How to remove ith column of a matrix using for loop - matlab

Question

Using MatLab, I am attempting to begin with a matrix,
column1
column2
column3
column4
column5
1
4
7
10
11
2
5
8
11
12
3
6
9
12
13
and use a for loop to obtain 5 matrices, one with each of the columns removed, according to:
column2
column3
column4
column5
4
7
10
11
5
8
11
12
6
9
12
13
column1
column3
column4
column5
1
7
10
11
2
8
11
12
3
9
12
13
column1
column2
column4
column5
1
4
10
11
2
5
11
12
3
6
12
13
column1
column2
column3
column5
1
4
7
11
2
5
8
12
3
6
9
13
column1
column2
column3
column4
1
4
7
10
2
5
8
11
3
6
9
12
Please note that it is extremely important that this be done IN A LOOP, so as to be replicable for an arbitrary number of columns, as I have managed to code this for a known number of columns already.
Thank you in advance for any help.

Answer 1

That's a pretty straightforward problem for Matlab or Octave. I wonder what your problem was?
m = [
1 4 7 10 11
2 5 8 11 12
3 6 9 12 13
];
outmatrices = {};
for col = 1:size(m,2)
outmatrices{end+1} = [m(:,1:col-1), m(:,col+1:end)];
end
outmatrices

Answer 2

You could use arrayfun( ) for this, which will handle any matrix size and hide the looping behind the function call. E.g.,
result = arrayfun(#(k)[m(:,1:k-1),m(:,k+1:end)],1:size(m,2),'uni',false);
The result will be a cell array with the various matrices as the cell elements.