Test Rigor to recognize your selection on a pop up action in a browser - testrigor

I'm creating a automation test using [Test Rigor} in chrome when I start a phone call a pop up will appear to Enable Microphone and Video. However Test Rigor isn't recognizing it. Is there a command that will

testRigor automatically closes all the popups.

Related

Enable location detection in TestRigor

could you please explain how I can enable location detection in the TestRigor browser? For user it looks like browser pop-up, but rigor skip this pop-up and I receive only errors which caused by unavailable location (important for my project). I mean this pop-up
testRigor automatically accepts location popups and other browser-based permission requests. There is no need to add an action in your custom steps to handle them.
Update: testRigor has updated this to allow you to click on these browser pop-ups. You can click these by using OCR only if you have screenshots enabled at the OS level.
To do this, you can check it in Settings->Advanced, then scroll down to Desktop Web Fine Tuning and select Use OS (more features) from the How to take screenshots: dropdown.
Once that is done, you can use a command to click on the browser pop-up. For the one in the picture, you can say the following:
click "Allow" using OCR only using the mouse

Google Actions trigger by physical button

Is it currently possible to trigger a google action (intent) command through a physical button, rather than voice?
Instead of Hey Google, (custom command for custom action),
A button is pressed and the text command is sent to the google home triggering the intent.
I'm attempting to do this through Raspberry Pi 3 (Android Things) and Actions Console.
Yes, you probably want to look into the Assistant SDK.

How do I use Chrome's Developer Tools to catch the end destination for a click-event?

As a policy for security I want to stay logged-in by default to my social media networks, but I do not want external desktop links to open in my browser that is logged in. So my default browser-mode is --incognito. I have an issue with Chromium's Signal App crashing when my browser is set to default in incognito mode. This much I've figured out.
I want to have a bookmark that I can manually run in my logged in browser to run the Signal app.
The Chrome web store provides one such link. I can run signal by running Chromium outside of incognito mode and clicking in the webstore LAUCNH APP. I would like to use the Developer Tools to catch that even and know what the end-url is that triggers the Signal App.
How do I go about introspecting that?
I don't really understand the specifics of your use case, but going off of the title of your question, perhaps this will help:
Set an event listener breakpoint for Mouse > click.
Click on the element to trigger the listener(s).
Step through the code.

Is it possible to quit iOS app after we do some checks

We don't want the user enter our app if the app is out-dated.
Is that is possible to quit a iOS app when we do some date check BEFORE the app launch?
Or it is possible to quit the application after the main view is loaded?
Before the app launches: no. The launch animation is already in progress when the OS calls main.
After some time (1-2 sec): yes. You can use one of
[[UIApplication sharedApplication] terminateWithSuccess];
exit(0);
abort();
assert(0);
pthread_kill(pthread_self());
so many ways, but neither will go through AppStpre - you're not supposed to close your app programmatically. You're supposed to notify the user via an UIAlertView about the outdated app and disable interaction with the app.
According to Apple you cannot exit(quit) your application through code. i.e if you use exit(0). Your application will be rejected for that. Although you can use exit(1) and delay the exit time of your application. Or you may like to use local notification which is quite handy.
Don’t Quit Programmatically
Never quit an iOS application programmatically because people tend to
interpret this as a crash. However, if external circumstances prevent
your application from functioning as intended, you need to tell your
users about the situation and explain what they can do about it.
Depending on how severe the application malfunction is, you have two
choices.
Display an attractive screen that describes the problem and suggests a
correction. A screen provides feedback that reassures users that
there’s nothing wrong with your application. It puts users in control,
letting them decide whether they want to take corrective action and
continue using your application or press the Home button and open a
different application
If only some of your application's features are not working, display
either a screen or an alert when people activate the feature. Display
the alert only when people try to access the feature that isn’t
functioning.
Source

How to detect WebKit Inspector?

I know how to detect Firebug in FF (if (window.console && window.console.firebug) alert ('Buu'); ) but how detect or disable Web Inspector in WebKit??
I don't recommend trying to reach out of your website and into the user's browser settings. If you succeed in turning off Web Inspector, users will start wondering why Web Inspector is spontaneously dying.
The Web Inspector injected code runs in an isolated world inside the inspected page for Chrome, so it cannot be detected from the code running in the inspected page's main world (see e.g. a class comment in http://www.opensource.apple.com/source/WebCore/WebCore-777.1/bindings/v8/V8IsolatedContext.h).