ReadToken() is returning "Instance of 'Future'"
I was following this tutorial on the Flutter Docs: https://docs.flutter.dev/cookbook/persistence/reading-writing-files.
So, my problem is that, if I just run ReadToken() without running the create function then the ReadToken() function always returns "Instance of 'Future'". Note: I made some changes to the ReadToken() function, like the name. The function is below.
Future<Object> readToken() async {
try {
final file = await _localFile;
// Read the file
final contents = await file.readAsString();
return contents;
} catch (e) {
// If encountering an error, return 0
return 0;
}
}
}
Is there anything that I'm doing wrong or anything that I should change?
You have to await readToken(). If you continue reading the documentation by the complete example section, it shows this example:
#override
void initState() {
super.initState();
widget.storage.readCounter().then((value) {
setState(() {
_counter = value;
});
});
}
It's using .then() instead of await, which await is a syntactic sugar for .then()
So, In your case it would be:
readToken().then((value) {
// Do something with the `value`
});
Related
This question already has answers here:
What is a Future and how do I use it?
(6 answers)
Closed 20 days ago.
How can I make sure I have a state variable available after an async function call? My belief is because getValues() is async, it should "wait" until moving on to the next line. Thus, getValues() shouldn't exit and configValue() shouldn't be invoked until after my call to setState has finished. However the behavior I'm seeing it that values is an empty array in my Widget.
late List values = [];
#override
void initState() {
super.initState();
getValues();
configValue();
}
getValues() async {
final String response = await rootBundle.loadString('assets/values.json');
final vals = await json.decode(response)['values'];
setState(() {
values = vals;
});
}
void configValue() {
// How to make sure I have values[0] here?
}
Thanks in advance!
You can change your getValues to this:
Future<List> getValues() async {
final String response = await rootBundle.loadString('assets/values.json');
final vals = await json.decode(response)['values'];
return vals;
}
then create another middle function like this:
callasyncs() async {
var result = await getValues();
configValue(result);
}
and call it inside initState like this:
#override
void initState() {
super.initState();
callasyncs();
}
also change your configValue to this:
void configValue(List values) {
// now you have updated values here.
}
here your both configValue and getValues are separated from each other and also your configValue will wait for the getValues result.
you need to use await before the method to complete the future. also can be use .then.
Future<void> getVids() async { //I prefer retuning value
final String response = await rootBundle.loadString('assets/values.json');
final vals = await json.decode(response)['values'];
setState(() {
values = vals;
});
}
void configValue() async {
await getVids();
}
Try the following code:
List? values;
#override
void initState() {
super.initState();
getValues();
configValue();
}
Future<void> getVids() async {
final String response = await rootBundle.loadString('assets/values.json');
final vals = await json.decode(response)['values'];
setState(() {
values = vals;
});
}
void configValue() {
if (values != null) {
if (values!.isNotEmpty) {
…
}
}
}
hello I want have to run two functions(Function1() and Function2()) and store value of these returns and run third function. But some time according to condition Function1() or Function2() or both not be run.
if(condition1){
await Function1();
}
if(condition2){
await Function2();
}
await Functon3();
I try as above but Function3() run simultaneously with Function1() or with Function2().
My Function1() code looks like following...
Future Function1() async {
apiService
.apiFileUpload()
.then((value) async {
///codes goes here
}).catchError((error) {
print('EEEE: ' + error.toString());
});
}
If anything not clear please let me know in the comment section.
Please do not use .then() in combination with async/await. It is technically possible, but it takes some skill to get it right, so why make it hard on yourself. Stick with one way of doing it, use either one or the other. You mixed it up and through a slight oversight, your Function1 does not actually wait on it's result. It just returns, with the function still running in the then block. So you await it, but that does not help.
Since you are using await already, stick with that and remove .then() from your repertoire for now:
Future Function1() async {
try {
final value = await apiService.apiFileUpload();
///codes goes here
} catch(error) {
print('EEEE: ' + error.toString());
}
}
You can use await
Future Function1() async {
try{
final value = await apiService
.apiFileUpload();
final value2 = await secondFuntion();
///add more and condition on values
} catch(e){
.....
