I use Jiffy for calculate the difference in between 2 date in month.
But I don't the good result.
For end = 2/4/2023 and start = 1/4/2022 I have 12 months.
For end = 1/4/2023 and start = 1/4/2022 I have 11 months (error: expected 12).
Thanks,
num month = Jiffy(end).diff(Jiffy(start), Units.MONTH);
Right now it is checking 12 at midnight to 12 at midnight of the end date which is 11 months 30 days. Now if the end date is one second greater than the correct date it should work. So a hackey solution is to add one day duration to the end date and check
end.add(duration(day:1))
Related
What is the best way to calculate the numbered day of the week over an 8 week period?
For example, my app tracks a users progress over an 8 week course.
I'm stuck on how to determine the current numbered day of the week according to the weeks progress, for example, Week 6 - Day 5
I have the users course start date as DateTime from Firebase, and can obviously get DateTime.now() to calculate the difference between course start date and now. How do I go from this so that I can display for example:
Week 2 - Day 3 or Week 6 - Day 4
Let's say the course is started 15 days ago, you can get what you want by something like this:
DateTime now = DateTime.now();
DateTime start = now.subtract(Duration(days:15));
int allDays = now.difference(start).inDays;
int w = allDays ~/ 7 + 1;
int d = allDays % 7;
print('Week $w - day $d');
~/ is the Truncating Division Operator which gives you the Integer result of a division
I am trying to convert EPOC time to date time and need to extract the time only from that
I am doing below
$min = $Time_Start | measure -Minimum
$max = $Time_End | measure -Maximum
[datetime]$oUNIXDatemin=(Get-Date 01.01.1970)+([System.TimeSpan]::fromseconds($min.Minimum))
$oUNIXDatemin_1 = $oUNIXDatemin.ToString("HH:mm:ss")
[datetime]$oUNIXDatemax=(Get-Date 01.01.1970)+([System.TimeSpan]::fromseconds($max.Maximum))
$oUNIXDatemax_1 = $oUNIXDatemax.ToString("HH:mm:ss")
Problem is while converting I am getting $oUNIXDatemin_1 and $oUNIXDatemax_1 value like
$oUNIXDatemin_1
12 October 2021 07:46:46
$oUNIXDatemax_1
12 October 2021 21:16:04
My EPOC values are
$min.Minimum
1634024806
$max.Maximum
1634073364
Please let me know what is wrong here. Need to find the difference in HH:mm:ss format.
In PowerShell, you'd usually use a format string. Subtracting two PowerShell datetimes returns a value of type Timespan, which is well-behaved over a span of more than 24 hours.
([datetime]"12 October 2021 21:16:04" - [datetime]"12 October 2021 07:46:46") -f "HH:mm:ss"
13:29:18
Be careful here. Both intervals (durations) and time (of day) have the same format, but different meanings. For example, it makes sense to multiply the interval "01:00:00" (1 hour) by 3 to get three hours; it doesn't make sense to multiply the time "01:00:00" (1 o'clock AM) by 3.
I'm sure the overall calculation can be simplified, but it's too early for me.
How can I in a smart way get the first business day of a month after the weekend?
To get the first business day of the month (given dateInput), we can do:
firstBusdayMonth = fbusdate(year(dateInput),month(dateInput));
As an example, for November, using the above function will return Thursday November 1 as the first business day. However, the first business day of the month after the first weekend is Monday November 5. How can I get this latter date?
Notes:
The weekend does not have to be in the same month.
If the Monday is not a working day, then I would like it to return the next business day
This function will do the trick. Here is the logic:
Create a datetime array for all days in the given month.
Get the day numbers.
Create a logical array, true from the first Monday onwards (so after the first weekend, accounting for the last day of the previous month being a Sunday).
Create another logical array using isbusday to exclude Mondays which aren't working days.
Finding the first day number where these two logical arrays are true, therefore the first business day after the weekend.
Code:
function d = fbusdateAferWE( y, m )
% Inputs: y = year, m = month
% Outputs: day of the month, first business day after weekend
% Create array of days for the given month
dates = datetime( y, m, 1 ):days(1):datetime( y, m, eomday( y, m ) );
% Get the weekday numbers to find first Monday, 1 = Sunday
dayNum = weekday( dates );
% Create the logical array to determine days from first Monday
afterFirstWeekend = ( cumsum(dayNum==2) > 0 ).';
% Get first day which is afterFirstWeekend and a business day.
d = find( afterFirstWeekend & isbusday( dates ), 1 );
end
You could probably speed this up (although it will be pretty rapid already) by not looking at the whole month, but say just 2 weeks. I used eomday to get the last day of the month, which means I don't have to make assumptions about a low number of holiday days in the first week or anything.
