Write a function that accepts a string and check whether it is a palindrome at a word level and returns a Boolean. Concretely, a string like “He was so was he” is a palindrome by this definition because the last word is identical to first and the last second word is equal to the second word. The function should be case insensitive, meaning it should return True for both “ThEY CAME CAME tHey” and “they came came they”.
Related
I am attempting to import a CSV into ADF however the file header is not the first line of the file. It is dynamic therefore I need to match it based on the first column (e.g "TestID,") which is a string.
Example Data (Header is on Line 4)
Date:,01/05/2022
Time:,00:30:25
Test Temperature:,25C
TestID,StartTime,EndTime,Result
TID12345-01,00:45:30,00:47:12,Pass
TID12345-02,00:46:50,00:49:12,Fail
TID12345-03,00:48:20,00:52:17,Pass
TID12345-04,00:49:12,00:49:45,Pass
TID12345-05,00:50:22,00:51:55,Fail
I found this article which addresses this issue however I am struggling to rewrite the expression from using an integer to using a string.
https://kromerbigdata.com/2019/09/28/adf-dynamic-skip-lines-find-data-with-variable-headers
First Expression
iif(!isNull(toInteger(left(toString(byPosition(1)),1))),toInteger(rownum),toInteger(0))
As the article states, this expression looks at the first character of each row and if it is an integer it will return the row number (rownum)
How do I perform this action for a string (e.g "TestID,")
Many Thanks
Jonny
I think you want to consider first line that starts with string as your header and preceding lines that starts with numbers should not be considered as header. You can use isNan function to check if the first character is Not a number(i.e. string) as seen in the below modified expression:
iif(isNan(left(toString(byPosition(1)),1))
,toInteger(rownum)
,toInteger(0)
)
Following is a breakdown of the above expression:
left(toString(byPosition(1)),1): gets first character fron left side of the first column.
isNan: checks if the character is "not a number".
iif: not a number, true then return rownum, false then return 0.
Or you can also use functions like isInteger() to check if the first character is an integer or not and perform actions accordingly.
Later on as explained in the cited article you need to find minimum rownum to skip.
Hope it helps.
Following the short docs on regexp_matches:
Return all captured substrings resulting from matching a POSIX regular expression against the string.
Example: regexp_matches('foobarbequebaz', '(bar)(beque)') returns {bar,beque}
With that in mind, I'd expect the result of regexp_matches('barbarbar', '(bar)') to be {bar,bar,bar}
However, only {bar} is returned.
Is this the expected behavior? Am I missing something?
Note:
calling regexp_matches('barbarbar', '(bar)', 'g') does return all 3 bars, but in table form:
regexp_matches text[]
{bar}
{bar}
{bar}
This behavior is described more in details in 9.7.3. POSIX Regular Expressions :
The regexp_matches function returns a set of text arrays of captured
substring(s) resulting from matching a POSIX regular expression
pattern to a string. It has the same syntax as regexp_match. This
function returns no rows if there is no match, one row if there is a
match and the g flag is not given, or N rows if there are N matches
and the g flag is given. Each returned row is a text array containing
the whole matched substring or the substrings matching parenthesized
subexpressions of the pattern, just as described above for
regexp_match. regexp_matches accepts all the flags shown in Table
9.24, plus the g flag which commands it to return all matches, not just the first one.
This is expected behavior. The function returns a set of text[] which means that multiple matches are presented in multiple rows. Why is it organized this way? The goal is to make it possible to find more than one token from a single match. In this case, they are presented in the form of an array. The documentation delivers a telling example:
SELECT regexp_matches('foobarbequebazilbarfbonk', '(b[^b]+)(b[^b]+)', 'g');
regexp_matches
----------------
{bar,beque}
{bazil,barf}
(2 rows)
The query returns two matches, each of them containing two tokens found.
I am working on FileMaker 14 and am using ScriptParameters. In my parameters I use text, not numbers. I am looking for a way to calculate whether a parameter is empty or not, but the code below returns a 0 value (false) if there is text in ScriptParameter or not:
If [ isEmpty ( Get ( ScriptParamter ) ) ]
The help docs in FileMaker do say that IsEmpty will return a value of 0 if the argument is text. So obviously I am looking for a different calculation or something. Ideas?
