Usually we use EXTRACT (FROM YEAR date_column) = 2000 (let it be 2000 year). Also we can add EXTRACT (MONTH FROM date_column) = 1 (let it be January). Also we can extract a day - EXTRACT (DAY FROM date_column) = 5 (let it 5). But is it possible to use the pattern for this data? How does it look like in Postgres SQL
Say we have the table Shipment, the columns - date_payment, quantity, sum.
I'd like to get the table that content all shipments for 01.01.2020
How to query this table with data format 'YYYY-MM-DD', not using EXTRACT-function?
If the date column is a date type then:
SELECT * FROM some_table WHERE date_col = '2020-01-01';
If the column is timestamp or timestamptz then:
SELECT * FROM some_table WHERE date_trunc('day', date_col) = '2020-01-01'
Beware that with timestamptz time zones come into play when doing the date_trunc. From here date_trunc:
When the input value is of type timestamp with time zone, the truncation is performed with respect to a particular time zone; for example, truncation to day produces a value that is midnight in that zone. By default, truncation is done with respect to the current TimeZone setting, but the optional time_zone argument can be provided to specify a different time zone. The time zone name can be specified in any of the ways described in Section 8.5.3.
For a timestamp value per the above link:
A time zone cannot be specified when processing timestamp without time zone or interval inputs. These are always taken at face value.
Related
There are two variables:
$mm = "01";
$yy = "22";
I need to store it in one column Postges mmyy.
What is type mmyy must be if there is not day?
Or I can use the first day of month always like: 010122.
Eventually, I want to filter rows with where mmyy > now().
If you want to treat it like a date/time value, preferably store it as date. That would be:
date '2022-01-01'
Occupies only 4 bytes, same as int4.
Always use ISO format, which is unambiguous regardless of your locale settings. More in the manual.
To convert your variables, you might use the Postgres function to_date():
test=> SELECT to_date('2201', 'YYMM');
to_date
------------
2022-01-01
(1 row)
test=> SELECT to_date('22'::text || '01'::text, 'YYMM');
to_date
------------
2022-01-01
(1 row)
Or prepare a date literal in ISO format.
When compared to now() (which returns timestamp with time zone) the date value is coerced to the first instant of Jan 1st, 2022 at the time zone determined by the current setting of your session. See:
Difference between now() and current_timestamp
So it works as intended out of the box - except that you possibly haven't thought about time zones, yet ...
For other tasks with date arithmetic, an integer might be a good choice. See:
How do you do date math that ignores the year?
Using psycopg to connect to a Redshift DB I am trying to group by date (in a specific time zone, given at query time). All date_times are stored without time zone (and correspond to UTC timestamps).
I have been trying the following:
SELECT DISTINCT DATE(TIME_ZONE(%(time_zone)s, date_time_dim.timestamp)) AS date,
SUM(meals.sugar_in_g) AS total_sugar
FROM meals
INNER JOIN date_time_dim
ON meals.created_at = date_time_dim.timestamp
WHERE meals.patient_id=%(patient_id)s
AND date_time_dim.timestamp >= %(utc_start_date_time)s
AND date_time_dim.timestamp <= %(utc_end_date_time)s
GROUP BY date
ORDER BY date ASC;
with the following query dictionary:
utc_start_date_time UTC-converted date time
utc_end_date_time UTC-converted date time
patient_id an integer
time_zone, a string, ex: 'US/Hawaii'
The goal being to have one entry for each date (in the given time zone).
What I tried gives me:
function time_zone("unknown", timestamp without time zone) does not exist
What am I missing ?
Edit: This is the same with CONVERT_TIME_ZONE, with and without source time_zone, with and without type casting time_zone to VARCHAR.
The function in Redshift to return a timestamp in a different timezone is TIMEZONE() not TIME_ZONE() - see https://docs.aws.amazon.com/redshift/latest/dg/Date_functions_header.html
I am getting my data: date and time in UTC, in a csv file format in separate columns. Since I will need to convert this zone to date and time of the place where I live, currently in summer to UTC+2, and maybe some other zones I was wondering what is the best practice to insert data in postgres when we are talking about type of data. Should I place both of my data in a single column or keep them separate as types: date and time, and if not should I use timestamp or timestampz (or something else).
use timestamptz it will store your time stamp in UTC. and will display it to the client according to it's locale.
https://www.postgresql.org/docs/current/static/datatype-datetime.html
For timestamp with time zone, the internally stored value is always in
UTC (Universal Coordinated Time, traditionally known as Greenwich Mean
Time, GMT). An input value that has an explicit time zone specified is
converted to UTC using the appropriate offset for that time zone. If
no time zone is stated in the input string, then it is assumed to be
in the time zone indicated by the system's TimeZone parameter, and is
converted to UTC using the offset for the timezone zone.
