Could You pls help me to type the condition using REGEXP_LIKE only one if it is doable :
WHERE ITEM_DESC LIKE '%P1%' AND ITEM_DESC NOT LIKE '%P2%'
Since Oracle does not support lookarounds, you need to get a little creative. Here's one way. Using a CTE, the first WITH just sets up test data. The second, ps1, contains only rows where the string contains 'PS1'. From those, select rows where the string does not contain 'PS2'. Only one REGEXP_LIKE like you asked for!
WITH tbl(ID, str) AS (
SELECT 1, 'test PS1 string' FROM dual UNION ALL
SELECT 2, 'test PS1 PS2 string' FROM dual UNION ALL
SELECT 3, 'test PS2 string' FROM dual
),
ps1(ID, str) AS (
SELECT ID, str
FROM tbl
WHERE REGEXP_LIKE(str, '.*PS1.*')
)
SELECT ID, str
FROM ps1
WHERE NOT str LIKE '%PS2%';
ID STR
---------- -------------------
1 test PS1 string
1 row selected.
Related
I have a string that I need to seperate into values seperated by commas. I have achieved this part with the below REPLACE statement:
declare #mc varchar(200)
declare #mc1 varchar(200)
select #mc = 'FRED&#g4;g;MARY&#g4;g;BILL&#g4;g;TIMOTHY&#g4;g;JOHNATHAN'
select #mc1 = REPLACE(#mc, '&#g4;g;',', ')
The replace returns a string 'FRED, MARY, BILL, TIMOTHY, JOHNATHAN'
I then want to have another variable that will return the first 3 characters of each value before the commas, so the above string would be returned as:
'FRE, MAR, TIM, JOH'
Anyone know how I can achieve this?
Also happy for this to be done directly to the original #mc variable
ON SQL Server 2017+ you can make use of openJson to split the string into manageble segments and then string_agg to assemble the desired result:
declare #mc varchar(100)='FRED&#g4;g;MARY&#g4;g;BILL&#g4;g;TIMOTHY&#g4;g;JOHNATHAN'
select String_Agg(v, ', ')
from (select #mc)x(s)
cross apply (
select Left(j.[value],3) v, Convert(tinyint,j.[key]) Seq
from OpenJson(Concat('["',replace(s,';', '","'),'"]')) j
where Convert(tinyint,j.[key]) % 2 = 0
)j;
Demo Fiddle
I find in my sql database string whit weird whitespace which cannot be replace like REPLACE(string, ' ', '') RTRIM and cant it even find with string = '% %'. This space is even transfered to new table when using SELECT string INTO
If i select this string in managment studio and copy that is seems is normal space and when everything is works but cant do nothing directly from database. What else can i do? Its some kind of error or can i try some special character for this?
First, you must identify the character.
You can do that by using a tally table (or a cte) and the Unicode function:
The following script will return a table with two columns: one contains a char and the other it's unicode value:
DECLARE #Str nvarchar(100) = N'This is a string containing 1 number and some words.';
with Tally(n) as
(
SELECT TOP(LEN(#str)) ROW_NUMBER() OVER(ORDER BY ##SPID)
FROM sys.objects a
--CROSS JOIN sys.objects b -- (unremark if there are not enough rows in the tally cte)
)
SELECT SUBSTRING(#str, n, 1) As TheChar,
UNICODE(SUBSTRING(#str, n, 1)) As TheCode
FROM Tally
WHERE n <= LEN(#str)
You can also add a condition to the where clause to only include "special" chars:
AND SUBSTRING(#str, n, 1) NOT LIKE '[a-zA-Z0-9]'
Then you can replace it using it's unicode value using nchar (I've used 32 in this example since it's unicode "regular" space:
SELECT REPLACE(#str, NCHAR(32), '|')
Result:
This|is|a|string|containing|1|number|and|some|words.
I have a column in my table having values of format:
COURSE_214/MODULE_5825/SUBMODULE_123/..../GOAL_124/ACTIVITY_125.
I need value for goal i.e 124 from goal_124. I am planning to use 'regexp_split_to_array' but don't know how to use elements from array.
I am using postgres 9.2.
You can use split_part like so:
select split_part(split_part('COURSE_214/MODULE_5825/SUBMODULE_123/..../GOAL_124/ACTIVITY_125', '/GOAL_', 2), '/', 1)
i.e.
select split_part(split_part(fieldname, '/GOAL_', 2), '/', 1)
Result:
124
Using json_object():
select json_object(string_to_array(translate(params, '_', '/'), '/'))
from test
json_object
------------------------------------------------------------------------------------------------
{"COURSE" : "214", "MODULE" : "5825", "SUBMODULE" : "123", "GOAL" : "124", "ACTIVITY" : "125"}
(1 row)
select json_object(string_to_array(translate(params, '_', '/'), '/'))->>'GOAL' as goal
from test
goal
------
124
(1 row)
The column has a format suitable for json. I would suggest to change the type of the column to jsonb. The first query may be used as a converter.