Edit: Working with datenum speeds it up by half (C/O JohnAndrews):
function d = fbusdateAferWE( y, m )
% Inputs: y = year, m = month
% Outputs: day of the month, first business day after weekend
% Create array of days for (first 2 weeks of) the given month
dates = datenum(datetime(y,m,1)):datenum(datetime(y,m,eomday(y,m)))-14;
% Get the weekday numbers to find first Monday, 1 = Sunday
dayNum = weekday( dates );
% Create the logical array to determine days from first Monday
afterFirstWeekend = ( cumsum(dayNum==2) > 0 ).';
% Get first day which is afterFirstWeekend and a business day.
d = find( afterFirstWeekend & isbusday( dates ), 1 );
end
I would add something like this after your statement:
[DayNumber, DayName] = weekday(firstBusdayMonth);
if DayNumber > 2
day = 10 - DayNumber;
else
This works because 'weekday' will return a number between 1 (Sunday) and 7 (Saturday).
The fbusdate() function will never return a 1 or 7, so we can ignore those cases.
If weekday(fbusdate()) == 2, the first is on a Monday and the firstBusdayMonth variable doesn't need to be changed.
If weekday(firstBusdayMonth) returns between 2 and 6, we need to skip to the next week, so we subtract the weekday value from 10 to find the next Monday.
It might not be the most elegant solution, but should work.
We can use fbusdate to get the first business day of a month:
Date = fbusdate(Year, Month);
However, how do we get the first business day of a week?
As an example, during the week that I'm posting this, Monday 09/07/2017 was a holiday in the US:
isbusday(736942) % = 0
How do I determine that the first business day for this week would be the next day 736943?
I'm not aware of a builtin function that returns the first working day of a week, but you can obtain it by requesting the next working day after Sunday:
busdate(736941); % 736941 = Sunday 09/03/2017
Your desired fbusdateweek function can be done in one line using just the function weekday to get the first Sunday of the week then busdate to get the next business day after that:
dn = 736942; % Date number for any day in a week
Date = busdate(dn-weekday(dn)+1);
Note: busdate uses the function holidays by default to get all holidays and special nontrading days for the New York Stock Exchange. If necessary, you can define an alternate set of holidays for busdate to use as follows:
holidayArray = ...; % Some set of date numbers, vectors, or datetimes
Date = busdate(dn-weekday(dn)+1, 1, holidayArray);
This way you can define a set of localized holidays.
Solved it. Here is a function that is based on the answer of #m7913d:
function Busday = fbusdateweek(date)
% Return the first business day after Sunday
% 'date' is a datenum input
dperiod = date-6:date;
sundays = weekday(dperiod)==1;
sunday = find(sundays==1,1,'first');
datesunday = dperiod(sunday);
% -->
Busday = busdate(datesunday);
end
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Calculate date from week number
Given Year, Month,Day and the Week number, is it possible to get the Date?
e.g. Year = 2010
Month =Jan
Day = Sun
WeekNumber = 3
output : 2010-01-10
I am trying it in c#
Thanks
I would make it like this:
int Year = 2010;
int Month = 1; //Jan=1, Feb=2, ...
int Day = 0; //Sun=0, Mon=1, ...
int WeekNumber = 3; // greater than 0
DateTime dateValue = new DateTime(Year, Month, 1);
int firstDay = (int)dateValue.DayOfWeek;
dateValue = dateValue.AddDays(Day - firstDay + (WeekNumber - 1) * 7);
I don't think there's something for such date calculations in plain .NET BCL. But there are libraries that can help you, see i.e. Fluent DateTime. Using this library, you can try something like that:
var firstWeekInYearBeginning = new DateTime(2010, 1, 2).Previous(DayOfWeek.Monday); // note 2 to not miss a week if the year begins on Monday
var expectedDate = 3.Weeks().From(firstWeekInYearBeginning);
Based on the APIs here, don't this its possible to initialize a DateTime Object from the information given. You would need to develop an algorithm to get the exact date of the year. A simple strategy would be to get the first Day of the month and based on that, find first Monday of the month. This is the start of WeekNumber 1 for that month, and you can locate your required Week by simpl loop and locate the exact date. You would then know the calendar date you are interested in.
BTW: I am assuming WeekNumber of a year/month starts from the first Monday of that Year/Month. Someone please correct me if I am wrong.
Maybe you should check out System.Globalization.Calendar class. It might be useful.