}
}
from your question you need to tell the compiler to stop on particular task with await and avoid using then function it will never stop your compiler
your future fuction:
Future Function1() async {
apiService
.apiFileUpload()
.then((value) async {
///codes goes here
}).catchError((error) {
print('EEEE: ' + error.toString());
});
}
Modified Future func
Future Function1() async {
var result = await apiService.apiFileUpload();
if(result == success){
// code goes here
}else{
//you can show your error here
}
}
I'm trying to get the return value in my function but the output is 'Instance of Future' instead of the value of school field name in the database
#override
void initState() {
userId = _auth.currentUser!.uid;
publisherSchool =
getName(widget.postInfo['publisher-Id'], 'school').toString();
super.initState();
}
Future getName(String publisherUid, String fieldname) async {
DocumentSnapshot publisherSnapshot = await FirebaseFirestore.instance
.collection('users')
.doc(publisherUid)
.get();
print(publisherSnapshot.get(fieldname));
return publisherSnapshot.get(fieldname);
}
but whenever i'm printing the publisherSnapshop.get(fieldname) i'm getting the correct value from the database
There are 2 ways to do it, you can create a Future method and call it inside the initState like below:
#override
void initState() {
initial();
super.initState();
}
Future<void> initial() async {
userId = _auth.currentUser!.uid;
// Remember using `()` to wrap the `await` to get it result
publisherSchool = (await getName(widget.postInfo['publisher-Id'], 'school')).toString();
}
Or you can use .then to call it directly inside the initState:
#override
void initState() {
userId = _auth.currentUser!.uid;
getName(widget.postInfo['publisher-Id'], 'school').then((value) {
publisherSchool = value.toString();
});
super.initState();
}
When you declare the getName() function, specify the return type as Future<String>, and then when you call getName(), you need to await the result e.g. publisherSchool = await getName(widget.postInfo['publisher-Id'], 'school').toString();
The reason why you are not getting the correct response is because whenever you are working with Futures it takes some time to finish and return the results. Meanwhile it is fetching the result you have to make it await so that the program will continue once that future function is complete since await/then is nowhere to be found in your code hence the issues.
To solve this make this change:
Change
publisherSchool =
getName(widget.postInfo['publisher-Id'], 'school').toString();
To
getName(widget.postInfo['publisher-Id'],
'school').then((value){
publisherSchool=value.toString()});
I have a page that writes a color on file, called "colors.txt".Then the page is closed, when it will be opened again this file will be read and its content (String) printed on the screen.
This is the class that handles reads and writes :
class Pathfinder {
Future<String> get _localPath async {
final directory = await getApplicationDocumentsDirectory();
return directory.path;
}
Future<File> get _localFile async {
final path = await _localPath;
return File('$path/colors.txt');
}
Future<File> writeColor(String color) async {
final file = await _localFile;
// Write the file
return file.writeAsString('$color');
}
Future<String> readColor() async {
try {
final file = await _localFile;
// Read the file
final contents = await file.readAsString();
return contents;
} catch (e) {
// If encountering an error, return 0
return "Error while reading colors";
}
}
}
Before page closure, the color has been saved with writeColor, we just need to read the file and print its content.
And this is how I read the color :
void initState() {
super.initState();
String colorRead;
() async {
pf = new Pathfinder();
colorRead = await pf.readColor();
}();
print("Color in initState: " + colorRead.toString());
}
The problem is that colorRead is always null. I already tried .then() and .whenCompleted() but nothing changed.
So my doubt is :
Am I not waiting read operation in right way or the file, for some reasons, is deleted when page is closed?
I think that if file wouldn't exists then readColor should throw an error.
EDIT : How writeColor is called :
Color bannerColor;
//some code
await pf.writeColor(bannerColor.value.toRadixString(16));
void initState() {
super.initState();
String colorRead;
() async {
pf = new Pathfinder();
colorRead = await pf.readColor();
}();
print("Color in initState: " + colorRead.toString()); /// << this will execute before the async code in the function is executed
}
It's null because of how async/await works. The print statement is going to be called before the anonymous async function finishes executing. If you print in inside the function you should see the color if everything else is working correctly.
I am reading over the documentation for Flutter.
On this page, I have observed the following curious method. In the method, the declared return type is Future. The method though, does not have the return keyword present anywhere. Why is this?
Future<void> _incrementCounter() async {
setState(() {
_counter++;
});
Directory directory = await getApplicationDocumentsDirectory();
final String dirName = directory.path;
await File('$dir/counter.txt').writeAsString('$_counter');
}
I have been able to ascertain that all flutter functions return a value, and the default return value is null. But if this method always returns null, then why declare a return type of Future<void>?
That is because the function is marked with the async modifier:
Future foo() async {
print('hello world');
}
is equivalent to
Future foo() {
try {
print('hello world');
return Future.value(null);
} catch (err) {
return Future.error(err);
}
}
In Dart even-though it's an optionally typed language which means you can omit the type , It's recommended to provide it
When method does not have a return type , return null is appended , So in your example it's fit to return Future.value(null);
please see Default return type in Dart