When a timestamp with time zone value is output, it is always
converted from UTC to the current timezone zone, and displayed as
local time in that zone. To see the time in another time zone, either
change timezone or use the AT TIME ZONE construct (see Section 9.9.3).
updated with another good point from Lukasz, I had to mention:
Also in favor of single column is the fact that if you would store
both date and time in separate columns you would still need to combine
them and convert to timestamp if you wanted to change time zone of
date.
Not doing that would lead to date '2017-12-31' with time '23:01:01' would in other time zone in fact be not only different time, but different date with all YEAR and MONTH and DAY different
another update As per Laurenz notice, don't forget the above docs quote
An input value that has an explicit time zone specified is converted to UTC using the appropriate offset for that time zone. Which means you have to manage the input dates carefully. Eg:
t=# create table t(t timestamptz);
CREATE TABLE
t=# set timezone to 'GMT+5';
SET
t=# insert into t select '2017-01-01 00:00:00';
INSERT 0 1
t=# insert into t select '2017-01-01 00:00:00' at time zone 'UTC';
INSERT 0 1
t=# insert into t select '2017-01-01 00:00:00+02';
INSERT 0 1
t=# select * from t;
t
------------------------
2017-01-01 00:00:00-05
2017-01-01 05:00:00-05
2016-12-31 17:00:00-05
(3 rows)
I need to convert the value stored in a bigint column to a date field. The first step of the conversion involves converting it to timestamp, and subsequently use the TRUNC method to convert this column to a date value.
However, my query is failing while converting the bigint value to timestamp.
The error that I'm getting is:-
Amazon Invalid operation: cannot cast type bigint to timestamp without time zone;
The query I'm trying for now is something like this:-
select ts::timestamp from events limit 1;
I was able to avoid the time zone error by using the method described in this thread: https://stackoverflow.com/a/36399361
My dates are based on epochs, and I was able to do the following:
SELECT
(TIMESTAMP 'epoch' + contract_start_date * INTERVAL '1 Second ')
FROM
table_name
SELECT TIMESTAMP 'epoch' + {column of bigint}/1000 * INTERVAL '1 second' as adate FROM tbl
If you are starting with a POSIX timestamp, and trying to get a timezone aware datetime value, you will need to supply a timezone - even if you later want to truncate the time part away. I'm not familiar with redshift, but perhaps there is a way to specify you mean UTC.
I'm trying to format the timestamps in my Postgres database to a certain format:
YYYY-MM-DD HH24:MI:SS
By doing:
update myTable set tds = to_char(tds, 'YYYY-MM-DD HH24:MI:SS')::timestamp;
I managed to set all the previously stored tds to this format. However, any newly added entry goes back to: YYYY-MM-DD HH24:MI:SS.MS since the default is set to now().
How do I change this so that newly added entries also have the format: YYYY-MM-DD HH24:MI:SS?
There is no format stored in a timestamp type. You can set its default to a timestamp truncated to the second at creation time
create table t (
tds timestamp default date_trunc('second', now())
)
Or alter the table
alter table t
alter column tds
set default date_trunc('second', now());
insert into t values (default);
INSERT 0 1
select * from t;
tds
---------------------
2014-03-11 19:24:11
If you just don't want to show the milliseconds part format the output
select to_char(now(), 'YYYY-MM-DD HH24:MI:SS');
to_char
---------------------
2014-03-11 19:39:40
The types timestamp or timestamptz optionally take a precision modifier p: timestamp(p).
To round to full seconds, set the default to:
now()::timestamp(0)
or:
now()::timestamptz(0)
Standard SQL functions CURRENT_TIMESTAMP (returns timestamptz) or LOCALTIMESTAMP (returns timestamp) allow the same precision modifier:
CURRENT_TIMESTAMP(0)
LOCALTIMESTAMP(0)
That's a bit shorter than calling date_trunc() - which truncates fractional seconds (may be what you really want!)
date_trunc('second', now())
Store timestamps as timestamptz (or timestamp), not as character type.
Finally, to make sure that ...
newly added entries also have the format: YYYY-MM-DD HH24:MI:SS
you could define your column as type timestamptz(0). This covers all values entered into that column, not just the default. But the rounding may introduce timestamps up to half a second in the future. If that can be an issue in any way, rather use date_trunc().
See #Clodoaldo's answer for instructions on to_char() and how to ALTER TABLE.
This related answer for in-depth information on timestamps and time zone handling:
Ignoring time zones altogether in Rails and PostgreSQL