Sequelize - How return rows only if included model has at least one record - postgresql

Question

I want to this query in Sequelize:
const results = await WorkflowAssignation.findAndCountAll(
{
limit: limit,
offset: offset,
where:
{
userId: userIds,
status: status
},
include: [
{
model: WorkflowStepAssignation,
include: [
{ model: WorkflowStepAssignationHasUser, include: [ users ]}
]
},
{ model: users }
],
distinct: true,
order: [ [ 'createdAt', 'DESC'], [ { model: WorkflowStepAssignation, as: "steps" }, 'stepNumber', 'ASC' ] ]
});
The problem is that I need to return only WorkflowAssignation if the WorkflowStepAssignationHasUser table contain at least 1 record with the value passed as parameter for userid.
if I used a where in this line { model: WorkflowStepAssignationHasUser, include: [ users ]} it will still return all the WorkflowAssignation with only the steps that has the userId value and that's not what I want.
It is like I want to return all the WorkflowAssignation including all the tables but only if in WorkflowStepAssignation -> WorkflowStepAssignationHasUser has the users in the parameters.
Relations are:
WorkflowAssignation
has Many
WorkflowStepAssignation
has Many
WorkflowStepAssignationHasUser (has a userId column)

Answer 1

add required: true
const results = await WorkflowAssignation.findAndCountAll(
{
limit: limit,
offset: offset,
where:
{
userId: userIds,
status: status
},
include: [
{
model: WorkflowStepAssignation,
include: [
{ model: WorkflowStepAssignationHasUser, include: [ users ]}
]
},
{ model: users }
],
distinct: true,
required: true,
order: [ [ 'createdAt', 'DESC'], [ { model:
WorkflowStepAssignation, as: "steps" }, 'stepNumber', 'ASC' ] ]
});