I want to calculate how far I am through the week and / or the current month in Google Sheets. What's the best way to do this?
Ideally in a single cell too. I also want to account for the difference in number of days from month to month.
see:
month progress:
=1-(EOMONTH(TODAY(), )+"23:59:59.999"-NOW())/
(EOMONTH(TODAY(), )+"23:59:59.999"-(EOMONTH(TODAY(), -1)+1))
week progress:
=1-((TODAY()+7-WEEKDAY(NOW(), 2)+"23:59:59.999")-NOW())/
((TODAY()+7-WEEKDAY(NOW(), 2)+"23:59:59.999")-(TODAY()-WEEKDAY(NOW(), 2)))
demo sheet
For weekly, I did this by taking the current timestamp (now()) and the timestamp at the beginning of the week and converting both to unix epoch times. Then, I used the difference between them and divided both by the number of seconds in a week (518400) and this gave me a decimal for the percent the now() is through the week.
=((now()-DATE(1970,1,1))*86400-((to_date(TODAY()-weekday(now(),3))
+ timevalue("00:00am"))-DATE(1970,1,1))*86400)/518400
For monthly, I did this similarly to the weekly method but, to account for the differing number of days in different months, I calculated the timestamp at the end of the month in unix epoch time and then subtracted the time at the beginning of the month from this to work out how many seconds are in the current month.
=((now()-DATE(1970,1,1))*86400-((to_date(eomonth(today(), -1)+1)
+ timevalue("00:00am")-DATE(1970,1,1))*86400))/((to_date(eomonth(today(), 0))
+ timevalue("23:59")-DATE(1970,1,1))*86400-(to_date(eomonth(today(), -1)+1)
+ timevalue("00:00am")-DATE(1970,1,1))*86400)
Related
I've been having a look around but I can't seem to find anything that answers this question. I want to calculate the date for the last week of every month. For example, the date for the last week of April 2021 is 26-04-2021. I want a date, not a week number.
I use Google Big Query, I do have a calendar table I could use to extract year and month.
Thanks,
Emily
Try date_trunc:
SELECT date_trunc(last_day(month1st, month), week(monday))
from unnest(GENERATE_DATE_ARRAY('2021-01-01', '2021-12-01', interval 1 month)) AS month1st;
I want to get two fields: Begin date and End date of last month. For example, 14-04-2020 should give me the Begin date as 01-03-2020 and End_date as 31-03-2020. I have read the Nifi Expression language docs but all it can do with a date format is add or subtract in milliseconds. This is not helpful for my use case as the number of days in a month is not fixed and conversion to milliseconds won't help.
Is there a way to achieve my use case somehow using Nifi Expression language?
#AdarshKumar
NiFI Expression Language for this Use Case would be very clunky and unreliable for different timezones, months with <> 30 days, and leap years.
Please reference this post below which goes into detail for how to get "last month":
How to insert previous month of data into database Nifi?
In the Case of NiFi you kind of have to play with the dates to get the outcome
if you have the dates you easily convert a date and then just hard set a day to get the 1st day of the month with a hard coded day
${now():toNumber():format('yyyy-MM-01')}
to get the last day of the month you can either use the script or play with the calc using epoch time.
so to get the last day of the previous month you can just use the date and convert the day into epoch time and subtract it from the epoch date to get last day of previous month
example
${now():toNumber():format('yyyy-MM-dd'):toDate('yyyy-MM-dd', 'GMT'):toNumber():minus(${now():toNumber():format('dd'):toNumber():multiply(86400):multiply(1000)}):format('yyyy-MM-dd')}
in this example above we convert the date to epoch format it to convert again, conversion happens to remove default timestamp and then we use the same formula to get just the day as a number to multiply it with 86400 seconds in a day and multiply that by 1000 for the epoch number to subtract from the date which is then formatted back into a date.
Raw Date: Thursday, August 26, 2021 11:20:31 AM
formatted: Thursday, August 26, 2021 12:00:00 AM
epoch of formatted date: 1629936000000
Subtract Epoch: 2246400000 (86400 seconds * 26 days * 1000)
result: 2021-07-31
alteratively you could first add a month and the work back to get the current day of the given month
this example is just to give you an idea of ways you can use built in date functions with epoch time to calculate the correct date, removing the issues with months that end on specific numbers.
I try UpdateAttribute to minus month
test${now():toNumber():format('yyyyMM'):minus(1)}01
I need to convert Week to start with Sunday (range 1-53, with a Sunday in this year)
Ex. DATE_PART(w,'2020-01-05') (Sunday)
This should return 2 instead of 1.
Thanks in advance.
If you wish to obtain the Week Number where a week starts on Monday instead of Sunday:
Subtract one day to the date being convert to the Week Number
So, use:
DATE_PART(w, date_field - INTERVAL '1 DAY')
This returns the Week Number of the 'previous day'.
Unfortunately, it won't work for the first day of the year, which will appear to be the last day of the previous year. Depending on how your organization treats the first/last weeks of the year, this might be okay.
If that is not satisfactory, then you could write your own User-Defined Function (UDF) and code it to return the values you desire.
I have a data set spanning 2 years and is updated daily, created a dashboard to give a view of incidents by date group. I have created a parameter using date trunc for Day/Week/Month/Quarter/Year. This is in Tableau.
I am trying to get the parameter to show a Week to date, Month to date and so on view. IE if on Weds 15th Dec I selected the weekly view, it would only show data for every week in the data set for Sat-Weds (My weeks go Sat-Fri) or the monthly view every month between 1st-15th
Ideally I am wanting this as a simple parameter for a drop down menu, I can do the week to date stuff as a rolling sum restarting every week in a separate table, but for ease I just need a date group function that will allow to do this.
Any suggestions would be appreciated.
Cheers
Pete
The solution is 5 parts:
Date Part Parameter
Max date [Max Date]
Dynamic date part of the Max date [Dynamic Date Part Max]
Dynamic date part of the historical dates [Dynamic Date Part]
Filter those date parts <= the Max date [Dynamic Date - Lass than Max]
Date Part Parameter
Max Date
This is the calculation you'd use with your dataset to find the max date.
{ MAX([Order Date]) }
In order to create a good example, I'm going to set my Max date to a specific date the falls in the middle of a week, in the middle of a month and middle of the year. I'm going use June 13th, 2018 as my Max Date.
So, if you want to follow along you can use the below date as your max date. You can also use this data set if you'd like.
DATE(#2018-06-13#)
Dynamic date part of the Max date
DATEPART([Select Date Part], [Max Date])
Dynamic date part of the Historical dates
DATEPART([Select Date Part], [Order Date])
Filter on Historical dates parts <= the Max Date
[Dynamic Date Part] <= [Dynamic Date Part Max]
Now that we have all the pieces we need let's check to make sure they are working as we would expect.
Looks like we're seeing all the days of the month that are <= the 13th.
When we change it to Day of the Week we see only the days of the week <= the 4th day of the week which is Wednesday when the week starts on Saturday.
Now let's calculate the running sum of sales along our dynamic date part to better help you with your example.
Drag the measure you want to calculate the running sum onto the label, then create a quick table calculation. We'll next need to edit this table calculation as so.
You'll then see your calculation working as you would expect.
Hope this was helpful. Happy vizzing!
I have a small application built in Excel. It is a time management workbook where I record the hours worked on projects for each month.
In one column I have the possible days
e.g.
DAY 1
DAY 2
DAY 3
DAY 4
....
DAY 22
for the possible 22 workdays in a month. I have a worksheet for each month.
For each of those day numbers how would I calculate the date for that day in the Month?
You can try WORKDAY - Does the following helps?