []
]
repeat 5 [
ask turtles [
rt random 90 - 45
fd 1
set xcor-list lput pxcor xcor-list
set ycor-list lput pycor ycor-list
]
]
reset-ticks
end
This reporter is what's actually doing the work of collapsing the list into a simple string for output:
to-report collapse-string-list [str-list]
report reduce word ( sentence map [ str -> word str ", " ] but-last str-list last str-list )
end
And this chunk pulls the desired turtle variables into a list of lists, calls the collapse-string-list reporter on them, then exports to a csv:
to output-coord-file
let all-turtles sort turtles
; Pull coordinates from each turtle
let who-coord-list map [
current-turtle ->
(list
[who] of current-turtle
collapse-string-list [xcor-list] of current-turtle
collapse-string-list [ycor-list] of current-turtle
)] all-turtles
; Add headers
set who-coord-list fput ["who" "x" "y"] who-coord-list
; Export
csv:to-file "toy.csv" (map [ row -> (map [i -> (word i)] row ) ] who-coord-list)
end
Output:

Subtract. SET variableX-variableY only once

I'm trying to set a resource variable. It will be time and will function like sugar in sugarscape. Its setup is: ask agentes [set time random-in-range 1 6].
The thing is... I want the agentesto participate in activities linking like we said here. But, with each participation, it should subtract a unity of agentes's time. I imagine it must be with foreachbut I seem to be unable to grasp how this works.
ask n-of n-to-link agentes with [n-t-activity = [n-t-activity] of myself] in-radius sight-radius [
while [time >= 2] [
create-participation-with myself [ set color [color] of myself ] ]
foreach (command I don't know)[
set time time - count participations]]
Essentially, I want the agentes to look if they have time to participate. If they do, they create the link and subtract 1 to their time. Only ONE per participation. If they have 3 time, they'll have 2 participations and 1 time. If they have 1 time, they won't have links at all.
EDIT
You're right. I don't need while. About foreach, every place I looked said the same thing but I can't think of other way. About colors, they're only for show purpose.
The relationship between time and participation counts is as follows: the agentes have time they can spend in activities. They participate if time>=2. But every participation (link with activity) consumes 1 time when the link is active (I didn't write the decay code yet; they'll regain their time when it is off).
EDIT V2
Nothing, it keeps subtracting even with the []. Maybe the best choice is if I give you the code so you can try it. You'll have to set 5 sliders: prob-female (53%), initial-people (around 200), num-activity (around 20), n-capacity (around 25) and sight-radius (around 7). And two buttons, setup and go. I also set a patch size of 10 with 30 max-pxcor and max-pycor. Here is the code. Sorry if I'm not clear enough!
undirected-link-breed [participations participation]
turtles-own [
n-t-activity
]
breed [activities activity]
activities-own [
t-culture-tags
shared-culture
]
breed [agentes agente]
agentes-own [
gender
time
culture-tags
shared-culture
]
to setup
clear-all
setup-world
setup-people-quotes
setup-activities
reset-ticks
END
to setup-world
ask patches [set pcolor white]
END
to setup-people-quotes
let quote (prob-female / 100 * initial-people)
create-agentes initial-people
[ while [any? other turtles-here ]
[ setxy random-xcor random-ycor ]
set gender "male" set color black
]
ask n-of quote agentes
[ set gender "female" set color blue
]
ask agentes [
set culture-tags n-values 11 [random 2]
set shared-culture (filter [ i -> i = 0 ] culture-tags)
]
ask agentes [
set time random-in-range 1 6
]
ask agentes [
assign-n-t-activity
]
END
to setup-activities
create-activities num-activity [
set shape "box"
set size 2
set xcor random-xcor
set ycor random-ycor
ask activities [
set t-culture-tags n-values 11 [random 2]
set shared-culture (filter [i -> i = 0] t-culture-tags)
]
ask activities [
assign-n-t-activity]
]
END
to assign-n-t-activity
if length shared-culture <= 4 [
set n-t-activity ["red"]
set color red
]
if length shared-culture = 5 [
set n-t-activity ["green"]
set color green
]
if length shared-culture = 6 [
set n-t-activity ["green"]
set color green
]
if length shared-culture >= 7 [
set n-t-activity ["black"]
set color black
]
END
to go
move-agentes
participate
tick
end
to move-agentes
ask agentes [
if time >= 2 [
rt random 40
lt random 40
fd 0.3
]
]
end
to participate
ask activities [
if count my-links < n-capacity [
let n-to-link ( n-capacity - count my-links)
let n-agentes-in-radius count (
agentes with [
n-t-activity = [n-t-activity] of myself ] in-radius sight-radius)
if n-agentes-in-radius < n-to-link [
set n-to-link n-agentes-in-radius
]
ask n-of n-to-link agentes with [
n-t-activity = [n-t-activity] of myself] in-radius sight-radius [
if time >= 2 [
create-participation-with myself [
set color [color] of myself ]
ask agentes [set time time - count my-participations] ]
]
ask activities [
if not any? agentes in-radius sight-radius [
ask participations [die]
]
]
]
]
end
to-report random-in-range [low high]
report low + random (high - low + 1)
END
EDIT V3
I asked Bill Rand to help me and he solved the problem. The issue was in this line: let candidates agentes with [ n-t-activity = [n-t-activity] of myself ] in-radius sight-radius. He solved the problem this way: let candidates agentes with [ n-t-activity = [n-t-activity] of myself and not participation-neighbor? myself ] in-radius sight-radius. Being this and not participation-neighbor? myself the condition to make sure that the agente is not already a part of that activity.
You almost never need foreach in NetLogo. If you find yourself thinking you need foreach, your immediate reaction should be that you need ask. In particular, if you are iterating through a group of agents, this is what ask does and you should only be using foreach when you need to iterate through a list (and that list should be something other than agents). Looking at your code, you probably don't want the while loop either.
UPDATED FOR COMMENTS and code - you definitely do not need while or foreach.
Your problem is the following code. You ask agentes that satisfy your conditions to create the links, but then you ask ALL AGENTES to change their time (line I have marked), not just the agentes that are creating participation links.
ask n-of n-to-link agentes with [
n-t-activity = [n-t-activity] of myself] in-radius sight-radius [
if time >= 2 [
create-participation-with myself [
set color [color] of myself ]
ask agentes [set time time - count my-participations] ] ; THIS LINE
]
The following code fixes this problem. I have also done something else to simplify reading and also make the code more efficient - I created an agentset (called candidates) of the agentes that satisfy the conditions. In this code, the candidates set is only created once (for each activity) instead of twice (for each activity) because you are creating it to count it and then creating it again to use for participation link generation.
to participate
ask activities
[ if count my-links < n-capacity
[ let candidates agentes with [
n-t-activity = [n-t-activity] of myself ] in-radius sight-radius
let n-to-link min (list (n-capacity - count my-links) (count candidates ) )
ask n-of n-to-link candidates
[ if time >= 2
[ create-participation-with myself [ set color [color] of myself ]
set time time - count my-participations ] ; REPLACED WITH THIS LINE
]
ask activities [
if not any? agentes in-radius sight-radius [
ask participations [die]
]
]
]
]
end