I have a column named membership_number varchar(255) in the memberships table.
Here is some sample data:
0000001234
0000002345
0000003456
membership_number must have 10 digits. If a user enters a number that has less than 10 digits, then the missing places are filled with leading zeroes accordingly.
At the moment, I have some data in this column as follows:
00001234.0
00002345.1
00003456.2
I would like to delete the decimal point which is the 2nd to the last digit and then add a leading zero to handle all of these undesired membership numbers. What would be the best way to do this?
I am aware of SUBSTRING() and its parameters but couldn't make it work so far.
Please backup your data before trying this.
Would that work?
UPDATE tablename SET membership_number = concat('0',replace(membership_number,'.','')) WHERE membership_number LIKE '%._'
Substring is not the function you want, you want a combination of REPLACE and LPAD functions:
select lpad( replace (membership_number, '.', ''), 10, '0')
from menberships;
(table name assumed) And why if it must be 10 digits do you define it as length up to 255?
Related
I have to split the content of a column into 2 differents columns using the QGIS Field Calculator. Basically, my table is something like that:
Basically I have to work with descriptio column omitting characters from 1-12 and then copy next 8 characters (in this case "AgilisSi") into the PresLACAGI column.
The other element to copy is the final number in descriptio column, ranging from 1 to 3 characters. Possibly the best is thing would be a syntax that reproduces in CodiClapa column the number after ": ", including the space in the syntax.
Thanks a lot!
Use the field calculator, check Update existing field and select column from drop down and type in the Expression window for:
PresLACAGI: substr(descriptio,12,8)
CodiClapa: right(descriptio,3)
I have a text column in my database table which contains values like
A/B
A/B/C
A/B/C/D
A/B/C/D/E
Now, I want to select only those rows where this column value contains maximum three occurrences of '/'.
For clarity - expected output should be:
A/B
A/B/C
A/B/C/D
Can anyone help me with such a query?
I think it would be easier to simply remove everything else and count the number of remaining characters:
where length(regexp_replace(the_column, '[^/]', '', 'g')) <= 3
Online example
I am looking to pull a substring from a Oracle database column using PL/SQL.
The column has a large string value which varies in size for different rows. Hence the substring I am referring to will not be in the same position for each row. But the substring is uniquely identifiable. It will be like ",RID!1455,". i.e. It will be preceded by a comma, have RID, followed by a !, followed by a number and then a comma.
I am interested in pulling this number followed by RID. Can you please help me with this. Thank you very much in advance
Consider below query:
Suppose table text1 has column text with string:
dfgggsdRID!3242dfgdfdg
Then below query will give you result '3242':
select substr(text, (select (INSTR(text, 'RID!', 1)+4) FROM text1),4) from text1;
I am loading data into Oracle 12c using sqlldr using a CTL file as below :
OPTIONS (rows=1000, bindsize=100000, readsize=100000, silent=header,feedback)
load data
CHARACTERSET UTF8
insert into table TABLEA
fields terminated by '^' optionally enclosed by ','
trailing nullcols
(
NAME,
VOLUME "decode(:VOLUME,null,0,to_number(:VOLUME,'9999999999D999'))",
TEXT
)
I am facing difficulty when the number field VOLUME defined in table as NUMBER(13,3) comes in different formats.
ABCD^1089.830^CIQ
ABCD^1,089.830^CIQ
ABCD^1.089,830^CIQ
Is there a way to load all three formats of number field in field 2 above using sqlldr ?
Expected value in the table is 1089.830 for the all three cases .
Thanks.
This is a tad ugly but it should work. It assumes your volume value data will always have 3 decimal points and the decimal symbol will be a period (based on your number format). First pass removes all region-specific characters, then second pass puts the period in 3 places from the end:
...
VOLUME decimal external "regexp_replace(regexp_replace(:VOLUME, '[\.,]', ''), '([0-9]+)([0-9]{3})', '\\1.\\2')",
...
You may not need the "decimal external", try it without and see.
If I have data that includes a numeric column with values into the miillions (eg 63254830038), and I want to format the number as a US Dollar amount (eg. $63,254,830,038), I know I can use:
SELECT numeric_column, to_char(numeric_column, '$999G999G999G999') from table
to format the values, but to do so reliably I either have to include an unnecessarily long text string ('$999G999G999G999') or know the maximum number of possible digits. Is there a way to say, broadly, "group numbers with a comma" instead of explicitly saying "group the hundreds, group the thousands, Oh! and please group the millions"?
You just need cast integer to money type.
E.g.:
tests=> select cast(63254830038 as money);
Or alternative syntax:
tests=> select 6323254830038::money;
And output (I'm from Poland, so money type take my locales and set correct currency symbol):
money
----------------------
63.254.830.038,00 zł
Monetary Types documentation.
You can try something like this (works in sql-server, not sure about postgresql)
select convert(varchar,cast('63254830038' as money),1)
You could do things the hard way using regular expressions: convert the number into a string, reverse it, use regexp_replace to insert commas between pairs of 3 digits, and then reverse it again:
select '$' || reverse(regexp_replace(
reverse(numeric_column::varchar),
E'(\\d\\d\\d)(?=\\d)', '\1,', 'g'))
Explanation
The first argument to regexp_replace is the expression to match, which contains two parts:
(\\d\\d\\d) means 3 digits, which are captured
(?=\\d) is a positive lookahead constraint of a single digit, meaning the match only counts if there is a digit following it. (That is, this digit is checked to exist, but it does not count as part of the match.)
The second argument is what to replace with: the 3 captured digits, plus a comma.
The third argument 'g' is a flag indicating that it should match and replace as many times as possible.
For more information on regular expressions in PostgreSQL, see the documentation.