Thanks
GW
FileMaker's IsEmpty() function absolutely returns TRUE (1) if a text argument is truly empty. If you're getting false, there's something in your script parameter.
It looks like you might be passing multiple values in your script parameter (based on your use of the plural "script parameters"). If so, your script parameter will never evaluate to true, because of the presence of one or more carriage returns. If you need to pass multiple values, you'll need to first extract a given value using GetValue( Get(ScriptParameter); ), which gets the nth line of text without a trailing carriage return, then test the extracted value.
If that's not right (and you're only passing a single value), this likely means you're passing invisible characters in your script parameter you're not aware of. To test, you can use Length( Get(ScriptParameter) ) to test how many characters FileMaker "sees" in your script parameter. To quickly get a handle on invisible characters, you might use Code( Get(ScriptParameter) ), which will return the ASCII codes for each character. This can quickly reveal if you have spaces, tabs, returns, etc.
The help docs in FileMaker do say that IsEmpty will return a value of
0 if the argument is text.
No, that's most certainly not true. IsEmpty() will return a value of
0 if the argument is empty. If your parameter is of type text, then IsEmpty() will return 0 if and only if the parameter is a string of zero length.
I re explain my pb in a large a.txt file i have
Amount of Food is 1
Desired Travel is 5
I need to read the 1 after the 'Amount of Food is ' expression and the 5 after the 'Desired Travel is' expression, Thanks again
You can have a look at this: with regexpi you can simply look for numbers in your strings.
The syntax is as simple as this:
startIndex = regexpi(str,expression)
where the expression parameter is a regex expression (i.e. '\d*' to retrieve consecutive digits).
In your specific case a way to perform this with regular expressions would be:
First you have to decide what strings are valid in your search
for example:
firstpar = 'First parameter is [0-9]+';
means that you are looking for a string 'First parameter is '
that ends with a sequence of digits.
Then you could use regexp or regexpi in the following way:
results = regexp(mystring, firstpar, 'match');
Where mystring is the text you perform the search on and 'match' means that you want parts of the text as output, not indexes.
Now, results is a cell matrix with each cell containing a string that appeared in your text and fulfilled your firstpar definition. In order to extract just the numbers from cell matrix of strings you could use regexp again, but now helping yourself with cellfun, which iteratively applies your command to all cells of a cell matrix:
numbers = cellfun(#(x) str2num(regexp(x, '[0-9]+', 'match', 'once')), results);
numbers is an array of numbers that you were looking for.
You can do the same for different string patterns - if you want to have a more general string definitions (instead of straightforward firstpar that we used here) read matlab documentation about regular expressions (alexcasalboni pasted it in his comment), scroll down to Input Arguments and expand 'expressions'.
The difference between regexp and regexpi is that the latter is case insensitive.
I have some code where I am converting some data elements in a flat file. I save the old:new values to a hash which is written to a file at the end of processing. On subsequence execution, I reload into a hash so I can reuse previously converted values on additional data files. I also save the last conversion value so if I encounter an unconverted value, I can assign it a new converted value and add it to the hash.
I had used this code before (back in Feb) on six files with no issues. I have a variable that is set to ZCKL0 (last character is a zero) which is retrieved from a file holding the last used value. I apply the increment operator
...
$data{$olddata} = ++$dataseed;
...
and the resultant value in $dataseed is 1 instead of ZCKL1. The original starting seed value was ZAAA0.
What am I missing here?
Do you use the $dataseed variable in a numeric context in your code?
From perlop:
If you increment a variable that is
numeric, or that has ever been used in
a numeric context, you get a normal
increment. If, however, the variable
has been used in only string contexts
since it was set, and has a value that
is not the empty string and matches
the pattern /^[a-zA-Z][0-9]\z/ , the
increment is done as a string,
preserving each character within its
range.
As prevously mentioned, ++ on strings is "magic" in that it operates differently based on the content of the string and the context in which the string is used.
To illustrate the problem and assuming:
my $s='ZCL0';
then
print ++$s;
will print:
ZCL1
while
$s+=0; print ++$s;
prints
1
NB: In other popular programming languages, the ++ is legal for numeric values only.
Using non-intuitive, "magic" features of Perl is discouraged as they lead to confusing and possibly unsupportable code.
You can write this almost as succinctly without relying on the magic ++ behavior:
s/(\d+)$/ $1 + 1 /e
The e flag makes it an expression substitution.