Agent moving from machine block (machine block delay is 9 minutes) to milling block. At the milling block, 7 percent gets rejected and goes back to the machine block.
Now rejected agents move from machine to milling block, but this time the machine block delay time is 12 minutes. The question is, how can I achieve this 12 minute delay time now?
*** The logic image is given below:***
In the agent type of of your agents going through the process, create a variable of type boolean and call it rejected with initial value false. On Exit (false) of the your selectOutput1 write:
agent.rejected = true
The delay of the machine block should be
agent.rejected ? 12 : 9
Related
The "Assembler" should stop working for 2 hours after 10 assemblies are done.
How can I achieve that?
There are so many ways to do this depending on what it means to stop working and what the implications are for the incoming parts.. but here's one option
create a resourcePool called Machine, this will be used along with the technicians:
on the "on exit" action of the assembler do this (I use 9 instead of 10 because the out.count() doesn't count until the agent is completely out, so when it counts 9, it means that you have produced 10)
if(self.out.count()==9){
machine.set_capacity(0);
create_MyDynamicEvent(2, HOUR);
}
In your dynamice event (that you have to create) you will add the following code:
machine.set_capacity(1);
A second option is to have a variable countAssembler count the number of items produced... then
on exit you write countAssembler++;
on enter delay you write the following:
if(countAssembler==10){
self.suspend(agent);
create_MyDynamicEvent(2, HOUR,agent);
}
on the dynamic event you write:
assembler.resume(agent);
Don't forget to add the parameter needed in the dynamic event:
Create a variable called countAssembler of type int. Increment this as agents pass through the assembler. Also create a variable called assemblerStopTime. You also record the assembler stop time with assemblerStopTime=time()
Place a selectOutputOut block before the and let them in if countAssembler value is less than 10. Otherwise send to a Wait block.
Now, to maintain the FIFO rule, in the first selectOutputOut condition, you need to check also if there is any agent in the wait block and if the current time - assemblerStopTime is greater than 2. If there is, you free it and send to the assembler with wait.free(0) function. And send the current agent to wait. You also need to reset the countAssembler to zero.
I create an integer to count the number of assemblies (e.g. countAssembler)
On exit from FA1 (countAssembler++;)
Then I have an event triggered by a condition such that when the count of assemblies reaches 10 ((countAssembler==10)), it suspends the FA1 for two hours using suspend function.
But how do I implement the suspend function? Do you have any ideas?
note that the suspend function doesn't suspend the assembler, but an item that is currently being processed in the assembler...
have a variable countAssembler count the number of items produced... then
on exit you write countAssembler++;
on enter delay you write the following:
if(countAssembler==10){
self.suspend(agent);
create_MyDynamicEvent(2, HOUR,agent);
}
on the dynamic event you write:
assembler.resume(agent);
Don't forget to add the parameter needed in the dynamic event:
Note that the suspend will start when part 11 starts being assembled, which means that the machine will be suspended for 2 hours + the time between the 10th assembly end and then 11th assembly start... you can fix that easily but im not including it in my answer
I'm using a state chart in combination with a schedule in Anylogic (see picture). The output of the schedule is equal to 1 during working hours and 0 otherwise. Now I want the transition from state1 to state2 to happen when the schedule is turning to 1 or is equal to 1(so otherwise wait until the working hours).
I have tried using an if statement
if( main.plannerSchedule()==1 )(<perform action>)
However, by this method, the state transition only happens if the statement is true but doesn't wait for it to become true. Is there a way to constantly update the state transition or is there a "wait until" function that can solve this problem?
Best let the schedule send a message to your statechart when it switches. This assumes that the statechart lives on the same agent type as the schedule. Write this code in the action code box of the schedule:
if (value==1) {
statechart.fireEvent("go to state 2");
}
Obviously, your message transition needs to await the "go to state 2" message.
Note the value keyword. See https://www.benjamin-schumann.com/blog/2016/2/4/the-magic-lightbulb-and-how-it-can-help-your-anylogic-modelling for more info on that
Hi working on Production Model where I am working in shifts( 8:00AM to 4:30PM) and the requirement is that work should be done in one shift only otherwise shift it to next day. so for example lets say my agent enter the service block at 4:00 PM and shift end at 4:30 PM, the average time require to complete this task is 3hours, What I want to do is to check the available time and if time is not sufficient ( like in this case i have only 30 mins) the agent should be sent to waiting area and next day service block should start working on that agent first.
One way: Add A SelectOutput block ahead of the Service. In the condition, check
mySchedule.getTimeOfNextValue() - time() > x
Where x is the remaining time window you allow, i.e. the task duration the agent will require once entering the servive.
If there is not enough x left, you send the agent to some Wait block, else they are allowed to enter
PS: Also check the other functions that Schedule allows, might be you need some of them. Always check all capabilities a block offers you via code-complete (ctrl+space or Option+space on Mac)
I'm trying out some code that is supposed to block until moving to a new simulation time step (similar to waiting for sys.tick_start in e).
I tried writing a function that does this:
task wait_triggered();
event e;
`uvm_info("DBG", "Waiting trig", UVM_NONE)
-> e;
$display("e.triggered = ", e.triggered);
wait (!e.triggered);
`uvm_info("DBG", "Wait trig done", UVM_NONE)
endtask
The idea behind it is that I trigger some event, meaning that its triggered field is going to be 1 when control reaches the line with wait(!e.triggered). This line should unblock in the next time slot, when triggered is going to be cleared.
To test this out I added some other thread that consumes simulation time:
fork
wait_triggered();
begin
`uvm_info("DBG", "Doing stuff", UVM_NONE)
#1;
`uvm_info("DBG", "Did stuff", UVM_NONE)
end
join
#1;
$finish(1);
I see the messages Doing stuff and Did stuff, but Wait trig done never comes. The simulation also stops before reaching the finish(1). One simulator told me that this is because no further events have been scheduled.
All simulators exhibit the same behavior, so there must be something I'm missing. Could anyone explain what's going on?
The problem is with wait (!e.triggered); when e.triggered is changing from 1 to zero. It has to change in a region where nothing can be scheduled, so whether it changes at the end of the current time slot, or the beginning of the next time slot is unobservable. So the wait will hang waiting for the end of the current time slot, which never comes.
I think the closest thing to what you are looking for is #1step. This blocks for the smallest simulation precision time step. But I've got to believe there is a better way to code what you want without having to know if time is advancing.