After the conversion you would access the parameters in an easy way, e.g.:
select *
from test
where params->>'COURSE' = '214'
and (params->>'GOAL')::int > 120;
Simple select of all GOAL_ parameters (if there are more than one)
select ltrim(elem, 'GOAL_')
from (
select unnest(string_to_array(params, '/')) elem
from test
) sub
where elem like 'GOAL_%'
You may try using regular expressions, getting the string between slashes
select substring(your_column from '^.*/(.*)/.*$') from your_table
If you expect to find in that part the GOAL value, use
select substring(your_column from '/GOAL_(.*)/') from your_table
With this query
SELECT trim(title) FROM (
SELECT
unnest( xpath('//p[#class="secTitle1"]', xmlText )::varchar[] ) AS title
FROM t1
) as t2
and XML input text with lines and spaces,
<root>
...
<p class="x">
text text
text text
</p><p> ...</p>
...
</root>
The trim() have no effect (!). It is a PostgreSQL bug? How to apply fn:normalize-space() with the XPath? I need something like "WHERE title is not null"? (Oracle is simpler...) How to do this simple query with PostreSQL?
Workaround
I need a well-configured build-in function, not a workaround... But I need to work and to show results, so I am using regular expression...
SELECT id, TRIM(regexp_replace(tit, E'[\\n\\r\\t ]+', ' ', 'g')) AS tit
FROM (
SELECT
id, -- xpath returns array of 1, 2, or more strings
unnest( xpath('//p[#class="secTitle1"]', texto )::VARCHAR[] ) AS tit
FROM t
) AS tmp
So, a "only simple space trim" is not friendly, not util (!).
EDIT after #mu comment
I try
SELECT id, TRIM(tit, E'\\n\\r\\t') AS tit
and
SELECT id, TRIM(tit, '\n\r\t') AS tit
both NOT WORKs.
QUESTION REMAINS:
there are no TRIM-option or postgresql configuration to say to TRIM work as it is required?
can I use normalize-space() at xpath? How?
I am using PostgreSQL 9.1, need to upgrade?
It works in 9.2, and it works on 8.4 too.
postgres=# select trim(unnest(string_to_array(e'\t\tHello\n\t\tHello\n\t\tHello', e'\n')), e'\t');
btrim
-------
Hello
Hello
Hello
(3 rows)
your regexp replace any char \n or \r or \t, but trim working with string "\n\r\t". It has different meaning than you expect.
I have had a look around and seem to have come across a strange issue with SQL Server 2008 R2.
I understand that with CONCAT_NULL_YIELDS_NULL = ON means that the following will always resolve to NULL
SELECT NULL + 'My String'
I'm happy with that, however when using this in conjunction with COALESCE() it doesn’t appear to be working on my database.
Consider the following query where MyString is VARCHAR(2000)
SELECT COALESCE(MyString + ', ', '') FROM MyTableOfValues
Now in my query, when MyString IS NULL it returns an empty (NOT NULL) string. I can see this in the query results window.
However unusually enough, when running this in conjunction with an INSERT it fails to recognise the CONCAT_NULL_YIELDS_NULL instead, inserting a blank ‘, ‘.
Query is as follows for insert.
CONCAT_NULL_YIELDS_NULL ON
INSERT INTO Mytable(StringValue)
SELECT COALESCE(MyString + ', ', '')
FROM MyTableOfValues
Further to this I have also checked the database and CONCAT_NULL_YIELDS_NULL = TRUE…
Use NULLIF(MyString, '') instead of just MyString:
SELECT COALESCE(NULLIF(MyString, '') + ', ', '') FROM MyTableOfValues
Coalesce returns the first nonnull expression among its arguments.
You're getting a ', ' because it's the first nonnull expression in your coalesce call.
http://msdn.microsoft.com/en-us/library/ms190349.aspx
From some of the answers provided I was able to assertain a more in depth understanding of COALESCE().
The reason the above query did not fully work was because although I was checking for nulls, and empty string ('') is not considered null. Therefore although the above query worked, I should have checked for empty strings in my table first.
e.g.
SELECT COALESCE(FirstName + ', ', '') + Surname
FROM
(
SELECT 'Joe' AS Firstname, 'Bloggs' AS Surname UNION ALL
SELECT NULL, 'Jones' UNION ALL
SELECT '', 'Jones' UNION ALL
SELECT 'Bob', 'Tielly'
) AS [MyTable]
Will return
FullName
-----------
Joe, Bloggs
Jones
, Jones
Bob, Tielly
Now row 3 has returned a "," character which I was not originally expecting due to a Blank but NOT NULL value.
The following code now works as expected as it checks for blank values. It works, but it looks like I took the long way around. There may be a better way.
-- Ammended Query
SELECT COALESCE(REPLACE(FirstName, Firstname , Firstname + ', '), '') + Surname AS FullName0
FROM
(
SELECT 'Joe' AS Firstname, 'Bloggs' AS Surname UNION ALL
SELECT NULL, 'Jones' UNION ALL
SELECT '', 'Jones' UNION ALL
SELECT 'Bob', 'Tielly'
) AS [MyTable]